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BOND ENERGY
BOND ENERGY
All chemical reactions involve the breaking of old
bonds followed by the making of new bonds.

The heat absorbed or released in a reaction comes
from the chemical bonds being broken or made
respectively.
BOND ENERGY
 Bond breaking is endothermic.


      C-H + energy                 C    H


 Bond formation is exothermic.


      H    H         H-H        + energy

The greater the bond energy is, the stronger the bond
BOND ENERGY
Table of average bond energies:
BOND ENERGY
The bond energies on the table are averages, because
they may differ depending on adjacent bonds.

i.e. the C-H bond requires 435kJ to break, but
breaking all 4 bonds of CH4 requires 1652kJ of
energy, this the average is 413kJ/mol


435kJ/mol H
        H C H               1652kJ/mol = 413kJ/mol
                             4 bonds
          H
BOND ENERGY
  Use bond energies to find the ΔH° of a reaction:
       Ex 1. H2(g) + Br2(g)  2HBr(g)
Bond energies   432kJ/mol   193kJ/mol         2 x -363kJ/mol

                                    There are 2       Bond formation
                                   moles of H-Br       is exothermic


 Add the bond energies together:

  ΔH° = 432kJ/mol + 193kJ/mol + 2 x (-363kJ/mol)
  ΔH° = -101kJ/mol
                    .: ΔH° is -101kJ/mol
BOND ENERGY
  Use bond energies to find the ΔH° of a reaction:
        Ex 1. H2(g) + Br2(g)  2HBr(g)
                 432kJ/mol     193kJ/mol        363kJ/mol

Can be solved using this formula as well

ΔH° = Σ       bond energy of reactants     –Σ   bond energy of products


   ΔH° = (432kJ/mol + 193 kJ/mol) – (2 x
   363kJ/mol)
   ΔH° = -101kJ/mol
                     .: ΔH° is -101kJ/mol
BOND ENERGY
For more complex molecules…
   Ex 2. Calculate the enthalpy of combustion
   for ethanol using average bond energies.
     C2H5OH(l) + 3O2(g)  2CO2(g) + 3H2O(g)
  Draw the structures to determine the types and number of bonds




        347
BOND ENERGY
Ex 2. Calculate the enthalpy of combustion for ethanol
using average bond energies.




             347

                                                               + (1 x C-C)
                                                          + (1 x 347)
                                       + 347
                             + 347 kJ/mol = 4731 kJ/mol
BOND ENERGY
Ex 2. Calculate the enthalpy of combustion for ethanol
using average bond energies.


         = 4731 kJ/mol – 5782 kJ/mol
         = -1051 kJ/mol



                    .: ΔH° is -1.05x103kJ

  The molar enthalpy of combustion of ethanol based on bond
  energies is -1051 kJ/mol. The accepted value is -1368 kJ/mol
  (using Hess’ Law).

  There difference is due to the use of average bond energies.
BOND ENERGY
Ex 3. Calculate the enthalpy of combustion for methoxy
methane (CH3OCH3) using average bond energies.

    CH3OCH3(l) + 3O2(g)  2CO2(g) + 3H2O(g)
BOND ENERGY
Ex 3. Calculate the enthalpy of combustion for methoxy
methane (CH3OCH3) using average bond energies.
BOND ENERGY
Ex 3. Calculate the enthalpy of combustion for methoxy
methane (CH3OCH3) using average bond energies.




                  .: ΔH° is -1.09x103kJ
BOND ENERGY
Bond dissociation energy (D) is also a
measure of bond strength in a chemical bond.

It is the change in enthalpy of a homolysis
reaction at abolute zero (0 kelvin) where a
molecule is broken down into two free radicals.



                                    ΔH = __kJ/mol



   It is not the same as average bond energy.

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Tang 06 bond energy

  • 2. BOND ENERGY All chemical reactions involve the breaking of old bonds followed by the making of new bonds. The heat absorbed or released in a reaction comes from the chemical bonds being broken or made respectively.
  • 3. BOND ENERGY Bond breaking is endothermic. C-H + energy  C H Bond formation is exothermic. H H  H-H + energy The greater the bond energy is, the stronger the bond
  • 4. BOND ENERGY Table of average bond energies:
  • 5. BOND ENERGY The bond energies on the table are averages, because they may differ depending on adjacent bonds. i.e. the C-H bond requires 435kJ to break, but breaking all 4 bonds of CH4 requires 1652kJ of energy, this the average is 413kJ/mol 435kJ/mol H H C H 1652kJ/mol = 413kJ/mol 4 bonds H
  • 6. BOND ENERGY Use bond energies to find the ΔH° of a reaction: Ex 1. H2(g) + Br2(g)  2HBr(g) Bond energies 432kJ/mol 193kJ/mol 2 x -363kJ/mol There are 2 Bond formation moles of H-Br is exothermic Add the bond energies together: ΔH° = 432kJ/mol + 193kJ/mol + 2 x (-363kJ/mol) ΔH° = -101kJ/mol .: ΔH° is -101kJ/mol
  • 7. BOND ENERGY Use bond energies to find the ΔH° of a reaction: Ex 1. H2(g) + Br2(g)  2HBr(g) 432kJ/mol 193kJ/mol 363kJ/mol Can be solved using this formula as well ΔH° = Σ bond energy of reactants –Σ bond energy of products ΔH° = (432kJ/mol + 193 kJ/mol) – (2 x 363kJ/mol) ΔH° = -101kJ/mol .: ΔH° is -101kJ/mol
  • 8. BOND ENERGY For more complex molecules… Ex 2. Calculate the enthalpy of combustion for ethanol using average bond energies. C2H5OH(l) + 3O2(g)  2CO2(g) + 3H2O(g) Draw the structures to determine the types and number of bonds 347
  • 9. BOND ENERGY Ex 2. Calculate the enthalpy of combustion for ethanol using average bond energies. 347 + (1 x C-C) + (1 x 347) + 347 + 347 kJ/mol = 4731 kJ/mol
  • 10. BOND ENERGY Ex 2. Calculate the enthalpy of combustion for ethanol using average bond energies. = 4731 kJ/mol – 5782 kJ/mol = -1051 kJ/mol .: ΔH° is -1.05x103kJ The molar enthalpy of combustion of ethanol based on bond energies is -1051 kJ/mol. The accepted value is -1368 kJ/mol (using Hess’ Law). There difference is due to the use of average bond energies.
  • 11. BOND ENERGY Ex 3. Calculate the enthalpy of combustion for methoxy methane (CH3OCH3) using average bond energies. CH3OCH3(l) + 3O2(g)  2CO2(g) + 3H2O(g)
  • 12. BOND ENERGY Ex 3. Calculate the enthalpy of combustion for methoxy methane (CH3OCH3) using average bond energies.
  • 13. BOND ENERGY Ex 3. Calculate the enthalpy of combustion for methoxy methane (CH3OCH3) using average bond energies. .: ΔH° is -1.09x103kJ
  • 14. BOND ENERGY Bond dissociation energy (D) is also a measure of bond strength in a chemical bond. It is the change in enthalpy of a homolysis reaction at abolute zero (0 kelvin) where a molecule is broken down into two free radicals. ΔH = __kJ/mol It is not the same as average bond energy.