The document contains a list of 16 programs related to arrays in Swift. The programs cover topics like printing arrays, searching arrays, sorting arrays, inserting/deleting elements from arrays, and performing operations on elements in arrays. Functions are defined to implement each program with arrays and size passed as parameters.

1. SWIFT
PROGRAMS ON ARRAY

2. INDEX
S.NO. PROGRAMS SIGNATURE
1 Program to print the numbers in an array horizontally
2 Program to search the number from a 1 D array using linear search
3 Program to search the number from a 1 D array using binary search
4 Program to insert the number in a 1 D array using Insertion sorted array
5 Program to insert the number in a 1 D array using Deletion sorted array
6 Program to sort the number in an array using bubble sort
7 Program to sort the number in an array using selection sort
8 Write a function Alter(), with array and size as a parameter ,which
should change all the multiples of 5 in the array to 5 and rest of the
element as 1
9 Write a function modify() with array and size as a parameter, which
should reposition the content after swapping each adjacent pair of
number in it
10 Write a function Large() with array and size as a parameter, which
should display the largest and second largest by returning both from an
array
11 Write a function addup() with array and size as a parameter,in which all
even position(0,2,4,…..) of the array should be added with the content
of element in the next position and odd position(1,3,5,…..) elements
should be increment by 10
12 Write a function twotoone() with array and size as an parameters,in
which accept two array X[] and Y[] and transfer all X[] numbers in even
places of Z[] and all Y[] numbers in odd places of Z[].
13 Write a function convert() with array and size as a parameter,which
reposition all the elements of the array by shifting each of them one to
one position before and by shifting the first elements to the last
position
14 Write a function SWAP() with array and size as a parameter,which swap
the numbers on the basis of example given:
If array A no : 10,20,30,40,50,60 the output after swapping
20,10,40,30,60,50
15 Write a function SWAP2() with array and size as a parameter,which
swap the numbers on the basis of example given:
If array A no : 10,20,30,40,50,60 the output after swapping
40,50,60,10,20,30
16 Write a function merge() with three array as a parameter array A,B, and
C with their size M , N , and M+N , where A is ascending order , B is
descending order and C accept numbers from A and B in ascending
order.
17 Write a function dispTen() with 2D array no and size as a parameter and
display only those numbers which are divisible by 10
18 Write a function rowsum() with 2D array A and size as a parameter and
display the sum of each row

3. 20 Write a function diagonalsum() with 2D array A and size as a parameter
and display the sum
21 program to find the largest no from a 1D array of 10 numbers
22 Write a function swaparr() with 2D array A and size as a parameter and
swap or interchange the first row with the last row elements.
23 Write a function lefttrg() with 2D array A and size as a parameter and
display the output as given
Example: output
1 2 3 4
6 4 5 6 6
2 1 5 4 2 1
1 2 3 5 1 2 3
24 Write a function summatrix() with 2D array A , B , C and size as a
parameter, and display the sum of two matrix in C
25 Write a function copyarr() with 2D array A and B as 1D array and size as
a parameter,display the output as given below:
Example: if array B values are 1,2,3,4,5
Array A store values as:
1,2,3,4,5
1,2,3,4,0
1,2,3,0,0
1,2,0,0,0
1,0,0,0,0

4. //Program to print the numbers in an array horizontally
func display(no:[Int], k:Int)
{
var x = 0
while x < k
{
print("(no[x]), ",terminator:"")
x = x + 1
}
print("")
}
var n:[Int] = [10,20,30,40,50,60,70,80,90,100 ]
display(no:n, k:10)
----------------------------output ----------------------------------
10, 20, 30, 40, 50, 60, 70, 80, 90, 100,

5. // Program to search the number from a 1 D array using linear search
func lsearch(no:[Int], src:Int, k:Int) -> Int
{
var tmp = -1
var x = 0
while x < k
{
if no[x] == src
{
tmp = x
break
}
x = x + 1
}
return tmp
}
var n:[Int] = [40,10,51,86,19,87,70,3,14,100 ]
var rs = lsearch(no:n, src:19, k:10)
if rs < 0
{
print("no not found")
}else
{
rs = rs + 1
print("no found at pos =(rs)")
}
--------------------------output----------------------------
no found at pos =5

