SlideShare une entreprise Scribd logo
1  sur  20
Free Body Diagram
      It’s Really Easy
HI
  THERE! MY
                 I’M BILLY THE
NAME IS VINNIE
                      BOX!
 THE VECTOR!




                                    AND I’M TERRY THE
                                  TABLE. TOGETHER WE
                                 WILL TRY TO EXPLAIN THE
                                   FREE BODY DIAGRAM
I AM MADE OF
MATTER, THEREFORE I
    HAVE MASS




                        AND BECAUSE BILLY
                      HAS MASS, THE EARTH
                       PULLS HIM DOWN. WE
                         CALL THIS PULL
                             “WEIGHT”
I HAVE A
    MASS OF 1O
KILOGRAMS. EVERYONE
SAYS I HAVE A REALLY
    NICE MASS.

                         BECAUSE OF THE EARTH’S
                       GRAVITY, BILLY HAS WEIGHT.
                       THE WEIGHT IS A FORCE. EACH
                        KILOGRAM OF MASS HAS A
                         WEIGHT OF 9.8 NEWTONS.
                        BILLY WEIGHS 98 NEWTONS.
I WEIGH 98
NEWTONS!




           I             BECAUSE WEIGHT IS A
      REPRESENT        FORCE, WE USE VECTORS TO
   BILLY’S WEIGHT. I   SHOW THE FORCE. VECTORS
   AM 98 NEWTONS        HAVE 2 PARTS, SIZE AND
        DOWN.                  DIRECTION.
I WEIGH 98
                    NEWTONS!      NOW BILLY IS SITTING ON
                                  ME. I AM HOLDING UP HIS
                                  WEIGHT. I DO THIS WITH A
                                 FORCE OF MY OWN. I CALL IT
                                     A NORMAL FORCE.




        I
   REPRESENT
BILLY’S WEIGHT. I
AM 98 NEWTONS
     DOWN.
NOTICE THAT THE
                      NORMAL FORCE IS EXACTLY
        I             THE SAME SIZE AS BILLY’S
  REPRESENT THE       WEIGHT. NOTICE ALSO THAT
NORMAL FORCE. I AM      IT IS THE OPPOSITE IN
 98 NEWTONS UP.               DIRECTION.




                             IMPORTANT
                            THE TWO FORCES ARE
                             THE SAME SIZE AND
                                 IN OPPOSITE
                            DIRECTIONS. BECAUSE
          I                 OF THIS, THEY CANCEL
     REPRESENT
  BILLY’S WEIGHT. I          EACH OTHER. WHEN
  AM 98 NEWTONS             FORCES CANCEL EACH
       DOWN.
                               OTHER, THE NET
                            FORCE = 0 NEWTONS.
NOW WE WILL
WORK TOGETHER TO      IT’S REALLY
  SHOW SOME        EASY. TRUST ME, I’M
   EXAMPLES!              A BOX




                                         LET’S START WITH AN
                                              EASY ONE....
BILLY THE BOX IS PLACED ON A FLAT SURFACE. BILLY HAS A MASS
OF 5 KILOGRAMS. A FORCE OF 12 NEWTONS IS APPLIED TO BILLY
CAUSING HIM TO MOVE AT A CONSTANT SPEED TO THE RIGHT. DRAW
THE FREE BODY DIAGRAM.
                                    I GET PUSHED
                                       AROUND.


                                                      AND I HOLD
                       5 KG                        EVERYTHING UP...



  I WILL BE SHOWING
      THE FORCES.
BILLY THE BOX IS PLACED ON A FLAT SURFACE. BILLY HAS A MASS
   OF 5 KILOGRAMS. A FORCE OF 12 NEWTONS IS APPLIED TO BILLY
   CAUSING HIM TO MOVE AT A CONSTANT SPEED TO THE RIGHT. DRAW
   THE FREE BODY DIAGRAM.
                                 BECAUSE I
                            HAVE A MASS OF 5
                          KG, I HAVE A WEIGHT OF         BECAUSE
               5 KG             49 NEWTONS.        BILLY IS MOVING AT A
                                                   CONSTANT SPEED, THE
                                                     NET FORCE ON HIM
                                                      MUST BE ZERO.




         I AM A
VECTOR THAT HAS A SIZE
 OF 49 NEWTONS AND MY
   DIRECTION IS DOWN
BILLY THE BOX IS PLACED ON A FLAT SURFACE. BILLY HAS A MASS
OF 5 KILOGRAMS. A FORCE OF 12 NEWTONS IS APPLIED TO BILLY
CAUSING HIM TO MOVE AT A CONSTANT SPEED TO THE RIGHT. DRAW
THE FREE BODY DIAGRAM.




