Given that X ~ epsilon (1), i.e., an exponentially distributed random variable with parameter beta = 1, determine the following probabilities: P(X - mu x 3 sigma x ) where mu x is the mean value, and sigma x is the standard deviation, the positive square root of the variance, sigma2. P(mu x - 2 sigma x Solution here mean = 1 and standard deviation =1 a) P(X-1 >3) = P(X >4) = 0.018 b) P(-1 < X <1) = 0.63.