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Lecture 22
Current loops.
Sources of magnetic field.
Force on a square loop of current
The square loop below has side length L and carries a current I.
The magnetic field B points out of the screen and is uniform.
What is the net force on the loop?

F
B
I

F

F

F

Magnitude of force is the same
on all four sides: F = ILB

Net force is zero.
Current loop in a uniform B field
r
B

(B in any direction, not necessarily in the
plane of the screen)

Ñ
∫ dl
r
F =

r

r
Ñ ×B
∫ Idl

=I

r

(Ñ )
∫ dl

r
×B

r

=0

=0

r
Constant B and I

The net force on a closed loop of current in a uniform
B field is always zero.
Torque on a square loop of current
The square loop below has side length L and carries a current I.
The magnetic field B is uniform.
Net force = 0

τ
F =0

B

F

Net torque about the center of
the loop:
τ =F

= FL

F

= IL2B

I
F =0

L
L
+F
2
2

F = ILB
Torque on a square loop of current (2)
Now the loop is in the xy plane and B is parallel to the xz plane.

B

FL

I
φ

z

FR

φ

Near side has force FN = ILB cosφ
out of the screen.
Far side has force FF = ILB cosφ
into of the screen.
⇒ These forces cancel out and don’t
do torque.

x

FL = FR = ILB

Net torque about the center of the loop:
ˆ
L
r  L
ˆ
τ =  FL sin φ + FR sin φ ÷j = IL2B sin φ j


2

2


Magnetic dipole
For a current loop of area A and current I:

r
r
µ = IA

Magnetic dipole moment of a current loop (=
magnetic dipole)

r
A = area vector, with direction given by the right-hand rule
Then, the torque by the uniform magnetic field is:

r
r r
2
ˆ
ˆ
τ = IL B sin φ j = µB sin φ j = µ × B

r r r
τ = µ ×B

B
φ

I

z

φ

x
Work by this torque as loop plane moves from φ1 to φ2:

W =

∫

φ2

φ1

φ2
φ2
r r
τ d φ = − ∫ τ d φ = − ∫ µB sin φd φ = + µB ( cos φ2 − cos φ1 )
φ1

φ1

r
τ is clockwise
r
φ is counterclockwise

r
µ

φ

r
τ

r
B

Motion of a magnetic dipole
(current loop) in a uniform B
field given by:

W = −∆U

r r
U = − µB cos φ = − µ ×B
Minimum (stable equilibrium) at φ = 0

r r r
τ = µ ×B
r r
U = − µ ×B

⇒ µ tends to align itself with B

Current loop in
magnetic field
ACT: Two turns
A cable forms a circular circuit of radius R. When connected to a
battery, current flows through it and we can assign it a magnetic
moment µ.
If we use the same cable to make a circular circuit with two turns of
radius R/2, and use the same battery, the magnetic moment is:
A. µ
B. µ/2

Rule of thumb: if there are N turns, count
area as NA (A = area of one loop)

C. 2µ

I
I
I

µ = I πR 2

equivalent to

2I

2

R 
1
1
µ ′ = 2I π  ÷ = I π R 2 = µ
2
2
2
MRI (Magnetic Resonance Imaging) and NMR
(Nuclear Magnetic Resonance)
A single proton (like the one in every hydrogen atom)
has a charge (+|e|) and an intrinsic angular momentum
(“spin”). If we (naively) imagine the charge circulating in
a loop  magnetic dipole moment μ.
In an external B-field:
– Classically: there will be torque unless µ is aligned along B or against it.
– Quantum Mechanics: The spin is always ~aligned along B or against it
Aligned: U1 = − µB

Anti-aligned: U2

= µB

∆U ≡ U2 − U1 = 2µB = 2.82 × 10 −26 J
μproton = 1.41×10−26 Am2
B = 1 Tesla (= 104 Gauss) Big field!

In QM, you will learn that photon
energy = frequency • Planck’s constant
h ≡ 6.63 × 10-34 J s

2.82 × 10 −26 J
f =
= 42.5 MHz
6.63 × 10 −34J s
If we “bathe” the protons in radio waves at this frequency, the protons
can flip back and forth.
If we detect this flipping → hydrogen!
The presence of other molecules can partially shield the applied B, thus
changing the resonant frequency (“chemical shift”).
Looking at what the resonant frequency is
nearby.

→ what molecules are

Finally, because f µ ∆U µ B , if we put a strong magnetic field gradient
across the sample, we can look at individual slices, with ~millimeter
spatial resolution.

B

Small B
low freq.

Bigger B
high freq.
Signal at the right frequency only from this slice!
Thanks to
What produces magnetic fields?
A moving charge experiences a force in a B-field
By symmetry, it is reasonable to think that B fields are also produced by
moving charges

generates B-field and
exerts a force on
moving charge 1

moving charge 2
generates B-field and
exerts a force on
Magnetic field by a moving charge:
experimental facts
• When q larger, and when v larger, larger B-field produced
1
• B-field decreases with 1/distance2 from the moving source B µ 2
r
• B-field is NOT directed away or towards moving charge

charge (q > 0) moving into screen

B-field line is circular
around moving charge
Magnetic field by a moving charge: equation
r µ vr × r
ˆ
B-field at point P B = 0 q
4π
r2

ˆ
r = unit vector from charge to P

µ0 permeability constant = 4π × 10 −7 T ×m/A

If q > 0 then
r
r
ˆ
B same direction as v × r
Lecture 22   current loops. sources of magnetic field.

