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Symbols and Geometric Elements Segment A B or Ray A B Line F E or
Ray Notation Notice the position of the end point and the ray above. A B C D
Line Variations A B C D E or Any two letters can be used to name the line. Therefore, there can be multiple correct answers  and confusion.
More Symbols Mathematical Shorthand B A Segments Set of Points Length or Measurement  Or Distance A Number NOT a set of points
[object Object],[object Object],[object Object],Measurements
Measure the Lines Below
Tolerance ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Coordinate Systems Coordinate are numbers. Points are letters
The name of the red pt. is ___ The coordinate of the red pt. is ___ The name of the grey pt. is ___ The coordinate of the grey pt. is __ E 0 J 5
[object Object],[object Object],[object Object],[object Object],[object Object],5 -4 -2 6
Calculation of Distance Using Coordinates 3 5 You could simply count the blocks. The answer is 2.
Calculation of Distance Using Coordinates 3 33 Counting blocks would be time consuming. The answer is 30. You could simply subtract. Subtraction means the difference between numbers.
Calculation of Distance Using Coordinates -8 33 The answer is 41. You could simply subtract. 33 – (-8) = 33 + 8 = 41 Note that negative numbers requires using algebra.
-8 -5 You could simply subtract. -5 – (-8) = -5 + 8 = 3 However if we subtract the numbers in reverse, then... -8 – (-5) = -8 + 5 = - 3 Therefore to avoid negative numbers,  we take the absolute value of the differences.
a b You subtract the coordinates  then take the absolute value  of the difference. Distance =
1 3 4 4 1 5 9 Method 1: Count the blocks. Method 2: Subtract coordinates and  take the absolute value. 1
1 2 3 4 4 1 5 9 Method 1: Count the blocks. Method 2: Subtract coordinates and  take the absolute value. 2
1 2 3 3 4 4 1 5 9 Method 1: Count the blocks. Method 2: Subtract coordinates and  take the absolute value. 3
1 2 3 3 1 5 9 Method 1: Count the blocks. Method 2: Subtract coordinates and  take the absolute value. 3
1 2 3 4 4 1 5 9 Method 1: Count the blocks. Method 2: Subtract coordinates and  take the absolute value. 3
1 2 3 4 4 4 1 5 9 Method 1: Count the blocks. Method 2: Subtract coordinates and  take the absolute value. 3
1 2 3 3 4 4 1 5 Method 1: Count the blocks. Method 2: Subtract coordinates and  take the absolute value. 5
1 2 3 3 4 4 1 5 9 Method 1: Count the blocks. Method 2: Subtract coordinates and  take the absolute value. 9
Ruler Postulate ,[object Object],[object Object],The measuring scale is arbitrary .
If   M is on the segment  and  M is a  midpoint  of It is necessary for both conditions.  Let’s see why?
D, E, and F  Are equidistant from both A  and  B But they are NOT midpoints. The midpoint Must be on the  Segment !
Bisectors  Bisectors can be any segment, ray, line, or plane if they go thru the midpoint of a segment.
D is midpoint of  E is midpoint of  C is midpoint of  B is midpoint of Find the value of their coordinates.
8 8 4 12 2
Symbol Scramble Segment Length of Segment Line Ray length of Segment Measure of Segment
Congruent Figures Same Size and Shape Yes NO Not the same shape Not the same size Not the same size
 
Distance Between Coordinates 4  12  12  8 -5  7 0  12 0  -12 -2  12  -12  -8 -5  7 0  18 0  -15 -12  12
Sometime, Always & Never ,[object Object],[object Object],[object Object],[object Object],[object Object],Always Never Always Never Sometimes
Sometime, Always & Never ,[object Object],[object Object],[object Object],[object Object],[object Object],Always Always Never Never Always
Segment Addition Postulate A B C If  B  is  between   A and C,  then…. AB  +  BC  =  AC Note: Between means that A, B, and C are collinear. B must be on the segment AC.
Segment Addition Postulate Applications A B C 22 AB = 8 BC = 22 AC = ? 8 First, label the diagram. x Second, find equation. Third, solve equation. 8 + 22 = x 30 = x
Segment Addition Postulate Applications A B C 22 AB = 8 AC = 22 BC = ? 8 First, label the diagram. x Second, find equation. Third, solve equation. 8 + x = 22 x = 14
Segment Addition Postulate Applications A B C 18 AB = 3x - 4 BC = 2x + 7 AC = 18 Find AB & BC 3x - 4 First, label the diagram. 2x + 7  Second, find equation. Third, solve equation. 3x- 4 + 2x + 7 = 18 5x + 3 = 18 5x = 15 x = 3 Not done yet?