                                FIRST, WE PLACE BILLY
                               ON ME. I AM NOW FEELING
                                 BILLY’S WEIGHT OF 49
                                      NEWTONS.

             5 KG




      49 NEWTONS DOWN
BILLY THE BOX IS PLACED ON A FLAT SURFACE. BILLY HAS A MASS
OF 5 KILOGRAMS. A FORCE OF 12 NEWTONS IS APPLIED TO BILLY
CAUSING HIM TO MOVE AT A CONSTANT SPEED TO THE RIGHT. DRAW
THE FREE BODY DIAGRAM.

        49 NEWTONS UP


                                 NEXT, IN ORDER TO
                               HOLD BILLY UP, I APPLY A
                               NORMAL FORCE. IT IS THE
                                SAME SIZE AS BILLY’S
                                      WEIGHT.

             5 KG




      49 NEWTONS DOWN
BILLY THE BOX IS PLACED ON A FLAT SURFACE. BILLY HAS A MASS
   OF 5 KILOGRAMS. A FORCE OF 12 NEWTONS IS APPLIED TO BILLY
   CAUSING HIM TO MOVE AT A CONSTANT SPEED TO THE RIGHT. DRAW
   THE FREE BODY DIAGRAM.

             49 NEWTONS UP
                                   NOW WE APPLY THE 12
                                 NEWTON FORCE PUSHING
                                  BILLY TO THE RIGHT. THE
                                 DIRECTION OF THE ARROW
12 NEWTONS                        IS THE THE DIRECTION OF
                                        THE FORCE.
    RIGHT
                 5 KG




         49 NEWTONS DOWN
BILLY THE BOX IS PLACED ON A FLAT SURFACE. BILLY HAS A MASS
   OF 5 KILOGRAMS. A FORCE OF 12 NEWTONS IS APPLIED TO BILLY
   CAUSING HIM TO MOVE AT A CONSTANT SPEED TO THE RIGHT. DRAW
   THE FREE BODY DIAGRAM.

             49 NEWTONS UP                 THIS IS
                                   IMPORTANT! BECAUSE
                                     BILLY MOVING AT A
                                 CONSTANT SPEED, THE NET
                                  FORCE ON HIM MUST BE
                                    ZERO. THEREFORE,
12 NEWTONS                           SOMETHING MUST
                                   BALANCE THE APPLIED
    RIGHT                                  FORCE.
                 5 KG




         49 NEWTONS DOWN
BILLY THE BOX IS PLACED ON A FLAT SURFACE. BILLY HAS A MASS
   OF 5 KILOGRAMS. A FORCE OF 12 NEWTONS IS APPLIED TO BILLY
   CAUSING HIM TO MOVE AT A CONSTANT SPEED TO THE RIGHT. DRAW
   THE FREE BODY DIAGRAM.

             49 NEWTONS UP
                                            THAT FORCE IS
                                        FRICTION. IT WORKS IN
                                       THE OPPOSITE DIRECTION
                                        THAT BILLY IS MOVING.
                                      BECAUSE HE IS MOVING AT A
12 NEWTONS                              CONSTANT SPEED, THE
                        12 NEWTONS    FRICTION IS THE SAME SIZE
    RIGHT                   LEFT        AS THE APPLIED FORCE.
                 5 KG




         49 NEWTONS DOWN
BILLY THE BOX IS PLACED ON A FLAT SURFACE. BILLY HAS A MASS
   OF 5 KILOGRAMS. A FORCE OF 12 NEWTONS IS APPLIED TO BILLY
   CAUSING HIM TO MOVE AT A CONSTANT SPEED TO THE RIGHT. DRAW
   THE FREE BODY DIAGRAM.

             49 NEWTONS UP

                                         BECAUSE ALL OF THE
                                        FORCES ON BILLY ARE
                                      BALANCED, THE NET FORCE
                                        IS ZERO AND HE IS AT
12 NEWTONS              12 NEWTONS     EQUILIBRIUM. LET’S TRY
    RIGHT                                    ANOTHER...
                            LEFT
                 5 KG




         49 NEWTONS DOWN
BILLY THE BOX IS PLACED ON A FLAT SURFACE. BILLY HAS A MASS
   OF 5 KILOGRAMS. A FORCE OF 12 NEWTONS IS APPLIED TO BILLY
   CAUSING HIM TO ACCELERATE TO THE RIGHT. IF THE NET FORCE ON
   BILLY IS 10 NEWTONS RIGHT, DRAW THE FREE BODY DIAGRAM.

