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Alright so, Friday's class was all 
about another method used to solve 
antiderivatives. It is called 
integration by parts.




                                      1
We started off with this question:




                                     2
Hmmm... the answer is, yes, but we have to 
use a different technique. As you can see 
the method of substitution will not work on 
this one. That's why we need another 
technique called integration by parts.




                                               3
4
Now, let us apply that new rule to solve the previous 
question.




First, we need to decide which one is going to be f and  g'. 
The question is how to decide which function will be f ?




                                                                5
The answer is, we just need to remember this mnemonic.




                                                         6
Now, according to that  mnemonic we will have this:




                                                      7
Then, we just need to find out the missing pieces required to 
use the rule of integration by parts. We still need to find f ' 
and g, so by finding the derivative of f and antidifferentiating 
g we get this:




                                                                    8
Now, we are set. We have all the needed pieces to make 
the rule work. All we need is to substitute the functions.




                                                             9
Now all we need is to antidifferentiate this part 
then we will get our answer, which is:




                                                     10
After that we practiced on more 
questions that use application of 
the rule of integration by parts. In 
some cases we need to use it more 
than once, but I'm not going to 
bother explaining those because 
there is nothing new, except that 
you just need to do use the rule 
again.




                                        11
The rule can be used in 
antidifferentiating a composite 
function but, it can also be applied 
when integrating a single function 
by considering the function g'(x) to 
be the factor 1.




                                        12
For example:




The only thing different here is that we just used 
function g'(x) to be the factor 1, in order to have two 
functions.




                                                           13

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