3. Demand
Description Current allowance (Amps)
Load Group
of load per unit Calculation
Circuit No (column 1)
(given list) (column 2)
L1 L2 L3
3 A (1st 20)
1 A (i) 13 Lighting points na 3.0
2 A (next 20)
2 A (i) 14 Lighting points 3 A (1st 20) na 3.0
3 A (i) 15 Lighting points 3 A (1st 20) na 3.0
8 + (4 x 2) = 16
8 single +
socket points +
4 B (i) 10 A (1st 20) 10.0
1 (pool filter
4 double outlets
pump) = 17
7 single +
7 + (5 x 2) =
5 B (i) 10 A (1st 20) 10.0
17 socket points
5 double outlets
One 15 A 10 A
B (ii) single phase (See note on group na 10.0
6
outlet in Table C1, B (ii))
50%
7 C Cook top 4200/240 x 0.5 8.8
(or x 0.5)
50%
8 C Oven rating 5200/240 x 0.5 10.8
(or x 0.5)
Pump rating = 4.3 A so socket outlet to
be used for pump supply.
9 B (i) Pool filter pump na
Socket will be part of circuit L1 so
Included with circuit 4 calculations
Air conditioner 75%
10 D 23.6 x 0.75 17.7 17.7 17.7
(23.6 A) (or x 0.75)
11a OPHWS
F Full load current 15.0
bottom element 3600/240
11b OPHWS Included
F Full load current 0.0
top element above
Total demand current per phase 40.7 39.5 46.5

4. Demand
Description Current allowance (Amps)
Load Group
of load per unit Calculation
Circuit No (column 1)
(given list) (column 2)
L1 L2 L3
3 A (1st 20)
1 A (i) 13 Lighting points na 3.0
2 A (next 20)
2 A (i) 14 Lighting points 3 A (1st 20) na 3.0
3 A (i) 15 Lighting points 3 A (1st 20) na 3.0
8 + (4 x 2) = 16
8 single +
socket points +
4 B (i) 10 A (1st 20) 10.0
1 (pool filter
4 double outlets
pump) = 17
7 single +
7 + (5 x 2) =
5 B (i) 10 A (1st 20) 10.0
17 socket points
5 double outlets
One 15 A 10 A
B (ii) single phase (See note on group na 10.0
6
outlet in Table C1, B (ii))
50%
7 C Cook top 4200/240 x 0.5 8.8
(or x 0.5)
50%
8 C Oven rating 5200/240 x 0.5 10.8
(or x 0.5)
Pump rating = 4.3 A so socket outlet to
be used for pump supply.
9 B (i) Pool filter pump na
Socket will be part of circuit L1 so
Included with circuit 4 calculations
Air conditioner 75%
10 D 23.6 x 0.75 17.7 17.7 17.7
(23.6 A) (or x 0.75)
11a OPHWS
F Full load current 15.0
bottom element 3600/240
11b OPHWS Included
F Full load current 0.0
top element above
Total demand current per phase 40.7 39.5 46.5

5. Demand
Description Current allowance (Amps)
Load Group
of load per unit Calculation
Circuit No (column 1)
(given list) (column 2)
L1 L2 L3
3 A (1st 20)
1 A (i) 13 Lighting points na 3.0
2 A (next 20)
2 A (i) 14 Lighting points 3 A (1st 20) na 3.0
3 A (i) 15 Lighting points 3 A (1st 20) na 3.0
8 + (4 x 2) = 16
8 single +
socket points +
4 B (i) 10 A (1st 20) 10.0
1 (pool filter
4 double outlets
pump) = 17
7 single +
7 + (5 x 2) =
5 B (i) 10 A (1st 20) 10.0
17 socket points
5 double outlets
One 15 A 10 A
B (ii) single phase (See note on group na 10.0
6
outlet in Table C1, B (ii))
50%
7 C Cook top 4200/240 x 0.5 8.8
(or x 0.5)
50%
8 C Oven rating 5200/240 x 0.5 10.8
(or x 0.5)
Pump rating = 4.3 A so socket outlet to
be used for pump supply.
9 B (i) Pool filter pump na
Socket will be part of circuit L1 so
Included with circuit 4 calculations
Air conditioner 75%
10 D 23.6 x 0.75 17.7 17.7 17.7
(23.6 A) (or x 0.75)
11a OPHWS
F Full load current 15.0
bottom element 3600/240
11b OPHWS Included
F Full load current 0.0
top element above
Total demand current per phase 40.7 39.5 46.5

