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Warm Up
The length of the edge of a cube is 10
inches. How does the volume of a cube
with edges 3 times as long compare to the
volume of the smaller cube?
Warm Up
     The length of the edge of a cube is 10
     inches. How does the volume of a cube
     with edges 3 times as long compare to the
     volume of the smaller cube?

The volume of the large one is 27,000 cubic inches
   while the smaller one is 1,000 cubic inches
Warm Up
     The length of the edge of a cube is 10
     inches. How does the volume of a cube
     with edges 3 times as long compare to the
     volume of the smaller cube?

The volume of the large one is 27,000 cubic inches
   while the smaller one is 1,000 cubic inches

     So, the volume will be 27 times as large.
2.3 Fundamental
   Theorem of
   Variation &
2.9 Combined and
 Joint Variation
THE ESSENTIAL
    QUESTION
          How do we solve variations?
What is the Fundamental Theorem of Variation?
The Fundamental
Theorem of Variation
The Fundamental
Theorem of Variation
 If y varies directly as xn (y = kxn), and x
 is multiplied by c, then y is multiplied by
 cn.
The Fundamental
Theorem of Variation
 If y varies directly as xn (y = kxn), and x
 is multiplied by c, then y is multiplied by
 cn.

 If y varies inversely as xn (y = k/xn), and x
 is multiplied by a nonzero constant c, then
 y is divided by cn.
Suppose that the value of x is doubling, how is
                y changing if:
Suppose that the value of x is doubling, how is
                y changing if:
                          3
1. If y varies directly as x , then ______
Suppose that the value of x is doubling, how is
                y changing if:
                           3
1. If y varies directly as x , then ______
         y is multiplied by 8, from 23
Suppose that the value of x is doubling, how is
                y changing if:
                           3
1. If y varies directly as x , then ______
         y is multiplied by 8, from 23
2. If y varies directly as x4 , then ______
Suppose that the value of x is doubling, how is
                y changing if:
                           3
1. If y varies directly as x , then ______
         y is multiplied by 8, from 23
2. If y varies directly as x4 , then ______

        y is multiplied by 16, from 24
Suppose that the value of x is doubling, how is
                y changing if:
                           3
1. If y varies directly as x , then ______
         y is multiplied by 8, from 23
2. If y varies directly as x4 , then ______

        y is multiplied by 16, from 24
                               2
3. If y varies inversely as x , then ________
Suppose that the value of x is doubling, how is
                y changing if:
                           3
1. If y varies directly as x , then ______
         y is multiplied by 8, from 23
2. If y varies directly as x4 , then ______

        y is multiplied by 16, from 24
                               2
3. If y varies inversely as x , then ________

         y is divided by 4, from 22
4. The formula I = k/D2 tells that the intensity of light varies
inversely as the square of the distance from the light source.
What effect does doubling the distance have on the intensity
of the light?
4. The formula I = k/D2 tells that the intensity of light varies
inversely as the square of the distance from the light source.
What effect does doubling the distance have on the intensity
of the light?

       We have an inverse variation so our
            answer is divided by cn .
4. The formula I = k/D2 tells that the intensity of light varies
inversely as the square of the distance from the light source.
What effect does doubling the distance have on the intensity
of the light?

       We have an inverse variation so our
            answer is divided by cn .
  In the formula D is squared, so our n value
  is 2, since we are doubling, our c value is 2.
4. The formula I = k/D2 tells that the intensity of light varies
  inversely as the square of the distance from the light source.
  What effect does doubling the distance have on the intensity
  of the light?

         We have an inverse variation so our
              answer is divided by cn .
    In the formula D is squared, so our n value
    is 2, since we are doubling, our c value is 2.

