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the  strength  of common materials is actually dictated not so much by  bond  strength but by something else:  Defects
Griffith’s equation for the strength of materials ,[object Object],[object Object],[object Object],a = length of defect    = surface energy
NANOSCALE Vs MICROSCALE   Griffith’s experiments with glass fibers (1921) FIBER DIAMETER (micron) Strength of bulk glass: 170 MPa   Extrapolates to  11 GPa 1 2 3 TENSILE STRENGTH (GPa) 0 20 40 60 80 100 120 0
Materials’ strength is critically sensitive to defects   ,[object Object],[object Object],[object Object],[object Object],[object Object], 0  
INGLIS, 1913
A If x = a (point A), then   YYlocal  = 3  0   If the local stress reaches the theoretical strength, then the applied stress (  0 ) at failure is   0  =   th /3 And assuming   th  ≈ E/10, we get, at failure:  0     E/30 A more realistic situation is that of a sharper crack:  0  0
[object Object],[object Object],[object Object],[object Object], 0 A   a So again, if  , and  a = 1 micron , and  r = 20 Å , then at fracture And thus:   0     E/460
Therefore, defects are indeed  a major source of material weakness ,[object Object],[object Object],[object Object],[object Object]
The strength of fibers is statistical
Probabilistic argument ,[object Object],[object Object],[object Object],[object Object]
Probability of occurrence of a critical defect (F(V)= Probability of  failure) against size for a given defect concentration   At very small volume, low P of occurrence of a critical defect – Thus:  strength tends to be very high   At larger volume, F(V) climbs rapidly: A plateau is reached where size has no more effect.
However : no real physics in the previous equation.  How do we draw stress into the picture?   ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Density function: As    increases, the distribution is more narrow, and    is proportional to the average of the distribution
The effect of size on strength: The ‘Weakest-Link’ model for a fiber ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Last topics in the ‘Basic Concepts’ Section ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Stress (ctd) ,[object Object],[object Object]
[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Strain ,[object Object],[object Object],[object Object]
[object Object],[object Object]
[object Object],[object Object],[object Object],[object Object],[object Object]
By definition, the (Helmholtz) free energy of the body is   = E-TS  Thus: So that for an  isothermal  deformation process (T = constant), we have: Therefore, we need to know the free energy per unit volume,   , as a function of   ik
This is easily calculated: since we have small deformations,   can be expanded in a Taylor series: where   0  is the free energy of the  undeformed  body, and the   ’s are given as follows:
By differentiating, we obtain: And we know that this is equal to   ik  (for an isothermal process). If there is no deformation, there are no internal stresses in the body, thus   ik  = 0 for   ik  = o, from which we obtain    = 0. Thus, no linear term in the expansion of    in powers of   ik : by limiting the expansion to the second order:    ~   2
And we can therefore compute the stress tensor in terms of the strain tensor: or This very simple expression provides a linear dependence between stress and strain: it is the basic form of Hooke’s law ! Also, remember the connection between Young’s modulus and the potential from the previous class?
A common general form (valid for anisotropic bodies) of Hooke’s law is the following: Where   ij  and   kl  are 2d rank tensors and C ijkl  is a 4 th  rank tensor with 3x3x3x3 = 81 components [or 9 stress components x 9 strain components = 81].  The C ijkl  are called the elastic constants. Historical parenthesis: Robert Hooke’s legacy
Elementary concepts of mechanics ,[object Object]
“ ut tensio, sic vis” (load ~ stretch) UNDER TENSION:
Similarly, under bending: load ~ deflection
Under shear… … and torsion: load ~ shear deformation load ~ angular  deformation
Thus, in all cases, Hooke observed: The ratio  applied force/distortion is a constant for the material.  This is (almost)  Hooke’s Law
Hooke’s Law This definition is valid whatever the mode of testing (tension, bending, torsion, shearing, hydrostatic compression, etc, and a specific modulus is then defined)
The stress-strain curve
A general stress-strain curve Elastic (fully reversible) Plastic  (irreversible)
Comparing various stress-strain curves
[object Object],[object Object],[object Object]
[object Object],[object Object],[object Object],[object Object]
2 5 Isotropic 4 5 Transversely isotropic 4 5 Orthorombic [Orthotropic] 6 9 Monoclinic 6 9 Triclinic 2D 2 12 Isotropic 5 12 Transversely isotropic 9 12 Orthorombic [Orthotropic] 13 20 Monoclinic 21 36 Triclinic 3D Number of independent coefficients Number of nonzero coefficients Class of Material
(From J.F. Nye, ‘Physical Properties of Crystals’) Form of the C ijkl  matrix
 
Notations:  ij  = C ijkl  kl (i, j, k, l = 1,2,3)  ij  = S ijkl  kl Historical paradox: The C ijkl  are called the  Stiffness  components The S ijkl  are called the  Compliance  components  Contracted notations in the mechanics of composites:
Contracted notations in the mechanics of composites:
Orthotropic lamina (9 constants) ,[object Object],[object Object],[object Object]
 