             49 NEWTONS UP


                                        BILLY STILL WEIGHS THE
                                       SAME, SO THE WEIGHT AND
                                       NORMAL FORCES ARE THE
12 NEWTONS               ? NEWTONS     SAME. WHAT’S DIFFERENT?
    RIGHT                    LEFT
                 5 KG




         49 NEWTONS DOWN
BILLY THE BOX IS PLACED ON A FLAT SURFACE. BILLY HAS A MASS
   OF 5 KILOGRAMS. A FORCE OF 12 NEWTONS IS APPLIED TO BILLY
   CAUSING HIM TO ACCELERATE TO THE RIGHT. IF THE NET FORCE ON
   BILLY IS 10 NEWTONS RIGHT, DRAW THE FREE BODY DIAGRAM.

             49 NEWTONS UP
                                           BECAUSE BILLY IS
                                        ACCELERATING, THE NET
                                       FORCE ON HIM CANNOT BE
                                          ZERO. THE FORCE OF
                                      FRICTION MUST BE SMALLER
12 NEWTONS               ? NEWTONS     THAN THE APPLIED FORCE.
    RIGHT                    LEFT        HOW MUCH SMALLER?
                 5 KG




         49 NEWTONS DOWN
BILLY THE BOX IS PLACED ON A FLAT SURFACE. BILLY HAS A MASS
   OF 5 KILOGRAMS. A FORCE OF 12 NEWTONS IS APPLIED TO BILLY
   CAUSING HIM TO ACCELERATE TO THE RIGHT. IF THE NET FORCE ON
   BILLY IS 10 NEWTONS RIGHT, DRAW THE FREE BODY DIAGRAM.

             49 NEWTONS UP
                                         IF WE ARE APPLYING A
                                      12 NEWTON FORCE TO BILLY
                                       AND YET THE NET FORCE IS
                                      ONLY 10 NEWTONS, THERE IS
                                           A DIFFERENCE OF 2
12 NEWTONS               ? NEWTONS          NEWTONS. THIS
    RIGHT                    LEFT      DIFFERENCE COMES FROM
                 5 KG                           FRICTION.




         49 NEWTONS DOWN
BILLY THE BOX IS PLACED ON A FLAT SURFACE. BILLY HAS A MASS
   OF 5 KILOGRAMS. A FORCE OF 12 NEWTONS IS APPLIED TO BILLY
   CAUSING HIM TO ACCELERATE TO THE RIGHT. IF THE NET FORCE ON
   BILLY IS 10 NEWTONS RIGHT, DRAW THE FREE BODY DIAGRAM.

             49 NEWTONS UP

                                       IN ORDER FOR ALL THIS TO
                                          WORK, THE FORCE OF
                                          FRICTION MUST BE 2
                                         NEWTONS TO THE LEFT.
12 NEWTONS               2 NEWTONS         HOPE THIS HELPS.
    RIGHT                    LEFT
                 5 KG




         49 NEWTONS DOWN

Contenu connexe

Tendances

Equations of motion
Equations of motionEquations of motion
Equations of motionLily Kotze
 
Physics-CIRCULAR MOTION
Physics-CIRCULAR MOTIONPhysics-CIRCULAR MOTION
Physics-CIRCULAR MOTIONvasudha7
 
Force,moment of a force and couple
Force,moment of a force and coupleForce,moment of a force and couple
Force,moment of a force and coupleRajeshPV12
 
Kinematics - The Study of Motion
Kinematics - The Study of MotionKinematics - The Study of Motion
Kinematics - The Study of Motionwalt sautter
 
6.2 newtons law of gravitation
6.2 newtons law of gravitation6.2 newtons law of gravitation
6.2 newtons law of gravitationPaula Mills
 
Projectile motion
Projectile motionProjectile motion
Projectile motionnlahoud
 
Newton’s laws and application of newton’s laws
Newton’s laws and application of newton’s lawsNewton’s laws and application of newton’s laws
Newton’s laws and application of newton’s lawsBlagoslov
 
System Of Particles And Rotational Motion
System Of Particles And Rotational MotionSystem Of Particles And Rotational Motion
System Of Particles And Rotational MotionAkrita Kaur
 
Projectile
ProjectileProjectile
ProjectileAnjani
 
Turning Effect of Forces
Turning Effect of ForcesTurning Effect of Forces
Turning Effect of Forcesmeenng
 

Tendances (20)

Center of mass
Center of massCenter of mass
Center of mass
 
Projectile motion
Projectile motionProjectile motion
Projectile motion
 
Equations of motion
Equations of motionEquations of motion
Equations of motion
 
Scalars and Vectors
Scalars and VectorsScalars and Vectors
Scalars and Vectors
 
Physics-CIRCULAR MOTION
Physics-CIRCULAR MOTIONPhysics-CIRCULAR MOTION
Physics-CIRCULAR MOTION
 
