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Chapter 3 – Linear
Systems
Systems of Equations
A set of equations is called a system of
equations.
The solutions must satisfy each equation in the
system.
If all equations in a system are linear, the system
is a system of linear equations, or a linear
system.
3
Systems of Linear Equations:
A solution to a system of equations is an
ordered pair that satisfy all the equations in
the system.
A system of linear equations can have:
1. Exactly one solution
2. No solutions
3. Infinitely many solutions
4
Systems of Linear Equations:
There are four ways to solve systems of linear
equations:
1. By graphing
2. By substitution
3. By elimination
4. By multiplication (Matrices)
5
Solving Systems by Graphing:
When solving a system by graphing:
1. Find ordered pairs that satisfy each of the
equations.
2. Plot the ordered pairs and sketch the
graphs of both equations on the same axis.
3. The coordinates of the point or points of
intersection of the graphs are the solution or
solutions to the system of equations.
6
Solving Systems by Graphing:
Consistent DependentInconsistent
One solution
Lines intersect
No solution
Lines are parallel
Infinite number of
solutions
Coincide-Same
line
Three possible solutions to a linear system in two
variables:
One solution: coordinates of a point
No solutions: inconsistent case
Infinitely many solutions: dependent case
Linear System in Two Variables
8
2x – y = 2
x + y = -2
2x – y = 2
-y = -2x + 2
y = 2x – 2
x + y = -2
y = -x - 2
Different slope, different intercept!
9
3x + 2y = 3
3x + 2y = -4
3x + 2y = 3
2y = -3x + 3
y = -3/2 x + 3/2
3x + 2y = -4
2y = -3x -4
y = -3/2 x - 2
Same slope, different intercept!!
x – y = -3
2x – 2y = -6
x – y = -3
-y = -x – 3
y = x + 3
2x – 2y = -6
-2y = -2x – 6
y = x + 3
Same slope, same intercept!
Same equation!!
11
Determine Without Graphing:
•There is a somewhat shortened way to
determine what type (one solution, no solutions,
infinitely many solutions) of solution exists
within a system.
•Notice we are not finding the solution, just what
type of solution.
•Write the equations in slope-intercept form: y
= mx + b.
(i.e., solve the equations for y, remember
that m = slope, b = y - intercept).
12
Determine Without Graphing:
Once the equations are in slope-intercept form,
compare the slopes and intercepts.
One solution – the lines will have different slopes.
No solution – the lines will have the same slope,
but different intercepts.
Infinitely many solutions – the lines will have the
same slope and the same intercept.
13
Determine Without Graphing:
Given the following lines, determine what type
of solution exists, without graphing.
Equation 1: 3x = 6y + 5
Equation 2: y = (1/2)x – 3
Writing each in slope-intercept form (solve for y)
Equation 1: y = (1/2)x – 5/6
Equation 2: y = (1/2)x – 3
Since the lines have the same slope but
different y-intercepts, there is no solution to the
system of equations. The lines are parallel.
Substitution Method:
Procedure for Substitution Method
1. Solve one of the equations for one of the variables.
2. Substitute the expression found in step 1 into the
other equation.
3. Now solve for the remaining variable.
4. Substitute the value from step 2 into the equation
written in step 1, and solve for the remaining
variable.
Substitution Method:
1. Solve the following system of equations by
substitution.
5
3
−=+
+=
yx
xy
5)3( −=++ xx
532 −=+x
82 −=x
4−=x
Step 1 is already completed.
Step 2:Substitute x+3 into
2nd
equation and solve.
Step 3: Substitute –4 into 1st
equation and solve.
1
34
3
−=
+−=
+=
y
y
xy
The answer: ( -4 , -1)
1) Solve the system using substitution
x + y = 5
y = 3 + x
Step 1: Solve an
equation for one
variable.
Step 2: Substitute
The second equation is
already solved for y!
x + y = 5
x + (3 + x) = 5
Step 3: Solve the
equation.