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Lecture 22 current loops. sources of magnetic field.

  • 2. Force on a square loop of current The square loop below has side length L and carries a current I. The magnetic field B points out of the screen and is uniform. What is the net force on the loop? F B I F F F Magnitude of force is the same on all four sides: F = ILB Net force is zero.
  • 3. Current loop in a uniform B field r B (B in any direction, not necessarily in the plane of the screen) Ñ ∫ dl r F = r r Ñ ×B ∫ Idl =I r (Ñ ) ∫ dl r ×B r =0 =0 r Constant B and I The net force on a closed loop of current in a uniform B field is always zero.
  • 4. Torque on a square loop of current The square loop below has side length L and carries a current I. The magnetic field B is uniform. Net force = 0 τ F =0 B F Net torque about the center of the loop: τ =F = FL F = IL2B I F =0 L L +F 2 2 F = ILB
  • 5. Torque on a square loop of current (2) Now the loop is in the xy plane and B is parallel to the xz plane. B FL I φ z FR φ Near side has force FN = ILB cosφ out of the screen. Far side has force FF = ILB cosφ into of the screen. ⇒ These forces cancel out and don’t do torque. x FL = FR = ILB Net torque about the center of the loop: ˆ L r  L ˆ τ =  FL sin φ + FR sin φ ÷j = IL2B sin φ j  2 2 
  • 6. Magnetic dipole For a current loop of area A and current I: r r µ = IA Magnetic dipole moment of a current loop (= magnetic dipole) r A = area vector, with direction given by the right-hand rule Then, the torque by the uniform magnetic field is: r r r 2 ˆ ˆ τ = IL B sin φ j = µB sin φ j = µ × B r r r τ = µ ×B B φ I z φ x
  • 7. Work by this torque as loop plane moves from φ1 to φ2: W = ∫ φ2 φ1 φ2 φ2 r r τ d φ = − ∫ τ d φ = − ∫ µB sin φd φ = + µB ( cos φ2 − cos φ1 ) φ1 φ1 r τ is clockwise r φ is counterclockwise r µ φ r τ r B Motion of a magnetic dipole (current loop) in a uniform B field given by: W = −∆U r r U = − µB cos φ = − µ ×B Minimum (stable equilibrium) at φ = 0 r r r τ = µ ×B r r U = − µ ×B ⇒ µ tends to align itself with B Current loop in magnetic field
  • 8. ACT: Two turns A cable forms a circular circuit of radius R. When connected to a battery, current flows through it and we can assign it a magnetic moment µ. If we use the same cable to make a circular circuit with two turns of radius R/2, and use the same battery, the magnetic moment is: A. µ B. µ/2 Rule of thumb: if there are N turns, count area as NA (A = area of one loop) C. 2µ I I I µ = I πR 2 equivalent to 2I 2 R  1 1 µ ′ = 2I π  ÷ = I π R 2 = µ 2 2 2
  • 9. MRI (Magnetic Resonance Imaging) and NMR (Nuclear Magnetic Resonance) A single proton (like the one in every hydrogen atom) has a charge (+|e|) and an intrinsic angular momentum (“spin”). If we (naively) imagine the charge circulating in a loop  magnetic dipole moment μ. In an external B-field: – Classically: there will be torque unless µ is aligned along B or against it. – Quantum Mechanics: The spin is always ~aligned along B or against it Aligned: U1 = − µB Anti-aligned: U2 = µB ∆U ≡ U2 − U1 = 2µB = 2.82 × 10 −26 J μproton = 1.41×10−26 Am2 B = 1 Tesla (= 104 Gauss) Big field! In QM, you will learn that photon energy = frequency • Planck’s constant h ≡ 6.63 × 10-34 J s 2.82 × 10 −26 J f = = 42.5 MHz 6.63 × 10 −34J s
  • 10. If we “bathe” the protons in radio waves at this frequency, the protons can flip back and forth. If we detect this flipping → hydrogen! The presence of other molecules can partially shield the applied B, thus changing the resonant frequency (“chemical shift”). Looking at what the resonant frequency is nearby. → what molecules are Finally, because f µ ∆U µ B , if we put a strong magnetic field gradient across the sample, we can look at individual slices, with ~millimeter spatial resolution. B Small B low freq. Bigger B high freq. Signal at the right frequency only from this slice!
  • 12. What produces magnetic fields? A moving charge experiences a force in a B-field By symmetry, it is reasonable to think that B fields are also produced by moving charges generates B-field and exerts a force on moving charge 1 moving charge 2 generates B-field and exerts a force on
  • 13. Magnetic field by a moving charge: experimental facts • When q larger, and when v larger, larger B-field produced 1 • B-field decreases with 1/distance2 from the moving source B µ 2 r • B-field is NOT directed away or towards moving charge charge (q > 0) moving into screen B-field line is circular around moving charge
  • 14. Magnetic field by a moving charge: equation r µ vr × r ˆ B-field at point P B = 0 q 4π r2 ˆ r = unit vector from charge to P µ0 permeability constant = 4π × 10 −7 T ×m/A If q > 0 then r r ˆ B same direction as v × r