3. Fixed costs :
Unaffected by changes in activity level over a
feasible range of operations for the capacity or
capability available.
Example :insurance and taxes on facilities,
administrative salaries, license fees, and
interest costs on borrowed capital.
4. Variable Costs :
• It vary in total with the number of the output
unite .
• Example :
costs of material and labor used in a product or
service, because they vary in total with the
number of output units even though costs per
unit remain the same.
5. More ways to categorize costs
• Direct: can be measured and allocated to a specific
work activity
(Materials, Labor)
• Indirect: difficult to attribute or allocate to a
specific output or work activity
(overhead, maintenance)
• Standard cost: cost per unit of output,
Standard costs play an important role in cost control and
other management functions.
6. • Cash cost: a cost that involves a payment of cash.
• Book cost: a cost that does not involve a cash
transaction but is reflected in the accounting
system.
( equipments, machines, Depreciation)
• Sunk cost: a cost that has occurred in the past and
has no relevance to estimates of future costs and
revenues related to an alternative course of action.
(money spend on a passport)
7. • Opportunity cost: the monetary advantage foregone due
to limited resources. The cost of the best rejected
opportunity.
( A student can work with 10,000$ Per year.
or goes to the university for a year and spend 5,000$.
Opportunity cost = 15,000$)
• Life-cycle cost: the summation of all costs related to a
product, structure, system, or service during its life
span.
9. Cost Factor Site A Site B •5,000 cubic yards of
Distance 6 miles 4.3 miles asphalt
Monthly $1,000 $5,000 •4 months (17 weeks
rental cost 5- days a week)
Cost (Set up $ $15,000 $25,000 •Compare the
Removing)
Equipment
2 sites??!!!!!
Hauling $1.15/yd3 – $1.15/yd3 – •NOTE:
expenses mile mile •Rent , Set up/
Removal and Flag
Flag person No need $96/day person are Fixed costs
($8,160)
BUT
10. BUT Hauling is variable cost
Site A = 6*5000*$1.15 = $345,000
Site B= 4.3*5,000*$1.15 = $247,250
Then the total cost is
11. 2. Which is the better site? Site B
3. How many cubic yards of asphalt does the contractor have to
deliver before starting to make a profit if paid 8.05$ per cubic yard
12. سئل الحسن البصري عن سر زهده في الدنيا فقال:
أربعة أشياء
علمت أن عملي ل يقوم به غيري فاشتغلت به.
وعلمت أن رزقي ل يذهب إلى غيري فاطمأن قلبي.
و علمت أن ال مطلع علي فاستحييت أن يراني على
معصية.
وعلمت أن الموت ينتظرني فاعددت الزاد للقاء ربي.
14. Goods and service are produced and desired because they
have utility.
Utility: The power to satisfy human wants and needs.
Utility is most commonly measured in terms of value.
Value: the price that must be paid to obtain the particular
item.
Necessities and Luxuries needs.
15. Price And Demand
Engineering focusing on increasing the utility
(value) of materials by changing their form or
location.
P : the price that must be paid
D: is the quantity that must be demanded or
purchased
17. The demand for a product or service is directly related to
its price according to
p = a - bD
for 0 ≤ D ≤ a/b , a > 0, b > 0
where p is price, D is demand, and a and b are constants
that depend on the particular product or service.
a = price axis intercept
-b = slope
18. Total Revenue Function
Total revenue is the product of the selling price per unit,
p, and the number of units sold, D.
TR = p × D
From: p = a – bD
We find:
19. Maximize Revenue
TR = a D − b D 2
d 2TR
2
= − 2b < 0
dD
The demand at maximum revenue: ˆ = a
D
2b
ˆ ˆ a2 a2 a2
Maximum TR = a D − b D 2 = − =
2b 4b 4b
20.
21. Profit
Profit = Total Revenue (TR) – Total Cost (CT)
Total Cost (CT) = Fixed Cost (CF) + Variable Cost (CV)
CT = C F + CV
Variable Cost (CV) = Variable cost per unit (cv) × Demand (D)
CV = cv × D
Total Cost: CT = C F + c v D
23. Profit = Total Revenue (TR) – Total Cost (CT)
and CT = C F + cv D
and TR = a D − b D 2
Then Profit = (a D − b D 2 ) − ( CF + cv D)
Profit = − b D 2 + (a − cv ) D − CF
To find the maximum profit d ( profit )
= a − cv − 2 b D = 0
dD
d 2 ( profit )
2
= − 2b < 0
dD
a − cv
Demand at Max profit: D *=
2b
24. Breakeven points are found when
Total Revenue = Total Cost.
a D − b D 2 = CF + cv D
− b D 2 + (a − cv ) D − CF = 0
The demand at breakeven:
D′ =
[
− ( a − c v ) ± ( a − c v ) − 4 ( − b )( − C F )
2
] 1
2
− 2b
25. Example: A company produces an electronic timing switch. The
fixed cost (CF) is 73,000$ per month. The variable cost per unit
(cv) is 83$. The selling price per unit (p = 180$ – 0.02D).
B. Determine the optimal volume of product?
C. Find the volume at breakeven occurs, what is the range of
profitable demand?
Solution:
A. a = 180, b = 0.02
a − cv 180 − 83
D *= = = 2,425 units per month
2b 2 × 0.02
26. B. Total Revenue = Total Cost.
a D − b D 2 = CF + cv D
− b D 2 + (a − cv ) D − CF = 0
D′ =
[
− ( a − c v ) ± ( a − c v ) − 4 ( − b )( − C F )
2
] 1
2
− 2b
D′ =
[
− 97 ± ( 97 ) − 4 ( − 0.02 )( − 73000 )
2
] 1
2
− 2( 0.02 )
− 97 + 59.74
′
D1 = = 932 unit per month
− 0.04
− 97 − 59.74
′
D2 = = 3,918 unit per month
− 0.04
Range = 932 to 3,918 unit per month
28. Example:
Variable cost per service hour = 62$.
Selling price = 85.56$ per hour.
Maximum Hours per year = 160,000 hours.
Fixed cost = 2,024,000$ per year.
F. What is the breakeven point in hours and in % of total capacity?
Total revenue = Total cost (breakeven)
p D′ = C F + cv D′
CF
D′ =
( p − cv )
2024000
D′ = = 85,908 hours per year
( 85.56 − 62)
85,908
D′ = = 0.537 = 53.7% of capacity
160,000
29. B. What is the % reduction In breakeven point (sensitivity) if:
1. Fixed cost reduced by 10%?
0.9( 2024000)
D′ = = 77,138 hours per year
( 85.56 − 62)
85,908 − 77,318
D′ reduction = = 0.1 =10%
85,908
2. variable cost per hour reduced by 10%?
2024000
D′ = = 68,011 hours per year
( 85.56 − 0.9 × 62)
85,908 − 68.011
D′ reduction = = 0.208 = 20.8%
85,908
30. 3. selling price increase by 10%?
2024000
D′ = = 63,021 hours per year
(1.1× 85.56 − 62)
85,908 − 63,021
D′ reduction = = 0.266 = 26.6%
85,908
Then the breakeven point is more sensitive to reduction in
variable cost than fixed cost