2x + 3 = 5
2x = 2
x = 1
1) Solve the system using substitution
x + y = 5
y = 3 + x
Step 4: Plug back in to
find the other
variable.
x + y = 5
(1) + y = 5
y = 4
Step 5: Check your
solution.
(1, 4)
(1) + (4) = 5
(4) = 3 + (1)
The solution is (1, 4). What do you think the answer
would be if you graphed the two equations?
2) Solve the system using substitution
3y + x = 7
4x – 2y = 0
Step 1: Solve an
equation for one
variable.
Step 2: Substitute
It is easiest to solve the
first equation for x.
3y + x = 7
-3y -3y
x = -3y + 7
4x – 2y = 0
4(-3y + 7) – 2y = 0
2) Solve the system using substitution
3y + x = 7
4x – 2y = 0
Step 4: Plug back in to
find the other
variable.
4x – 2y = 0
4x – 2(2) = 0
4x – 4 = 0
4x = 4
x = 1
Step 3: Solve the
equation.
-12y + 28 – 2y = 0
-14y + 28 = 0
-14y = -28
y = 2
2) Solve the system using substitution
3y + x = 7
4x – 2y = 0
Step 5: Check your
solution.
(1, 2)
3(2) + (1) = 7
4(1) – 2(2) = 0
Deciding whether an ordered pair is a
solution of a linear system.
The solution set of a linear system of equations contains all ordered
pairs that satisfy all the equations at the same time.
Example 1: Is the ordered pair a solution of the given system?
2x + y = -6 Substitute the ordered pair into each equation.
x + 3y = 2 Both equations must be satisfied.
A) (-4, 2) B) (3, -12)
2(-4) + 2 = -6 2(3) + (-12) = -6
(-4) + 3(2) = 2 (3) + 3(-12) = 2
-6 = -6 -6 = -6
2 = 2 -33 ≠ -6
∴ Yes ∴ No
Substitution Method
Example Solve the system.
Solution
4
31
1
55
11623
11)3(23
3
=
+=
=
=
=++
=++
+=
y
y
x
x
xx
xx
xy Solve (2) for y.
Substitute y = x + 3 in (1).
Solve for x.
Substitute x = 1 in y = x + 3.
Solution set: {(1, 4)}
3
1123
=+−
=+
yx
yx (1)
(2)
Systems of Linear Equations in Two Variables
Solving Linear Systems by Graphing.
One way to find the solution set of a linear system of equations is to graph
each equation and find the point where the graphs intersect.
Example 1: Solve the system of equations by
graphing.
A) x + y = 5 B) 2x + y = -5
2x - y = 4 -x + 3y = 6
Solution: {(3,2)} Solution: {(-3,1)}
Systems of Linear Equations in Two Variables
Solving Linear Systems by Graphing.
There are three possible solutions to a system of linear equations in two
variables that have been graphed:
1) The two graphs intersect at a single point. The coordinates give the solution of
the system. In this case, the solution is “consistent” and the equations are
“independent”.
2) The graphs are parallel lines. (Slopes are equal) In this case the system is
“inconsistent” and the solution set is 0 or null.
3) The graphs are the same line. (Slopes and y-intercepts are the same) In this
case, the equations are “dependent” and the solution set is an infinite set of
ordered pairs.
4-1 Systems of Linear Equations in Two Variables
Solving Linear Systems of two variables by
Method of Substitution.
Step 1: Solve one of the equations for either variable
Step 2: Substitute for that variable in the other equation
(The result should be an equation with just one variable)
Step 3: Solve the equation from step 2
Step 4: Substitute the result of Step 3 into either of the original
equations and solve for the other value.
Step 6: Check the solution and write the solution set.
4-1 Systems of Linear Equations in Two Variables
Solving Linear Systems of two variables by
Method of Substitution.
