suppose a point is randomly relected from within the interior of a cube centered at the origin (0,0,0) with -a ? x ? a, -a ?y? a, and -a? z ? a. use a geometric approach to find the probability the point is the sphere inscribed in the cube. (reminder, the volume of a sphere is V = 4/3? r^3). Solution a probability of point in sphere = ( {4/3} * pi * { *a }^3 } / 2a*2a*2a on solving probability of point in sphere = 0.52.