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Interference
Superposition in water ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Hearing superposition 1m Same frequency from Signal generator Walk along a path that is one metre away What do you hear?
Today you will... ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Thomas Young ,[object Object],[object Object],[object Object],http:// www.youtube.com/watch?v =DfPeprQ7oGc
The Interference Pattern
The laser interference ,[object Object],[object Object],[object Object],[object Object],This gives a very sharp image
What are the factors that affect fringe separation? Fringe separation = distance between bright lines
Fringe separation w  =  separation of the fringes (bright to bright or dark to dark) λ = wavelength of the light s  = separation of the two slits D  = distance between slits and screen w D s W = λD S
Young’s Questions ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],W = λD S
Young’s answers
Ripple Tank
The geometric analysis of Young’s experiment s
What is the use of knowing  θ ? For it to be in phase (first fringe) θ  = sin -1  d/ λ For it to be out of phase  θ  = sin -1  2d/ λ
At the first dark fringe The waves must be in anti-phase λ difference at the point on the wall λ = s sin  θ θ  = sin -1  2d/ λ θ s θ What is this length? O = s sin  θ Opposite Sin  θ    Hypotenuse s s
At the first Bright fringe The waves must be in phase λ difference at the point on the wall λ = s sin  θ θ  = sin -1  s/ λ s s s
What is the use of knowing  θ ? For it to be in phase (first fringe) θ  = sin -1  d/ λ For it to be out of phase  θ  = sin -1  2d/ λ

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Interference And Youngs two Slit

  • 2.
  • 3. Hearing superposition 1m Same frequency from Signal generator Walk along a path that is one metre away What do you hear?
  • 4.
  • 5.
  • 7.
  • 8. What are the factors that affect fringe separation? Fringe separation = distance between bright lines
  • 9. Fringe separation w  = separation of the fringes (bright to bright or dark to dark) λ = wavelength of the light s  = separation of the two slits D  = distance between slits and screen w D s W = λD S
  • 10.
  • 13. The geometric analysis of Young’s experiment s
  • 14. What is the use of knowing θ ? For it to be in phase (first fringe) θ = sin -1 d/ λ For it to be out of phase θ = sin -1 2d/ λ
  • 15. At the first dark fringe The waves must be in anti-phase λ difference at the point on the wall λ = s sin θ θ = sin -1 2d/ λ θ s θ What is this length? O = s sin θ Opposite Sin θ Hypotenuse s s
  • 16. At the first Bright fringe The waves must be in phase λ difference at the point on the wall λ = s sin θ θ = sin -1 s/ λ s s s
  • 17. What is the use of knowing θ ? For it to be in phase (first fringe) θ = sin -1 d/ λ For it to be out of phase θ = sin -1 2d/ λ