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V63.0121.021, Calculus I                                                Section 2.3 : Basic Differentiation Rules    September 29, 2010



                                                                                                            Notes
                             Section 2.3
                      Basic Differentiation Rules

                                   V63.0121.021, Calculus I

                                        New York University


                                     September 29, 2010



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       Last chance for extra credit on Quiz 1: Do the get-to-know you
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 Announcements
                                                                                                            Notes




          Last chance for extra credit
          on Quiz 1: Do the
          get-to-know you survey and
          photo by October 1.




  V63.0121.021, Calculus I (NYU)   Section 2.3 Basic Differentiation Rules     September 29, 2010   2 / 42




 Objectives
                                                                                                            Notes



          Understand and use these
          differentiation rules:
                 the derivative of a
                 constant function (zero);
                 the Constant Multiple
                 Rule;
                 the Sum Rule;
                 the Difference Rule;
                 the derivatives of sine and
                 cosine.




  V63.0121.021, Calculus I (NYU)   Section 2.3 Basic Differentiation Rules     September 29, 2010   3 / 42




                                                                                                                                     1
V63.0121.021, Calculus I                                                      Section 2.3 : Basic Differentiation Rules      September 29, 2010


 Recall: the derivative
                                                                                                                    Notes

 Definition
 Let f be a function and a a point in the domain of f . If the limit

                                         f (a + h) − f (a)       f (x) − f (a)
                    f (a) = lim                            = lim
                                   h→0           h           x→a     x −a

 exists, the function is said to be differentiable at a and f (a) is the
 derivative of f at a.
 The derivative . . .
       . . . measures the slope of the line through (a, f (a)) tangent to the
       curve y = f (x);
       . . . represents the instantaneous rate of change of f at a
       . . . produces the best possible linear approximation to f near a.


  V63.0121.021, Calculus I (NYU)         Section 2.3 Basic Differentiation Rules       September 29, 2010   4 / 42




 Notation
                                                                                                                    Notes

       Newtonian notation                                                    Leibnizian notation
                                                                           dy      d                df
       f (x)           y (x)         y                                                f (x)
                                                                           dx      dx               dx




  V63.0121.021, Calculus I (NYU)         Section 2.3 Basic Differentiation Rules       September 29, 2010   5 / 42




 Link between the notations
                                                                                                                    Notes



                                         f (x + ∆x) − f (x)       ∆y   dy
                  f (x) = lim                               = lim    =
                              ∆x→0              ∆x           ∆x→0 ∆x   dx

                                     dy
       Leibniz thought of               as a quotient of “infinitesimals”
                                     dx
                    dy
       We think of     as representing a limit of (finite) difference quotients,
                    dx
       not as an actual fraction itself.
       The notation suggests things which are true even though they don’t
       follow from the notation per se




  V63.0121.021, Calculus I (NYU)         Section 2.3 Basic Differentiation Rules       September 29, 2010   6 / 42




                                                                                                                                             2
V63.0121.021, Calculus I                                                   Section 2.3 : Basic Differentiation Rules        September 29, 2010


 Outline
                                                                                                                   Notes


 Derivatives so far
    Derivatives of power functions by hand
    The Power Rule

 Derivatives of polynomials
    The Power Rule for whole number powers
    The Power Rule for constants
    The Sum Rule
    The Constant Multiple Rule

 Derivatives of sine and cosine



  V63.0121.021, Calculus I (NYU)      Section 2.3 Basic Differentiation Rules         September 29, 2010   7 / 42




 Derivative of the squaring function
                                                                                                                   Notes

 Example
 Suppose f (x) = x 2 . Use the definition of derivative to find f (x).

 Solution


                                     f (x + h) − f (x)       (x + h)2 − x 2
                  f (x) = lim                          = lim
                               h→0           h           h→0       h
                                     x2         2  x2
                                       + 2xh + h −  
                                                                                        2
                                                                                2x h + h¡
                                                                                   ¡
                           = lim                                     = lim
                               h→0        h                               h→0        h
                                                                                     ¡
                           = lim (2x + h) = 2x.
                               h→0

 So f (x) = 2x.


  V63.0121.021, Calculus I (NYU)      Section 2.3 Basic Differentiation Rules         September 29, 2010   8 / 42




 The second derivative
                                                                                                                   Notes



 If f is a function, so is f , and we can seek its derivative.