 So we would divide by 4, which is the same as
multiplying by 1/4, so the light is 1/4 the intensity.
Combined & Joint Variation
Combined & Joint Variation


 Combined variation - when direct and inverse
 variations occur together
Combined & Joint Variation


 Combined variation - when direct and inverse
 variations occur together
Combined & Joint Variation


 Combined variation - when direct and inverse
 variations occur together



 Joint variation - when one quantity varies
 directly as the product of two or more
 independent variables
Combined & Joint Variation


 Combined variation - when direct and inverse
 variations occur together



 Joint variation - when one quantity varies
 directly as the product of two or more
 independent variables
Combined & Joint Variation


 Combined variation - when direct and inverse
 variations occur together



 Joint variation - when one quantity varies
 directly as the product of two or more
 independent variables
Combined & Joint Variation


 Combined variation - when direct and inverse
 variations occur together
                              kx
          for example -    y=
                               z
 Joint variation - when one quantity varies
 directly as the product of two or more
                    €
 independent variables
Combined & Joint Variation


 Combined variation - when direct and inverse
 variations occur together
                              kx
          for example -    y=
                               z
 Joint variation - when one quantity varies
 directly as the product of two or more
                    €
 independent variables
         for example - A = kbh
5. A baseball pitcher’s earned run average (ERA) varies directly
  as the number of earned runs allowed and inversely as the
number of innings pitched. Write a general equation to model
                       this situation.
5. A baseball pitcher’s earned run average (ERA) varies directly
  as the number of earned runs allowed and inversely as the
number of innings pitched. Write a general equation to model
                       this situation.
            Let e = ERA, R = # of earned runs and I = # of innings.
5. A baseball pitcher’s earned run average (ERA) varies directly
  as the number of earned runs allowed and inversely as the
number of innings pitched. Write a general equation to model
                       this situation.
            Let e = ERA, R = # of earned runs and I = # of innings.
                                 kR
                              E=
                                  I



                  €
5. A baseball pitcher’s earned run average (ERA) varies directly
   as the number of earned runs allowed and inversely as the
 number of innings pitched. Write a general equation to model
                        this situation.
              Let e = ERA, R = # of earned runs and I = # of innings.
                                   kR
                                E=
                                    I
6. In a recent year, a pitcher had an ERA of 2.56, having given up
72 earned runs in 253 innings. How many earned runs would the
pitcher have given up if he had pitched 300 innings, assuming
                     €
that his ERA remained the same?
5. A baseball pitcher’s earned run average (ERA) varies directly
       as the number of earned runs allowed and inversely as the
     number of innings pitched. Write a general equation to model
                            this situation.
                  Let e = ERA, R = # of earned runs and I = # of innings.
                                       kR
                                    E=
                                        I
    6. In a recent year, a pitcher had an ERA of 2.56, having given up
    72 earned runs in 253 innings. How many earned runs would the
    pitcher have given up if he had pitched 300 innings, assuming
                         €
    that his ERA remained the same?

          kR
       E=
           I



€
5. A baseball pitcher’s earned run average (ERA) varies directly
       as the number of earned runs allowed and inversely as the
     number of innings pitched. Write a general equation to model
                            this situation.
                  Let e = ERA, R = # of earned runs and I = # of innings.
                                       kR
                                    E=
                                        I
    6. In a recent year, a pitcher had an ERA of 2.56, having given up
    72 earned runs in 253 innings. How many earned runs would the
    pitcher have given up if he had pitched 300 innings, assuming
                         €
    that his ERA remained the same?

          kR            72k
       E=        2.56 =
           I            253



€        €
5. A baseball pitcher’s earned run average (ERA) varies directly
       as the number of earned runs allowed and inversely as the
     number of innings pitched. Write a general equation to model
                            this situation.
                  Let e = ERA, R = # of earned runs and I = # of innings.
                                       kR
                                    E=
                                        I
    6. In a recent year, a pitcher had an ERA of 2.56, having given up
    72 earned runs in 253 innings. How many earned runs would the
    pitcher have given up if he had pitched 300 innings, assuming
                         €
    that his ERA remained the same?

          kR            72k                   72k
       E=        2.56 =           253⋅ 2.56 =     ⋅ 253
           I            253                   253