6. Demand
Description Current allowance (Amps)
Load Group
of load per unit Calculation
Circuit No (column 1)
(given list) (column 2)
L1 L2 L3
3 A (1st 20)
1 A (i) 13 Lighting points na 3.0
2 A (next 20)
2 A (i) 14 Lighting points 3 A (1st 20) na 3.0
3 A (i) 15 Lighting points 3 A (1st 20) na 3.0
8 + (4 x 2) = 16
8 single +
socket points +
4 B (i) 10 A (1st 20) 10.0
1 (pool filter
4 double outlets
pump) = 17
7 single +
7 + (5 x 2) =
5 B (i) 10 A (1st 20) 10.0
17 socket points
5 double outlets
One 15 A 10 A
B (ii) single phase (See note on group na 10.0
6
outlet in Table C1, B (ii))
50%
7 C Cook top 4200/240 x 0.5 8.8
(or x 0.5)
50%
8 C Oven rating 5200/240 x 0.5 10.8
(or x 0.5)
Pump rating = 4.3 A so socket outlet to
be used for pump supply.
9 B (i) Pool filter pump na
Socket will be part of circuit L1 so
Included with circuit 4 calculations
Air conditioner 75%
10 D 23.6 x 0.75 17.7 17.7 17.7
(23.6 A) (or x 0.75)
11a OPHWS
F Full load current 15.0
bottom element 3600/240
11b OPHWS Included
F Full load current 0.0
top element above
Total demand current per phase 40.7 39.5 46.5

7. Demand
Description Current allowance (Amps)
Load Group
of load per unit Calculation
Circuit No (column 1)
(given list) (column 2)
L1 L2 L3
3 A (1st 20)
1 A (i) 13 Lighting points na 3.0
2 A (next 20)
2 A (i) 14 Lighting points 3 A (1st 20) na 3.0
3 A (i) 15 Lighting points 3 A (1st 20) na 3.0
8 + (4 x 2) = 16
8 single +
socket points +
4 B (i) 10 A (1st 20) 10.0
1 (pool filter
4 double outlets
pump) = 17
7 single +
7 + (5 x 2) =
5 B (i) 10 A (1st 20) 10.0
17 socket points
5 double outlets
One 15 A 10 A
B (ii) single phase (See note on group na 10.0
6
outlet in Table C1, B (ii))
50%
7 C Cook top 4200/240 x 0.5 8.8
(or x 0.5)
50%
8 C Oven rating 5200/240 x 0.5 10.8
(or x 0.5)
Pump rating = 4.3 A so socket outlet to
be used for pump supply.
9 B (i) Pool filter pump na
Socket will be part of circuit L1 so
Included with circuit 4 calculations
Air conditioner 75%
10 D 23.6 x 0.75 17.7 17.7 17.7
(23.6 A) (or x 0.75)
11a OPHWS
F Full load current 15.0
bottom element 3600/240
11b OPHWS Included
F Full load current 0.0
top element above
Total demand current per phase 40.7 39.5 46.5

8. Demand
Description Current allowance (Amps)
Load Group
of load per unit Calculation
Circuit No (column 1)
(given list) (column 2)
L1 L2 L3
3 A (1st 20)
1 A (i) 13 Lighting points na 3.0
2 A (next 20)
2 A (i) 14 Lighting points 3 A (1st 20) na 3.0
3 A (i) 15 Lighting points 3 A (1st 20) na 3.0
8 + (4 x 2) = 16
8 single +
socket points +
4 B (i) 10 A (1st 20) 10.0
1 (pool filter
4 double outlets
pump) = 17
7 single +
7 + (5 x 2) =
5 B (i) 10 A (1st 20) 10.0
17 socket points
5 double outlets
One 15 A 10 A
B (ii) single phase (See note on group na 10.0
6
outlet in Table C1, B (ii))
50%
7 C Cook top 4200/240 x 0.5 8.8
(or x 0.5)
50%
8 C Oven rating 5200/240 x 0.5 10.8
(or x 0.5)
Pump rating = 4.3 A so socket outlet to
be used for pump supply.
9 B (i) Pool filter pump na
Socket will be part of circuit L1 so
Included with circuit 4 calculations
Air conditioner 75%
10 D 23.6 x 0.75 17.7 17.7 17.7
(23.6 A) (or x 0.75)
11a OPHWS
F Full load current 15.0
bottom element 3600/240
11b OPHWS Included
F Full load current 0.0
top element above
Total demand current per phase 40.7 39.5 46.5