                                                f = (f )

 It measures the rate of change of the rate of change! Leibnizian notation:

                                     d 2y         d2                    d 2f
                                                       f (x)
                                     dx 2         dx 2                  dx 2




  V63.0121.021, Calculus I (NYU)      Section 2.3 Basic Differentiation Rules         September 29, 2010   9 / 42




                                                                                                                                            3
V63.0121.021, Calculus I                                                    Section 2.3 : Basic Differentiation Rules     September 29, 2010


 The squaring function and its derivatives
                                                                                                                 Notes



                     y
                         f
                                        f                    f increasing =⇒ f ≥ 0
                              f                              f decreasing =⇒ f ≤ 0
                                        x                    horizontal tangent at 0
                                                             =⇒ f (0) = 0




  V63.0121.021, Calculus I (NYU)       Section 2.3 Basic Differentiation Rules     September 29, 2010   10 / 42




 Derivative of the cubing function
                                                                                                                 Notes
 Example
 Suppose f (x) = x 3 . Use the definition of derivative to find f (x).

 Solution




  V63.0121.021, Calculus I (NYU)       Section 2.3 Basic Differentiation Rules     September 29, 2010   11 / 42




 The cubing function and its derivatives
                                                                                                                 Notes




                                   y                                   Notice that f is increasing,
                                       f f                             and f > 0 except f (0) = 0
                                                                       Notice also that the tangent
                                            f                          line to the graph of f at
                                                            x          (0, 0) crosses the graph
                                                                       (contrary to a popular
                                                                       “definition” of the tangent
                                                                       line)




  V63.0121.021, Calculus I (NYU)       Section 2.3 Basic Differentiation Rules     September 29, 2010   12 / 42




                                                                                                                                          4
V63.0121.021, Calculus I                                                      Section 2.3 : Basic Differentiation Rules         September 29, 2010


 Derivative of the square root function
                                                                                                                       Notes
 Example
                        √
 Suppose f (x) =            x = x 1/2 . Use the definition of derivative to find f (x).

 Solution

                                                           √         √
                                  f (x + h) − f (x)          x +h− x
                    f (x) = lim                     = lim
                              h→0         h            h→0      h
                                  √          √ √              √
                                     x +h− x          x +h+ x
                            = lim                  ·√         √
                              h→0        h            x +h+ x
                                      (& + h) − &
                                       x         x                  h
                                      √                        √
                                                                    ¡
                            = lim               √ = lim                √
                              h→0 h     x +h+ x          h→0 h
                                                             ¡   x +h+ x
                                1
                            = √
                              2 x
                √
 So f (x) =         x = 1 x −1/2 .
                        2


  V63.0121.021, Calculus I (NYU)         Section 2.3 Basic Differentiation Rules         September 29, 2010   13 / 42




 The square root function and its derivatives
                                                                                                                       Notes



         y


                    f                                                    Here lim+ f (x) = ∞ and f
                                                                                  x→0
                                     f                                   is not differentiable at 0
                                         x
                                                                         Notice also lim f (x) = 0
                                                                                        x→∞




  V63.0121.021, Calculus I (NYU)         Section 2.3 Basic Differentiation Rules         September 29, 2010   14 / 42




 Derivative of the cube root function
                                                                                                                       Notes
 Example
                        √
 Suppose f (x) =        3
                            x = x 1/3 . Use the definition of derivative to find f (x).

 Solution




  V63.0121.021, Calculus I (NYU)         Section 2.3 Basic Differentiation Rules         September 29, 2010   15 / 42




                                                                                                                                                5
V63.0121.021, Calculus I                                                Section 2.3 : Basic Differentiation Rules          September 29, 2010


 The cube root function and its derivatives
                                                                                                                  Notes




                              y

                                                                      Here lim f (x) = ∞ and f is
                                   f                                        x→0
                                                                      not differentiable at 0
                                                       f
                                                           x          Notice also lim f (x) = 0
                                                                                      x→±∞




  V63.0121.021, Calculus I (NYU)   Section 2.3 Basic Differentiation Rules          September 29, 2010   16 / 42




 One more
                                                                                                                  Notes

 Example
 Suppose f (x) = x 2/3 . Use the definition of derivative to find f (x).

 Solution




  V63.0121.021, Calculus I (NYU)   Section 2.3 Basic Differentiation Rules          September 29, 2010   17 / 42




 The function x → x 2/3 and its derivative
                                                                                                                  Notes




                              y

                                                                      f is not differentiable at 0
                                   f                                  and lim f (x) = ±∞
                                                                            x→0±
                                                       f
                                                           x          Notice also lim f (x) = 0
                                                                                      x→±∞




  V63.0121.021, Calculus I (NYU)   Section 2.3 Basic Differentiation Rules          September 29, 2010   18 / 42




                                                                                                                                           6
V63.0121.021, Calculus I                                                 Section 2.3 : Basic Differentiation Rules     September 29, 2010


 Recap: The Tower of Power
                                                                                                              Notes



                  y           y
                  x2         2x 1                                   The power goes down by
                  x3         3x 2                                   one in each derivative
                           1 −1/2                                   The coefficient in the
                x 1/2      2x                                       derivative is the power of
                           1 −2/3
                x 1/3      3x                                       the original function
                           2 −1/3
                x 2/3      3x




  V63.0121.021, Calculus I (NYU)    Section 2.3 Basic Differentiation Rules     September 29, 2010   19 / 42




 The Power Rule
                                                                                                              Notes

 There is mounting evidence for
 Theorem (The Power Rule)
 Let r be a real number and f (x) = x r . Then

                                           f (x) = rx r −1

 as long as the expression on the right-hand side is defined.

