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MIND MAP
SOHCAHTOA
                   1. You use Sin when you
                   have the opposite and
SOH = 0    Sin     hypotenuse
      H
                 2. You use Cos when you
                 have the adjacent and
                 hypotenuse
CAH = A   Cos
     H           3. You use Tan when you have the
                 opposite and the adjacent



TOA = O    Tan
      A
Labeling the Right Triangle
                      1. The angle is either at the
                      top or bottom

OPP         HY        2. The opposite is always
               P
                      opposite of the angle


                      3. The Hypotenuse is always
                      the longest side

                       4. Adjacent is the side
      ADJ
                       that is not labelled yet
Trigonometry: The branch of mathematics concerned with the properties of triangles and calculations based on these
properties.
Acute Triangle : A triangle which all interior angles are acute angles
Obtuse Triangle : A triangle in which one of the angles is an obtuse angle that is an angle greater than 90 o and less than 180o
Right Triangle: A triangle with one right angle
Primary Trig Ratio : The basic ratios of trigonometry sine, cosine, tangent
Sine : is one of the primary trig ratios in a right angle triangle for opposite over hypotenuse
Sine Law : in any of triangle ABC with sides abc opposite angles A,B,C respectively
Cosine : is one of the primary trig ratios in a right angle triangle for adjacent over hypotenuse
Cosine Law: an equation used when a triangle does not have a right angle all 3 sides or 2 sides angle between
       Law
Pythagorean theorem: in a right angle triangle the square of the length of the hypotenuse is equal to the sun of the square of
the squares of the lengths of the other two sides
Tangent: one of the primary trig ratios in a right angle triangle the ratio of the length of the side opposite angle to the length of
the adjacent side
Hypotenuse: In a right angle triangle the side opposite the right angle
Angle of Elevation: An angle measured from the horizontal plane upward from an observer's eye to a given point above the
plane
Angle of Depression : The angle measured below the horizontal that an observer must look to see an object that is lower than
the observer
Bearings: A bearing is an angle, measured clockwise from the north direction
An airplane is approaching a runway at an angle
                       of descent of 30o
      What is the altitude of the airplane when it is 15
         km along its flight path from the runway


          H
           yp
                                        • Label The Triangle
                15                      • Decide which Trig
OPP                km
                                          Ratio will be used
                                        • Sin, Cos, Tan
                   30o

       Adj
1. Use Tan because
                                               where already have
            H                                  Hypotenuse and we
OPP          yp                                want to find the
                  15km                         opposite

                   30o   Tan 30o = O
                                            2. Calculate Tan of 30
      Adj                         A         then cross multiply

                          Tan 30o = x          3. Multiply 0.5773
                                       15         by 15
                                               4. Gives you
                          0.5773 = x              8.67cm
                                 15
                                            Therefore, The altitude is
                          X=8.67cm          8.67com
Louise is a naturalist studying the effect of acid rain on fish population in
         different lakes. As part of her research she needs to know the length of lake
         Lebarge. Louise makes the measurements shown. How Long is the Lake.


                  A                      a     = b = c                   Sin 320 x 340 = Sin 960c
                  96o
                                        Sin A Sin B Sin C                 0.5299 x 340 = 0.99452c
    c                    b
                                                                          180.17254 = 0.99452c
                                                                          0.99452         0.99452
                                        340 =        b =        c
        520              32o                                              181. 2cm = c
B             340 cm           C        Sin 96 Sin 52 Sin 32
                 a                                                       Therefore, Lake Lebarge is
                                        340 =       c                    181.2 cm long.

                                        Sin 96 Sin 32                3. Multiply 0.5299 with 340 and
                                                                     0.99452 with c
                                                                    4. Divide both side by 0.99452
        1.    Fill in the correct information in the equation
         2. Cross Multiply the 340 with sin of 32
         and sin 96 with c
Angle S = 560
                                                                       Length a = 14 cm
                                                                       Length t = 25 cm
        A Farmer is building a fence around his chicken pen
        Find the perimeter of the Triangle SAT with the given lengths
        and angles                                                  1. Fill in all the angles
                             S2 = a2 + t2 – 2at Cos S                   and lengths

                                                                       2. Do 14 squared and
               S            S2 = 142 + 252 – 2(14) (25) Cos 56         25 squared then
                                                                       multiply -2 by 14 and 25
              560            S2 = 196 + 625 – 700 Cos 56             3. Do Cos of 56o and
                                S2 = 196 + 625 – 700 0.5591          multiply it by 700
    25cm            14cm
                                                                     4. Add 196 and 625 then
                             S = 196 + 625 – 391.37
                                2
                                                                     subtract 391.37
    t                   a                                           Square root 429.63 to give
                                S = 429. 63                         you 20.7

