1. 2005 د 2
ا -- ت ا ت ر
ح آ د ا http://said5109.unblog.fr/
4874
- 4804
-73
= 32222
7)480487)(480487( −+−
4874
- 4804
-73
= 322
7)480487)(480487)(480487( −++−
4874
- 4804
-73
= 322
7)480487(9677 −+×
4874
- 4804
-73
= ]7)480487(967[7 222
−+×
4874
- 4804
-73
= k×7
]7)480487(967[ 222
−+=k
7 ا 4874
- 4804
-73
دادن ]7)480487(967[7 222
−+×
a -c = 2a - 2b 2b = 2a – a + c 2b = a + c
)( ca − )( ca + = 2(a – b) a -c = 2(a – b)
(1) =
+ ca
2
ba
ca
−
−
ba +
1
+
cb +
1
=
cb
cb
ba
ba
−
−
+
−
−
a -b = b - c b+ b = a + c 2b = a + c
ba +
1
+
cb +
1
=
ba
cbba
−
−+−
(2)
ba +
1
+
cb +
1
=
ba
ca
−
−
=
+ ca
2
ba +
1
+
cb +
1
أن (2) و (1)
1))(( =+− baba 122
=− ba
1)()( =+− nn
baba ان د 1))(( =+− baba
( )n
n
ba
ba
+=
−
1
أي ( )n
n
ba
ba
+=
− )(
1
2. 2005 د 2
ا -- ت ا ت ر
ح آ د ا http://said5109.unblog.fr/
+
−
n
ba
1
n
ba
+
1
= ( )n
ba + +
n
ba
+
1
( x) ( )n
ba + = x
x
x
x
xx
x
x
22
)1(12
2
1 −
=
+−+
=−+
n
ba
+
1
+ 2
1
≥
−
n
ba
و 2
1
≥+
x
x 02
1
≥−+
x
x 0
)1( 2
≥
−
x
x
ا
M’
∈(AB) M∈(BC) BMM’
و BAC
AC
MM
BC
BM
BA
MB ′
==
′
(1)
M∈ [BC] و [BAC] او ا ا ا [AM)
MB
AB
MC
AC
= و
AC
AB
MC
MB
=
MB
AB
MCMB
ACAB
MC
AC
+
+
==
(2)
BC
MB
ACAB
AB
=
+
و
MB
AB
BC
ACAB +
=
ACAB
AB
+ AC
MM ′
= ان (2)و (1)
ACABACABMM ×=+′ )( و
ACAB
ACAB
MM ×
+
=
′
1
ACAB
AB
MM ×
=
′
1
ACAB
AC
×
+
ACMM
11
=
′ AB
1
+