       Perhaps the most famous rule in calculus
       We will assume it as of today
       We will prove it many ways for many different r .



  V63.0121.021, Calculus I (NYU)    Section 2.3 Basic Differentiation Rules     September 29, 2010   20 / 42




 The other Tower of Power
                                                                                                              Notes




  V63.0121.021, Calculus I (NYU)    Section 2.3 Basic Differentiation Rules     September 29, 2010   21 / 42




                                                                                                                                       7
V63.0121.021, Calculus I                                                                  Section 2.3 : Basic Differentiation Rules    September 29, 2010


 Outline
                                                                                                                              Notes


 Derivatives so far
    Derivatives of power functions by hand
    The Power Rule

 Derivatives of polynomials
    The Power Rule for whole number powers
    The Power Rule for constants
    The Sum Rule
    The Constant Multiple Rule

 Derivatives of sine and cosine



  V63.0121.021, Calculus I (NYU)                     Section 2.3 Basic Differentiation Rules    September 29, 2010   22 / 42




 Remember your algebra
                                                                                                                              Notes
 Fact
 Let n be a positive whole number. Then

             (x + h)n = x n + nx n−1 h + (stuff with at least two hs in it)


 Proof.
 We have
                                                                                                n
         (x + h)n = (x + h) · (x + h) · (x + h) · · · (x + h) =                                      ck x k hn−k
                                                              n copies                         k=0

                                     n
 The coefficient of x is 1 because we have to choose x from each
 binomial, and there’s only one way to do that. The coefficient of x n−1 h is
 the number of ways we can choose x n − 1 times, which is the same as the
 number of different hs we can pick, which is n.
  V63.0121.021, Calculus I (NYU)                     Section 2.3 Basic Differentiation Rules    September 29, 2010   23 / 42




 Pascal’s Triangle
                                                                                                                              Notes

                             1

                         1       1

                     1       2       1

                 1       3       3       1
                                                                       (x + h)0 = 1
             1       4       6       4       1                         (x + h)1 = 1x + 1h
                                                                       (x + h)2 = 1x 2 + 2xh + 1h2
         1       5 10 10 5                       1
                                                                       (x + h)3 = 1x 3 + 3x 2 h + 3xh2 + 1h3
                                                                                ... ...
     1       6 15 20 15 6                            1


  V63.0121.021, Calculus I (NYU)                     Section 2.3 Basic Differentiation Rules    September 29, 2010   24 / 42




                                                                                                                                                       8
V63.0121.021, Calculus I                                                   Section 2.3 : Basic Differentiation Rules         September 29, 2010


 Proving the Power Rule
                                                                                                                    Notes
 Theorem (The Power Rule)
 Let n be a positive whole number. Then
                                             d n
                                                x = nx n−1
                                             dx


 Proof.
 As we showed above,

                (x + h)n = x n + nx n−1 h + (stuff with at least two hs in it)

 So
                (x + h)n − x n   nx n−1 h + (stuff with at least two hs in it)
                               =
                      h                               h
                               = nx n−1 + (stuff with at least one h in it)

 and this tends to nx n−1 as h → 0.
  V63.0121.021, Calculus I (NYU)      Section 2.3 Basic Differentiation Rules         September 29, 2010   25 / 42




 The Power Rule for constants
                                                                                                                    Notes

 Theorem                                                                          d 0
                                                                           like      x = 0x −1
 Let c be a constant. Then                                                        dx
                                                 d
                                                    c=0
                                                 dx

 (although x → 0x −1 is not defined at zero.)
 Proof.
 Let f (x) = c. Then

                                   f (x + h) − f (x)   c −c
                                                     =      =0
                                           h             h
 So f (x) = lim 0 = 0.
                  h→0



  V63.0121.021, Calculus I (NYU)      Section 2.3 Basic Differentiation Rules         September 29, 2010   26 / 42




 Calculus
                                                                                                                    Notes




                                                                                                                                             9
V63.0121.021, Calculus I                                                  Section 2.3 : Basic Differentiation Rules    September 29, 2010


 Recall the Limit Laws
                                                                                                              Notes




 Fact
 Suppose lim f (x) = L and lim g (x) = M and c is a constant. Then
              x→a                        x→a
  1. lim [f (x) + g (x)] = L + M
        x→a
  2. lim [f (x) − g (x)] = L − M
        x→a
  3. lim [cf (x)] = cL
        x→a
  4. . . .