Free body diagram
Free body diagramFree body diagram
Free body diagram
 
Unit 5 rigid body dynamics
Unit 5 rigid body dynamicsUnit 5 rigid body dynamics
Unit 5 rigid body dynamics
 
Force,moment of a force and couple
Force,moment of a force and coupleForce,moment of a force and couple
Force,moment of a force and couple
 
Kinematics - The Study of Motion
Kinematics - The Study of MotionKinematics - The Study of Motion
Kinematics - The Study of Motion
 
Kinematics(class)
Kinematics(class)Kinematics(class)
Kinematics(class)
 
Kinematics 2012
Kinematics 2012Kinematics 2012
Kinematics 2012
 
6.2 newtons law of gravitation
6.2 newtons law of gravitation6.2 newtons law of gravitation
6.2 newtons law of gravitation
 
Projectile motion
Projectile motionProjectile motion
Projectile motion
 
Newton’s laws and application of newton’s laws
Newton’s laws and application of newton’s lawsNewton’s laws and application of newton’s laws
Newton’s laws and application of newton’s laws
 
System Of Particles And Rotational Motion
System Of Particles And Rotational MotionSystem Of Particles And Rotational Motion
System Of Particles And Rotational Motion
 
Projectile
ProjectileProjectile
Projectile
 
ROTATIONAL KINEMATICS
ROTATIONAL KINEMATICSROTATIONAL KINEMATICS
ROTATIONAL KINEMATICS
 
Projectile motion
Projectile motionProjectile motion
Projectile motion
 
Turning Effect of Forces
Turning Effect of ForcesTurning Effect of Forces
Turning Effect of Forces
 
Rotational motion
Rotational motionRotational motion
Rotational motion
 

Plus de Loyal Perry

Plus de Loyal Perry (9)

Bonding Basics 2
Bonding Basics 2Bonding Basics 2
Bonding Basics 2
 
Bonding Basics
Bonding BasicsBonding Basics
Bonding Basics
 
Molecules and Compounds
Molecules and CompoundsMolecules and Compounds
Molecules and Compounds
 
Chapter 6.1
Chapter 6.1Chapter 6.1
Chapter 6.1
 
Chapter 5.1
Chapter 5.1Chapter 5.1
Chapter 5.1
 
Chapter 5.1 Review
Chapter 5.1 ReviewChapter 5.1 Review
Chapter 5.1 Review
 
Atoms
AtomsAtoms
Atoms
 
G Tthe Atom
G Tthe AtomG Tthe Atom
G Tthe Atom
 
Element Connections V1.1
Element Connections V1.1Element Connections V1.1
Element Connections V1.1
 

Dernier

PSYCHIATRIC History collection FORMAT.pptx
PSYCHIATRIC   History collection FORMAT.pptxPSYCHIATRIC   History collection FORMAT.pptx
PSYCHIATRIC History collection FORMAT.pptxPoojaSen20
 
Software Engineering Methodologies (overview)
Software Engineering Methodologies (overview)Software Engineering Methodologies (overview)
Software Engineering Methodologies (overview)eniolaolutunde
 
Call Girls in Dwarka Mor Delhi Contact Us 9654467111
Call Girls in Dwarka Mor Delhi Contact Us 9654467111Call Girls in Dwarka Mor Delhi Contact Us 9654467111
Call Girls in Dwarka Mor Delhi Contact Us 9654467111Sapana Sha
 
Introduction to AI in Higher Education_draft.pptx
Introduction to AI in Higher Education_draft.pptxIntroduction to AI in Higher Education_draft.pptx
Introduction to AI in Higher Education_draft.pptxpboyjonauth
 
BASLIQ CURRENT LOOKBOOK LOOKBOOK(1) (1).pdf
BASLIQ CURRENT LOOKBOOK  LOOKBOOK(1) (1).pdfBASLIQ CURRENT LOOKBOOK  LOOKBOOK(1) (1).pdf
BASLIQ CURRENT LOOKBOOK LOOKBOOK(1) (1).pdfSoniaTolstoy
 
Paris 2024 Olympic Geographies - an activity
Paris 2024 Olympic Geographies - an activityParis 2024 Olympic Geographies - an activity
Paris 2024 Olympic Geographies - an activityGeoBlogs
 
Mastering the Unannounced Regulatory Inspection
Mastering the Unannounced Regulatory InspectionMastering the Unannounced Regulatory Inspection
Mastering the Unannounced Regulatory InspectionSafetyChain Software
 