Segment Addition Postulate Applications A B C 18 AB = 3x - 4 BC = 2x + 7 AC = 18 Find AB & BC 3x - 4 2x + 7  3x- 4 + 2x + 7 = 18 5x + 3 = 18 5x = 15 x = 3 Substitute Back in. 3x - 4 3(3) - 4 9- 4 = 5 2x + 7  2(3) + 7  6 + 7 = 13  13  5
Segment Addition Postulate Applications A B C 16 AB = 3x - 13 BC = 16  AC = 4x + 14 Find AB & AC 3x - 13 4x - 4  3x- 13 + 16 = 4x - 4 - x = - 7 Label diagram. Find equation. Solve equation. 3x+3 = 4x - 4 x =  7 Not Done Yet NDY
Segment Addition Postulate Applications A B C 16 AB = 3x - 13 BC = 16  AC = 4x + 14 Find AB & AC 3x - 13 4x - 4  3x- 13 + 16 = 4x - 4 - x = - 7 Substitute into expressions. 3x+3 = 4x - 4 x =  7 3x - 13 3(7) - 13 21 - 13 8 8 4(7) - 14  4x - 14  28 - 14  24  24
You  must  be able to do these  complex algebraic problems. They will be in the chapter test  and   the marking period exam (QPA)
Summary A B There are several symbols for geometric terms. C D F E B C No symbol means… The distance from B to C. A  numerical value.
Summary 2 A B There are alternate symbols for  distance, length, or measurement. 5 5 Measurements are always arbitrary due to  the choice of units (meters, feet, etc.), degree of accuracy and scale.
Summary 3 The letters are the names of the points. The numbers are the coordinates that indicate  the relative position of each point.
Summary 4 The  ruler postulate  allows us to… 1. Build number lines at any scale. 2. Compute distance by taking the absolute value of the  difference of the coordinates.
Summary 5 The  segment addition postulate   allows us to conclude… The distance on a line is  the sum of its parts. A B C AB  +  BC  =  AC
Summary 6 A B C 18 AB = 3x - 4 BC = 2x + 7 AC = 18 Find AB & BC 3x - 4 2x + 7  You must be able to do these algebraic problems.
C’est fini. Good day and good luck.

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Arihant handbook biology for class 11 .pdf
 

Ac1.3fNumberLineDistanceAndNotation

  • 1. Symbols and Geometric Elements Segment A B or Ray A B Line F E or
  • 2. Ray Notation Notice the position of the end point and the ray above. A B C D
  • 3. Line Variations A B C D E or Any two letters can be used to name the line. Therefore, there can be multiple correct answers and confusion.
  • 4. More Symbols Mathematical Shorthand B A Segments Set of Points Length or Measurement Or Distance A Number NOT a set of points
  • 5.
  • 7.
  • 8. Coordinate Systems Coordinate are numbers. Points are letters
  • 9. The name of the red pt. is ___ The coordinate of the red pt. is ___ The name of the grey pt. is ___ The coordinate of the grey pt. is __ E 0 J 5
  • 10.
  • 11. Calculation of Distance Using Coordinates 3 5 You could simply count the blocks. The answer is 2.
  • 12. Calculation of Distance Using Coordinates 3 33 Counting blocks would be time consuming. The answer is 30. You could simply subtract. Subtraction means the difference between numbers.
  • 13. Calculation of Distance Using Coordinates -8 33 The answer is 41. You could simply subtract. 33 – (-8) = 33 + 8 = 41 Note that negative numbers requires using algebra.
  • 14. -8 -5 You could simply subtract. -5 – (-8) = -5 + 8 = 3 However if we subtract the numbers in reverse, then... -8 – (-5) = -8 + 5 = - 3 Therefore to avoid negative numbers, we take the absolute value of the differences.
  • 15. a b You subtract the coordinates then take the absolute value of the difference. Distance =
  • 16. 1 3 4 4 1 5 9 Method 1: Count the blocks. Method 2: Subtract coordinates and take the absolute value. 1
  • 17. 1 2 3 4 4 1 5 9 Method 1: Count the blocks. Method 2: Subtract coordinates and take the absolute value. 2
  • 18. 1 2 3 3 4 4 1 5 9 Method 1: Count the blocks. Method 2: Subtract coordinates and take the absolute value. 3
  • 19. 1 2 3 3 1 5 9 Method 1: Count the blocks. Method 2: Subtract coordinates and take the absolute value. 3
  • 20. 1 2 3 4 4 1 5 9 Method 1: Count the blocks. Method 2: Subtract coordinates and take the absolute value. 3
  • 21. 1 2 3 4 4 4 1 5 9 Method 1: Count the blocks. Method 2: Subtract coordinates and take the absolute value. 3
  • 22. 1 2 3 3 4 4 1 5 Method 1: Count the blocks. Method 2: Subtract coordinates and take the absolute value. 5
  • 23. 1 2 3 3 4 4 1 5 9 Method 1: Count the blocks. Method 2: Subtract coordinates and take the absolute value. 9
  • 24.
