An induction motor turning at 1750 RPM consumes 4750 watts of power and produces 14.37 ft- lbs of torque. the efficiency of the motor is a) 33.7% b) 66.6% c)75.2% d)133% Solution efficiency = output power/input power = pout/pin given input power = 4750 rpm output power = torque(ft-lbs) = power (HP) * 5252 / RPM from the above formula, we get pout = 4.7 HP = 3.506KW (approx) efficiency = 75.2%.

1. An induction motor turning at 1750 RPM consumes 4750 watts of power and produces 14.37 ft-
lbs of torque. the efficiency of the motor is
a) 33.7% b) 66.6% c)75.2% d)133%
Solution
efficiency = output power/input power = pout/pin
given input power = 4750 rpm
output power =
torque(ft-lbs) = power (HP) * 5252 / RPM
from the above formula, we get pout = 4.7 HP = 3.506KW (approx)
efficiency = 75.2%