Fail to PASS!!

1. MODUL
SUPER
SCORE
SBP
2014
1
KERTAS 1
SET 4
NAMA MARKAH
TARIKH
Answer all questions.
Jawab semua soalan.
1. The relation between set P and set Q is defined by the set of ordered pairs {(1, a), (1, c),
(3, a),(4, b),(4, d), (6, d)}.
Hubungan antara set P dan set Q ditakrifkan oleh set pasangan bertertib {(1, a), (1, c),
(3, a),(4, b), (4, d), (6, d)}.
State
Nyatakan
(a) the image of 4,
imej bagi 4,
(b) the type of the relation,
jenis hubungan tersebut,
(c) the relation in the graph form.
hubungan dalam bentuk graf.
[3 marks]
[3 markah]
Answer/ Jawapan :
(a)
(b)
(c)
For
examiner’s
use only
3
1

2. MODUL
SUPER
SCORE
SBP
2014
2
2. The following information refers to the function f and g.
Maklumat berikut merujuk kepada fungsi f dan g.
f : x → 4x – 6
g : x → 2x – 3
Find gf–1
(x).
Cari gf–1
(x).
[3 marks]
[3 markah]
Answer/ Jawapan :
3. Given the function h(x) = 4x + 5 and the composite function hg(x) = 8x + 7.
Diberi fungsi h(x) = 4x + 5dan fungsi gubahan hg(x) = 8x + 7.
Find
Cari
(a) hg(–1)
(b) g(x) [3 marks]
[3 markah]
Answer/ Jawapan :
For
examiner’s
use only
3
2
3
3

3. MODUL
SUPER
SCORE
SBP
2014
3
4. Find the roots for the quadratic equation x(x – 3) = 9 – x. Give your answer correct to three
significant figures.
Cari punca-punca bagi persamaan kuadratik x(x – 3) = 9 – x. Beri jawapan anda betul
kepada tiga angka bererti.
[3 marks]
[3 markah]
Answer/ Jawapan :
5. It is given that 4 and m + 1 are the roots of the quadratic equation x2
+ (2 – n)x + 8 = 0,
where m and n are constants. Find the value of m and n.
Diberi bahawa 4 dan m + 1 ialah punca-punca bagi persamaan kuadratik
x2
+ (2 – n)x + 8 = 0, dengan keadaan m dan n ialah pemalar. Cari nilai m dan n.
[3 marks]
[3markah]
Answer/ Jawapan :
3
5
3
4
For
examiner’s
use only

4. MODUL
SUPER
SCORE
SBP
2014
4
6. The diagram shows the graph of a quadratic function y = –(x – 4)2
– 1.
Rajah menunjukkan graf fungsi kuadratiky = –(x – 4)2
– 1.
Find
Cari
(a) the value of k,
nilai k,
(b) the equation of the axis of symmetry,
persamaan paksi simetri,
(c) the coordinate of the maximum point.
koordinat titik maksimum.
[3 marks]
[3 markah]
Answer/ Jawapan :
7. The quadratic function f(x) = p(x + q)2
+ r, where p, q and r are constants, has maximum
value of 10. The equation of axis of symmetry is x = 2.
Fungsi kuadratik f(x) = p(x + q)2
+ r, dengan keadaan p, q dan r ialah pemalar,
mempunyai nilai maksimum 10. Persamaan paksi simetri ialah x = 2.
State
Nyatakan
(a) the range of value of p,
julat nilai p,
(b) the value of q,
nilai q,
(c) the value of r.
nilai r.
[3 marks]
[3 markah]
Answer/ Jawapan :
3
7
3
6
–3
y
(k, –3)
0
x
For
examiner’s
use only

5. MODUL
SUPER
SCORE
SBP
2014
5
8. Find the range of values of x for x2
– 2(2x + 1) ≥ 2x2
– x.
Cari julat nilai-nilai x bagi x2
– 2(2x + 1) ≥ 2x2
– x.
[4 marks]
[4markah]
Answer/ Jawapan :
9. Solve the equation(27x
)x
×
x
243
1
= 9.
Selesaikan persamaan (27x
)x
×
x
243
1
= 9.
[4 marks]
[4markah]
Answer/ Jawapan :
10. Solve the equation3x– 1
+3x + 2
= 2.
Selesaikan persamaan 3x – 1
+ 3x + 2
= 2.
[3 marks]
[3markah]
Answer/ Jawapan :
4
8
4
9
3
10
For
examiner’s
use only

6. MODUL
SUPER
SCORE
SBP
2014
6
11. Given that loga 2 = x and loga 3 = y, express loga ⎟
⎠
⎞
⎜
⎝
⎛
a9
8
in terms of x and y.
Diberi loga 2 = x dan loga 3 = y, nyatakan loga ⎟
⎠
⎞
⎜
⎝
⎛
a9
8
dalam sebutan x dan y.
[4 marks]
[4 markah]
Answer/ Jawapan :
12. Solve the equation 2 + log4 x = log22x.
Selesaikan persamaan 2 + log4 x = log2 2x.
[4 markah]
[4 marks]
Answer/ Jawapan :
4
11
4
12
For
examiner’s
use only