                         €
€        €
5. A baseball pitcher’s earned run average (ERA) varies directly
       as the number of earned runs allowed and inversely as the
     number of innings pitched. Write a general equation to model
                            this situation.
                  Let e = ERA, R = # of earned runs and I = # of innings.
                                       kR
                                    E=
                                        I
    6. In a recent year, a pitcher had an ERA of 2.56, having given up
    72 earned runs in 253 innings. How many earned runs would the
    pitcher have given up if he had pitched 300 innings, assuming
                         €
    that his ERA remained the same?

          kR            72k                   72k
       E=        2.56 =           253⋅ 2.56 =     ⋅ 253   647.68 = 72k
           I            253                   253



                         €                         €
€        €
5. A baseball pitcher’s earned run average (ERA) varies directly
       as the number of earned runs allowed and inversely as the
     number of innings pitched. Write a general equation to model
                            this situation.
                  Let e = ERA, R = # of earned runs and I = # of innings.
                                       kR
                                    E=
                                        I
    6. In a recent year, a pitcher had an ERA of 2.56, having given up
    72 earned runs in 253 innings. How many earned runs would the
    pitcher have given up if he had pitched 300 innings, assuming
                         €
    that his ERA remained the same?

          kR            72k                   72k
       E=        2.56 =           253⋅ 2.56 =     ⋅ 253   647.68 = 72k      k ≈9
           I            253                   253



                         €                         €
€        €                                                      €
5. A baseball pitcher’s earned run average (ERA) varies directly
       as the number of earned runs allowed and inversely as the
     number of innings pitched. Write a general equation to model
                            this situation.
                  Let e = ERA, R = # of earned runs and I = # of innings.
                                       kR
                                    E=
                                        I
    6. In a recent year, a pitcher had an ERA of 2.56, having given up
    72 earned runs in 253 innings. How many earned runs would the
    pitcher have given up if he had pitched 300 innings, assuming
                         €
    that his ERA remained the same?

          kR            72k                   72k
       E=        2.56 =           253⋅ 2.56 =     ⋅ 253   647.68 = 72k      k ≈9
           I            253                   253

                        9R
                 2.56 =
                        300
                         €                         €
€        €                                                      €
5. A baseball pitcher’s earned run average (ERA) varies directly
       as the number of earned runs allowed and inversely as the
     number of innings pitched. Write a general equation to model
                            this situation.
                  Let e = ERA, R = # of earned runs and I = # of innings.
                                       kR
                                    E=
                                        I
    6. In a recent year, a pitcher had an ERA of 2.56, having given up
    72 earned runs in 253 innings. How many earned runs would the
    pitcher have given up if he had pitched 300 innings, assuming
                         €
    that his ERA remained the same?

          kR            72k                   72k
       E=        2.56 =           253⋅ 2.56 =     ⋅ 253     647.68 = 72k    k ≈9
           I            253                   253

                        9R                       9R
                 2.56 =           300 ⋅ 2.56 =      ⋅ 300
                        300
                         €                       300 €
€        €                                                        €
5. A baseball pitcher’s earned run average (ERA) varies directly
       as the number of earned runs allowed and inversely as the
     number of innings pitched. Write a general equation to model
                            this situation.
                  Let e = ERA, R = # of earned runs and I = # of innings.
                                       kR
                                    E=
                                        I
    6. In a recent year, a pitcher had an ERA of 2.56, having given up
    72 earned runs in 253 innings. How many earned runs would the
    pitcher have given up if he had pitched 300 innings, assuming
                         €
    that his ERA remained the same?

          kR            72k                   72k
       E=        2.56 =           253⋅ 2.56 =     ⋅ 253     647.68 = 72k        k ≈9
           I            253                   253

                        9R                       9R
                 2.56 =
                        300
                                  300 ⋅ 2.56 =      ⋅ 300
                                                 300 €
                                                            R ≈ 85       runs
                         €                                           €
€        €
7. The power in an electrical circuit varies jointly as the square
of the current and the resistance. Write a formula to show this
relationship.
7. The power in an electrical circuit varies jointly as the square
of the current and the resistance. Write a formula to show this
relationship.

