52. If
𝑎
𝑏
𝑥−1
=
𝑏
𝑎
𝑥−3
,then the value of x is
2
1
1
2
7
2
12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 58
𝑎
𝑏
𝑥−1
=
𝑏
𝑎
𝑥−3
𝑎
𝑏
𝑥−1
=
𝑎
𝑏
−(𝑥−3)
53. If
𝑎
𝑏
𝑥−1
=
𝑏
𝑎
𝑥−3
,then the value of x is
2
1
1
2
7
2
12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 59
𝑎
𝑏
𝑥−1
=
𝑏
𝑎
𝑥−3
𝑎
𝑏
𝑥−1
=
𝑎
𝑏
−(𝑥−3)
x – 1 = 3 – x
Solving x = 2
54. Given 100.48 = x, 100.7 = y and xz = y2, value of z = ?
1.45
1.88
2.9
3.7
12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 60
55. Given 100.48 = x, 100.7 = y and xz = y2, value of z = ?
1.45
1.88
2.9
3.7
12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 61
xz = y2
100.48z = 102*0.7
56. Given 100.48 = x, 100.7 = y and xz = y2, value of z = ?
1.45
1.88
2.9
3.7
12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 62
xz = y2
100.48z = 102*0.7
0.48z = 1.4
57. Given 100.48 = x, 100.7 = y and xz = y2, value of z = ?
1.45
1.88
2.9
3.7
12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 63
xz = y2
100.48z = 102*0.7
0.48z = 1.4
Z =
140
48
=
35
12
≈ 2.9
58. If 5a = 3125, then the value of 5a – 3 is?
25
125
625
1625
12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 64
59. If 3x – y = 27 and 3x + y = 243, then x =?
0
2
4
6
12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 65
60. If 3x – y = 27 and 3x + y = 243, then x = ?
0
2
4
6
12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 66
3x – y = 27 = 33
3x + y = 243 = 35
61. If 3x – y = 27 and 3x + y = 243, then x = ?
0
2
4
6
12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 67
3x – y = 27 = 33
3x + y = 243 = 35
x – y = 3
62. If 3x – y = 27 and 3x + y = 243, then x = ?
0
2
4
6
12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 68
3x – y = 27 = 33
3x + y = 243 = 35
x – y = 3
x + y = 5
63. If 3x – y = 27 and 3x + y = 243, then x = ?
0
2
4
6
12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 69
3x – y = 27 = 33
3x + y = 243 = 35
x – y = 3
x + y = 5
Solving x = 4
78. If mn = 121, the value of (m – 1)n+1 is
1
10
121
1000
12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 84
79. xb
xc
b + c − a
xc
xa
c +a −b
xa
xb
a +b −c
xabc
1
xab+bc+ca
xa+b+c
12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 85
80. xb
xc
b + c − a
xc
xa
c +a −b
xa
xb
a +b −c
xabc
1
xab+bc+ca
xa+b+c
12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 86
xb
xc
b + c − a
xc
xa
c +a −b
xa
xb
a +b −c
81. xb
xc
b + c − a
xc
xa
c +a −b
xa
xb
a +b −c
xabc
1
xab+bc+ca
xa+b+c
12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 87
xb
xc
b + c − a
xc
xa
c +a −b
xa
xb
a +b −c
= x(b - c)(b + c - a) . x(c - a)(c + a - b) . x(a - b)(a + b - c)
82. xb
xc
b + c − a
xc
xa
c +a −b
xa
xb
a +b −c
xabc
1
xab+bc+ca
xa+b+c
12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 88
xb
xc
b + c − a
xc
xa
c +a −b
xa
xb
a +b −c
= x(b - c)(b + c - a) . x(c - a)(c + a - b) . x(a - b)(a + b - c)
= x(b - c)(b + c) – (b-c)(a) . x(c - a)(c + a) – (c-a)(b) . x(a - b)(a + b – (a-b)(c)
83. xb
xc
b + c − a
xc
xa
c +a −b
xa
xb
a +b −c
xabc
1
xab+bc+ca
xa+b+c
12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 89
xb
xc
b + c − a
xc
xa
c +a −b
xa
xb
a +b −c
= x(b - c)(b + c - a) . x(c - a)(c + a - b) . x(a - b)(a + b - c)
= x(b - c)(b + c) – (b-c)(a) . x(c - a)(c + a) – (c-a)(b) . x(a - b)(a + b – (a-b)(c)
=𝑥 𝑏2−𝑐2+𝑐2−𝑎2+𝑎2−𝑏2
∗ 𝑥 𝑏𝑎−𝑐𝑎+𝑏𝑐−𝑎𝑏+𝑎𝑐−𝑏𝑐
84. If x = 3 + 2 2, then 𝑥 −
1
𝑥
is
1
2
2 2
3 3
12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 90
85. If x = 3 + 2 2, then 𝑥 −
1
𝑥
is
1
2
2 2
3 3
12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 91
X = 3 + 2 2
86. If x = 3 + 2 2, then 𝑥 −
1
𝑥
is
1
2
2 2
3 3
12-Jun-15 C.S.VEERARAGAVAN 98948 34264 veeraa1729@gmail.com 92
X = 3 + 2 2
𝑥 −
1
𝑥
2
= 𝑥 +
1
𝑥
− 2