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1
T.PARAMESH
Department of Mechanical
engineering
 Magnitude
 Direction
 Point of application
 Nature
 Resolution of force
 The process of replacing a single force into
number of components, without changing its
effect on the body is called Resolution of
force
7
Systemof
Forces
Coplanar
2D
Concurrent Non-
concurrent
Parallel General
Non-
coplanar
3D
Concurrent
Non-
concurrent
Parallel General
8
9
Method of approach to solve CONCURRENT and NON CONCURRENT FORCE Systems
Problem
2-D
Concurrent
NotEquilibrium
(Resultant)
1.ParallelogramLaw
2. Trianglelaw
3. Polygonlaw
4.Methodof
projections
Equilibrium
(Unknowns)
Fx=0
Fy=0
Non-concurrent
NotEquilibrium
(Resultant)
1.Choose a reference
Point
2.Shift all the forces
to apoint
3.Find the resultant
force and couple at
thatpoint
4.Reduce the force-
couple system to a
single force
Equilibrium
(Unknowns)
ΣFx=0
ΣFy=0
ΣMz=0
3-D
Concurrent
Notequilibrium
(Resultant)
--- --- --- -- R
= F1+F2+F3
Equilibrium
(Unknowns)
--- ---
R = 0
--- --- -- --
F1+F2+F3,,= 0
ΣFx=0
ΣFy=0
ΣFz=0,
NonConcurrent
NotEquilibrium
(Resultant)
--- -- -- --
R=F1+F2+F3….
--- --- --- ---
M = M1+M2+M3....
--- ---
OPͯr R =M
Equilibrium
(Unknowns)
--- ---
R = 0
--- ---
M = 0
10
ΣFx=0 , ΣMx=0
ΣFy=0, ΣMy=0
ΣFz=0, ΣMz=0
Method of approach to solve Coplanar (2D) problems
Problem
2-D
Concurrent
NotEquilibrium
(Resultant)
1. ParallelogramLaw
2. Trianglelaw
3. Polygon law
4. Method ofprojections
Equilibrium
(Unknowns)
F =0x
Fy=0
Non-concurrent
NotEquilibrium
(Resultant)
1.Choose a referencePoint
2. Shift all the forces to apoint
3.Find the resultant forceand
couple at that point
4.Reduce theforce-couple
system to a singleforce
Equilibrium
(Unknowns)
ΣFx=0
ΣFy=0
ΣMz=0
11
 Laws of mechanics
Newton’s first law of motion
Newton’s second law of motion
Newton’s third law of motion
Newton’s law of gravitation
Laws of parallelogram of force
Determine the resultant of the following figure
Determine the resultant of the following figure
Determine the resultant of the following figure
Problem – 2D- Concurrent - Resultant
17
R  199.12
14.32
R 199.6N
5
Force Mag x comp y comp
F1 150 150cos30 150Sin30
F2
80 80sin 20 80Cos20
F3
110 0 110
F4
100 100cos15 100sin1
F x
199.1 F y
14.3
2 2
 F X
  FY
R Resultant is
199.1N
tan  
14.3 N
  4.1
Direction is
8
Problemsolution
Determine the resultant of the following figure
Problem – 2D- Non Concurrent - Resultant
11
Moment of force
 The rotational effect produced by force is
known as Moment of force
Couple
 Two non collinear parallel forces of equal
magnitude but acting in opposite direction
from couple
FBD
 FBD is a sketch of the body showing all active
and reactive forces that acts on it after
removing all supports with consideration of
geometrical angles and distance.
Lamis theorem
 If a body is an equilibrium under the action of
three forces each force is proportional to the
sine of the angle between the other two
forces
Determine the resultant of the following figure
23

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Mechanical Engineering Forces and Systems

  • 2.
  • 3.
  • 4.  Magnitude  Direction  Point of application  Nature
  • 5.
  • 6.  Resolution of force  The process of replacing a single force into number of components, without changing its effect on the body is called Resolution of force
  • 8. 8
  • 9. 9
  • 10. Method of approach to solve CONCURRENT and NON CONCURRENT FORCE Systems Problem 2-D Concurrent NotEquilibrium (Resultant) 1.ParallelogramLaw 2. Trianglelaw 3. Polygonlaw 4.Methodof projections Equilibrium (Unknowns) Fx=0 Fy=0 Non-concurrent NotEquilibrium (Resultant) 1.Choose a reference Point 2.Shift all the forces to apoint 3.Find the resultant force and couple at thatpoint 4.Reduce the force- couple system to a single force Equilibrium (Unknowns) ΣFx=0 ΣFy=0 ΣMz=0 3-D Concurrent Notequilibrium (Resultant) --- --- --- -- R = F1+F2+F3 Equilibrium (Unknowns) --- --- R = 0 --- --- -- -- F1+F2+F3,,= 0 ΣFx=0 ΣFy=0 ΣFz=0, NonConcurrent NotEquilibrium (Resultant) --- -- -- -- R=F1+F2+F3…. --- --- --- --- M = M1+M2+M3.... --- --- OPͯr R =M Equilibrium (Unknowns) --- --- R = 0 --- --- M = 0 10 ΣFx=0 , ΣMx=0 ΣFy=0, ΣMy=0 ΣFz=0, ΣMz=0
  • 11. Method of approach to solve Coplanar (2D) problems Problem 2-D Concurrent NotEquilibrium (Resultant) 1. ParallelogramLaw 2. Trianglelaw 3. Polygon law 4. Method ofprojections Equilibrium (Unknowns) F =0x Fy=0 Non-concurrent NotEquilibrium (Resultant) 1.Choose a referencePoint 2. Shift all the forces to apoint 3.Find the resultant forceand couple at that point 4.Reduce theforce-couple system to a singleforce Equilibrium (Unknowns) ΣFx=0 ΣFy=0 ΣMz=0 11
  • 12.  Laws of mechanics Newton’s first law of motion Newton’s second law of motion Newton’s third law of motion Newton’s law of gravitation Laws of parallelogram of force
  • 13.
  • 14.
  • 15. Determine the resultant of the following figure
  • 16. Determine the resultant of the following figure
  • 17. Determine the resultant of the following figure Problem – 2D- Concurrent - Resultant 17
  • 18. R  199.12 14.32 R 199.6N 5 Force Mag x comp y comp F1 150 150cos30 150Sin30 F2 80 80sin 20 80Cos20 F3 110 0 110 F4 100 100cos15 100sin1 F x 199.1 F y 14.3 2 2  F X   FY R Resultant is 199.1N tan   14.3 N   4.1 Direction is 8 Problemsolution
  • 19. Determine the resultant of the following figure Problem – 2D- Non Concurrent - Resultant 11
  • 20. Moment of force  The rotational effect produced by force is known as Moment of force Couple  Two non collinear parallel forces of equal magnitude but acting in opposite direction from couple
  • 21. FBD  FBD is a sketch of the body showing all active and reactive forces that acts on it after removing all supports with consideration of geometrical angles and distance. Lamis theorem  If a body is an equilibrium under the action of three forces each force is proportional to the sine of the angle between the other two forces
  • 22. Determine the resultant of the following figure
  • 23. 23