9. Demand
Description Current allowance (Amps)
Load Group
of load per unit Calculation
Circuit No (column 1)
(given list) (column 2)
L1 L2 L3
3 A (1st 20)
1 A (i) 13 Lighting points na 3.0
2 A (next 20)
2 A (i) 14 Lighting points 3 A (1st 20) na 3.0
3 A (i) 15 Lighting points 3 A (1st 20) na 3.0
8 + (4 x 2) = 16
8 single +
socket points +
4 B (i) 10 A (1st 20) 10.0
1 (pool filter
4 double outlets
pump) = 17
7 single +
7 + (5 x 2) =
5 B (i) 10 A (1st 20) 10.0
17 socket points
5 double outlets
One 15 A 10 A
B (ii) single phase (See note on group na 10.0
6
outlet in Table C1, B (ii))
50%
7 C Cook top 4200/240 x 0.5 8.8
(or x 0.5)
50%
8 C Oven rating 5200/240 x 0.5 10.8
(or x 0.5)
Pump rating = 4.3 A so socket outlet to
be used for pump supply.
9 B (i) Pool filter pump na
Socket will be part of circuit L1 so
Included with circuit 4 calculations
Air conditioner 75%
10 D 23.6 x 0.75 17.7 17.7 17.7
(23.6 A) (or x 0.75)
11a OPHWS
F Full load current 15.0
bottom element 3600/240
11b OPHWS Included
F Full load current 0.0
top element above
Total demand current per phase 40.7 39.5 46.5

10. Demand
Description Current allowance (Amps)
Load Group
of load per unit Calculation
Circuit No (column 1)
(given list) (column 2)
L1 L2 L3
3 A (1st 20)
1 A (i) 13 Lighting points na 3.0
2 A (next 20)
2 A (i) 14 Lighting points 3 A (1st 20) na 3.0
3 A (i) 15 Lighting points 3 A (1st 20) na 3.0
8 + (4 x 2) = 16
8 single +
socket points +
4 B (i) 10 A (1st 20) 10.0
1 (pool filter
4 double outlets
pump) = 17
7 single +
7 + (5 x 2) =
5 B (i) 10 A (1st 20) 10.0
17 socket points
5 double outlets
One 15 A 10 A
B (ii) single phase (See note on group na 10.0
6
outlet in Table C1, B (ii))
50%
7 C Cook top 4200/240 x 0.5 8.8
(or x 0.5)
50%
8 C Oven rating 5200/240 x 0.5 10.8
(or x 0.5)
Pump rating = 4.3 A so socket outlet to
be used for pump supply.
9 B (i) Pool filter pump na
Socket will be part of circuit L1 so
Included with circuit 4 calculations
Air conditioner 75%
10 D 23.6 x 0.75 17.7 17.7 17.7
(23.6 A) (or x 0.75)
11a OPHWS
F Full load current 15.0
bottom element 3600/240
11b OPHWS Included
F Full load current 0.0
top element above
Total demand current per phase 40.7 39.5 46.5