Micromeritics - Fundamental and Derived Properties of Powders
Micromeritics - Fundamental and Derived Properties of PowdersMicromeritics - Fundamental and Derived Properties of Powders
Micromeritics - Fundamental and Derived Properties of PowdersChitralekhaTherkar
 
Alper Gobel In Media Res Media Component
Alper Gobel In Media Res Media ComponentAlper Gobel In Media Res Media Component
Alper Gobel In Media Res Media ComponentInMediaRes1
 
Organic Name Reactions for the students and aspirants of Chemistry12th.pptx
Organic Name Reactions  for the students and aspirants of Chemistry12th.pptxOrganic Name Reactions  for the students and aspirants of Chemistry12th.pptx
Organic Name Reactions for the students and aspirants of Chemistry12th.pptxVS Mahajan Coaching Centre
 
mini mental status format.docx
mini    mental       status     format.docxmini    mental       status     format.docx
mini mental status format.docxPoojaSen20
 
CARE OF CHILD IN INCUBATOR..........pptx
CARE OF CHILD IN INCUBATOR..........pptxCARE OF CHILD IN INCUBATOR..........pptx
CARE OF CHILD IN INCUBATOR..........pptxGaneshChakor2
 
Presiding Officer Training module 2024 lok sabha elections
Presiding Officer Training module 2024 lok sabha electionsPresiding Officer Training module 2024 lok sabha elections
Presiding Officer Training module 2024 lok sabha electionsanshu789521
 
POINT- BIOCHEMISTRY SEM 2 ENZYMES UNIT 5.pptx
POINT- BIOCHEMISTRY SEM 2 ENZYMES UNIT 5.pptxPOINT- BIOCHEMISTRY SEM 2 ENZYMES UNIT 5.pptx
POINT- BIOCHEMISTRY SEM 2 ENZYMES UNIT 5.pptxSayali Powar
 
A Critique of the Proposed National Education Policy Reform
A Critique of the Proposed National Education Policy ReformA Critique of the Proposed National Education Policy Reform
A Critique of the Proposed National Education Policy ReformChameera Dedduwage
 
Grant Readiness 101 TechSoup and Remy Consulting
Grant Readiness 101 TechSoup and Remy ConsultingGrant Readiness 101 TechSoup and Remy Consulting
Grant Readiness 101 TechSoup and Remy ConsultingTechSoup
 
Arihant handbook biology for class 11 .pdf
Arihant handbook biology for class 11 .pdfArihant handbook biology for class 11 .pdf
Arihant handbook biology for class 11 .pdfchloefrazer622
 
Introduction to ArtificiaI Intelligence in Higher Education
Introduction to ArtificiaI Intelligence in Higher EducationIntroduction to ArtificiaI Intelligence in Higher Education
Introduction to ArtificiaI Intelligence in Higher Educationpboyjonauth
 

Dernier (20)

PSYCHIATRIC History collection FORMAT.pptx
PSYCHIATRIC   History collection FORMAT.pptxPSYCHIATRIC   History collection FORMAT.pptx
PSYCHIATRIC History collection FORMAT.pptx
 
Software Engineering Methodologies (overview)
Software Engineering Methodologies (overview)Software Engineering Methodologies (overview)
Software Engineering Methodologies (overview)
 
Call Girls in Dwarka Mor Delhi Contact Us 9654467111
Call Girls in Dwarka Mor Delhi Contact Us 9654467111Call Girls in Dwarka Mor Delhi Contact Us 9654467111
Call Girls in Dwarka Mor Delhi Contact Us 9654467111
 
Introduction to AI in Higher Education_draft.pptx
Introduction to AI in Higher Education_draft.pptxIntroduction to AI in Higher Education_draft.pptx
Introduction to AI in Higher Education_draft.pptx
 
BASLIQ CURRENT LOOKBOOK LOOKBOOK(1) (1).pdf
BASLIQ CURRENT LOOKBOOK  LOOKBOOK(1) (1).pdfBASLIQ CURRENT LOOKBOOK  LOOKBOOK(1) (1).pdf
BASLIQ CURRENT LOOKBOOK LOOKBOOK(1) (1).pdf
 
Paris 2024 Olympic Geographies - an activity
Paris 2024 Olympic Geographies - an activityParis 2024 Olympic Geographies - an activity
Paris 2024 Olympic Geographies - an activity
 
Mastering the Unannounced Regulatory Inspection
Mastering the Unannounced Regulatory InspectionMastering the Unannounced Regulatory Inspection
Mastering the Unannounced Regulatory Inspection
 
Model Call Girl in Tilak Nagar Delhi reach out to us at 🔝9953056974🔝
Model Call Girl in Tilak Nagar Delhi reach out to us at 🔝9953056974🔝Model Call Girl in Tilak Nagar Delhi reach out to us at 🔝9953056974🔝
Model Call Girl in Tilak Nagar Delhi reach out to us at 🔝9953056974🔝
 
