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please solve this python question and do not use a user-defined function. make it as simple as possible. pls explain. thanks For the list below: - Remove the odd numbers from the list - Evaluate the average of the resulting list \[ \text { var_list }=[1,2,3,5,4,67,87,76,12,45,99,22,35] \].

$please solve this python question and do not use a user-defined function. make it as simple as possible. pls explain. thanks For the list below: - Remove the odd numbers from the list - Evaluate the average of the resulting list [ text { var_list }=[1,2,3,5,4,67,87,76,12,45,99,22,35] ]$

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Pls introduced to various themes and theoretical issues pertaining to Global Entrepreneurship and Innovation of Global Marketing; brands and social media. You need to formally introduced to various themes and theoretical issues and challenges of Global Entrepreneurship, Innovation, and Sustainability. An important aspect of this is exploring the impact and disruption caused by the Covid 19 pandemic, climate change, and other key themes and issues being prioritized by stakeholders in offering local and global solutions. Pls be your own words (1200 -1500 words) Thanks you..

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please! 1. Match and pair the following basic genetic concepts with their respective descriptions/definitions: 1. Gene a. Two different alleles 2. Allele b. Observable heritable feature that may vary among organisms. 3. Phenotype c. Two identical alleles 4. Genotype d. Describes the specific alleles present in the offspring. 5. Homozygous e. Segments of DNA responsible for producing a particular trait. 6. Heterozygous f. Variants of a gene present for a particular character. 2. From the figure presented here, determine the following: a. Which letter(s) show a phenotype? b. Which letter(s) show a genotype? c. In letter (c), are we looking at a homozygous recessive, a homozygous dominant, or a heterozygous individual? d. In letter (e), are we looking at a homozygous recessive, a homozygous dominant, or a heterozygous individual? 3. A and a are dominant and recessive alleles, respectively, of the same gene. Which genotype(s) would result in an individual with the dominant trait? A) AA and aa B) AA and aa C) only AA D) AA and Aa E) only Aa 4. For Labrador retrievers, black fur color (B) is dominant to yellow fur color (b). If a heterozygous black male mated with a homozygous yellow female, what would the puppies look like? Determine the phenotypic ratios. - Step 1: Determine the genotype of the female and male Labradors. Heterozygous black male: Homozygous yellow female: - Step 2: Write/Type the cross between the two Labradors. X -Step 3: Do a Punnett Square to determine the probable genotypes for the offspring and to determine the phenotypic ratio. -Step 4: Determine the Phenotype ratios of the progeny: s. There are many humans traits that are fairly simple and that follow the Mendelian pattern of inheritance. However, most of our traits are much more complex, involving many genes or interactions between genes. For example, hair color is determined by at least four genes, each one coding for the productions of melanin, a brown pigment. Because the effect of these genes is cumulative, hair color can range from blonde (little melanin) to very dark brown (much melanin). 2 Human traits are of great interest to us and there are few traits that seem to exhibit Mendelian inheritance, such as the ones shown below (this can be found in your lab manual). Figure 134 some madiy absenutle human Menoulae tak. Mid-digital hair b. Tongue rolling c. Widow's peak d. Earlobe attachment e. Hitchhiker's thumb f. Relative finger length With the information provided in your lab manual, Section 13-3 (pages 172-174), choose one out the six traits presented here and complete the following table..