                                S= 20.7                            5. Add all the sides together to
                                                                   give you the perimeter of 59.73
                            T
A                   s           P=s+s+s
           20cm
                                P= 25 + 14 + 20.7            Therefore, the perimeter of the
                                P = 59.73                    triangle is 59.73
BY: Shehribane
Haziri

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Math project by Shehribane

  • 1.
  • 3. SOHCAHTOA 1. You use Sin when you have the opposite and SOH = 0 Sin hypotenuse H 2. You use Cos when you have the adjacent and hypotenuse CAH = A Cos H 3. You use Tan when you have the opposite and the adjacent TOA = O Tan A
  • 4. Labeling the Right Triangle 1. The angle is either at the top or bottom OPP HY 2. The opposite is always P opposite of the angle 3. The Hypotenuse is always the longest side 4. Adjacent is the side ADJ that is not labelled yet
  • 5. Trigonometry: The branch of mathematics concerned with the properties of triangles and calculations based on these properties. Acute Triangle : A triangle which all interior angles are acute angles Obtuse Triangle : A triangle in which one of the angles is an obtuse angle that is an angle greater than 90 o and less than 180o Right Triangle: A triangle with one right angle Primary Trig Ratio : The basic ratios of trigonometry sine, cosine, tangent Sine : is one of the primary trig ratios in a right angle triangle for opposite over hypotenuse Sine Law : in any of triangle ABC with sides abc opposite angles A,B,C respectively Cosine : is one of the primary trig ratios in a right angle triangle for adjacent over hypotenuse Cosine Law: an equation used when a triangle does not have a right angle all 3 sides or 2 sides angle between Law Pythagorean theorem: in a right angle triangle the square of the length of the hypotenuse is equal to the sun of the square of the squares of the lengths of the other two sides Tangent: one of the primary trig ratios in a right angle triangle the ratio of the length of the side opposite angle to the length of the adjacent side Hypotenuse: In a right angle triangle the side opposite the right angle Angle of Elevation: An angle measured from the horizontal plane upward from an observer's eye to a given point above the plane Angle of Depression : The angle measured below the horizontal that an observer must look to see an object that is lower than the observer Bearings: A bearing is an angle, measured clockwise from the north direction
  • 6. An airplane is approaching a runway at an angle of descent of 30o What is the altitude of the airplane when it is 15 km along its flight path from the runway H yp • Label The Triangle 15 • Decide which Trig OPP km Ratio will be used • Sin, Cos, Tan 30o Adj
  • 7. 1. Use Tan because where already have H Hypotenuse and we OPP yp want to find the 15km opposite 30o Tan 30o = O 2. Calculate Tan of 30 Adj A then cross multiply Tan 30o = x 3. Multiply 0.5773 15 by 15 4. Gives you 0.5773 = x 8.67cm 15 Therefore, The altitude is X=8.67cm 8.67com
  • 8. Louise is a naturalist studying the effect of acid rain on fish population in different lakes. As part of her research she needs to know the length of lake Lebarge. Louise makes the measurements shown. How Long is the Lake. A a = b = c Sin 320 x 340 = Sin 960c 96o Sin A Sin B Sin C 0.5299 x 340 = 0.99452c c b 180.17254 = 0.99452c 0.99452 0.99452 340 = b = c 520 32o 181. 2cm = c B 340 cm C Sin 96 Sin 52 Sin 32 a Therefore, Lake Lebarge is 340 = c 181.2 cm long. Sin 96 Sin 32 3. Multiply 0.5299 with 340 and 0.99452 with c 4. Divide both side by 0.99452 1. Fill in the correct information in the equation 2. Cross Multiply the 340 with sin of 32 and sin 96 with c
  • 9. Angle S = 560 Length a = 14 cm Length t = 25 cm A Farmer is building a fence around his chicken pen Find the perimeter of the Triangle SAT with the given lengths and angles 1. Fill in all the angles S2 = a2 + t2 – 2at Cos S and lengths 2. Do 14 squared and S S2 = 142 + 252 – 2(14) (25) Cos 56 25 squared then multiply -2 by 14 and 25 560 S2 = 196 + 625 – 700 Cos 56 3. Do Cos of 56o and S2 = 196 + 625 – 700 0.5591 multiply it by 700 25cm 14cm 4. Add 196 and 625 then S = 196 + 625 – 391.37 2 subtract 391.37 t a Square root 429.63 to give S = 429. 63 you 20.7 S= 20.7 5. Add all the sides together to give you the perimeter of 59.73 T A s P=s+s+s 20cm P= 25 + 14 + 20.7 Therefore, the perimeter of the P = 59.73 triangle is 59.73