               Let p = power, c = current and r = resistance.
7. The power in an electrical circuit varies jointly as the square
of the current and the resistance. Write a formula to show this
relationship.

               Let p = power, c = current and r = resistance.

                          Then P = kc2r
7. The power in an electrical circuit varies jointly as the square
of the current and the resistance. Write a formula to show this
relationship.

               Let p = power, c = current and r = resistance.

                          Then P = kc2r
b. The power in a certain circuit is 1500 watts when the
current is 15 amps and the resistance is 10 ohms. Find
the power in that circuit when the current is 20 amps and
the resistance is 21 ohms.
7. The power in an electrical circuit varies jointly as the square
of the current and the resistance. Write a formula to show this
relationship.

               Let p = power, c = current and r = resistance.

                          Then P = kc2r
b. The power in a certain circuit is 1500 watts when the
current is 15 amps and the resistance is 10 ohms. Find
the power in that circuit when the current is 20 amps and
the resistance is 21 ohms.
HINT: Find k first.
7. The power in an electrical circuit varies jointly as the square
of the current and the resistance. Write a formula to show this
relationship.

               Let p = power, c = current and r = resistance.

                          Then P = kc2r
b. The power in a certain circuit is 1500 watts when the
current is 15 amps and the resistance is 10 ohms. Find
the power in that circuit when the current is 20 amps and
the resistance is 21 ohms.
HINT: Find k first.
so... 1500 = k(15)2(10)
7. The power in an electrical circuit varies jointly as the square
of the current and the resistance. Write a formula to show this
relationship.

               Let p = power, c = current and r = resistance.

                          Then P = kc2r
b. The power in a certain circuit is 1500 watts when the
current is 15 amps and the resistance is 10 ohms. Find
the power in that circuit when the current is 20 amps and
the resistance is 21 ohms.
HINT: Find k first.
so... 1500 = k(15)2(10)
     1500 = k(2250)
7. The power in an electrical circuit varies jointly as the square
of the current and the resistance. Write a formula to show this
relationship.

                 Let p = power, c = current and r = resistance.

                            Then P = kc2r
b. The power in a certain circuit is 1500 watts when the
current is 15 amps and the resistance is 10 ohms. Find
the power in that circuit when the current is 20 amps and
the resistance is 21 ohms.
HINT: Find k first.
so... 1500 = k(15)2(10)
     1500 = k(2250)
       2/3 = k
7. The power in an electrical circuit varies jointly as the square
of the current and the resistance. Write a formula to show this
relationship.

                 Let p = power, c = current and r = resistance.

                            Then P = kc2r
b. The power in a certain circuit is 1500 watts when the
current is 15 amps and the resistance is 10 ohms. Find
the power in that circuit when the current is 20 amps and
the resistance is 21 ohms.
HINT: Find k first.                NOW: Find the power.
so... 1500 = k(15)2(10)
     1500 = k(2250)
       2/3 = k
7. The power in an electrical circuit varies jointly as the square
of the current and the resistance. Write a formula to show this
relationship.

                 Let p = power, c = current and r = resistance.

                            Then P = kc2r
b. The power in a certain circuit is 1500 watts when the
current is 15 amps and the resistance is 10 ohms. Find
the power in that circuit when the current is 20 amps and
the resistance is 21 ohms.
HINT: Find k first.                NOW: Find the power.
so... 1500 = k(15)2(10)                     P = (2/3)c2r
     1500 = k(2250)
       2/3 = k
7. The power in an electrical circuit varies jointly as the square
of the current and the resistance. Write a formula to show this
relationship.

                 Let p = power, c = current and r = resistance.

                            Then P = kc2r
b. The power in a certain circuit is 1500 watts when the
current is 15 amps and the resistance is 10 ohms. Find
the power in that circuit when the current is 20 amps and
the resistance is 21 ohms.
HINT: Find k first.                NOW: Find the power.
so... 1500 = k(15)2(10)                     P = (2/3)c2r
     1500 = k(2250)                         P = (2/3)(20)2(21)
       2/3 = k
7. The power in an electrical circuit varies jointly as the square
of the current and the resistance. Write a formula to show this
relationship.

