2. Experiment:
Molisch’s test:
1 ml starch + 2 or 3 drops of Molisch’s reagent.
Mix well & add 1-2 ml Conc. Sulphuric acid along the
sides of the test tube without shaking.
Observation:
A reddish violet ring at the junction of two liquids.
Inference:
Starch is a carbohydrate.
3.
4. Composition of Molisch’s reagent:
1% α- naphthol in 95% ethanol.
Principle:
Carbohydrates when treated with Conc.
Sulphuric acid undergo dehydration to give
furfural or furfural derivatives.
These compounds condense with α- naphthol
to form reddish violet ring.
5. General test for all carbohydrates
Excess α- naphthol & impurities in reagent give green
colored ring.
Molisch’s test is given by carbohydrates with at least 5
carbons.
Trioses & tetroses do not answer this test.
Interaction of acid & water produces heat & can cause
charring of carbohydrates (due to precipitation of
carbon) resulting in the formation of black ring.
Acid should be layered very slowly.
6. Experiment:
2 ml starch + add 2-3 drops of iodine solution.
Observation:
Deep blue color
Inference:
Starch is a polysaccharide
7. Principle:
The amylose component of starch has helical
structure & when treated with iodine
solution, the iodine gets trapped inside the
helical structure giving the solution blue
color, which indicates the presence of starch.
8. Experiment:
5 ml Benedict’s reagent + add 8 drops of starch
solution.
Boil it for 2 mints.
Observation:
No colored precipitate.
Inference:
Starch is a non-reducing sugar.
9.
10. Experiment:
5 ml starch + add 4 drops of Conc. HCl + keep
in boiling water bath for 10 min + cool under
running water + neutralize by adding 5
drops of 10% sodium carbonate, till the
effervescence ceases.
Inference:
The solution is hydrolysed
11. Experiment:
5 ml Benedict’s reagent + 8 drops of
hydrolysate of starch, mix + boil for 2 min.
Observation:
Brick red precipitate.
Inference:
Hydrolysate contains reducing sugar.