  V63.0121.021, Calculus I (NYU)     Section 2.3 Basic Differentiation Rules    September 29, 2010   28 / 42




 Adding functions
                                                                                                              Notes



 Theorem (The Sum Rule)
 Let f and g be functions and define

                                    (f + g )(x) = f (x) + g (x)

 Then if f and g are differentiable at x, then so is f + g and

                                   (f + g ) (x) = f (x) + g (x).

 Succinctly, (f + g ) = f + g .




  V63.0121.021, Calculus I (NYU)     Section 2.3 Basic Differentiation Rules    September 29, 2010   29 / 42




 Proof of the Sum Rule
                                                                                                              Notes

 Proof.
 Follow your nose:

                                    (f + g )(x + h) − (f + g )(x)
             (f + g ) (x) = lim
                                   h→0             h
                                    f (x + h) + g (x + h) − [f (x) + g (x)]
                              = lim
                                h→0                   h
                                    f (x + h) − f (x)       g (x + h) − g (x)
                              = lim                   + lim
                                h→0         h           h→0          h
                              = f (x) + g (x)


 Note the use of the Sum Rule for limits. Since the limits of the difference
 quotients for for f and g exist, the limit of the sum is the sum of the limits.

  V63.0121.021, Calculus I (NYU)     Section 2.3 Basic Differentiation Rules    September 29, 2010   30 / 42




                                                                                                                                      10
V63.0121.021, Calculus I                                                Section 2.3 : Basic Differentiation Rules         September 29, 2010


 Scaling functions
                                                                                                                 Notes



 Theorem (The Constant Multiple Rule)
 Let f be a function and c a constant. Define

                                        (cf )(x) = cf (x)

 Then if f is differentiable at x, so is cf and

                                      (cf ) (x) = c · f (x)

 Succinctly, (cf ) = cf .




  V63.0121.021, Calculus I (NYU)   Section 2.3 Basic Differentiation Rules         September 29, 2010   31 / 42




 Proof of the Constant Multiple Rule
                                                                                                                 Notes


 Proof.
 Again, follow your nose.

                                             (cf )(x + h) − (cf )(x)
                            (cf ) (x) = lim
                                         h→0             h
                                             cf (x + h) − cf (x)
                                     = lim
                                       h→0            h
                                               f (x + h) − f (x)
                                     = c lim
                                         h→0           h
                                     = c · f (x)




  V63.0121.021, Calculus I (NYU)   Section 2.3 Basic Differentiation Rules         September 29, 2010   32 / 42




 Derivatives of polynomials
                                                                                                                 Notes
 Example
      d
 Find    2x 3 + x 4 − 17x 12 + 37
      dx

 Solution


   d
      2x 3 + x 4 − 17x 12 + 37
   dx
                  d            d 4      d               d
               =      2x 3 +      x +       −17x 12 +      (37)
                  dx          dx       dx               dx
                          d        d 4         d
                     = 2 x3 +         x − 17 x 12 + 0
                          dx       dx         dx
                        = 2 · 3x 2 + 4x 3 − 17 · 12x 11
                                                                            = 6x 2 + 4x 3 − 204x 11

  V63.0121.021, Calculus I (NYU)   Section 2.3 Basic Differentiation Rules         September 29, 2010   33 / 42




                                                                                                                                         11
V63.0121.021, Calculus I                                                 Section 2.3 : Basic Differentiation Rules    September 29, 2010


 Outline
                                                                                                             Notes


 Derivatives so far
    Derivatives of power functions by hand
    The Power Rule

 Derivatives of polynomials
    The Power Rule for whole number powers
    The Power Rule for constants
    The Sum Rule
    The Constant Multiple Rule

 Derivatives of sine and cosine



  V63.0121.021, Calculus I (NYU)    Section 2.3 Basic Differentiation Rules    September 29, 2010   34 / 42




 Derivatives of Sine and Cosine
                                                                                                             Notes
 Fact

                                           d
                                              sin x = cos x
                                           dx

 Proof.
 From the definition:
                       d                sin(x + h) − sin x
                          sin x = lim
                       dx         h→0            h
                                       ( sin x cos h + cos x sin h) − sin x
                                = lim
                                  h→0                    h
                                               cos h − 1                 sin h
                                = sin x · lim             + cos x · lim
                                          h→0       h               h→0 h
                                = sin x · 0 + cos x · 1 = cos x




  V63.0121.021, Calculus I (NYU)    Section 2.3 Basic Differentiation Rules    September 29, 2010   35 / 42




 Angle addition formulas
 See Appendix A                                                                                              Notes




  V63.0121.021, Calculus I (NYU)    Section 2.3 Basic Differentiation Rules    September 29, 2010   36 / 42




                                                                                                                                     12
V63.0121.021, Calculus I                                                    Section 2.3 : Basic Differentiation Rules         September 29, 2010