                 Let p = power, c = current and r = resistance.

                            Then P = kc2r
b. The power in a certain circuit is 1500 watts when the
current is 15 amps and the resistance is 10 ohms. Find
the power in that circuit when the current is 20 amps and
the resistance is 21 ohms.
HINT: Find k first.                NOW: Find the power.
so... 1500 = k(15)2(10)                     P = (2/3)c2r
     1500 = k(2250)                         P = (2/3)(20)2(21)
       2/3 = k                              P = 5600 watts
Homework
worksheet 2.3A/2.9A

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AA 2.3 & 2.9

  • 1. Warm Up The length of the edge of a cube is 10 inches. How does the volume of a cube with edges 3 times as long compare to the volume of the smaller cube?
  • 2. Warm Up The length of the edge of a cube is 10 inches. How does the volume of a cube with edges 3 times as long compare to the volume of the smaller cube? The volume of the large one is 27,000 cubic inches while the smaller one is 1,000 cubic inches
  • 3. Warm Up The length of the edge of a cube is 10 inches. How does the volume of a cube with edges 3 times as long compare to the volume of the smaller cube? The volume of the large one is 27,000 cubic inches while the smaller one is 1,000 cubic inches So, the volume will be 27 times as large.
  • 4. 2.3 Fundamental Theorem of Variation & 2.9 Combined and Joint Variation
  • 5. THE ESSENTIAL QUESTION How do we solve variations? What is the Fundamental Theorem of Variation?
  • 7. The Fundamental Theorem of Variation If y varies directly as xn (y = kxn), and x is multiplied by c, then y is multiplied by cn.
  • 8. The Fundamental Theorem of Variation If y varies directly as xn (y = kxn), and x is multiplied by c, then y is multiplied by cn. If y varies inversely as xn (y = k/xn), and x is multiplied by a nonzero constant c, then y is divided by cn.
  • 9. Suppose that the value of x is doubling, how is y changing if:
  • 10. Suppose that the value of x is doubling, how is y changing if: 3 1. If y varies directly as x , then ______
  • 11. Suppose that the value of x is doubling, how is y changing if: 3 1. If y varies directly as x , then ______ y is multiplied by 8, from 23
  • 12. Suppose that the value of x is doubling, how is y changing if: 3 1. If y varies directly as x , then ______ y is multiplied by 8, from 23 2. If y varies directly as x4 , then ______
  • 13. Suppose that the value of x is doubling, how is y changing if: 3 1. If y varies directly as x , then ______ y is multiplied by 8, from 23 2. If y varies directly as x4 , then ______ y is multiplied by 16, from 24
  • 14. Suppose that the value of x is doubling, how is y changing if: 3 1. If y varies directly as x , then ______ y is multiplied by 8, from 23 2. If y varies directly as x4 , then ______ y is multiplied by 16, from 24 2 3. If y varies inversely as x , then ________
  • 15. Suppose that the value of x is doubling, how is y changing if: 3 1. If y varies directly as x , then ______ y is multiplied by 8, from 23 2. If y varies directly as x4 , then ______ y is multiplied by 16, from 24 2 3. If y varies inversely as x , then ________ y is divided by 4, from 22
  • 16.
  • 17. 4. The formula I = k/D2 tells that the intensity of light varies inversely as the square of the distance from the light source. What effect does doubling the distance have on the intensity of the light?
  • 18. 4. The formula I = k/D2 tells that the intensity of light varies inversely as the square of the distance from the light source. What effect does doubling the distance have on the intensity of the light? We have an inverse variation so our answer is divided by cn .
  • 19. 4. The formula I = k/D2 tells that the intensity of light varies inversely as the square of the distance from the light source. What effect does doubling the distance have on the intensity of the light? We have an inverse variation so our answer is divided by cn . In the formula D is squared, so our n value is 2, since we are doubling, our c value is 2.