7. MODUL
SUPER
SCORE
SBP
2014
7
13. In a geometric progression, the first term is
2
1
and the fourth term is
27
4
− .
Dalam suatu janjang geometri, sebutan pertama ialah
2
1
dan sebutan keempat ialah
27
4
− .
Calculate
Hitung
(a) the common ratio,
nisbah sepunya,
(b) the sum to infinity of the geometric progression.
hasil tambah hingga sebutan ketakterhinggaan bagi janjang geometri itu.
[3 marks]
[3 markah]
Answer/ Jawapan :
14. The 3rd
term of a geometric progression is 18. The sum of the 3rd
term and 4th
term is 27.
Sebutan ke-3 suatu janjang geometri ialah 18. Hasil tambah sebutan ke-3 dan sebutan ke-4
ialah 27
Find
Cari
(a) the first term and the common ratio of the progression,
sebutan pertama dan nisbah sepunya janjang itu,
(b) the sum to infinity of the progression.
hasil tambah hingga sebutan ketakterhinggaan janjang itu.
[4 marks]
[4 markah]
Answer/ Jawapan :
4
14
3
13
For
examiner’s
use only

8. MODUL
SUPER
SCORE
SBP
2014
8
15. The nth
term of a geometric progression, Tn, is given by Tn = 2
2
3
2
−
⎟
⎠
⎞
⎜
⎝
⎛
n
, find
Sebutan ke-n bagi suatu janjang geometri, Tn, diberi oleh Tn = 2
2
3
2
−
⎟
⎠
⎞
⎜
⎝
⎛
n
, cari
(a) the first term and the common ratio,
sebutan pertama dan nisbah sepunya.
(b) the sum to infinity of the progression.
hasil tambah hingga sebutan ketakterhinggaan bagi janjang itu.
[ 3 marks]
[3 markah]
Answer/ Jawapan :
16. The diagram shows two vectors, OA and OB.
Rajah menunjukkan dua vektor, OA dan OB.
Express
Ungkapkan
(a) AO in the form ⎟⎟
⎠
⎞
⎜⎜
⎝
⎛
y
x
,
OA dalam bentuk ⎟⎟
⎠
⎞
⎜⎜
⎝
⎛
y
x
,
(b) AB in the form xi + yj.
AB dalam bentuk xi + yj.
[3 marks]
[3markah]
Answer/ Jawapan :
3
15
3
16
For
examiner’s
use only
y
x
• A(4, 10)
• B(2, –6 )
O

9. MODUL
SUPER
SCORE
SBP
2014
9
17. Given p = ⎟⎟
⎠
⎞
⎜⎜
⎝
⎛
−12
5
and q = ⎟⎟
⎠
⎞
⎜⎜
⎝
⎛ +
3
1m
, find
Diberi p = ⎟⎟
⎠
⎞
⎜⎜
⎝
⎛
−12
5
dan q = ⎟⎟
⎠
⎞
⎜⎜
⎝
⎛ +
3
1m
, cari
(a) | p |,
(b) the value of m such that p + q is parallel to y-axis.
nilai m dengan keadaan p + q adalah selari dengan paksi y.
[4 marks]
[4 markah]
Answer / Jawapan :
18. The diagram shows the vectors OA, OB and OP drawn on a grid of equal squares with sides
of 1 unit.
Rajah menunjukkan vektor OA, OB dan OP dilukis pada grid segiempat sama yang sama
besar bersisi 1 unit.
Determine
Tentukan
(a) | OP |,
(b) OP in terms of a and b.
OP dalam sebutan a and b.
[2 marks]
[2 markah]
Answer/ Jawapan :
4
17
2
18
For
examiner’s
use only
~ ~
~ ~
~
A B P
a
~
b
~
~ ~
~ ~
O

10. MODUL
SUPER
SCORE
SBP
2014
10

11. MODUL
SUPER
SCORE
SBP
2014
11
Jawapan/Answer :
No Answer No Answer
1
(a) b and d
(b) many to many
(c)
16
(a) ⎟⎟
⎠
⎞
⎜⎜
⎝
⎛
−
−
10
4
(b) –2i – 16j
2
2
x
17
(a) 13
(b) –6
3
(a) –1
(b) 2x +
2
1 18 (a) 20
(b) 2b – a
4 4.16 and –2.16
5 m = 1 and n = 8
6
(a) 8
(b) x = 4
(c) (4, –1)
7
(a) p < 0
(b) q = –2
(c) r = 10
8 –2 ≤ x ≤ –1
9 x = 2,
3
1
−
10 x = –1.4022
11 3x – 2y – 1
12 x = 0 and x = 4
13
(a)
3
2
−
(b)
10
3
14
(a) a = 72, r =
2
1
(b) 144
15
(a) a = 3, r =
3
2
(b) 9
1 3 4 6
Set P
Set Q
a
b
c
d