revision A

1. Simplest Formula Prepared by: Stephen Boylan October 20, 2009

2. Simplest Formula . . .

3. Simplest Formula - Simple001 A. Combustion in Excess oxygen 12.795 g. HC ----> 32.689 g. CO2 + 13.377 g. H2O B. 5 Step Calculation C. The Simplest Formula .CxHy Oz

4. Molar Mass CO2 Element Number Atomic Mass Formula n Units, amu Mass, C 1 12.01 12.01 O 2 16.00 32.00 44.01grams per mole CO2

5. Molar Mass H2O Element Number Atomic Mass Formula n Units, amu Mass, n(amu) H 2 1.008 2.016 O 1 16.00 16.00 18.02 grams per mole H2O

6. 2.0 Calculate the grams of carbon, hydrogen and oxygen. 12.795g. HC --> 32.689 g CO2 + 13.377 g. H2O C: 32.689 grams CO2 12.01 grams C = 8.921 g. C 44.01 grams CO2 H: 13.377 grams H2O 2x1.008 grams H = 1.497 g H 18.02 grams H2O O: 12.795 g HC - 8.921g C - 1.497 g H= 2.377 g O

7. Moles of carbon, hydrogen and oxygen. C: 8.921 g. C 1 mole C = 0.7429 moles C 12.01 grams C H: 1.497 g. H 1 mole H = 1.485 mole H 1.008 grams H O: 2.377 g. O 1 mole O = 0.1485 mole O 16.00 grams O

8. Ratios Divide by smallest C: 0.7429 moles C 1 = 5.003 ~ 5 moles C 0.1485 H: 1.485 mole H 1 = 10 moles H 0.1485 O: 0.1485 mole O 1 = 1 moles O 0.1485

9. C5 H10 O1

10. The End