6. // Program to search the number from a 1 D array using binary search
func bsearch(no:[Int], src:Int, k:Int) -> Int
{
var tmp = -1
var x = 0
var beg = 0 , last = k - 1 , mid = 0
while beg < last
{
mid = (beg + last) / 2
if no[mid] == src
{
tmp = x
break
}else
{ if no[mid] > src
{
last = mid - 1
}else
{
beg = mid + 1
}
}
x = x + 1
}
return tmp
}
var n:[Int] = [40,45,58,75,86,89,92,97,99,120]
var rs = bsearch(no:n, src:58, k:10)
if rs < 0
{
print("no not found")
}else
{
rs = rs + 1
print("no found at pos =(rs)")
}
---------------output------------------
no found at pos =3

7. // Program to insert the number in a 1 D array using Insertion sorted array
func insertionUN(no:[Int],ser:Int,k:Int) -> Int
{
var pos:Int = -1
var flag = -1
var x = 0
let last = k - 1
while x < k
{
if no[0] >= ser
{
flag = 0
pos = 0
break
}else if no[last] <= ser
{
pos = last
flag = 1
break;
}
else if no[x] < ser && no[x + 1] > ser
{
flag = 2
pos = x + 1
break
}
x = x + 1
}
if flag == 0
{
pos = 0
}else if flag == 1
{
pos = pos + 1
}
return pos
}

8. var search = 67
print("before insertion")
var n:[Int] = [10,20,30,40,50,60,70,80]
var k1 = insertionUN(no:n, ser:search, k:n.count)
print("after insertion")
n.insert(search,at:k1)
print(n)
----------------------------output------------------------------
before insertion
[10, 20, 30, 40, 50, 60, 70, 80]
after insertion
[10, 20, 30, 40, 50, 60, 67, 70, 80]

9. // Program to insert the number in a 1 D array using Deletion sorted array
func deletionUN(no:[Int],ser:Int,k:Int) -> Int
{
var pos:Int = -1
var x = 0
while x < k
{
if no[x] == ser
{
pos = x
break
}
x = x + 1
}
return pos
}
var search = 40
var y = 0
var n:[Int] = [10,20,30,40,50,60,70,80]
print("before deletion array size = (n.count)")
print(n)
var k1 = deletionUN(no:n, ser:search, k:n.count)
if k1 > 0
{
y = k1
while y < n.count - 1
{
n[y] = n[y + 1]
y = y + 1
}
}
n.remove(at:n.count - 1)
print("after deletion array size =(n.count)")
print(n)
-------output----------------
before deletion array size = 8
[10, 20, 30, 40, 50, 60, 70, 80]
after deletion array size =7
[10, 20, 30, 50, 60, 70, 80]

10. // Program to sort the number in an array using bubble sort
func sortbubble(no:inout [Int],k:Int)
{
var x = 0 , y = 0
var tmp = 0
while x < k
{
y = 0
while y < k - 1
{
if no[y] > no[y + 1]
{
tmp = no[y]
no[y] = no[y + 1]
no[y + 1] = tmp
}
y = y + 1
}
x = x + 1
}
}
var n:[Int] = [60,2,33,55,5,22,1,8]
print("before sorting array ")
print(n)
sortbubble(no: &n, k:n.count)
print("after sorting array")
print(n)
----------------------------------output------------------------------------
before sorting array
[60, 2, 33, 55, 5, 22, 1, 8]
after sorting array
[1, 2, 5, 8, 22, 33, 55, 60]

11. // Program to sort the number in an array using selection sort
func sortselection(no:inout [Int],k:Int)
{
var x = 0 , y = 0
var tmp = 0
while x < k
{
y = x + 1
while y < k
{
if no[x] > no[y]
{
tmp = no[x]
no[x] = no[y]
no[y] = tmp
}
y = y + 1
}
x = x + 1
}
}
var n:[Int] = [60,2,33,55,5,22,1,8]
print("before sorting array ")
print(n)
sortselection(no: &n, k:n.count)
print("after sorting array")
print(n)
-----------------------------output------------------------------
before sorting array
[60, 2, 33, 55, 5, 22, 1, 8]
after sorting array
[1, 2, 5, 8, 22, 33, 55, 60]

