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7.2



Solving Systems of Linear
Equations by Substitution
The Substitution Method

Another method (beside getting lucky with
trial and error or graphing the equations) that
can be used to solve systems of equations is
called the substitution method.
You solve one equation for one of the
variables, then substitute the new form of the
equation into the other equation for the solved
variable.


             Martin-Gay, Developmental Mathematics   2
The Substitution Method
Solving a System of Linear Equations by the
Substitution Method
  1)    Solve one of the equations for y.
  2)    Substitute the value of y from step 1 into the
        other equation.
  3)    Solve for x.
  4)    Substitute the value of x found in step 3 into
        either equation containing both variables.
  5)    Check your answer.



                Martin-Gay, Developmental Mathematics    3
The Substitution Method
 Example
Solve the following system using the substitution method.
     3x – y = 6 and – 4x + 2y = –8
Solving the first equation for y,
      3x – y = 6
         –y = –3x + 6      (subtract 3x from both sides)
           y = 3x – 6      (multiply both sides by – 1)
Substitute this value for y in the second equation.
            –4x + 2y = –8
      –4x + 2(3x – 6) = –8        (replace y with result from first equation)
        –4x + 6x – 12 = –8        (use the distributive property)
               2x – 12 = –8         (simplify the left side)
                    2x = 4         (add 12 to both sides)
                     x=2           (divide both sides by 2)                     Continued.
                        Martin-Gay, Developmental Mathematics                         4
The Substitution Method
Example continued
  Substitute x = 2 into the first equation solved for y.
       y = 3x – 6 = 3(2) – 6 = 6 – 6 = 0
  Our computations have produced the point (2, 0).
  Check the point in the original equations.
       First equation,
                    3x – y = 6
                 3(2) – 0 = 6      true
       Second equation,
                     –4x + 2y = –8
                  –4(2) + 2(0) = –8       true
  The solution of the system is (2, 0).
                     Martin-Gay, Developmental Mathematics   5
The Substitution Method
Example
Solve the following system of equations using the
substitution method.
                y = 2x – 5 and 8x – 4y = 20
Since the first equation is already solved for y, substitute
this value into the second equation.
                    8x – 4y = 20
      8x – 4(2x – 5) = 20      (replace y with result from first
    equation)
        8x – 8x + 20 = 20             (use distributive property)
                                                                    Continued.
                  20 = 20              (simplify left side)
                     Martin-Gay, Developmental Mathematics                6
The Substitution Method
Example continued
When you get a result, like the one on the previous
slide, that is obviously true for any value of the
replacements for the variables, this indicates that the
two equations actually represent the same line.
There are an infinite number of solutions for this
system. Any solution of one equation would
automatically be a solution of the other equation.
This represents a consistent system and the linear
equations are dependent equations.
                  Martin-Gay, Developmental Mathematics   7
The Substitution Method
 Example
Solve the following system of equations using the substitution
method.
                3x – y = 4 and 6x – 2y = 4
Solve the first equation for y.
                3x – y = 4
                    –y = –3x + 4          (subtract 3x from both sides)
                     y = 3x – 4         (multiply both sides by –1)
Substitute this value for y into the second equation.
              6x – 2y = 4
     6x – 2(3x – 4) = 4       (replace y with the result from the first equation)
         6x – 6x + 8 = 4       (use distributive property)
                     8=4       (simplify the left side)                 Continued.
                        Martin-Gay, Developmental Mathematics                8
The Substitution Method
Example continued
When you get a result, like the one on the previous
slide, that is never true for any value of the
replacements for the variables, this indicates that the
two equations actually are parallel and never
intersect.
There is no solution to this system.
This represents an inconsistent system, even though
the linear equations are independent.

                   Martin-Gay, Developmental Mathematics   9
The Substitution Method
Example continued
When you get a result, like the one on the previous
slide, that is never true for any value of the
replacements for the variables, this indicates that the
two equations actually are parallel and never
intersect.
There is no solution to this system.
This represents an inconsistent system, even though
the linear equations are independent.

