SolPowerPeople #SolarMOOC final inter-row shading solution..

1. Final Trig Problem Solution?
SolPowerPeople, Inc.
Austin, TX
March 10, 2012

2. Last Trig Problem

3. 24”
?
20°

4. opposite
sin(q )° =
24”
hypotenuse
opposite
sin(20)° =
? 24"
20° opposite
.342 =
24"
24 *.342 = opposite
8.2" = opposite

5. opposite
sin(q )° =
24”
hypotenuse
opposite
sin(20)° =
8.2” 24"
20°
opposite
.342 =
24"
24 *.342 = opposite
8.2" = opposite

6. Last Trig Problem

7. Angle of a 4/12 roof
Tangent of the angle is equal to the
4/12=rise/run opposite over the hypotenuse.
Therefore 4/12 = tangent of the angle
4”
4/12= 0.3333333
12” Arctan of 0.333333= 18.4°
(see earlier slideshow on “arctan”)

8. 6°
8.2”
18.4°

9. 6°
8.2” bring up by
Bring
down to roof pitch
zero° amount
18.4°

10. 8.2”
24.4°
(18.4° + 6°)

11. 8.2”
24.4°
?

12. opposite
tan(q )° =
adjacent
8.2"
tan(24.4)° =
adjacent
8.2"
.4536 =
adjacent
8.2"
adjacent =
.4536
adjacent = 18.077" 8.2”
24.4°
18.077”

13. adjacent
cos(q )° =
hypotenuse
adjacent
cos(53)° =
18.077" ?
adjacent 53° 18.077”
.6018 =
18.707"
18.077 *.6018 = adjacent
adjacent = 10.87"

14. adjacent
cos(q )° =
hypotenuse
adjacent
cos(53)° =
18.077" 10.87”
adjacent 53° 18.077”
.6018 =
18.707"
18.077 *.6018 = adjacent
adjacent = 10.87"