  • 20. 4. The formula I = k/D2 tells that the intensity of light varies inversely as the square of the distance from the light source. What effect does doubling the distance have on the intensity of the light? We have an inverse variation so our answer is divided by cn . In the formula D is squared, so our n value is 2, since we are doubling, our c value is 2. So we would divide by 4, which is the same as multiplying by 1/4, so the light is 1/4 the intensity.
  • 21. Combined & Joint Variation
  • 22. Combined & Joint Variation Combined variation - when direct and inverse variations occur together
  • 23. Combined & Joint Variation Combined variation - when direct and inverse variations occur together
  • 24. Combined & Joint Variation Combined variation - when direct and inverse variations occur together Joint variation - when one quantity varies directly as the product of two or more independent variables
  • 25. Combined & Joint Variation Combined variation - when direct and inverse variations occur together Joint variation - when one quantity varies directly as the product of two or more independent variables
  • 26. Combined & Joint Variation Combined variation - when direct and inverse variations occur together Joint variation - when one quantity varies directly as the product of two or more independent variables
  • 27. Combined & Joint Variation Combined variation - when direct and inverse variations occur together kx for example - y= z Joint variation - when one quantity varies directly as the product of two or more € independent variables
  • 28. Combined & Joint Variation Combined variation - when direct and inverse variations occur together kx for example - y= z Joint variation - when one quantity varies directly as the product of two or more € independent variables for example - A = kbh
  • 29.
  • 30. 5. A baseball pitcher’s earned run average (ERA) varies directly as the number of earned runs allowed and inversely as the number of innings pitched. Write a general equation to model this situation.
  • 31. 5. A baseball pitcher’s earned run average (ERA) varies directly as the number of earned runs allowed and inversely as the number of innings pitched. Write a general equation to model this situation. Let e = ERA, R = # of earned runs and I = # of innings.
  • 32. 5. A baseball pitcher’s earned run average (ERA) varies directly as the number of earned runs allowed and inversely as the number of innings pitched. Write a general equation to model this situation. Let e = ERA, R = # of earned runs and I = # of innings. kR E= I €
  • 33. 5. A baseball pitcher’s earned run average (ERA) varies directly as the number of earned runs allowed and inversely as the number of innings pitched. Write a general equation to model this situation. Let e = ERA, R = # of earned runs and I = # of innings. kR E= I 6. In a recent year, a pitcher had an ERA of 2.56, having given up 72 earned runs in 253 innings. How many earned runs would the pitcher have given up if he had pitched 300 innings, assuming € that his ERA remained the same?
  • 34. 5. A baseball pitcher’s earned run average (ERA) varies directly as the number of earned runs allowed and inversely as the number of innings pitched. Write a general equation to model this situation. Let e = ERA, R = # of earned runs and I = # of innings. kR E= I 6. In a recent year, a pitcher had an ERA of 2.56, having given up 72 earned runs in 253 innings. How many earned runs would the pitcher have given up if he had pitched 300 innings, assuming € that his ERA remained the same? kR E= I €
  • 35. 5. A baseball pitcher’s earned run average (ERA) varies directly as the number of earned runs allowed and inversely as the number of innings pitched. Write a general equation to model this situation. Let e = ERA, R = # of earned runs and I = # of innings. kR E= I 6. In a recent year, a pitcher had an ERA of 2.56, having given up 72 earned runs in 253 innings. How many earned runs would the pitcher have given up if he had pitched 300 innings, assuming € that his ERA remained the same? kR 72k E= 2.56 = I 253 € €