TataKelola dan KamSiber Kecerdasan Buatan v022.pdf
TataKelola dan KamSiber Kecerdasan Buatan v022.pdfTataKelola dan KamSiber Kecerdasan Buatan v022.pdf
TataKelola dan KamSiber Kecerdasan Buatan v022.pdf
 
Micromeritics - Fundamental and Derived Properties of Powders
Micromeritics - Fundamental and Derived Properties of PowdersMicromeritics - Fundamental and Derived Properties of Powders
Micromeritics - Fundamental and Derived Properties of Powders
 
Alper Gobel In Media Res Media Component
Alper Gobel In Media Res Media ComponentAlper Gobel In Media Res Media Component
Alper Gobel In Media Res Media Component
 
Organic Name Reactions for the students and aspirants of Chemistry12th.pptx
Organic Name Reactions  for the students and aspirants of Chemistry12th.pptxOrganic Name Reactions  for the students and aspirants of Chemistry12th.pptx
Organic Name Reactions for the students and aspirants of Chemistry12th.pptx
 
mini mental status format.docx
mini    mental       status     format.docxmini    mental       status     format.docx
mini mental status format.docx
 
CARE OF CHILD IN INCUBATOR..........pptx
CARE OF CHILD IN INCUBATOR..........pptxCARE OF CHILD IN INCUBATOR..........pptx
CARE OF CHILD IN INCUBATOR..........pptx
 
Presiding Officer Training module 2024 lok sabha elections
Presiding Officer Training module 2024 lok sabha electionsPresiding Officer Training module 2024 lok sabha elections
Presiding Officer Training module 2024 lok sabha elections
 
POINT- BIOCHEMISTRY SEM 2 ENZYMES UNIT 5.pptx
POINT- BIOCHEMISTRY SEM 2 ENZYMES UNIT 5.pptxPOINT- BIOCHEMISTRY SEM 2 ENZYMES UNIT 5.pptx
POINT- BIOCHEMISTRY SEM 2 ENZYMES UNIT 5.pptx
 
A Critique of the Proposed National Education Policy Reform
A Critique of the Proposed National Education Policy ReformA Critique of the Proposed National Education Policy Reform
A Critique of the Proposed National Education Policy Reform
 
Grant Readiness 101 TechSoup and Remy Consulting
Grant Readiness 101 TechSoup and Remy ConsultingGrant Readiness 101 TechSoup and Remy Consulting
Grant Readiness 101 TechSoup and Remy Consulting
 
Arihant handbook biology for class 11 .pdf
Arihant handbook biology for class 11 .pdfArihant handbook biology for class 11 .pdf
Arihant handbook biology for class 11 .pdf
 
Introduction to ArtificiaI Intelligence in Higher Education
Introduction to ArtificiaI Intelligence in Higher EducationIntroduction to ArtificiaI Intelligence in Higher Education
Introduction to ArtificiaI Intelligence in Higher Education
 

