The employees in the textile industry can be segmented as follows: Employees Number Female and union 12,000 Female and nonunion 25,000 Male and union 21,000 Male and nonunion 42,000 a. Determine the probability of each event in this distribution. An event refers to the combinations shown in the Employees column. For example, female and union is one event while female and nonunion is another event. b. Are the events in this distribution mutually exclusive? Explain. c. What is the probability that an employee is male? d. Is this experiment of segmenting employees in the textile industry collectively exhaustive? Explain.EmployeesNumberFemale and union12,000Female and nonunion25,000Male and union21,000Male and nonunion42,000 Solution FU = 12,000/(12,000 + 25,000 + 21,000 + 42,000) = .12 FN = .25 MU = .21 MN = .42 b. yes. male and female are exclusive categories, as are union and non-union c. MU + MN = .63 d. yes.