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Please do parts labeled TODO /** * LinkedList.java * * Replace all //TODO tags with your code * * Note that below the "//TODO" tag there may be * something like "return null;", "return 0;", etc. * That line is just "stubbed in" so the class * will compile. When you add your code (one or many * statements), you will want to delete the "stubbed" line. * By "stubbed in" we mean "mocked" or "faked in" temporarily. * * When testing, construct using the static factory methods: LinkedList.newEmpty() LinkedList.from(arrayElements) */ package model.list; import java.lang.reflect.Array; import java.util.concurrent.atomic.AtomicInteger; import java.util.function.BiFunction; import java.util.function.Consumer; import java.util.function.Function; import model.linearpub.DynamicList; import model.linearpub.StructureIterator; //This class is NOT java.util.LinkedList public class LinkedList implements DynamicList { //--------------------------------- // Instance Variables //TODO - declare instance variable(s) //--------------------------------- // Private Constructor /** Constructs and returns new LinkedList (no args constructor) */ private LinkedList() { } //-------------------- List Statistics --------------------- /** * Return number of elements in this list. */ @Override public int size() { //TODO return 0; } /** * Return true is this list contains no elements. */ @Override public boolean isEmpty() { //TODO return false; } //------------------ Accessing Elements -------------------- /** * Return element at given index. * Throws IndexOutOfBoundsException if passed index is invalid. */ @Override public E get(int index) { //TODO return null; } /** * Return first element * Throws RuntimeException if list is empty */ @Override public E first() { //TODO return null; } /** * Return last element * Throws RuntimeException if list is empty */ @Override public E last() { //TODO return null; } /** * Return a new list containing the elements of this list * between the given index "start" (inclusive) and * the given index "stop" (exclusive). * Throws IndexOutOfBoundsException if either passed index is invalid. */ @Override public DynamicList subList(int start, int stop) { //TODO return null; } /** * Return index of first matching element (where searchFct outputs true) * Return -1 if no match * Example usage (first list of integers, then employees): * index = list.find(eaInteger -> eaInteger == 10); * index = employeeList.find(employee -> employee .getFirstName().equals("Kofi")); */ @Override public int findFirst(Function searchFct) { //TODO return 0; } /** * Return index of last matching element (where searchFct outputs true) * E.g., if searching for employee with name "Kofi" and there is a match * at index=3 and index=8, findLast will return 8 (the last matching index). * Hint: start search at end of list and work backwards through list. * Return -1 if no match */ @Override public int findLast(Function searchFct) { //TODO return 0; } //------------------- Setting Elem.

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Please show work/steps You have genotyped an entire population of lab mice for a single locus (let's label it F) that you have noticed have some interesting differences in size at a certain age. Based on your genotyping work, you calculate the average of the FF genotype to be 78 grams, the Ff genotype to be 34 grams and the ff genotype to be 24 grams. The frequency of the F allele is 0.76. What is the average allele effect of the F locus in grams for this population (rounded to the nearest 0.01)?.

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Please show all steps of algebra. I have the answer shown below but I need to know the steps to solve. Suppose that tastes for leisure (l) and consumption (c) are represented by CES utility function: U(l,c)=(l+(1)c)1/ Find the labor supply assuming a leisure endowment of L. (5 points) ider the more general constamt ciastancion probl (c+(1))1/. Solving the maximization tility function, and doing some tedious algebra, we get =(w)1/(+1)+(1)1/(+1)L(1)1/(+1) ng labor supply function l(w,L)=L(w)1/(+1)+(1)1/(+1)L(1)1/(+1).

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Please read the case and do the external factors based on the factors below, and do a discussion about it . Case Study: Mark, the Volunteer Mark is an employee of a small community drugstore and has volunteered for different assignments with nonprofit agencies. One of the assignments he thinks that he will enjoy the most is working as a member of the core committee which organizes and runs the yearly community festival for the neighborhood. Because of his experience with community events, Mark has been placed in charge of logistics coordination, planning, security, and public safety. While this appears to be an extensive workload, Mark has a great deal of previous experience and understands the tasks that need to be completed. Because the planning for the festival started a year in advance, he knows that as the festival grows closer there will be additional volunteers to assist him, so he will not be individually responsible for each one of these areas; for now, the workload is sufficient for one person. The Community Festival The community festival is a nonprofit organization that has a tax exempt status as well as a history of over 20 years. The organization and the event are run by a board of directors and a small, permanent staff composed of no more than five employees at any given time. The goal of the festival is to promote local arts and crafts and to support local artists by providing a venue through which they can sell their work, advertise their work, and develop and expand their customer base. Because the festival has been held for many years, it is well-known in the area and typically attracts supporters of the arts and owners of small and independent art galleries as well as boutique and specialty stores owners who are in search of unique forms of art for clientele. As a result, the festival has established a reputation as a well-known venue for local art. One of the unique aspects of this festival is that it has enjoyed growth and continuity within the community even though the community itself was part of a much larger metropolitan area in the southwestern United States. The identity of the festival has remained intact and is considered a part of the local community. Part of the mission of the community festival Board of Directors is to educate the community about art in addition to creating a venue for creative expression. During its growth, the festivals mission gradually expanded to include educational and other programs which run throughout the year. However, in recent times local artists who used to be yearly participants have drifted away and local funding used to support the festival is diminishing, because fewer and fewer local artists were participating. As a result, the Board of Directors focused on bringing in a nationally known talent and artists in various fields to attract more participants. Because local funding was lost, more funding now is being sought through grants. The focus of the festival is gradually chan.