Free Body Diagram

  • 1. Free Body Diagram It’s Really Easy
  • 2. HI THERE! MY I’M BILLY THE NAME IS VINNIE BOX! THE VECTOR! AND I’M TERRY THE TABLE. TOGETHER WE WILL TRY TO EXPLAIN THE FREE BODY DIAGRAM
  • 3. I AM MADE OF MATTER, THEREFORE I HAVE MASS AND BECAUSE BILLY HAS MASS, THE EARTH PULLS HIM DOWN. WE CALL THIS PULL “WEIGHT”
  • 4. I HAVE A MASS OF 1O KILOGRAMS. EVERYONE SAYS I HAVE A REALLY NICE MASS. BECAUSE OF THE EARTH’S GRAVITY, BILLY HAS WEIGHT. THE WEIGHT IS A FORCE. EACH KILOGRAM OF MASS HAS A WEIGHT OF 9.8 NEWTONS. BILLY WEIGHS 98 NEWTONS.
  • 5. I WEIGH 98 NEWTONS! I BECAUSE WEIGHT IS A REPRESENT FORCE, WE USE VECTORS TO BILLY’S WEIGHT. I SHOW THE FORCE. VECTORS AM 98 NEWTONS HAVE 2 PARTS, SIZE AND DOWN. DIRECTION.
  • 6. I WEIGH 98 NEWTONS! NOW BILLY IS SITTING ON ME. I AM HOLDING UP HIS WEIGHT. I DO THIS WITH A FORCE OF MY OWN. I CALL IT A NORMAL FORCE. I REPRESENT BILLY’S WEIGHT. I AM 98 NEWTONS DOWN.
  • 7. NOTICE THAT THE NORMAL FORCE IS EXACTLY I THE SAME SIZE AS BILLY’S REPRESENT THE WEIGHT. NOTICE ALSO THAT NORMAL FORCE. I AM IT IS THE OPPOSITE IN 98 NEWTONS UP. DIRECTION. IMPORTANT THE TWO FORCES ARE THE SAME SIZE AND IN OPPOSITE DIRECTIONS. BECAUSE I OF THIS, THEY CANCEL REPRESENT BILLY’S WEIGHT. I EACH OTHER. WHEN AM 98 NEWTONS FORCES CANCEL EACH DOWN. OTHER, THE NET FORCE = 0 NEWTONS.
  • 8. NOW WE WILL WORK TOGETHER TO IT’S REALLY SHOW SOME EASY. TRUST ME, I’M EXAMPLES! A BOX LET’S START WITH AN EASY ONE....
  • 9. BILLY THE BOX IS PLACED ON A FLAT SURFACE. BILLY HAS A MASS OF 5 KILOGRAMS. A FORCE OF 12 NEWTONS IS APPLIED TO BILLY CAUSING HIM TO MOVE AT A CONSTANT SPEED TO THE RIGHT. DRAW THE FREE BODY DIAGRAM. I GET PUSHED AROUND. AND I HOLD 5 KG EVERYTHING UP... I WILL BE SHOWING THE FORCES.
  • 10. BILLY THE BOX IS PLACED ON A FLAT SURFACE. BILLY HAS A MASS OF 5 KILOGRAMS. A FORCE OF 12 NEWTONS IS APPLIED TO BILLY CAUSING HIM TO MOVE AT A CONSTANT SPEED TO THE RIGHT. DRAW THE FREE BODY DIAGRAM. BECAUSE I HAVE A MASS OF 5 KG, I HAVE A WEIGHT OF BECAUSE 5 KG 49 NEWTONS. BILLY IS MOVING AT A CONSTANT SPEED, THE NET FORCE ON HIM MUST BE ZERO. I AM A VECTOR THAT HAS A SIZE OF 49 NEWTONS AND MY DIRECTION IS DOWN
  • 11. BILLY THE BOX IS PLACED ON A FLAT SURFACE. BILLY HAS A MASS OF 5 KILOGRAMS. A FORCE OF 12 NEWTONS IS APPLIED TO BILLY CAUSING HIM TO MOVE AT A CONSTANT SPEED TO THE RIGHT. DRAW THE FREE BODY DIAGRAM. FIRST, WE PLACE BILLY ON ME. I AM NOW FEELING BILLY’S WEIGHT OF 49 NEWTONS. 5 KG 49 NEWTONS DOWN
  • 12. BILLY THE BOX IS PLACED ON A FLAT SURFACE. BILLY HAS A MASS OF 5 KILOGRAMS. A FORCE OF 12 NEWTONS IS APPLIED TO BILLY CAUSING HIM TO MOVE AT A CONSTANT SPEED TO THE RIGHT. DRAW THE FREE BODY DIAGRAM. 49 NEWTONS UP NEXT, IN ORDER TO HOLD BILLY UP, I APPLY A NORMAL FORCE. IT IS THE SAME SIZE AS BILLY’S WEIGHT. 5 KG 49 NEWTONS DOWN
  • 13. BILLY THE BOX IS PLACED ON A FLAT SURFACE. BILLY HAS A MASS OF 5 KILOGRAMS. A FORCE OF 12 NEWTONS IS APPLIED TO BILLY CAUSING HIM TO MOVE AT A CONSTANT SPEED TO THE RIGHT. DRAW THE FREE BODY DIAGRAM. 49 NEWTONS UP NOW WE APPLY THE 12 NEWTON FORCE PUSHING BILLY TO THE RIGHT. THE DIRECTION OF THE ARROW 12 NEWTONS IS THE THE DIRECTION OF THE FORCE. RIGHT 5 KG 49 NEWTONS DOWN