12. /* Write a function Alter(), with array and size as a parameter ,which should
change all the multiples of 5 in the array to 5 and rest of the element as 1 */
func alter(no:inout [Int],k:Int)
{
var x = 0
while x < k
{
if no[x] % 5 == 0
{
no [x] = 5
}else
{
no[x] = 1
}
x = x + 1
}
}
var n:[Int] = [55,43,20,16,39,90,83,40,48,25]
print("before ")
print(n)
alter(no: &n, k:n.count)
print("after")
print(n)
------------------------output-----------------------------
before
[55, 43, 20, 16, 39, 90, 83, 40, 48, 25]
after
[5, 1, 5, 1, 1, 5, 1, 5, 1, 5]

13. /* Write a function modify() with array and size as a parameter, which should
reposition the content after swapping each adjacent pair of number in it */
func modify(no:inout [Int],k:Int)
{
var x = 0 , tmp = 0
while x < k
{
tmp = no[x]
no[x] = no[x + 2]
no[x + 2] = tmp
if x % 4 >= 1
{
x = x + 2
}
x = x + 1
}
}
var n:[Int] = [86,93,40,36,52,21,70,10]
print("before ")
print(n)
modify(no: &n, k:n.count)
print("after")
print(n)
----------------------------output-------------------------------------------------
before
[86, 93, 40, 36, 52, 21, 70, 10]
after
[40, 36, 86, 93, 70, 10, 52

14. /*Write a function Large() with array and size as a parameter, which should
display the largest and second largest by returning both from an array.*/
func large(no:inout [Int],k:Int) -> ( Int , Int )
{
var x = 0 , l = no[0] , sec1 = no[0]
while x < k
{
if no[x] > l
{
sec1 = l
l = no[x]
}else if no[x] > sec1
{
sec1 = no[x]
}
x = x + 1
}
return (l , sec1)
}
var n:[Int] = [86,93,40,136,52,21,70,10]
var (k , s ) = large(no: &n, k:n.count)
print("Largest no = (k) and second large = (s)")
--------------------------------output------------------------------------
Largest no = 136 and second large = 93

15. /* Write a function addup() with array and size as a parameter,in which all even
position(0,2,4,…..) of the array should be added with the content of element in
the next position and odd position(1,3,5,…..) elements should be increment by 10
*/
func addup(no:inout [Int] , k:Int)
{
var x:Int = 0
while x < k
{
if no[x] % 2 == 0
{
no[x] = no[x] + no[x + 1]
}else
{
no[x] = no[x] + 10
}
x = x + 1
}
}
var n:[Int] = [23,30,45,10,15,25,45,10,56,78,33]
print("before ")
print(n)
addup(no: &n, k:n.count)
print("after")
print(n)
----------------------------output--------------------------------
before
[23, 30, 45, 10, 15, 25, 45, 10, 56, 78, 33]
after
[33, 75, 55, 25, 25, 35, 55, 66, 134, 111, 43]

16. /* Write a function twotoone() with array and size as an parameters,in
which accept two array X[] and Y[] and transfer all X[] numbers in even
places of Z[] and all Y[] numbers in odd places of Z[]. */
func twotoone(z:inout [Int] ,x:[Int] ,y:[Int] , k:Int)
{
var a:Int = 0 , b:Int = 0
var c:Int = 0
while c < k
{
if c % 2 == 0
{
z.insert(x[a],at:c)
a = a + 1
}else
{
z.insert(y[b],at:c)
b = b + 1
}
c = c + 1
}}
var Z:[Int] = []
var X:[Int] = [10,20,30,40,50]
var Y:[Int] = [11,12,13,14,15]
print("before array Z")
print(Z)
print("before array X")
print(X)
print("before array Y")
print(Y)
twotoone(z:&Z, x:X, y:Y, k:10)
print("after")
print(Z)
---------------output---------------------
before array Z
[]
before array X
[10, 20, 30, 40, 50]
before array Y
[11, 12, 13, 14, 15]
After array Z
[10, 11, 20, 12, 30, 13, 40, 14, 50,
15]