 Two important trigonometric limits
 See Section 1.4                                                                                                     Notes




                                                                                  sin θ
                                                                                lim     =1
                                                                                θ→0 θ
                                   sin θ θ                                      cos θ − 1
                                                                            lim           =0
                    θ                                                       θ→0     θ

                             1 − cos θ         1



  V63.0121.021, Calculus I (NYU)       Section 2.3 Basic Differentiation Rules         September 29, 2010   38 / 42




 Illustration of Sine and Cosine
                                                                                                                     Notes



                                                   y


                                                                                            x
                      π             −π              0               π             π
                                     2                              2                      cos x
                                                                                           sin x


        f (x) = sin x has horizontal tangents where f = cos(x) is zero.
        what happens at the horizontal tangents of cos?




  V63.0121.021, Calculus I (NYU)       Section 2.3 Basic Differentiation Rules         September 29, 2010   40 / 42




 Derivatives of Sine and Cosine
                                                                                                                     Notes
 Fact

                               d                            d
                                  sin x = cos x                cos x = − sin x
                               dx                           dx

 Proof.
 We already did the first. The second is similar (mutatis mutandis):

                        d               cos(x + h) − cos x
                           cos x = lim
                        dx         h→0            h
                                        (cos x cos h − sin x sin h) − cos x
                                 = lim
                                   h→0                    h
                                               cos h − 1                 sin h
                                 = cos x · lim             − sin x · lim
                                           h→0      h                h→0 h
                                 = cos x · 0 − sin x · 1 = − sin x



  V63.0121.021, Calculus I (NYU)       Section 2.3 Basic Differentiation Rules         September 29, 2010   41 / 42




                                                                                                                                             13
V63.0121.021, Calculus I                                                Section 2.3 : Basic Differentiation Rules    September 29, 2010


 What have we learned today?
                                                                                                            Notes




       The Power Rule
       The derivative of a sum is the sum of the derivatives
       The derivative of a constant multiple of a function is that constant
       multiple of the derivative
       The derivative of sine is cosine
       The derivative of cosine is the opposite of sine.




  V63.0121.021, Calculus I (NYU)   Section 2.3 Basic Differentiation Rules    September 29, 2010   42 / 42




                                                                                                            Notes




                                                                                                            Notes




                                                                                                                                    14

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Lesson 8: Basic Differentiation Rules (Section 21 handout)