Transversely  isotropic lamina (5 constants)
Isotropic lamina (2 constants)
Orthotropic material under plane stress ,[object Object],[object Object],[object Object]
How can we derive relations between mathematical  and engineering constants ? ,[object Object],[object Object]
Elementary experiments
Remember: an orthotropic lamina (9 constants)
Example ,[object Object],[object Object],From which we obtain:
All other elementary experiments provide similar links. Eventually we obtain what we wanted, the stress-strain relations in terms of engineering constants (E,   , G):
[object Object],In general, we conclude that the relations between the compliances S ij  and the engineering constants are simple. It can be shown that the relations between the stiffnesses C ij  and the engineering constants are more complicated.
Finally, the connection between the stiffness constants C ij  and the compliance constants S ij  are as follows:
Last remarks ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]

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Class3

  • 1. the strength of common materials is actually dictated not so much by bond strength but by something else: Defects
  • 2.
  • 3. NANOSCALE Vs MICROSCALE Griffith’s experiments with glass fibers (1921) FIBER DIAMETER (micron) Strength of bulk glass: 170 MPa Extrapolates to 11 GPa 1 2 3 TENSILE STRENGTH (GPa) 0 20 40 60 80 100 120 0
  • 4.
  • 6. A If x = a (point A), then  YYlocal = 3  0 If the local stress reaches the theoretical strength, then the applied stress (  0 ) at failure is  0 =  th /3 And assuming  th ≈ E/10, we get, at failure:  0  E/30 A more realistic situation is that of a sharper crack:  0  0
  • 7.
  • 8.
  • 9. The strength of fibers is statistical
  • 10.
  • 11. Probability of occurrence of a critical defect (F(V)= Probability of failure) against size for a given defect concentration At very small volume, low P of occurrence of a critical defect – Thus: strength tends to be very high At larger volume, F(V) climbs rapidly: A plateau is reached where size has no more effect.
  • 12.
  • 13. Density function: As  increases, the distribution is more narrow, and  is proportional to the average of the distribution
  • 14.
  • 15.
  • 16.
  • 17.
  • 18.
  • 19.
  • 20.
  • 21.
  • 22. By definition, the (Helmholtz) free energy of the body is  = E-TS Thus: So that for an isothermal deformation process (T = constant), we have: Therefore, we need to know the free energy per unit volume,  , as a function of  ik
  • 23. This is easily calculated: since we have small deformations,  can be expanded in a Taylor series: where  0 is the free energy of the undeformed body, and the  ’s are given as follows:
  • 24. By differentiating, we obtain: And we know that this is equal to  ik (for an isothermal process). If there is no deformation, there are no internal stresses in the body, thus  ik = 0 for  ik = o, from which we obtain  = 0. Thus, no linear term in the expansion of  in powers of  ik : by limiting the expansion to the second order:  ~  2
  • 25. And we can therefore compute the stress tensor in terms of the strain tensor: or This very simple expression provides a linear dependence between stress and strain: it is the basic form of Hooke’s law ! Also, remember the connection between Young’s modulus and the potential from the previous class?
  • 26. A common general form (valid for anisotropic bodies) of Hooke’s law is the following: Where  ij and  kl are 2d rank tensors and C ijkl is a 4 th rank tensor with 3x3x3x3 = 81 components [or 9 stress components x 9 strain components = 81]. The C ijkl are called the elastic constants. Historical parenthesis: Robert Hooke’s legacy
  • 27.
  • 28. “ ut tensio, sic vis” (load ~ stretch) UNDER TENSION:
  • 29. Similarly, under bending: load ~ deflection
  • 30. Under shear… … and torsion: load ~ shear deformation load ~ angular deformation
  • 31. Thus, in all cases, Hooke observed: The ratio applied force/distortion is a constant for the material. This is (almost) Hooke’s Law
  • 32. Hooke’s Law This definition is valid whatever the mode of testing (tension, bending, torsion, shearing, hydrostatic compression, etc, and a specific modulus is then defined)
  • 34. A general stress-strain curve Elastic (fully reversible) Plastic (irreversible)
  • 36.
  • 37.
  • 38. 2 5 Isotropic 4 5 Transversely isotropic 4 5 Orthorombic [Orthotropic] 6 9 Monoclinic 6 9 Triclinic 2D 2 12 Isotropic 5 12 Transversely isotropic 9 12 Orthorombic [Orthotropic] 13 20 Monoclinic 21 36 Triclinic 3D Number of independent coefficients Number of nonzero coefficients Class of Material
  • 39. (From J.F. Nye, ‘Physical Properties of Crystals’) Form of the C ijkl matrix
  • 40.  
  • 41. Notations:  ij = C ijkl  kl (i, j, k, l = 1,2,3)  ij = S ijkl  kl Historical paradox: The C ijkl are called the Stiffness components The S ijkl are called the Compliance components Contracted notations in the mechanics of composites:
  • 42. Contracted notations in the mechanics of composites:
  • 43.
  • 44.  
  • 45. Transversely isotropic lamina (5 constants)
  • 46. Isotropic lamina (2 constants)
  • 47.
  • 48.
  • 50. Remember: an orthotropic lamina (9 constants)
  • 51.
  • 52. All other elementary experiments provide similar links. Eventually we obtain what we wanted, the stress-strain relations in terms of engineering constants (E,  , G):
  • 53.
  • 54. Finally, the connection between the stiffness constants C ij and the compliance constants S ij are as follows:
  • 55.