48. �Qu� funci�n de gesti�n implica medir los resultados, compararlo.pdf

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48. Qu funcin de gestin implica medir los resultados, compararlos con las expectativas y tomar medidas correctivas? a.Planificacin b.Lder c.Organizar d.Control 49. Cul de los siguientes no es un beneficio de la planificacin? a.La planificacin reduce la superposicin y el desperdicio de actividades. b.La planificacin reduce los riesgos de incertidumbre. c.La planificacin proporciona instrucciones. d.La planificacin es un ejercicio mental..

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5. Design and implement a method contains 2 for BinarySearchTree, functionall equivalent to the contains method, that does not use recursion. show the driver code and do this in java this is the binarysearchtree import java.util.*; // Iterator, Comparator public class BinarySearchTree implements BSTInterface { protected BSTNode root; // reference to the root of this BST protected Comparator comp; // used for all comparisons protected boolean found; // used by remove public BinarySearchTree() // Precondition: T implements Comparable // Creates an empty BST object - uses the natural order of elements. { root = null; comp = new Comparator() { public int compare(T element1, T element2) { return ((Comparable)element1).compareTo(element2); } }; } public BinarySearchTree(Comparator comp) // Creates an empty BST object - uses Comparator comp for order // of elements. { root = null; this.comp = comp; } public boolean isFull() // Returns false; this link-based BST is never full. { return false; } public boolean isEmpty() // Returns true if this BST is empty; otherwise, returns false. { return (root == null); } public T min() // If this BST is empty, returns null; // otherwise returns the smallest element of the tree. { if (isEmpty()) return null; else { BSTNode node = root; while (node.getLeft() != null) node = node.getLeft(); return node.getInfo(); } } public T max() // If this BST is empty, returns null; // otherwise returns the largest element of the tree. { if (isEmpty()) return null; else { BSTNode node = root; while (node.getRight() != null) node = node.getRight(); return node.getInfo(); } } private int recSize(BSTNode node) // Returns the number of elements in subtree rooted at node. { if (node == null) return 0; else return 1 + recSize(node.getLeft()) + recSize(node.getRight()); } public int size() // Returns the number of elements in this BST. { return recSize(root); } public int size2() // Returns the number of elements in this BST. { int count = 0; if (root != null) { LinkedStack> nodeStack = new LinkedStack>(); BSTNode currNode; nodeStack.push(root); while (!nodeStack.isEmpty()) { currNode = nodeStack.top(); nodeStack.pop(); count++; if (currNode.getLeft() != null) nodeStack.push(currNode.getLeft()); if (currNode.getRight() != null) nodeStack.push(currNode.getRight()); } } return count; } private boolean recContains(T target, BSTNode node) // Returns true if the subtree rooted at node contains info i such that // comp.compare(target, i) == 0; otherwise, returns false. { if (node == null) return false; // target is not found else if (comp.compare(target, node.getInfo()) < 0) return recContains(target, node.getLeft()); // Search left subtree else if (comp.compare(target, node.getInfo()) > 0) return recContains(target, node.getRight()); // Search right subtree else return true; // target is found } public boolean contains (T target) // Returns true if this BST contains a node with info i such that // comp.compare(target, i) == 0; otherwise, re.

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