17. /* Write a function convert() with array and size as a parameter,which
reposition all the elements of the array by shifting each of them one to
one position before and by shifting the first elements to the last
position*/
func convert(no:inout [Int] ,k:Int ,size:Int)
{
var tmp:Int = 0
var last:Int = size - 1
var x:Int = 1
var y:Int = 0
while x <= k
{
tmp = no[0]
y = 0
while y < size - 1
{
no[y] = no[y + 1]
y = y + 1
}
no[last] = tmp
x = x + 1
}
}
var X:[Int] = [10,20,30,40,50,60,70,80]
print("before")
print(X)
convert(no: &X, k:2, size:X.count)
print("After")
print(X)
--------------------------------------output----------------------------------------
before
[10, 20, 30, 40, 50, 60, 70, 80]
After
[30, 40, 50, 60, 70, 80, 10, 20]

18. /*Write a function SWAP() with array and size as a parameter,which
swap the numbers on the basis of example given:
If array A no : 10,20,30,40,50,60 the output after swapping
20,10,40,30,60,50 */
func swap(no:inout [Int] ,size:Int)
{
var tmp:Int = 0
var y:Int = 0
while y < size - 1
{
tmp = no[y]
no[y] = no[y + 1]
no[y + 1] = tmp
y = y + 2
}
}
var X:[Int] = [10,20,30,40,50,60]
print("before")
print(X)
swap(no: &X, size:X.count)
print("After")
print(X)
------------------------------output---------------------------
before
[10, 20, 30, 40, 50, 60]
After
[20, 10, 40, 30, 60, 50]

19. /*Write a function SWAP2() with array and size as a parameter,which
swap the numbers on the basis of example given:
If array A no : 10,20,30,40,50,60 the output after swapping
40,50,60,10,20,30 */
func swap2(no:inout [Int] ,size:Int)
{
var tmp:Int = 0
var y:Int = 0
var x:Int = size / 2
while y < size / 2
{
tmp = no[y]
no[y] = no[x]
no[x] = tmp
y = y + 1
x = x + 1
}
}
var X:[Int] = [10,20,30,40,50,60]
print("before")
print(X)
swap(no: &X, size:X.count)
print("After")
print(X)
---------------------------output---------------------------
before
[10, 20, 30, 40, 50, 60]
After
[40, 50, 60, 10, 20, 30]

20. /* Write a function merge() with three array as a parameter array A,B,
and C with their size M , N , and M+N , where A is ascending order , B
is descending order and C accept numbers from A and B in ascending
order. */
func merge(A1:[Int],B1:[Int],C1:inout [Int], M:Int, N:Int)
{
var x = 0
var a = 0
var k = 0
// var y = ( M + N ) - 1
var y = N - 1
while x < M && y >= 0
{
if A1[x] <= B1[y]
{
C1.append(A1[x])
k = k + 1
x = x + 1
}else
{
C1.append(B1[y])
k = k + 1
y = y - 1
}
}
if x < M
{
a = x
while a < M
{
C1.append(A1[a])
a = a + 1
}
}
if y >= 0
{

21. a = y
while a >= 0
{
C1.append(B1[a])
a = a - 1
}
}
}
var A:[Int] = [1,2,3,4,5,6,9,10,12]
var B:[Int] = [9,8,7,5,3,2,1]
var C:[Int] = []
print("before A")
print(A)
print("b numbers")
print(B)
merge(A1: A,B1: B,C1: &C,M:A.count , N:B.count)
print("After")
print(C)
----------------------------------output--------------------------------------
before A
[1, 2, 3, 4, 5, 6, 9, 10, 12]
b numbers
[9, 8, 7, 5, 3, 2, 1]
After
[1, 1, 2, 2, 3, 3, 4, 5, 5, 6, 7, 8, 9, 9, 10, 12

