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:: PRESENTATION ON ::
Linear Transformation
Guided by : Mr Sachin Gaikwad
Department of
Computer Engineering
2th semester
2
Prepared By
Odhavani prashant
160920107003
Linear Transformation
3
Zero transformation : VT  vv ,0)(WVT :
Identity transformation : VVT : VT  vvv ,)(
VWVT  vu,,:Properties of linear transformations :
00 )((1)T )()((2) vv TT 
)()()((3) vuvu TTT  1 1 2 2
1 1 2 2
1 1 2 2
(4) If
Then ( ) ( )
( ) ( ) ( )
n n
n n
n n
c v c v c v
T T c v c v c v
c T v c T v c T v
   
   
   
v
v
L
L
L
The Kernel and Range of a Linear Transformation
4
 Kernel of a linear transformation T
Let be a linear transformation then the set of all vectors
v in V that satisfy is called the kernel of T and is denoted by ker(T)
},0)(|{)ker( VTT  vvv
WVT :
The kernel is a subspace of V
The kernel of a linear transformation is a subspace of the domain V.
then.ofkernelin thevectorsbeandLet Tvu
000)()()(  vuvu TTT
00)()(  ccTcT uu )ker(Tc  u
)ker(T vu
.ofsubspaceais)ker(Thus, VT
Note:
The kernel of T is sometimes called the nullspace of T.
WVT :
5
6
Ex : Finding a basis for the kernel
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82000
10201
01312
11021
andRiniswhere,)(bydefinedbe:Let 545
A
ATRRT xxx
Find a basis for ker(T) as a subspace of R5.
7
Solution
 
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000000
041000
020110
010201
082000
010201
001312
011021
0
.. EJG
A
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1
4
0
2
1
0
0
1
1
2
4
2
2
5
4
3
2
1
ts
t
t
s
ts
ts
x
x
x
x
x
x
  TB ofkernelfor thebasisone:)1,4,0,2,1(),0,0,1,1,2( 
Range of a linear transformation T
)(bydenotedisandTofrangethecalledisVin
vectorofimagesarein W thatwvectorsallofsetThen the
L.T.abe:Let
Trange
WVT 
}|)({)( VTTrange  vv
8
.:Tnnsformatiolinear traaofrangeThe WWV foecapsbusasi
The range of T is a subspace of W
TTT ofrangein thevectorbe)(and)(Let vu
)()()()( TrangeTTT  vuvu
)()()( TrangecTcT  uu
),( VVV  vuvu
)( VcV  uu
.subspaceis)(Therefore, WTrange
9
Notes:-
ofsubspaceis)()1( VTKer
L.T.ais: WVT 
ofsubspaceis)()2( WTrange
10
11
Ex: Finding a basis for the range of a linear transformation
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
82000
10201
01312
11021
andiswhere,)(bydefinedbe:Let 545
A
RATRRT xxx
Find a basis for the range of T.
12
BA EJG
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 
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00000
41000
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82000
10201
01312
11021
..
54321 ccccc 54321 wwwww
  Tofrangefor thebasisais)2,0,1,1(),0,0,1,2(),0,1,2,1( 
Solution
 
  )(forbasisais,,
)(forbasisais,,
421
421
ACSccc
BCSwww
Rank and Nullity of Linear Transformation
13
 Rank of a linear transformation T:V→W:
TTrank ofrangetheofdimensionthe)( 
 Nullity of a linear transformation T:V→W:
TTnullity ofkerneltheofdimensionthe)( 
 Note:
)()(
)()(
then,)(bygivenL.T.thebe:Let
AnullityTnullity
ArankTrank
ATRRT mn


 xx
Sum of rank and nullity
AmatrixnmT anbydrepresenteisLet 
)ofdomaindim()ofkerneldim()ofrangedim(
)()(
TTT
nTnullityTrank


rArank )(Assume
Let T:V→W be a L.T. form an n dimation 1 Vector space
V into a Vector space W . Then
14
rArank
ATTrank