  • 25. If M is on the segment and M is a midpoint of It is necessary for both conditions. Let’s see why?
  • 26. D, E, and F Are equidistant from both A and B But they are NOT midpoints. The midpoint Must be on the Segment !
  • 27. Bisectors Bisectors can be any segment, ray, line, or plane if they go thru the midpoint of a segment.
  • 28. D is midpoint of E is midpoint of C is midpoint of B is midpoint of Find the value of their coordinates.
  • 29. 8 8 4 12 2
  • 30. Symbol Scramble Segment Length of Segment Line Ray length of Segment Measure of Segment
  • 31. Congruent Figures Same Size and Shape Yes NO Not the same shape Not the same size Not the same size
  • 32.  
  • 33. Distance Between Coordinates 4 12 12 8 -5 7 0 12 0 -12 -2 12 -12 -8 -5 7 0 18 0 -15 -12 12
  • 34.
  • 35.
  • 36. Segment Addition Postulate A B C If B is between A and C, then…. AB + BC = AC Note: Between means that A, B, and C are collinear. B must be on the segment AC.
  • 37. Segment Addition Postulate Applications A B C 22 AB = 8 BC = 22 AC = ? 8 First, label the diagram. x Second, find equation. Third, solve equation. 8 + 22 = x 30 = x
  • 38. Segment Addition Postulate Applications A B C 22 AB = 8 AC = 22 BC = ? 8 First, label the diagram. x Second, find equation. Third, solve equation. 8 + x = 22 x = 14
  • 39. Segment Addition Postulate Applications A B C 18 AB = 3x - 4 BC = 2x + 7 AC = 18 Find AB & BC 3x - 4 First, label the diagram. 2x + 7 Second, find equation. Third, solve equation. 3x- 4 + 2x + 7 = 18 5x + 3 = 18 5x = 15 x = 3 Not done yet?
  • 40. Segment Addition Postulate Applications A B C 18 AB = 3x - 4 BC = 2x + 7 AC = 18 Find AB & BC 3x - 4 2x + 7 3x- 4 + 2x + 7 = 18 5x + 3 = 18 5x = 15 x = 3 Substitute Back in. 3x - 4 3(3) - 4 9- 4 = 5 2x + 7 2(3) + 7 6 + 7 = 13 13 5
  • 41. Segment Addition Postulate Applications A B C 16 AB = 3x - 13 BC = 16 AC = 4x + 14 Find AB & AC 3x - 13 4x - 4 3x- 13 + 16 = 4x - 4 - x = - 7 Label diagram. Find equation. Solve equation. 3x+3 = 4x - 4 x = 7 Not Done Yet NDY
  • 42. Segment Addition Postulate Applications A B C 16 AB = 3x - 13 BC = 16 AC = 4x + 14 Find AB & AC 3x - 13 4x - 4 3x- 13 + 16 = 4x - 4 - x = - 7 Substitute into expressions. 3x+3 = 4x - 4 x = 7 3x - 13 3(7) - 13 21 - 13 8 8 4(7) - 14 4x - 14 28 - 14 24 24
  • 43. You must be able to do these complex algebraic problems. They will be in the chapter test and the marking period exam (QPA)
  • 44. Summary A B There are several symbols for geometric terms. C D F E B C No symbol means… The distance from B to C. A numerical value.
  • 45. Summary 2 A B There are alternate symbols for distance, length, or measurement. 5 5 Measurements are always arbitrary due to the choice of units (meters, feet, etc.), degree of accuracy and scale.
  • 46. Summary 3 The letters are the names of the points. The numbers are the coordinates that indicate the relative position of each point.
  • 47. Summary 4 The ruler postulate allows us to… 1. Build number lines at any scale. 2. Compute distance by taking the absolute value of the difference of the coordinates.
  • 48. Summary 5 The segment addition postulate allows us to conclude… The distance on a line is the sum of its parts. A B C AB + BC = AC
  • 49. Summary 6 A B C 18 AB = 3x - 4 BC = 2x + 7 AC = 18 Find AB & BC 3x - 4 2x + 7 You must be able to do these algebraic problems.
  • 50. C’est fini. Good day and good luck.