Example 6: Solve the system : 4x + y = 5
2x - 3y =13
Step 1: Choose the variable y to solve for in the top equation:
y = -4x + 5
Step 2: Substitute this variable into the bottom equation
2x - 3(-4x + 5) = 13 2x + 12x - 15 = 13
Step 3: Solve the equation formed in step 2
14x = 28 x = 2
Step 4: Substitute the result of Step 3 into either of the original equations and solve for the other
value. 4(2) + y = 5
y = -3
Solution Set: {(2,-3)}
Step 5: Check the solution and write the solution set.
Systems of Linear Equations in Two Variables
Solving Linear Systems of two variables by
Method of Substitution.
Example 7:
Solve the system :
y = -2x + 2
-2x + 5(-2x + 2) = 22 -2x - 10x + 10 = 22
-12x = 12
x = -1 2(-1) + y = 2
y = 4
Solution Set: {(-1,4)}
1 1 1
2 4 2
2
1 1 1
rewrite as 4[ ] 2 2
2 4 2
: 2 2
-2 5 2
5 2
2
2
x y
x y
x y x y
Solve x y
x y
⇒ + = ⇒ + =
+
+
=
+
=
=
=
+
−
3x – y = 4
x = 4y - 17
Your Turn:
Your Turn:
2x + 4y = 4
3x + 2y = 22
Clearing Fractions or Decimals



Systems without a Single Point Solution
0 = 4 untrue
Inconsistent Systems - how can you tell?
An inconsistent system
has no solutions.
(parallel lines)
Substitution Technique
ntinconsiste
xx
xx
xyB
xyA
07
22
25
33
2353
23)(
53)(
=
++
−=
++
−−=+−
−−=
+−=



0 = 0 or n = n
Dependent Systems – how can you tell?
A dependent system has
infinitely many solutions.
(it’s the same line!)
Substitution Technique
dependent
yy
yyA
yx
yxB
xyB
xyA
66
6633
6)3(23)(
3
24128)(
24812)(
623)(
2
3
2
3
=
=+−
=−−
−=
−=
−=+−
=−




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Solving systems of Linear Equations

  • 1. Chapter 3 – Linear Systems
  • 2. Systems of Equations A set of equations is called a system of equations. The solutions must satisfy each equation in the system. If all equations in a system are linear, the system is a system of linear equations, or a linear system.
  • 3. 3 Systems of Linear Equations: A solution to a system of equations is an ordered pair that satisfy all the equations in the system. A system of linear equations can have: 1. Exactly one solution 2. No solutions 3. Infinitely many solutions
  • 4. 4 Systems of Linear Equations: There are four ways to solve systems of linear equations: 1. By graphing 2. By substitution 3. By elimination 4. By multiplication (Matrices)
  • 5. 5 Solving Systems by Graphing: When solving a system by graphing: 1. Find ordered pairs that satisfy each of the equations. 2. Plot the ordered pairs and sketch the graphs of both equations on the same axis. 3. The coordinates of the point or points of intersection of the graphs are the solution or solutions to the system of equations.
  • 6. 6 Solving Systems by Graphing: Consistent DependentInconsistent One solution Lines intersect No solution Lines are parallel Infinite number of solutions Coincide-Same line
  • 7. Three possible solutions to a linear system in two variables: One solution: coordinates of a point No solutions: inconsistent case Infinitely many solutions: dependent case Linear System in Two Variables
  • 8. 8 2x – y = 2 x + y = -2 2x – y = 2 -y = -2x + 2 y = 2x – 2 x + y = -2 y = -x - 2 Different slope, different intercept!
  • 9. 9 3x + 2y = 3 3x + 2y = -4 3x + 2y = 3 2y = -3x + 3 y = -3/2 x + 3/2 3x + 2y = -4 2y = -3x -4 y = -3/2 x - 2 Same slope, different intercept!!
  • 10. x – y = -3 2x – 2y = -6 x – y = -3 -y = -x – 3 y = x + 3 2x – 2y = -6 -2y = -2x – 6 y = x + 3 Same slope, same intercept! Same equation!!