)(
)ofspacecolumndim()ofrangedim()((1)
nrnrTnullityTrank  )()()(
rn
ATTnullity

 )ofspacesolutiondim()ofkerneldim()()2(
15
Sum of rank and nullity
16
Ex : Finding the rank and nullity of a linear transformation
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
000
110
201
bydefine:L.T.theofnullityandranktheFind 33
A
RRT
123)()ofdomaindim()(
2)()(


TrankTTnullity
ArankTrank
Solution
One-to-one Linear Transformation
17
vector.singleaofconsistsrangein theevery w
ofpreimagetheifone-to-onecalledis:functionA WVT 
.thatimplies
)()(inV,vanduallforifone-to-oneis
vu
vu

 TTT
one-to-one not one-to-one
}0{)(if1-1isTThenL.T.abe:Let  TKerWVT
1-1isSuppose T 0:solutiononeonlyhavecan0)(Then  vvT
}0{)(i.e. TKer
)()(and}0{)(Suppose vTuTTKer 
0)()()(  vTuTvuT
0)(  vuTKervu
1-1isT
One-to-one Linear Transformation
18
Onto Transformation
19
.ofdimensionthetoequalisofranktheiffontoisThen
l.dimensionafiniteiswhereL.T.,abe:Let
WTT
WWVT 
20One-to-one and onto linear transformation
onto.isitifonlyandifone-to-oneisThen.dimension
ofbothandspaceorwith vectL.T.abe:Let
Tn
WVWVT 
0))(dim(and}0{)(thenone,-to-oneisIf  TKerTKerT
)dim())(dim())(dim( WnTKernTrange 
onto.isly,Consequent T
0)ofrangedim())(dim(  nnTnTKer
one.-to-oneisTherefore,T
nWTT  )dim()ofrangedim(thenonto,isIf
21
Inverse linear Transformation
ineveryfors.t.L.T.are:and:If 21
nnnnn
RRRTRRT v
))((and))(( 2112 vvvv  TTTT
invertiblebetosaidisandofinversethecalledisThen 112 TTT
Note:
If the transformation T is invertible, then the
inverse is unique and denoted by T–1 .
22Finding the inverse of a linear transformation
bydefinedis:L.T.The 33
RRT 
)42,33,32(),,( 321321321321 xxxxxxxxxxxxT 
142
133
132
formatrixstandardThe
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T
321
321
321
42
33
32
xxx
xxx
xxx

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100142
010133
001132
3IA
Show that T is invertible, and find its inverse.
22
Solution
23 1..
326100
101010
011001
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  AIEJG
11
isformatrixstandardtheandinvertibleisTherefore 
ATT
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101
011
1
A
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 
321
31
21
3
2
1
11
326326
101
011
)(
xxx
xx
xx
x
x
x
AT vv
)326,,(),,(
s,other wordIn
3213121321
1
xxxxxxxxxxT 
24
Finding the matrix of a linear transformation
.formatrixstandardtheFindaxis.-xtheontoinpointeach
projectingbygivenis:nnsformatiolinear traThe
2
22
TR
RRT 
)0,(),( xyxT      




00
01
)1,0()0,1()()( 21 TTeTeTA
Notes:
(1) The standard matrix for the zero transformation from Rn into Rm is the mn zero matrix.
(2) The standard matrix for the zero transformation from Rn into Rnis the nn identity matrix In
Solution
25
Composition of T1:Rn→Rm with T2:Rm→Rp
n
RTTT  vvv )),(()( 12
112 ofdomainofdomain, TTTTT  
Composition of linear transformations
then,andmatricesstandardwith
L.T.be:and:Let
21
21
AA
RRTRRT pmmn

L.T.ais)),(()(bydefined,:ncompositioThe(1) 12 vv TTTRRT pn

12productmatrixby thegivenisformatrixstandardThe)2( AAATA 
Note:
1221 TTTT  
26
The standard matrix of a composition
33
21 intofromL.T.beandLet RRTT
),0,2(),,(1 zxyxzyxT  ),z,(),,(2 yyxzyxT 
,'andnscompositiofor thematricesstandardtheFind 2112 TTTTTT  
)formatrixstandard(
101
000
012
11 TA
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 )formatrixstandard(
010
100
011
22 TA
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26
Solution
2712formatrixstandardThe TTT 
21'formatrixstandardThe TTT 
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
000
101
012
101
000
012
010
100
011
12 AAA

