lfur and oxygenreact to produce sulfur trioxide- In a particular exper.docx

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lfur and oxygenreact to produce sulfur trioxide. In a particular experiment, tis ge% a are produced by the reaction of 5.0 grams of O2 with 6.0 grams o SO3 in this experiment? 79 grams of S. What is the % yield s (s) O2 (8) SO3 (8) (not balanced) Solution 2S + 3O2 -------> 2SO3 according to balanced reaction 2 x 32 g S reacts with 3 x 32 g O2 6.0 g S reacts with 6.0 x 3 x 32 / 2 x 32 = 9.0 g O2 but we have only 5.0 g O2. so limiting reagent = O2. now 3 x 32 g O2 gives 2 x 80 g SO3 5 g O2 gives 5 x 2 x 80 / 3 x 32 = 8.33 g SO3 therotical yield of SO3 = 8.33 g actual yield = 7.9 g % yield = (7.9 / 8.33) x 100 % yield = 94.8 % .

lfur and oxygenreact to produce sulfur trioxide. In a particular experiment, tis ge% a are
produced by the reaction of 5.0 grams of O2 with 6.0 grams o SO3 in this experiment? 79 grams
of S. What is the % yield s (s) O2 (8) SO3 (8) (not balanced)
Solution
2S + 3O2 -------> 2SO3
according to balanced reaction
2 x 32 g S reacts with 3 x 32 g O2
6.0 g S reacts with 6.0 x 3 x 32 / 2 x 32 = 9.0 g O2
but we have only 5.0 g O2.
so limiting reagent = O2.
now
3 x 32 g O2 gives 2 x 80 g SO3
5 g O2 gives 5 x 2 x 80 / 3 x 32 = 8.33 g SO3
therotical yield of SO3 = 8.33 g
actual yield = 7.9 g
% yield = (7.9 / 8.33) x 100
% yield = 94.8 %

lfur and oxygenreact to produce sulfur trioxide- In a particular exper.docx

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maom an learning What is the concentration of an HBr solution if 28.5 mL of a 0.200 M NaOH solution are needed to titrate 55.5 mL of the acid? Number Solution Before dilution After dilution M1 = 0.2M M2 = V1 = 28.5ml V2 = 55.5ml M1V1 = M2V2 M2 = M1V1/V2 = 0.2*28.5/55.5 = 0.1027M final concentration = 0.1027M .

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1029 - Danh muc Sach Giao Khoa 10 . pdf

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Key note speaker Neum_Admir Softic_ENG.pdf

Key note speaker Neum_Admir Softic_ENG.pdf

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Advanced Views - Calendar View in Odoo 17

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Class 11th Physics NEET formula sheet pdf

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lfur and oxygenreact to produce sulfur trioxide- In a particular exper.docx

1. lfur and oxygenreact to produce sulfur trioxide. In a particular experiment, tis ge% a are produced by the reaction of 5.0 grams of O2 with 6.0 grams o SO3 in this experiment? 79 grams of S. What is the % yield s (s) O2 (8) SO3 (8) (not balanced) Solution 2S + 3O2 -------> 2SO3 according to balanced reaction 2 x 32 g S reacts with 3 x 32 g O2 6.0 g S reacts with 6.0 x 3 x 32 / 2 x 32 = 9.0 g O2 but we have only 5.0 g O2. so limiting reagent = O2. now 3 x 32 g O2 gives 2 x 80 g SO3 5 g O2 gives 5 x 2 x 80 / 3 x 32 = 8.33 g SO3 therotical yield of SO3 = 8.33 g actual yield = 7.9 g % yield = (7.9 / 8.33) x 100 % yield = 94.8 %