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Please provide everything correct. I will upvote!! Why do proposals often take the indirect approach? a. To increase efficiency and make the proposal easy to follow b. To enable the use of AIDA-style persuasion c. To better incorporate the use of topical headings d. To make the proposal as short as possible e. To incorporate more visual aids to enhance review Which aspect of a formal work plan describes what you plan to accomplish and defines the boundaries of your work? a. Statement of the products or activities that will result from the investigation b. Audience analysis c. Statement of the problem and opportunity d. Working outline e. Statement of the purpose and scope of your investigation Which of the following help readers summarize and remember what they have read while giving them a mental framework to process new information? a. Transitions b. Reviews c. Previews d. Headings e. Documented sources.

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please navigate to cs112 webpage and go to assignments --> Trees. This will give you the directions for the assignment. Please do the last 2 methods in huffman.java called encode() and decode() Code is provided below: HuffmanCoding.java package huffman; import java.io.File; import java.io.FileInputStream; import java.io.FileOutputStream; import java.util.ArrayList; import java.util.Collections; /** * This class contains methods which, when used together, perform the * entire Huffman Coding encoding and decoding process * * @author Ishaan Ivaturi * @author Prince Rawal */ public class HuffmanCoding { private String fileName; private ArrayList sortedCharFreqList; private TreeNode huffmanRoot; private String[] encodings; /** * Constructor used by the driver, sets filename * DO NOT EDIT * @param f The file we want to encode */ public HuffmanCoding(String f) { fileName = f; } /** * Reads from filename character by character, and sets sortedCharFreqList * to a new ArrayList of CharFreq objects with frequency > 0, sorted by frequency */ public void makeSortedList() { StdIn.setFile(fileName); /* Your code goes here */ } /** * Uses sortedCharFreqList to build a huffman coding tree, and stores its root * in huffmanRoot */ public void makeTree() { /* Your code goes here */ } /** * Uses huffmanRoot to create a string array of size 128, where each * index in the array contains that ASCII character's bitstring encoding. Characters not * present in the huffman coding tree should have their spots in the array left null. * Set encodings to this array. */ public void makeEncodings() { /* Your code goes here */ } /** * Using encodings and filename, this method makes use of the writeBitString method * to write the final encoding of 1's and 0's to the encoded file. * * @param encodedFile The file name into which the text file is to be encoded */ public void encode(String encodedFile) { StdIn.setFile(fileName); /* Your code goes here */ } /** * Writes a given string of 1's and 0's to the given file byte by byte * and NOT as characters of 1 and 0 which take up 8 bits each * DO NOT EDIT * * @param filename The file to write to (doesn't need to exist yet) * @param bitString The string of 1's and 0's to write to the file in bits */ public static void writeBitString(String filename, String bitString) { byte[] bytes = new byte[bitString.length() / 8 + 1]; int bytesIndex = 0, byteIndex = 0, currentByte = 0; // Pad the string with initial zeroes and then a one in order to bring // its length to a multiple of 8. When reading, the 1 signifies the // end of padding. int padding = 8 - (bitString.length() % 8); String pad = ""; for (int i = 0; i < padding-1; i++) pad = pad + "0"; pad = pad + "1"; bitString = pad + bitString; // For every bit, add it to the right spot in the corresponding byte, // and store bytes in the array when finished for (char c : bitString.toCharArray()) { if (c != '1' && c != '0') { System.out.println("Invalid characters in bitstring"); return; } if (c .

please navigate to cs112 webpage and go to assignments -- Trees. Th.pdf

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