  • 1. V63.0121.021, Calculus I Section 2.3 : Basic Differentiation Rules September 29, 2010 Notes Section 2.3 Basic Differentiation Rules V63.0121.021, Calculus I New York University September 29, 2010 Announcements Last chance for extra credit on Quiz 1: Do the get-to-know you survey and photo by October 1. Announcements Notes Last chance for extra credit on Quiz 1: Do the get-to-know you survey and photo by October 1. V63.0121.021, Calculus I (NYU) Section 2.3 Basic Differentiation Rules September 29, 2010 2 / 42 Objectives Notes Understand and use these differentiation rules: the derivative of a constant function (zero); the Constant Multiple Rule; the Sum Rule; the Difference Rule; the derivatives of sine and cosine. V63.0121.021, Calculus I (NYU) Section 2.3 Basic Differentiation Rules September 29, 2010 3 / 42 1
  • 2. V63.0121.021, Calculus I Section 2.3 : Basic Differentiation Rules September 29, 2010 Recall: the derivative Notes Definition Let f be a function and a a point in the domain of f . If the limit f (a + h) − f (a) f (x) − f (a) f (a) = lim = lim h→0 h x→a x −a exists, the function is said to be differentiable at a and f (a) is the derivative of f at a. The derivative . . . . . . measures the slope of the line through (a, f (a)) tangent to the curve y = f (x); . . . represents the instantaneous rate of change of f at a . . . produces the best possible linear approximation to f near a. V63.0121.021, Calculus I (NYU) Section 2.3 Basic Differentiation Rules September 29, 2010 4 / 42 Notation Notes Newtonian notation Leibnizian notation dy d df f (x) y (x) y f (x) dx dx dx V63.0121.021, Calculus I (NYU) Section 2.3 Basic Differentiation Rules September 29, 2010 5 / 42 Link between the notations Notes f (x + ∆x) − f (x) ∆y dy f (x) = lim = lim = ∆x→0 ∆x ∆x→0 ∆x dx dy Leibniz thought of as a quotient of “infinitesimals” dx dy We think of as representing a limit of (finite) difference quotients, dx not as an actual fraction itself. The notation suggests things which are true even though they don’t follow from the notation per se V63.0121.021, Calculus I (NYU) Section 2.3 Basic Differentiation Rules September 29, 2010 6 / 42 2
  • 3. V63.0121.021, Calculus I Section 2.3 : Basic Differentiation Rules September 29, 2010 Outline Notes Derivatives so far Derivatives of power functions by hand The Power Rule Derivatives of polynomials The Power Rule for whole number powers The Power Rule for constants The Sum Rule The Constant Multiple Rule Derivatives of sine and cosine V63.0121.021, Calculus I (NYU) Section 2.3 Basic Differentiation Rules September 29, 2010 7 / 42 Derivative of the squaring function Notes Example Suppose f (x) = x 2 . Use the definition of derivative to find f (x). Solution f (x + h) − f (x) (x + h)2 − x 2 f (x) = lim = lim h→0 h h→0 h x2 2 x2   + 2xh + h −       2 2x h + h¡ ¡ = lim = lim h→0 h h→0 h ¡ = lim (2x + h) = 2x. h→0 So f (x) = 2x. V63.0121.021, Calculus I (NYU) Section 2.3 Basic Differentiation Rules September 29, 2010 8 / 42 The second derivative Notes If f is a function, so is f , and we can seek its derivative. f = (f ) It measures the rate of change of the rate of change! Leibnizian notation: d 2y d2 d 2f f (x) dx 2 dx 2 dx 2 V63.0121.021, Calculus I (NYU) Section 2.3 Basic Differentiation Rules September 29, 2010 9 / 42 3
  • 4. V63.0121.021, Calculus I Section 2.3 : Basic Differentiation Rules September 29, 2010 The squaring function and its derivatives Notes y f f f increasing =⇒ f ≥ 0 f f decreasing =⇒ f ≤ 0 x horizontal tangent at 0 =⇒ f (0) = 0 V63.0121.021, Calculus I (NYU) Section 2.3 Basic Differentiation Rules September 29, 2010 10 / 42 Derivative of the cubing function Notes Example Suppose f (x) = x 3 . Use the definition of derivative to find f (x). Solution V63.0121.021, Calculus I (NYU) Section 2.3 Basic Differentiation Rules September 29, 2010 11 / 42 The cubing function and its derivatives Notes y Notice that f is increasing, f f and f > 0 except f (0) = 0 Notice also that the tangent f line to the graph of f at x (0, 0) crosses the graph (contrary to a popular “definition” of the tangent line) V63.0121.021, Calculus I (NYU) Section 2.3 Basic Differentiation Rules September 29, 2010 12 / 42 4