22. /* Write a function dispTen() with 2D array A and size
as a parameter and display only those numbers which are
divisible by 10 */
func dispTen(n: [[Int]], size:Int)
{
var x = 0 , y = 0
while x < size
{
y = 0
while y < size
{
if n[x][y] % 10 == 0
{
print("(n[x][y]), ",terminator:"")
}
y = y + 1
}
x = x + 1
}
print("")
}
var no:[[Int]] = [[12,20,13],[2,10,30],[40,5,16]]
dispTen(n:no,size:no.count)
----------------------------output-----------------------------------
20, 10, 30, 40,

23. // Write a function rowsum() with 2D array A and size as
a parameter and display the sum of each row
func rowsum(n: [[Int]], size:Int)
{
var x = 0 , y = 0
var sum = 0
while x < size
{
y = 0
sum = 0
while y < size
{
sum = sum + n[x][y]
print("(n[x][y]) +",terminator:"")
y = y + 1
}
x = x + 1
print("=(sum)n",terminator:"")
}
print("")
}
var no:[[Int]] = [[12,20,13],[2,10,30],[40,5,16]]
rowsum(n:no,size:no.count)
----------------------output------------------------------
12 +20 +13 =45
2 +10 +30 =42
40 +5 +16 =61

24. // Write a function diagonalsum() with 2D array A and
size as a parameter and display the sum
func diagonalsum(A1:inout [[Int]] , k:Int) -> Int
{
var x:Int = 0 , y:Int = 0
var lsum = 0 , rsum = 0
while x < k
{
y = 0
while y < k
{
if x == y
{
lsum = lsum + A1[x][y]
}else if x + y == k - 1
{
rsum = rsum + A1[x][y]
}
y = y + 1
}
x = x + 1
}
return lsum + rsum
}
var A:[[Int]] = [[4,5,6],[7,8,9],[1,2,3]]
print("before array A")
print(A)
var rs = diagonalsum (A1:&A, k:A.count)
print(“sum of diagonal =(rs)”)
-----------------------------output--------------------------------
before array A
[[4, 5, 6], [7, 8, 9], [1, 2, 3]]
Sum of diagonal = 22

25. //program to find the largest no from a 1D array of 10 numbers
func largest(no:[Int], k:Int) -> Int
{
var large = no[0]
var x = 0
while x < k
{
if no[x] > large
{
large = no[x]
}
x = x + 1
}
return large
}
var n:[Int] = [51, 21, 30, 45, 75, 15, 2, 56, 120, 11 ]
var rs = largest(no:n, k:10)
print("largest no = (rs)")
------------------------output-------------------------------
Largest no = 120

26. /*Write a function swaparr() with 2D array A and size as
a parameter and swap or interchange the first row with
the last row elements.*/
func display(tmp:[[Int]], size:Int)
{
var x = 0 , y = 0
while x < size
{
y = 0
while y < size
{
print("(tmp[x][y]) , ",terminator:"")
y = y + 1
}
x = x + 1
print("n")
}
print("")
}
func swaparr (A1:inout [[Int]] , k:Int)
{
var a = 0 , last = k - 1
var t = 0
while a < k
{
t = A1[0][a]
A1[0][a] = A1[last][a]
A1[last][a] = t
a = a + 1
}
}
var A:[[Int]] = [[5,6,2,3],[1,2,4,9],[2,5,8,1],[9,7,5,8]]
print("before")
display(tmp:A,size:A.count)
swaparr(A1:&A,k:A.count)
print("after")
display(tmp:A,size:A.count)
-----------------------output--------------------------------------
before
5 , 6 , 2 , 3
1 , 2 , 4 , 9
2 , 5 , 8 , 1
9 , 7 , 5 , 8
after
9 , 7 , 5 , 8
1 , 2 , 4 , 9
2 , 5 , 8 , 1
5 , 6 , 2 , 3