11. Demand
Description Current allowance (Amps)
Load Group
of load per unit Calculation
Circuit No (column 1)
(given list) (column 2)
L1 L2 L3
3 A (1st 20)
1 A (i) 13 Lighting points na 3.0
2 A (next 20)
2 A (i) 14 Lighting points 3 A (1st 20) na 3.0
3 A (i) 15 Lighting points 3 A (1st 20) na 3.0
8 + (4 x 2) = 16
8 single +
socket points +
4 B (i) 10 A (1st 20) 10.0
1 (pool filter
4 double outlets
pump) = 17
7 single +
7 + (5 x 2) =
5 B (i) 10 A (1st 20) 10.0
17 socket points
5 double outlets
One 15 A 10 A
B (ii) single phase (See note on group na 10.0
6
outlet in Table C1, B (ii))
50%
7 C Cook top 4200/240 x 0.5 8.8
(or x 0.5)
50%
8 C Oven rating 5200/240 x 0.5 10.8
(or x 0.5)
Pump rating = 4.3 A so socket outlet to
be used for pump supply.
9 B (i) Pool filter pump na
Socket will be part of circuit L1 so
Included with circuit 4 calculations
Air conditioner 75%
10 D 23.6 x 0.75 17.7 17.7 17.7
(23.6 A) (or x 0.75)
11a OPHWS
F Full load current 15.0
bottom element 3600/240
11b OPHWS Included
F Full load current 0.0
top element above
Total demand current per phase 40.7 39.5 46.5

12. Demand
Description Current allowance (Amps)
Load Group
of load per unit Calculation
Circuit No (column 1)
(given list) (column 2)
L1 L2 L3
3 A (1st 20)
1 A (i) 13 Lighting points na 3.0
2 A (next 20)
2 A (i) 14 Lighting points 3 A (1st 20) na 3.0
3 A (i) 15 Lighting points 3 A (1st 20) na 3.0
8 + (4 x 2) = 16
8 single +
socket points +
4 B (i) 10 A (1st 20) 10.0
1 (pool filter
4 double outlets
pump) = 17
7 single +
7 + (5 x 2) =
5 B (i) 10 A (1st 20) 10.0
17 socket points
5 double outlets
One 15 A 10 A
B (ii) single phase (See note on group na 10.0
6
outlet in Table C1, B (ii))
50%
7 C Cook top 4200/240 x 0.5 8.8
(or x 0.5)
50%
8 C Oven rating 5200/240 x 0.5 10.8
(or x 0.5)
Pump rating = 4.3 A so socket outlet to
be used for pump supply.
9 B (i) Pool filter pump na
Socket will be part of circuit L1 so
Included with circuit 4 calculations
Air conditioner 75%
10 D 23.6 x 0.75 17.7 17.7 17.7
(23.6 A) (or x 0.75)
11a OPHWS
F Full load current 15.0
bottom element 3600/240
11b OPHWS Included
F Full load current 0.0
top element above
Total demand current per phase 40.7 39.5 46.5

13. Demand
Description Current allowance (Amps)
Load Group
of load per unit Calculation
Circuit No (column 1)
(given list) (column 2)
L1 L2 L3
3 A (1st 20)
1 A (i) 13 Lighting points na 3.0
2 A (next 20)
2 A (i) 14 Lighting points 3 A (1st 20) na 3.0
3 A (i) 15 Lighting points 3 A (1st 20) na 3.0
8 + (4 x 2) = 16
8 single +
socket points +
4 B (i) 10 A (1st 20) 10.0
1 (pool filter
4 double outlets
pump) = 17
7 single +
7 + (5 x 2) =
5 B (i) 10 A (1st 20) 10.0
17 socket points
5 double outlets
One 15 A 10 A
B (ii) single phase (See note on group na 10.0
6
outlet in Table C1, B (ii))
50%
7 C Cook top 4200/240 x 0.5 8.8
(or x 0.5)
50%
8 C Oven rating 5200/240 x 0.5 10.8
(or x 0.5)
Pump rating = 4.3 A so socket outlet to
be used for pump supply.
9 B (i) Pool filter pump na
Socket will be part of circuit L1 so
Included with circuit 4 calculations
Air conditioner 75%
10 D 23.6 x 0.75 17.7 17.7 17.7
(23.6 A) (or x 0.75)
11a OPHWS
F Full load current 15.0
bottom element 3600/240
11b OPHWS Included
F Full load current 0.0
top element above
Total demand current per phase 40.7 39.5 46.5