  • 5. V63.0121.021, Calculus I Section 2.3 : Basic Differentiation Rules September 29, 2010 Derivative of the square root function Notes Example √ Suppose f (x) = x = x 1/2 . Use the definition of derivative to find f (x). Solution √ √ f (x + h) − f (x) x +h− x f (x) = lim = lim h→0 h h→0 h √ √ √ √ x +h− x x +h+ x = lim ·√ √ h→0 h x +h+ x (& + h) − & x x h √ √ ¡ = lim √ = lim √ h→0 h x +h+ x h→0 h ¡ x +h+ x 1 = √ 2 x √ So f (x) = x = 1 x −1/2 . 2 V63.0121.021, Calculus I (NYU) Section 2.3 Basic Differentiation Rules September 29, 2010 13 / 42 The square root function and its derivatives Notes y f Here lim+ f (x) = ∞ and f x→0 f is not differentiable at 0 x Notice also lim f (x) = 0 x→∞ V63.0121.021, Calculus I (NYU) Section 2.3 Basic Differentiation Rules September 29, 2010 14 / 42 Derivative of the cube root function Notes Example √ Suppose f (x) = 3 x = x 1/3 . Use the definition of derivative to find f (x). Solution V63.0121.021, Calculus I (NYU) Section 2.3 Basic Differentiation Rules September 29, 2010 15 / 42 5
  • 6. V63.0121.021, Calculus I Section 2.3 : Basic Differentiation Rules September 29, 2010 The cube root function and its derivatives Notes y Here lim f (x) = ∞ and f is f x→0 not differentiable at 0 f x Notice also lim f (x) = 0 x→±∞ V63.0121.021, Calculus I (NYU) Section 2.3 Basic Differentiation Rules September 29, 2010 16 / 42 One more Notes Example Suppose f (x) = x 2/3 . Use the definition of derivative to find f (x). Solution V63.0121.021, Calculus I (NYU) Section 2.3 Basic Differentiation Rules September 29, 2010 17 / 42 The function x → x 2/3 and its derivative Notes y f is not differentiable at 0 f and lim f (x) = ±∞ x→0± f x Notice also lim f (x) = 0 x→±∞ V63.0121.021, Calculus I (NYU) Section 2.3 Basic Differentiation Rules September 29, 2010 18 / 42 6
  • 7. V63.0121.021, Calculus I Section 2.3 : Basic Differentiation Rules September 29, 2010 Recap: The Tower of Power Notes y y x2 2x 1 The power goes down by x3 3x 2 one in each derivative 1 −1/2 The coefficient in the x 1/2 2x derivative is the power of 1 −2/3 x 1/3 3x the original function 2 −1/3 x 2/3 3x V63.0121.021, Calculus I (NYU) Section 2.3 Basic Differentiation Rules September 29, 2010 19 / 42 The Power Rule Notes There is mounting evidence for Theorem (The Power Rule) Let r be a real number and f (x) = x r . Then f (x) = rx r −1 as long as the expression on the right-hand side is defined. Perhaps the most famous rule in calculus We will assume it as of today We will prove it many ways for many different r . V63.0121.021, Calculus I (NYU) Section 2.3 Basic Differentiation Rules September 29, 2010 20 / 42 The other Tower of Power Notes V63.0121.021, Calculus I (NYU) Section 2.3 Basic Differentiation Rules September 29, 2010 21 / 42 7
  • 8. V63.0121.021, Calculus I Section 2.3 : Basic Differentiation Rules September 29, 2010 Outline Notes Derivatives so far Derivatives of power functions by hand The Power Rule Derivatives of polynomials The Power Rule for whole number powers The Power Rule for constants The Sum Rule The Constant Multiple Rule Derivatives of sine and cosine V63.0121.021, Calculus I (NYU) Section 2.3 Basic Differentiation Rules September 29, 2010 22 / 42 Remember your algebra Notes Fact Let n be a positive whole number. Then (x + h)n = x n + nx n−1 h + (stuff with at least two hs in it) Proof. We have n (x + h)n = (x + h) · (x + h) · (x + h) · · · (x + h) = ck x k hn−k n copies k=0 n The coefficient of x is 1 because we have to choose x from each binomial, and there’s only one way to do that. The coefficient of x n−1 h is the number of ways we can choose x n − 1 times, which is the same as the number of different hs we can pick, which is n. V63.0121.021, Calculus I (NYU) Section 2.3 Basic Differentiation Rules September 29, 2010 23 / 42 Pascal’s Triangle Notes 1 1 1 1 2 1 1 3 3 1 (x + h)0 = 1 1 4 6 4 1 (x + h)1 = 1x + 1h (x + h)2 = 1x 2 + 2xh + 1h2 1 5 10 10 5 1 (x + h)3 = 1x 3 + 3x 2 h + 3xh2 + 1h3 ... ... 1 6 15 20 15 6 1 V63.0121.021, Calculus I (NYU) Section 2.3 Basic Differentiation Rules September 29, 2010 24 / 42 8
  • 9. V63.0121.021, Calculus I Section 2.3 : Basic Differentiation Rules September 29, 2010 Proving the Power Rule Notes Theorem (The Power Rule) Let n be a positive whole number. Then d n x = nx n−1 dx Proof. As we showed above, (x + h)n = x n + nx n−1 h + (stuff with at least two hs in it) So (x + h)n − x n nx n−1 h + (stuff with at least two hs in it) = h h = nx n−1 + (stuff with at least one h in it) and this tends to nx n−1 as h → 0. V63.0121.021, Calculus I (NYU) Section 2.3 Basic Differentiation Rules September 29, 2010 25 / 42 The Power Rule for constants Notes Theorem d 0 like x = 0x −1 Let c be a constant. Then dx d c=0 dx (although x → 0x −1 is not defined at zero.) Proof. Let f (x) = c. Then f (x + h) − f (x) c −c = =0 h h So f (x) = lim 0 = 0. h→0 V63.0121.021, Calculus I (NYU) Section 2.3 Basic Differentiation Rules September 29, 2010 26 / 42 Calculus Notes 9