  • 14. BILLY THE BOX IS PLACED ON A FLAT SURFACE. BILLY HAS A MASS OF 5 KILOGRAMS. A FORCE OF 12 NEWTONS IS APPLIED TO BILLY CAUSING HIM TO MOVE AT A CONSTANT SPEED TO THE RIGHT. DRAW THE FREE BODY DIAGRAM. 49 NEWTONS UP THIS IS IMPORTANT! BECAUSE BILLY MOVING AT A CONSTANT SPEED, THE NET FORCE ON HIM MUST BE ZERO. THEREFORE, 12 NEWTONS SOMETHING MUST BALANCE THE APPLIED RIGHT FORCE. 5 KG 49 NEWTONS DOWN
  • 15. BILLY THE BOX IS PLACED ON A FLAT SURFACE. BILLY HAS A MASS OF 5 KILOGRAMS. A FORCE OF 12 NEWTONS IS APPLIED TO BILLY CAUSING HIM TO MOVE AT A CONSTANT SPEED TO THE RIGHT. DRAW THE FREE BODY DIAGRAM. 49 NEWTONS UP THAT FORCE IS FRICTION. IT WORKS IN THE OPPOSITE DIRECTION THAT BILLY IS MOVING. BECAUSE HE IS MOVING AT A 12 NEWTONS CONSTANT SPEED, THE 12 NEWTONS FRICTION IS THE SAME SIZE RIGHT LEFT AS THE APPLIED FORCE. 5 KG 49 NEWTONS DOWN
  • 16. BILLY THE BOX IS PLACED ON A FLAT SURFACE. BILLY HAS A MASS OF 5 KILOGRAMS. A FORCE OF 12 NEWTONS IS APPLIED TO BILLY CAUSING HIM TO MOVE AT A CONSTANT SPEED TO THE RIGHT. DRAW THE FREE BODY DIAGRAM. 49 NEWTONS UP BECAUSE ALL OF THE FORCES ON BILLY ARE BALANCED, THE NET FORCE IS ZERO AND HE IS AT 12 NEWTONS 12 NEWTONS EQUILIBRIUM. LET’S TRY RIGHT ANOTHER... LEFT 5 KG 49 NEWTONS DOWN
  • 17. BILLY THE BOX IS PLACED ON A FLAT SURFACE. BILLY HAS A MASS OF 5 KILOGRAMS. A FORCE OF 12 NEWTONS IS APPLIED TO BILLY CAUSING HIM TO ACCELERATE TO THE RIGHT. IF THE NET FORCE ON BILLY IS 10 NEWTONS RIGHT, DRAW THE FREE BODY DIAGRAM. 49 NEWTONS UP BILLY STILL WEIGHS THE SAME, SO THE WEIGHT AND NORMAL FORCES ARE THE 12 NEWTONS ? NEWTONS SAME. WHAT’S DIFFERENT? RIGHT LEFT 5 KG 49 NEWTONS DOWN
  • 18. BILLY THE BOX IS PLACED ON A FLAT SURFACE. BILLY HAS A MASS OF 5 KILOGRAMS. A FORCE OF 12 NEWTONS IS APPLIED TO BILLY CAUSING HIM TO ACCELERATE TO THE RIGHT. IF THE NET FORCE ON BILLY IS 10 NEWTONS RIGHT, DRAW THE FREE BODY DIAGRAM. 49 NEWTONS UP BECAUSE BILLY IS ACCELERATING, THE NET FORCE ON HIM CANNOT BE ZERO. THE FORCE OF FRICTION MUST BE SMALLER 12 NEWTONS ? NEWTONS THAN THE APPLIED FORCE. RIGHT LEFT HOW MUCH SMALLER? 5 KG 49 NEWTONS DOWN
  • 19. BILLY THE BOX IS PLACED ON A FLAT SURFACE. BILLY HAS A MASS OF 5 KILOGRAMS. A FORCE OF 12 NEWTONS IS APPLIED TO BILLY CAUSING HIM TO ACCELERATE TO THE RIGHT. IF THE NET FORCE ON BILLY IS 10 NEWTONS RIGHT, DRAW THE FREE BODY DIAGRAM. 49 NEWTONS UP IF WE ARE APPLYING A 12 NEWTON FORCE TO BILLY AND YET THE NET FORCE IS ONLY 10 NEWTONS, THERE IS A DIFFERENCE OF 2 12 NEWTONS ? NEWTONS NEWTONS. THIS RIGHT LEFT DIFFERENCE COMES FROM 5 KG FRICTION. 49 NEWTONS DOWN
  • 20. BILLY THE BOX IS PLACED ON A FLAT SURFACE. BILLY HAS A MASS OF 5 KILOGRAMS. A FORCE OF 12 NEWTONS IS APPLIED TO BILLY CAUSING HIM TO ACCELERATE TO THE RIGHT. IF THE NET FORCE ON BILLY IS 10 NEWTONS RIGHT, DRAW THE FREE BODY DIAGRAM. 49 NEWTONS UP IN ORDER FOR ALL THIS TO WORK, THE FORCE OF FRICTION MUST BE 2 NEWTONS TO THE LEFT. 12 NEWTONS 2 NEWTONS HOPE THIS HELPS. RIGHT LEFT 5 KG 49 NEWTONS DOWN

Notes de l'éditeur