Código Fonte da Aula 05

1. Programação Estruturada II
CÓDIGO FONTE DA AULA 05
PONTEIROS – 2015.1
Prof. Thomás da Costa
thomasdacosta@gmail.com

2. TEMA: Aula de LAB 04 – PONTEIROS – 2015.1
Nos exercíciosdessaaula, iremosseguiros seguintespassos:
1) Copiar os exercíciospara o Dev-C++ e analisar sua execução.
2) Após a cópia, escrevernesta folhao que foi identificadonaexecuçãodo programa.
3) Por favormanter a atençãona aula, evitaracessosà internete outrasdistrações,para melhorentendimento
dos programas
Boa Codificação
Prof. Thomás da Costa
CENTRO UNIVERSITÁRIO ANHANGUERA DE SÃO PAULO
Unidade Marte: Av. Braz Leme, 3.029 – Santana – São Paulo (SP) – 02022-011 – (11) 2972-9000
DISCIPLINA: Programação Estruturada II
PROFESSOR: Thomás da Costa
ALUNO: RA:
TURMA: PERÍODO: DATA:
CURSO:
AVALIAÇÃO: ASS. PROFESSOR:

3. 1) explique a funcionalidade doprograma abaixo:
#include <iostream>
using namespace std;
int main()
{
int *ptr;
cout << ptr << endl;
}
Resposta:
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2) explique a funcionalidade doprograma abaixo:
#include <iostream>
using namespace std;
int main()
{
int *ptr;
int valor;
valor = 1500;
ptr = &valor;
cout << ptr << endl;
cout << *ptr << endl;
}
Resposta:
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4. 3) explique a funcionalidade doprograma abaixo:
#include <iostream>
using namespace std;
int main()
{
int *ptr;
int valor;
int total;
valor = 1600;
ptr = &valor;
total = *ptr;
cout << *ptr << endl;
cout << total << endl;
}
Resposta:
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4) explique a funcionalidade doprograma abaixo:
#include <iostream>
using namespace std;
int main()
{
// PROGRAMA COM ERRO NAO COMPILA !!!!
int *ptr_inteiro;
double valor;
valor = 345.76;
ptr_inteiro = &valor;
cout << *ptr_inteiro << endl;
}
Resposta:
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5. 5) explique a funcionalidade doprograma abaixo:
#include <iostream>
using namespace std;
int main()
{
int *ptr_inteiro;
double valor;
valor = 345.76;
ptr_inteiro = (int *)&valor;
cout << *ptr_inteiro << endl;
}
Resposta:
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6) explique a funcionalidade doprograma abaixo:
#include <iostream>
using namespace std;
int main()
{
int *ptr_inteiro;
double valor_1;
double valor_2;
valor_1 = 345.76;
ptr_inteiro = (int *)&valor_1;
valor_2 = *ptr_inteiro;
cout << valor_1 << endl;
cout << *ptr_inteiro << endl;
cout << valor_2 << endl;
}
Resposta:
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6. 7) explique a funcionalidade doprograma abaixo:
#include <iostream>
using namespace std;
int main()
{
int *ptr;
int x;
ptr = &x;
*ptr = 999;
cout << &x << endl;
cout << ptr << endl;
cout << *ptr << endl;
}
Resposta:
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8) explique a funcionalidade doprograma abaixo:
#include <iostream>
using namespace std;
int main()
{
int *ptr;
int x;
ptr = &x;
*ptr = 999;
cout << "Valor Original:" << ptr << endl;
ptr++;
cout << "Incremento:" << ptr << endl;
ptr--;
cout << "Decremento:" << ptr << endl;
(*ptr)++;
cout << "Inc. valor:" << *ptr << endl;
(*ptr)--;
cout << "Dec. valor:" << *ptr << endl;
}
Resposta:
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7. 9) explique a funcionalidade doprograma abaixo:
#include <iostream>
using namespace std;
int main()
{
double *ptr;
double x;
ptr = &x;
*ptr = 999.98;
cout << "Valor Original:" << ptr << endl;
ptr++;
cout << "Incremento:" << ptr << endl;
ptr--;
cout << "Decremento:" << ptr << endl;
(*ptr)++;
cout << "Inc. valor:" << *ptr << endl;
(*ptr)--;
cout << "Dec. valor:" << *ptr << endl;
}
Resposta:
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8. 10) explique afuncionalidade doprograma abaixo:
#include <iostream>
using namespace std;
int main()
{
int *ptr_1;
int *ptr_2;
int x, y;
ptr_1 = &x;
ptr_2 = &y;
cout << ptr_1 << endl;
cout << ptr_2 << endl;
cout << (ptr_1 > ptr_2) << endl;
cout << (ptr_1 < ptr_2) << endl;
ptr_1 = &x;
ptr_2 = &x;
cout << (ptr_1 == ptr_2) << endl;
}
Resposta:
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9. 11) explique afuncionalidade doprograma abaixo:
#include <iostream>
#include <strings.h>
using namespace std;
int main()
{
char valores[100];
char *ptr;
strcpy(valores, "Isto é um teste");
ptr = valores;
cout << valores << endl;
cout << ptr << endl;
ptr = (char *)"Isto é um outro teste";
cout << ptr << endl;
cout << valores[3] << endl;
cout << *(ptr+3) << endl;
}
Resposta:
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10. 12) explique afuncionalidade doprograma abaixo:
#include <iostream>
#include <strings.h>
#include <stdlib.h>
using namespace std;
int main()
{
int *ptr_1, *ptr_2;
int valor_1, valor_2;
char valor_convertido[100];
ptr_1 = &valor_1;
ptr_2 = &valor_2;
valor_1 = 316;
valor_2 = 206;
*ptr_1 = *ptr_1 << 2;
cout << *ptr_1 << endl;
*ptr_1 = *ptr_1 >> 2;
cout << *ptr_1 << endl;
itoa(*ptr_1, valor_convertido, 2);
cout << "Valor binário:" << valor_convertido << endl;
itoa(*ptr_2, valor_convertido, 2);
cout << "Valor binário:" << valor_convertido << endl;
itoa(*ptr_2 & *ptr_1, valor_convertido, 2);
cout << "Operador AND:" << valor_convertido << endl;
itoa(*ptr_2 | *ptr_1, valor_convertido, 2);
cout << "Operador OR:" << valor_convertido << endl;
itoa(*ptr_2 ^ *ptr_1, valor_convertido, 2);
cout << "Operador XOR:" << valor_convertido << endl;
itoa(~*ptr_2, valor_convertido, 2);
cout << "Operador NEG:" << valor_convertido << endl;
}
Resposta:
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