Use a graphng utlty and table below to solve. a) fnd a quadratc functon that models the data. (Example:y= -0.1839x^2+2.0789x+1.830) ^ denotes an exponent follows.Round each to 3 decmal pts. X......Y 1....3.5 2.....5.6 3.....6.4 4.....7.4 5.....7 6.....8 Solution Y= ax^2+bx+c let put different values of x to find a,b,c 3.5= a+b+c..............1 5.6= 4a+2b+c..........2 6.4= 9a+3b+c..........3 2-1 2.1= 3a+b...........5 3-2 0.8=5a+b.............6 6-5 -1.3=2a a= -0.65 b=4.05 c=0.1 so equation is y=-1.3x^2+4.05x+.1c .

1. Use a graphng utlty and table below to solve.
a) fnd a quadratc functon that models the data. (Example:y=
-0.1839x^2+2.0789x+1.830) ^ denotes an exponent follows.Round each to 3 decmal pts.
X......Y
1....3.5
2.....5.6
3.....6.4
4.....7.4
5.....7
6.....8
Solution
Y= ax^2+bx+c let
put different values of x to find a,b,c
3.5= a+b+c..............1
5.6= 4a+2b+c..........2

2. 6.4= 9a+3b+c..........3
2-1
2.1= 3a+b...........5
3-2
0.8=5a+b.............6
6-5
-1.3=2a
a= -0.65
b=4.05
c=0.1
so equation is
y=-1.3x^2+4.05x+.1c