  • 36. 5. A baseball pitcher’s earned run average (ERA) varies directly as the number of earned runs allowed and inversely as the number of innings pitched. Write a general equation to model this situation. Let e = ERA, R = # of earned runs and I = # of innings. kR E= I 6. In a recent year, a pitcher had an ERA of 2.56, having given up 72 earned runs in 253 innings. How many earned runs would the pitcher have given up if he had pitched 300 innings, assuming € that his ERA remained the same? kR 72k 72k E= 2.56 = 253⋅ 2.56 = ⋅ 253 I 253 253 € € €
  • 37. 5. A baseball pitcher’s earned run average (ERA) varies directly as the number of earned runs allowed and inversely as the number of innings pitched. Write a general equation to model this situation. Let e = ERA, R = # of earned runs and I = # of innings. kR E= I 6. In a recent year, a pitcher had an ERA of 2.56, having given up 72 earned runs in 253 innings. How many earned runs would the pitcher have given up if he had pitched 300 innings, assuming € that his ERA remained the same? kR 72k 72k E= 2.56 = 253⋅ 2.56 = ⋅ 253 647.68 = 72k I 253 253 € € € €
  • 38. 5. A baseball pitcher’s earned run average (ERA) varies directly as the number of earned runs allowed and inversely as the number of innings pitched. Write a general equation to model this situation. Let e = ERA, R = # of earned runs and I = # of innings. kR E= I 6. In a recent year, a pitcher had an ERA of 2.56, having given up 72 earned runs in 253 innings. How many earned runs would the pitcher have given up if he had pitched 300 innings, assuming € that his ERA remained the same? kR 72k 72k E= 2.56 = 253⋅ 2.56 = ⋅ 253 647.68 = 72k k ≈9 I 253 253 € € € € €
  • 39. 5. A baseball pitcher’s earned run average (ERA) varies directly as the number of earned runs allowed and inversely as the number of innings pitched. Write a general equation to model this situation. Let e = ERA, R = # of earned runs and I = # of innings. kR E= I 6. In a recent year, a pitcher had an ERA of 2.56, having given up 72 earned runs in 253 innings. How many earned runs would the pitcher have given up if he had pitched 300 innings, assuming € that his ERA remained the same? kR 72k 72k E= 2.56 = 253⋅ 2.56 = ⋅ 253 647.68 = 72k k ≈9 I 253 253 9R 2.56 = 300 € € € € €
  • 40. 5. A baseball pitcher’s earned run average (ERA) varies directly as the number of earned runs allowed and inversely as the number of innings pitched. Write a general equation to model this situation. Let e = ERA, R = # of earned runs and I = # of innings. kR E= I 6. In a recent year, a pitcher had an ERA of 2.56, having given up 72 earned runs in 253 innings. How many earned runs would the pitcher have given up if he had pitched 300 innings, assuming € that his ERA remained the same? kR 72k 72k E= 2.56 = 253⋅ 2.56 = ⋅ 253 647.68 = 72k k ≈9 I 253 253 9R 9R 2.56 = 300 ⋅ 2.56 = ⋅ 300 300 € 300 € € € €
  • 41. 5. A baseball pitcher’s earned run average (ERA) varies directly as the number of earned runs allowed and inversely as the number of innings pitched. Write a general equation to model this situation. Let e = ERA, R = # of earned runs and I = # of innings. kR E= I 6. In a recent year, a pitcher had an ERA of 2.56, having given up 72 earned runs in 253 innings. How many earned runs would the pitcher have given up if he had pitched 300 innings, assuming € that his ERA remained the same? kR 72k 72k E= 2.56 = 253⋅ 2.56 = ⋅ 253 647.68 = 72k k ≈9 I 253 253 9R 9R 2.56 = 300 300 ⋅ 2.56 = ⋅ 300 300 € R ≈ 85 runs € € € €
  • 42.
  • 43. 7. The power in an electrical circuit varies jointly as the square of the current and the resistance. Write a formula to show this relationship.
  • 44. 7. The power in an electrical circuit varies jointly as the square of the current and the resistance. Write a formula to show this relationship. Let p = power, c = current and r = resistance.
  • 45. 7. The power in an electrical circuit varies jointly as the square of the current and the resistance. Write a formula to show this relationship. Let p = power, c = current and r = resistance. Then P = kc2r