  • 10. V63.0121.021, Calculus I Section 2.3 : Basic Differentiation Rules September 29, 2010 Recall the Limit Laws Notes Fact Suppose lim f (x) = L and lim g (x) = M and c is a constant. Then x→a x→a 1. lim [f (x) + g (x)] = L + M x→a 2. lim [f (x) − g (x)] = L − M x→a 3. lim [cf (x)] = cL x→a 4. . . . V63.0121.021, Calculus I (NYU) Section 2.3 Basic Differentiation Rules September 29, 2010 28 / 42 Adding functions Notes Theorem (The Sum Rule) Let f and g be functions and define (f + g )(x) = f (x) + g (x) Then if f and g are differentiable at x, then so is f + g and (f + g ) (x) = f (x) + g (x). Succinctly, (f + g ) = f + g . V63.0121.021, Calculus I (NYU) Section 2.3 Basic Differentiation Rules September 29, 2010 29 / 42 Proof of the Sum Rule Notes Proof. Follow your nose: (f + g )(x + h) − (f + g )(x) (f + g ) (x) = lim h→0 h f (x + h) + g (x + h) − [f (x) + g (x)] = lim h→0 h f (x + h) − f (x) g (x + h) − g (x) = lim + lim h→0 h h→0 h = f (x) + g (x) Note the use of the Sum Rule for limits. Since the limits of the difference quotients for for f and g exist, the limit of the sum is the sum of the limits. V63.0121.021, Calculus I (NYU) Section 2.3 Basic Differentiation Rules September 29, 2010 30 / 42 10
  • 11. V63.0121.021, Calculus I Section 2.3 : Basic Differentiation Rules September 29, 2010 Scaling functions Notes Theorem (The Constant Multiple Rule) Let f be a function and c a constant. Define (cf )(x) = cf (x) Then if f is differentiable at x, so is cf and (cf ) (x) = c · f (x) Succinctly, (cf ) = cf . V63.0121.021, Calculus I (NYU) Section 2.3 Basic Differentiation Rules September 29, 2010 31 / 42 Proof of the Constant Multiple Rule Notes Proof. Again, follow your nose. (cf )(x + h) − (cf )(x) (cf ) (x) = lim h→0 h cf (x + h) − cf (x) = lim h→0 h f (x + h) − f (x) = c lim h→0 h = c · f (x) V63.0121.021, Calculus I (NYU) Section 2.3 Basic Differentiation Rules September 29, 2010 32 / 42 Derivatives of polynomials Notes Example d Find 2x 3 + x 4 − 17x 12 + 37 dx Solution d 2x 3 + x 4 − 17x 12 + 37 dx d d 4 d d = 2x 3 + x + −17x 12 + (37) dx dx dx dx d d 4 d = 2 x3 + x − 17 x 12 + 0 dx dx dx = 2 · 3x 2 + 4x 3 − 17 · 12x 11 = 6x 2 + 4x 3 − 204x 11 V63.0121.021, Calculus I (NYU) Section 2.3 Basic Differentiation Rules September 29, 2010 33 / 42 11
  • 12. V63.0121.021, Calculus I Section 2.3 : Basic Differentiation Rules September 29, 2010 Outline Notes Derivatives so far Derivatives of power functions by hand The Power Rule Derivatives of polynomials The Power Rule for whole number powers The Power Rule for constants The Sum Rule The Constant Multiple Rule Derivatives of sine and cosine V63.0121.021, Calculus I (NYU) Section 2.3 Basic Differentiation Rules September 29, 2010 34 / 42 Derivatives of Sine and Cosine Notes Fact d sin x = cos x dx Proof. From the definition: d sin(x + h) − sin x sin x = lim dx h→0 h ( sin x cos h + cos x sin h) − sin x = lim h→0 h cos h − 1 sin h = sin x · lim + cos x · lim h→0 h h→0 h = sin x · 0 + cos x · 1 = cos x V63.0121.021, Calculus I (NYU) Section 2.3 Basic Differentiation Rules September 29, 2010 35 / 42 Angle addition formulas See Appendix A Notes V63.0121.021, Calculus I (NYU) Section 2.3 Basic Differentiation Rules September 29, 2010 36 / 42 12
  • 13. V63.0121.021, Calculus I Section 2.3 : Basic Differentiation Rules September 29, 2010 Two important trigonometric limits See Section 1.4 Notes sin θ lim =1 θ→0 θ sin θ θ cos θ − 1 lim =0 θ θ→0 θ 1 − cos θ 1 V63.0121.021, Calculus I (NYU) Section 2.3 Basic Differentiation Rules September 29, 2010 38 / 42 Illustration of Sine and Cosine Notes y x π −π 0 π π 2 2 cos x sin x f (x) = sin x has horizontal tangents where f = cos(x) is zero. what happens at the horizontal tangents of cos? V63.0121.021, Calculus I (NYU) Section 2.3 Basic Differentiation Rules September 29, 2010 40 / 42 Derivatives of Sine and Cosine Notes Fact d d sin x = cos x cos x = − sin x dx dx Proof. We already did the first. The second is similar (mutatis mutandis): d cos(x + h) − cos x cos x = lim dx h→0 h (cos x cos h − sin x sin h) − cos x = lim h→0 h cos h − 1 sin h = cos x · lim − sin x · lim h→0 h h→0 h = cos x · 0 − sin x · 1 = − sin x V63.0121.021, Calculus I (NYU) Section 2.3 Basic Differentiation Rules September 29, 2010 41 / 42 13
  • 14. V63.0121.021, Calculus I Section 2.3 : Basic Differentiation Rules September 29, 2010 What have we learned today? Notes The Power Rule The derivative of a sum is the sum of the derivatives The derivative of a constant multiple of a function is that constant multiple of the derivative The derivative of sine is cosine The derivative of cosine is the opposite of sine. V63.0121.021, Calculus I (NYU) Section 2.3 Basic Differentiation Rules September 29, 2010 42 / 42 Notes Notes 14