27. /* Write a function lefttrg() with 2D array A and size as a parameter and
display lower triangle as the output given
Example: output
1 2 3 4
6 4 5 6 6
2 1 5 4 2 1
1 2 3 5 1 2 3 */
func display(tmp:[[Int]], size:Int)
{
var x = 0 , y = 0
while x < size
{
y = 0
while y < size
{
print("(tmp[x][y]) , ",terminator:"")
y = y + 1
}
x = x + 1
print("n")
}
print("")
}
func lfttrg(z:[[Int]] , k:Int)
{
var a = 0 , b = 0
var t = 0
while a < k
{
b = 0
while b < k
{
if a > b
{
print("(z[a][b]) , ",terminator:"")
}
b = b + 1
}

28. print("n",terminator:"")
a = a + 1
}
print("")
}
var A:[[Int]] = [[1,2,3,4],[6,4,5,6],[2,1,5,4],[1,2,3,5]]
print("before")
display(tmp:A,size:A.count)
print("lower triangle")
lfttrg(z:A,k:A.count)
-----------------------------output---------------------------
before
1 , 2 , 3 , 4
6 , 4 , 5 , 6
2 , 1 , 5 , 4
1 , 2 , 3 , 5
lower triangle
6
2 , 1
1 , 2 , 3

29. /* Write a function summatrix() with 2D array A , B , C and size as a parameter,
and display the sum of two matrix in C */
func display(tmp:[[Int]], size:Int)
{
var x = 0 , y = 0
while x < size
{
y = 0
while y < size
{
print("(tmp[x][y]) , ",terminator:"")
y = y + 1
}
x = x + 1
print("n")
}
print("")
}
func summat(A1:[[Int]], B1:[[Int]], C1:inout [[Int]], size:Int)
{
var x = 0 , y = 0
var sum = 0
while x < size
{
y = 0
while y < size
{
sum = A1[x][y] + B1[x][y]
C1[x][y] = sum
y = y + 1
}
x = x + 1
}
}
var A:[[Int]] = [[1,2,3],[1,2,3],[1,2,3]]
var B:[[Int]] = [[4,5,6],[4,5,6],[4,5,6]]
var C:[[Int]] = [[Int]](repeating:[Int] (repeating: 0, count: 3), count: 3)
print("Array A")
display(tmp:A,size:A.count)
print("Array B")
display(tmp:B,size:B.count)
summat(A1:A,B1:B,C1:&C,size:3)
print("Array C")
display(tmp:C,size:C.count)
--------------------output-----------------------
Array C
5 , 7 , 9 ,
5 , 7 , 9 ,
5 , 7 , 9 ,
---------------------output--------------------------
Array A
1 , 2 , 3 ,
1 , 2 , 3 ,
1 , 2 , 3 ,
Array B
4 , 5 , 6 ,
4 , 5 , 6 ,
4 , 5 , 6 ,

30. /* Write a function copyarr() with 2D array A and B as 1D array and size as a
parameter,display the output as given below:
Example: if array B values are 1,2,3,4,5
Array A store values as:
1,2,3,4,5
1,2,3,4,0
1,2,3,0,0
1,2,0,0,0
1,0,0,0,0
*/
func display(tmp:[[Int]], size:Int)
{
var x = 0 , y = 0
while x < size
{
y = 0
while y < size
{
print("(tmp[x][y]) , ",terminator:"")
y = y + 1
}
x = x + 1
print("n")
}
print("")
}
func copyarr(A1:inout [[Int]] , B1:[Int] , k:Int)
{
var x = 0 , y = 0
while x < k
{
y = 0
while y < k
{
if x + y < k
{
A1[x][y] = B1[y]

31. }else
{
A1[x][y] = 0
}
y = y + 1
}
x = x + 1
}
}
var B:[Int] = [10,20,30,40,50]
var A:[[Int]] = [[Int]](repeating:[Int] (repeating: 0, count: B.count), count: B.count)
print("before array B")
print(B)
copyarr(A1:&A, B1:B, k:B.count)
print("after array A")
display(tmp:A,size:A.count)
--------------------output--------------------------
before array B
[10, 20, 30, 40, 50]
After array A
10 20 30 40 50
10 20 30 40 0
10 20 30 0 0
10 20 0 0 0
10 0 0 0 0