  • 11. 11 Determine Without Graphing: •There is a somewhat shortened way to determine what type (one solution, no solutions, infinitely many solutions) of solution exists within a system. •Notice we are not finding the solution, just what type of solution. •Write the equations in slope-intercept form: y = mx + b. (i.e., solve the equations for y, remember that m = slope, b = y - intercept).
  • 12. 12 Determine Without Graphing: Once the equations are in slope-intercept form, compare the slopes and intercepts. One solution – the lines will have different slopes. No solution – the lines will have the same slope, but different intercepts. Infinitely many solutions – the lines will have the same slope and the same intercept.
  • 13. 13 Determine Without Graphing: Given the following lines, determine what type of solution exists, without graphing. Equation 1: 3x = 6y + 5 Equation 2: y = (1/2)x – 3 Writing each in slope-intercept form (solve for y) Equation 1: y = (1/2)x – 5/6 Equation 2: y = (1/2)x – 3 Since the lines have the same slope but different y-intercepts, there is no solution to the system of equations. The lines are parallel.
  • 14. Substitution Method: Procedure for Substitution Method 1. Solve one of the equations for one of the variables. 2. Substitute the expression found in step 1 into the other equation. 3. Now solve for the remaining variable. 4. Substitute the value from step 2 into the equation written in step 1, and solve for the remaining variable.
  • 15. Substitution Method: 1. Solve the following system of equations by substitution. 5 3 −=+ += yx xy 5)3( −=++ xx 532 −=+x 82 −=x 4−=x Step 1 is already completed. Step 2:Substitute x+3 into 2nd equation and solve. Step 3: Substitute –4 into 1st equation and solve. 1 34 3 −= +−= += y y xy The answer: ( -4 , -1)
  • 16. 1) Solve the system using substitution x + y = 5 y = 3 + x Step 1: Solve an equation for one variable. Step 2: Substitute The second equation is already solved for y! x + y = 5 x + (3 + x) = 5 Step 3: Solve the equation. 2x + 3 = 5 2x = 2 x = 1
  • 17. 1) Solve the system using substitution x + y = 5 y = 3 + x Step 4: Plug back in to find the other variable. x + y = 5 (1) + y = 5 y = 4 Step 5: Check your solution. (1, 4) (1) + (4) = 5 (4) = 3 + (1) The solution is (1, 4). What do you think the answer would be if you graphed the two equations?
  • 18. 2) Solve the system using substitution 3y + x = 7 4x – 2y = 0 Step 1: Solve an equation for one variable. Step 2: Substitute It is easiest to solve the first equation for x. 3y + x = 7 -3y -3y x = -3y + 7 4x – 2y = 0 4(-3y + 7) – 2y = 0
  • 19. 2) Solve the system using substitution 3y + x = 7 4x – 2y = 0 Step 4: Plug back in to find the other variable. 4x – 2y = 0 4x – 2(2) = 0 4x – 4 = 0 4x = 4 x = 1 Step 3: Solve the equation. -12y + 28 – 2y = 0 -14y + 28 = 0 -14y = -28 y = 2
  • 20. 2) Solve the system using substitution 3y + x = 7 4x – 2y = 0 Step 5: Check your solution. (1, 2) 3(2) + (1) = 7 4(1) – 2(2) = 0
  • 21. Deciding whether an ordered pair is a solution of a linear system. The solution set of a linear system of equations contains all ordered pairs that satisfy all the equations at the same time. Example 1: Is the ordered pair a solution of the given system? 2x + y = -6 Substitute the ordered pair into each equation. x + 3y = 2 Both equations must be satisfied. A) (-4, 2) B) (3, -12) 2(-4) + 2 = -6 2(3) + (-12) = -6 (-4) + 3(2) = 2 (3) + 3(-12) = 2 -6 = -6 -6 = -6 2 = 2 -33 ≠ -6 ∴ Yes ∴ No