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
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
001
000
122
010
100
011
101
000
012
' 21AAA
27
Thankyou
28

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Linear transformation vcla (160920107003)

  • 1. 1 :: PRESENTATION ON :: Linear Transformation Guided by : Mr Sachin Gaikwad Department of Computer Engineering 2th semester
  • 3. Linear Transformation 3 Zero transformation : VT  vv ,0)(WVT : Identity transformation : VVT : VT  vvv ,)( VWVT  vu,,:Properties of linear transformations : 00 )((1)T )()((2) vv TT  )()()((3) vuvu TTT  1 1 2 2 1 1 2 2 1 1 2 2 (4) If Then ( ) ( ) ( ) ( ) ( ) n n n n n n c v c v c v T T c v c v c v c T v c T v c T v             v v L L L
  • 4. The Kernel and Range of a Linear Transformation 4  Kernel of a linear transformation T Let be a linear transformation then the set of all vectors v in V that satisfy is called the kernel of T and is denoted by ker(T) },0)(|{)ker( VTT  vvv WVT :
  • 5. The kernel is a subspace of V The kernel of a linear transformation is a subspace of the domain V. then.ofkernelin thevectorsbeandLet Tvu 000)()()(  vuvu TTT 00)()(  ccTcT uu )ker(Tc  u )ker(T vu .ofsubspaceais)ker(Thus, VT Note: The kernel of T is sometimes called the nullspace of T. WVT : 5
  • 6. 6 Ex : Finding a basis for the kernel                 82000 10201 01312 11021 andRiniswhere,)(bydefinedbe:Let 545 A ATRRT xxx Find a basis for ker(T) as a subspace of R5.
  • 7. 7 Solution                                  000000 041000 020110 010201 082000 010201 001312 011021 0 .. EJG A                                                                 1 4 0 2 1 0 0 1 1 2 4 2 2 5 4 3 2 1 ts t t s ts ts x x x x x x   TB ofkernelfor thebasisone:)1,4,0,2,1(),0,0,1,1,2( 
  • 8. Range of a linear transformation T )(bydenotedisandTofrangethecalledisVin vectorofimagesarein W thatwvectorsallofsetThen the L.T.abe:Let Trange WVT  }|)({)( VTTrange  vv 8
  • 9. .:Tnnsformatiolinear traaofrangeThe WWV foecapsbusasi The range of T is a subspace of W TTT ofrangein thevectorbe)(and)(Let vu )()()()( TrangeTTT  vuvu )()()( TrangecTcT  uu ),( VVV  vuvu )( VcV  uu .subspaceis)(Therefore, WTrange 9
  • 10. Notes:- ofsubspaceis)()1( VTKer L.T.ais: WVT  ofsubspaceis)()2( WTrange 10
  • 11. 11 Ex: Finding a basis for the range of a linear transformation                 82000 10201 01312 11021 andiswhere,)(bydefinedbe:Let 545 A RATRRT xxx Find a basis for the range of T.
  • 12. 12 BA EJG                                 00000 41000 20110 10201 82000 10201 01312 11021 .. 54321 ccccc 54321 wwwww   Tofrangefor thebasisais)2,0,1,1(),0,0,1,2(),0,1,2,1(  Solution     )(forbasisais,, )(forbasisais,, 421 421 ACSccc BCSwww
  • 13. Rank and Nullity of Linear Transformation 13  Rank of a linear transformation T:V→W: TTrank ofrangetheofdimensionthe)(   Nullity of a linear transformation T:V→W: TTnullity ofkerneltheofdimensionthe)(   Note: )()( )()( then,)(bygivenL.T.thebe:Let AnullityTnullity ArankTrank ATRRT mn    xx
  • 14. Sum of rank and nullity AmatrixnmT anbydrepresenteisLet  )ofdomaindim()ofkerneldim()ofrangedim( )()( TTT nTnullityTrank   rArank )(Assume Let T:V→W be a L.T. form an n dimation 1 Vector space V into a Vector space W . Then 14