14. Demand
Description Current allowance (Amps)
Load Group
of load per unit Calculation
Circuit No (column 1)
(given list) (column 2)
L1 L2 L3
3 A (1st 20)
1 A (i) 13 Lighting points na 3.0
2 A (next 20)
2 A (i) 14 Lighting points 3 A (1st 20) na 3.0
3 A (i) 15 Lighting points 3 A (1st 20) na 3.0
8 + (4 x 2) = 16
8 single +
socket points +
4 B (i) 10 A (1st 20) 10.0
1 (pool filter
4 double outlets
pump) = 17
7 single +
7 + (5 x 2) =
5 B (i) 10 A (1st 20) 10.0
17 socket points
5 double outlets
One 15 A 10 A
B (ii) single phase (See note on group na 10.0
6
outlet in Table C1, B (ii))
50%
7 C Cook top 4200/240 x 0.5 8.8
(or x 0.5)
50%
8 C Oven rating 5200/240 x 0.5 10.8
(or x 0.5)
Pump rating = 4.3 A so socket outlet to
be used for pump supply.
9 B (i) Pool filter pump na
Socket will be part of circuit L1 so
Included with circuit 4 calculations
Air conditioner 75%
10 D 23.6 x 0.75 17.7 17.7 17.7
(23.6 A) (or x 0.75)
11a OPHWS
F Full load current 15.0
bottom element 3600/240
11b OPHWS Included
F Full load current 0.0
top element above
Total demand current per phase 40.7 39.5 46.5

15. Demand
Description Current allowance (Amps)
Load Group
of load per unit Calculation
Circuit No (column 1)
(given list) (column 2)
L1 L2 L3
3 A (1st 20)
1 A (i) 13 Lighting points na 3.0
2 A (next 20)
2 A (i) 14 Lighting points 3 A (1st 20) na 3.0
3 A (i) 15 Lighting points 3 A (1st 20) na 3.0
8 + (4 x 2) = 16
8 single +
socket points +
4 B (i) 10 A (1st 20) 10.0
1 (pool filter
4 double outlets
pump) = 17
7 single +
7 + (5 x 2) =
5 B (i) 10 A (1st 20) 10.0
17 socket points
5 double outlets
One 15 A 10 A
B (ii) single phase (See note on group na 10.0
6
outlet in Table C1, B (ii))
50%
7 C Cook top 4200/240 x 0.5 8.8
(or x 0.5)
50%
8 C Oven rating 5200/240 x 0.5 10.8
(or x 0.5)
Pump rating = 4.3 A so socket outlet to
be used for pump supply.
9 B (i) Pool filter pump na
Socket will be part of circuit L1 so
Included with circuit 4 calculations
Air conditioner 75%
10 D 23.6 x 0.75 17.7 17.7 17.7
(23.6 A) (or x 0.75)
11a OPHWS
F Full load current 15.0
bottom element 3600/240
11b OPHWS Included
F Full load current 0.0
top element above
Total demand current per phase 40.7 39.5 46.5

16. Demand
Description Current allowance (Amps)
Load Group
of load per unit Calculation
Circuit No (column 1)
(given list) (column 2)
L1 L2 L3
3 A (1st 20)
1 A (i) 13 Lighting points na 3.0
2 A (next 20)
2 A (i) 14 Lighting points 3 A (1st 20) na 3.0
3 A (i) 15 Lighting points 3 A (1st 20) na 3.0
8 + (4 x 2) = 16
8 single +
socket points +
4 B (i) 10 A (1st 20) 10.0
1 (pool filter
4 double outlets
pump) = 17
7 single +
7 + (5 x 2) =
5 B (i) 10 A (1st 20) 10.0
17 socket points
5 double outlets
One 15 A 10 A
B (ii) single phase (See note on group na 10.0
6
outlet in Table C1, B (ii))
50%
7 C Cook top 4200/240 x 0.5 8.8
(or x 0.5)
50%
8 C Oven rating 5200/240 x 0.5 10.8
(or x 0.5)
Pump rating = 4.3 A so socket outlet to
be used for pump supply.
9 B (i) Pool filter pump na
Socket will be part of circuit L1 so
Included with circuit 4 calculations
Air conditioner 75%
10 D 23.6 x 0.75 17.7 17.7 17.7
(23.6 A) (or x 0.75)
11a OPHWS
F Full load current 15.0
bottom element 3600/240
11b OPHWS Included
F Full load current 0.0
top element above
Total demand current per phase 40.7 39.5 46.5