  • 22. Substitution Method Example Solve the system. Solution 4 31 1 55 11623 11)3(23 3 = += = = =++ =++ += y y x x xx xx xy Solve (2) for y. Substitute y = x + 3 in (1). Solve for x. Substitute x = 1 in y = x + 3. Solution set: {(1, 4)} 3 1123 =+− =+ yx yx (1) (2)
  • 23. Systems of Linear Equations in Two Variables Solving Linear Systems by Graphing. One way to find the solution set of a linear system of equations is to graph each equation and find the point where the graphs intersect. Example 1: Solve the system of equations by graphing. A) x + y = 5 B) 2x + y = -5 2x - y = 4 -x + 3y = 6 Solution: {(3,2)} Solution: {(-3,1)}
  • 24. Systems of Linear Equations in Two Variables Solving Linear Systems by Graphing. There are three possible solutions to a system of linear equations in two variables that have been graphed: 1) The two graphs intersect at a single point. The coordinates give the solution of the system. In this case, the solution is “consistent” and the equations are “independent”. 2) The graphs are parallel lines. (Slopes are equal) In this case the system is “inconsistent” and the solution set is 0 or null. 3) The graphs are the same line. (Slopes and y-intercepts are the same) In this case, the equations are “dependent” and the solution set is an infinite set of ordered pairs.
  • 25. 4-1 Systems of Linear Equations in Two Variables Solving Linear Systems of two variables by Method of Substitution. Step 1: Solve one of the equations for either variable Step 2: Substitute for that variable in the other equation (The result should be an equation with just one variable) Step 3: Solve the equation from step 2 Step 4: Substitute the result of Step 3 into either of the original equations and solve for the other value. Step 6: Check the solution and write the solution set.
  • 26. 4-1 Systems of Linear Equations in Two Variables Solving Linear Systems of two variables by Method of Substitution. Example 6: Solve the system : 4x + y = 5 2x - 3y =13 Step 1: Choose the variable y to solve for in the top equation: y = -4x + 5 Step 2: Substitute this variable into the bottom equation 2x - 3(-4x + 5) = 13 2x + 12x - 15 = 13 Step 3: Solve the equation formed in step 2 14x = 28 x = 2 Step 4: Substitute the result of Step 3 into either of the original equations and solve for the other value. 4(2) + y = 5 y = -3 Solution Set: {(2,-3)} Step 5: Check the solution and write the solution set.
  • 27. Systems of Linear Equations in Two Variables Solving Linear Systems of two variables by Method of Substitution. Example 7: Solve the system : y = -2x + 2 -2x + 5(-2x + 2) = 22 -2x - 10x + 10 = 22 -12x = 12 x = -1 2(-1) + y = 2 y = 4 Solution Set: {(-1,4)} 1 1 1 2 4 2 2 1 1 1 rewrite as 4[ ] 2 2 2 4 2 : 2 2 -2 5 2 5 2 2 2 x y x y x y x y Solve x y x y ⇒ + = ⇒ + = + + = + = = = + −
  • 28. 3x – y = 4 x = 4y - 17 Your Turn:
  • 29. Your Turn: 2x + 4y = 4 3x + 2y = 22
  • 30. Clearing Fractions or Decimals   
  • 31. Systems without a Single Point Solution
  • 32. 0 = 4 untrue Inconsistent Systems - how can you tell? An inconsistent system has no solutions. (parallel lines) Substitution Technique ntinconsiste xx xx xyB xyA 07 22 25 33 2353 23)( 53)( = ++ −= ++ −−=+− −−= +−=   
  • 33. 0 = 0 or n = n Dependent Systems – how can you tell? A dependent system has infinitely many solutions. (it’s the same line!) Substitution Technique dependent yy yyA yx yxB xyB xyA 66 6633 6)3(23)( 3 24128)( 24812)( 623)( 2 3 2 3 = =+− =−− −= −= −=+− =−   