  • 46. 7. The power in an electrical circuit varies jointly as the square of the current and the resistance. Write a formula to show this relationship. Let p = power, c = current and r = resistance. Then P = kc2r b. The power in a certain circuit is 1500 watts when the current is 15 amps and the resistance is 10 ohms. Find the power in that circuit when the current is 20 amps and the resistance is 21 ohms.
  • 47. 7. The power in an electrical circuit varies jointly as the square of the current and the resistance. Write a formula to show this relationship. Let p = power, c = current and r = resistance. Then P = kc2r b. The power in a certain circuit is 1500 watts when the current is 15 amps and the resistance is 10 ohms. Find the power in that circuit when the current is 20 amps and the resistance is 21 ohms. HINT: Find k first.
  • 48. 7. The power in an electrical circuit varies jointly as the square of the current and the resistance. Write a formula to show this relationship. Let p = power, c = current and r = resistance. Then P = kc2r b. The power in a certain circuit is 1500 watts when the current is 15 amps and the resistance is 10 ohms. Find the power in that circuit when the current is 20 amps and the resistance is 21 ohms. HINT: Find k first. so... 1500 = k(15)2(10)
  • 49. 7. The power in an electrical circuit varies jointly as the square of the current and the resistance. Write a formula to show this relationship. Let p = power, c = current and r = resistance. Then P = kc2r b. The power in a certain circuit is 1500 watts when the current is 15 amps and the resistance is 10 ohms. Find the power in that circuit when the current is 20 amps and the resistance is 21 ohms. HINT: Find k first. so... 1500 = k(15)2(10) 1500 = k(2250)
  • 50. 7. The power in an electrical circuit varies jointly as the square of the current and the resistance. Write a formula to show this relationship. Let p = power, c = current and r = resistance. Then P = kc2r b. The power in a certain circuit is 1500 watts when the current is 15 amps and the resistance is 10 ohms. Find the power in that circuit when the current is 20 amps and the resistance is 21 ohms. HINT: Find k first. so... 1500 = k(15)2(10) 1500 = k(2250) 2/3 = k
  • 51. 7. The power in an electrical circuit varies jointly as the square of the current and the resistance. Write a formula to show this relationship. Let p = power, c = current and r = resistance. Then P = kc2r b. The power in a certain circuit is 1500 watts when the current is 15 amps and the resistance is 10 ohms. Find the power in that circuit when the current is 20 amps and the resistance is 21 ohms. HINT: Find k first. NOW: Find the power. so... 1500 = k(15)2(10) 1500 = k(2250) 2/3 = k
  • 52. 7. The power in an electrical circuit varies jointly as the square of the current and the resistance. Write a formula to show this relationship. Let p = power, c = current and r = resistance. Then P = kc2r b. The power in a certain circuit is 1500 watts when the current is 15 amps and the resistance is 10 ohms. Find the power in that circuit when the current is 20 amps and the resistance is 21 ohms. HINT: Find k first. NOW: Find the power. so... 1500 = k(15)2(10) P = (2/3)c2r 1500 = k(2250) 2/3 = k
  • 53. 7. The power in an electrical circuit varies jointly as the square of the current and the resistance. Write a formula to show this relationship. Let p = power, c = current and r = resistance. Then P = kc2r b. The power in a certain circuit is 1500 watts when the current is 15 amps and the resistance is 10 ohms. Find the power in that circuit when the current is 20 amps and the resistance is 21 ohms. HINT: Find k first. NOW: Find the power. so... 1500 = k(15)2(10) P = (2/3)c2r 1500 = k(2250) P = (2/3)(20)2(21) 2/3 = k
  • 54. 7. The power in an electrical circuit varies jointly as the square of the current and the resistance. Write a formula to show this relationship. Let p = power, c = current and r = resistance. Then P = kc2r b. The power in a certain circuit is 1500 watts when the current is 15 amps and the resistance is 10 ohms. Find the power in that circuit when the current is 20 amps and the resistance is 21 ohms. HINT: Find k first. NOW: Find the power. so... 1500 = k(15)2(10) P = (2/3)c2r 1500 = k(2250) P = (2/3)(20)2(21) 2/3 = k P = 5600 watts