                   Martin-Gay, Developmental Mathematics   9

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7.2

  • 1. 7.2 Solving Systems of Linear Equations by Substitution
  • 2. The Substitution Method Another method (beside getting lucky with trial and error or graphing the equations) that can be used to solve systems of equations is called the substitution method. You solve one equation for one of the variables, then substitute the new form of the equation into the other equation for the solved variable. Martin-Gay, Developmental Mathematics 2
  • 3. The Substitution Method Solving a System of Linear Equations by the Substitution Method 1) Solve one of the equations for y. 2) Substitute the value of y from step 1 into the other equation. 3) Solve for x. 4) Substitute the value of x found in step 3 into either equation containing both variables. 5) Check your answer. Martin-Gay, Developmental Mathematics 3
  • 4. The Substitution Method Example Solve the following system using the substitution method. 3x – y = 6 and – 4x + 2y = –8 Solving the first equation for y, 3x – y = 6 –y = –3x + 6 (subtract 3x from both sides) y = 3x – 6 (multiply both sides by – 1) Substitute this value for y in the second equation. –4x + 2y = –8 –4x + 2(3x – 6) = –8 (replace y with result from first equation) –4x + 6x – 12 = –8 (use the distributive property) 2x – 12 = –8 (simplify the left side) 2x = 4 (add 12 to both sides) x=2 (divide both sides by 2) Continued. Martin-Gay, Developmental Mathematics 4
  • 5. The Substitution Method Example continued Substitute x = 2 into the first equation solved for y. y = 3x – 6 = 3(2) – 6 = 6 – 6 = 0 Our computations have produced the point (2, 0). Check the point in the original equations. First equation, 3x – y = 6 3(2) – 0 = 6 true Second equation, –4x + 2y = –8 –4(2) + 2(0) = –8 true The solution of the system is (2, 0). Martin-Gay, Developmental Mathematics 5
  • 6. The Substitution Method Example Solve the following system of equations using the substitution method. y = 2x – 5 and 8x – 4y = 20 Since the first equation is already solved for y, substitute this value into the second equation. 8x – 4y = 20 8x – 4(2x – 5) = 20 (replace y with result from first equation) 8x – 8x + 20 = 20 (use distributive property) Continued. 20 = 20 (simplify left side) Martin-Gay, Developmental Mathematics 6
  • 7. The Substitution Method Example continued When you get a result, like the one on the previous slide, that is obviously true for any value of the replacements for the variables, this indicates that the two equations actually represent the same line. There are an infinite number of solutions for this system. Any solution of one equation would automatically be a solution of the other equation. This represents a consistent system and the linear equations are dependent equations. Martin-Gay, Developmental Mathematics 7
  • 8. The Substitution Method Example Solve the following system of equations using the substitution method. 3x – y = 4 and 6x – 2y = 4 Solve the first equation for y. 3x – y = 4 –y = –3x + 4 (subtract 3x from both sides) y = 3x – 4 (multiply both sides by –1) Substitute this value for y into the second equation. 6x – 2y = 4 6x – 2(3x – 4) = 4 (replace y with the result from the first equation) 6x – 6x + 8 = 4 (use distributive property) 8=4 (simplify the left side) Continued. Martin-Gay, Developmental Mathematics 8
  • 9. The Substitution Method Example continued When you get a result, like the one on the previous slide, that is never true for any value of the replacements for the variables, this indicates that the two equations actually are parallel and never intersect. There is no solution to this system. This represents an inconsistent system, even though the linear equations are independent. Martin-Gay, Developmental Mathematics 9
  • 10. The Substitution Method Example continued When you get a result, like the one on the previous slide, that is never true for any value of the replacements for the variables, this indicates that the two equations actually are parallel and never intersect. There is no solution to this system. This represents an inconsistent system, even though the linear equations are independent. Martin-Gay, Developmental Mathematics 9