  • 16. 16 Ex : Finding the rank and nullity of a linear transformation              000 110 201 bydefine:L.T.theofnullityandranktheFind 33 A RRT 123)()ofdomaindim()( 2)()(   TrankTTnullity ArankTrank Solution
  • 17. One-to-one Linear Transformation 17 vector.singleaofconsistsrangein theevery w ofpreimagetheifone-to-onecalledis:functionA WVT  .thatimplies )()(inV,vanduallforifone-to-oneis vu vu   TTT one-to-one not one-to-one
  • 18. }0{)(if1-1isTThenL.T.abe:Let  TKerWVT 1-1isSuppose T 0:solutiononeonlyhavecan0)(Then  vvT }0{)(i.e. TKer )()(and}0{)(Suppose vTuTTKer  0)()()(  vTuTvuT 0)(  vuTKervu 1-1isT One-to-one Linear Transformation 18
  • 20. 20One-to-one and onto linear transformation onto.isitifonlyandifone-to-oneisThen.dimension ofbothandspaceorwith vectL.T.abe:Let Tn WVWVT  0))(dim(and}0{)(thenone,-to-oneisIf  TKerTKerT )dim())(dim())(dim( WnTKernTrange  onto.isly,Consequent T 0)ofrangedim())(dim(  nnTnTKer one.-to-oneisTherefore,T nWTT  )dim()ofrangedim(thenonto,isIf
  • 21. 21 Inverse linear Transformation ineveryfors.t.L.T.are:and:If 21 nnnnn RRRTRRT v ))((and))(( 2112 vvvv  TTTT invertiblebetosaidisandofinversethecalledisThen 112 TTT Note: If the transformation T is invertible, then the inverse is unique and denoted by T–1 .
  • 22. 22Finding the inverse of a linear transformation bydefinedis:L.T.The 33 RRT  )42,33,32(),,( 321321321321 xxxxxxxxxxxxT  142 133 132 formatrixstandardThe           A T 321 321 321 42 33 32 xxx xxx xxx               100142 010133 001132 3IA Show that T is invertible, and find its inverse. 22 Solution
  • 23. 23 1.. 326100 101010 011001                AIEJG 11 isformatrixstandardtheandinvertibleisTherefore  ATT             326 101 011 1 A                                  321 31 21 3 2 1 11 326326 101 011 )( xxx xx xx x x x AT vv )326,,(),,( s,other wordIn 3213121321 1 xxxxxxxxxxT 
  • 24. 24 Finding the matrix of a linear transformation .formatrixstandardtheFindaxis.-xtheontoinpointeach projectingbygivenis:nnsformatiolinear traThe 2 22 TR RRT  )0,(),( xyxT           00 01 )1,0()0,1()()( 21 TTeTeTA Notes: (1) The standard matrix for the zero transformation from Rn into Rm is the mn zero matrix. (2) The standard matrix for the zero transformation from Rn into Rnis the nn identity matrix In Solution
  • 25. 25 Composition of T1:Rn→Rm with T2:Rm→Rp n RTTT  vvv )),(()( 12 112 ofdomainofdomain, TTTTT   Composition of linear transformations then,andmatricesstandardwith L.T.be:and:Let 21 21 AA RRTRRT pmmn  L.T.ais)),(()(bydefined,:ncompositioThe(1) 12 vv TTTRRT pn  12productmatrixby thegivenisformatrixstandardThe)2( AAATA  Note: 1221 TTTT  
  • 26. 26 The standard matrix of a composition 33 21 intofromL.T.beandLet RRTT ),0,2(),,(1 zxyxzyxT  ),z,(),,(2 yyxzyxT  ,'andnscompositiofor thematricesstandardtheFind 2112 TTTTTT   )formatrixstandard( 101 000 012 11 TA            )formatrixstandard( 010 100 011 22 TA             26 Solution
  • 27. 2712formatrixstandardThe TTT  21'formatrixstandardThe TTT                             000 101 012 101 000 012 010 100 011 12 AAA                                   001 000 122 010 100 011 101 000 012 ' 21AAA 27