1.) Find the slope and the equation for the line passing through the point (−6,8) with y-intercept at y=−1y=−1.   a) m=  b)  The equation for the line in slope-intercept form:  2.)  The graphs given above show data representing the percentage of women and the percentage of men on weight-loss diets for three selected years after 1987. The lines were drawn to pass through or be near the three points. Estimate the slope and the equation for the line for the percentage of men on diets.   a) Slope of the line for the men: m=   b) The equation of the line for the men in slope-intercept form:  3.) Find the slope, mm, and y-intercept of the line y=3x+1.   a) m =    b) The y-intercept is   4.) The equation of the line that goes through the points (−2,7)and (3,−3)can be written in the form y=mx+b m=  b=  5.) (a) Put the linear expression 4−9(x+3)+3(4x+4)in the form mx+b  b) Give the constant term and the coefficient of x in the linear expression   4−9(x+3)+3(4x+4)  The constant term is    The coefficient of x is  6.) A line’s equation is given in point-slope form:   y−29=5(x−5)  This line’s slope is    A point on this line that is apparent from the given equation is  7.) Write an equation for the line through the point (2,9) with slope 5 in point-slope form y=y0+m(x−x0). 8.)  Write an equation for the line through the points (8,10) and (5,4) in point-slope form y=y0+m(x−x0).  9.)  Find the slope, x-intercept, and y-intercept for the line 2x−10y−16=0  The slope is   The x-intercept is   The y-intercept is  Note: Your answers must be decimals. 10.)  The equation, in general form, of the line that passes through the point (0,5) and is perpendicular to the line 6x+7y+9=0  is Ax+By+C=0, where  A= B= C= 12) *  Fine the equation for the line passing through the point (−4,−1) and parallel to the line whose equation is y=2x+7. 13) Find the value of k so that the line containing the points (3,k) and (−8,1) is perpendicular to the line y=−6/5x−4.  k= 16.) Find the slope of the line passing through the points (a,−1a+5)(a,−1a+5) and (a+h,−1(a+2h)+5).  The slope is   18.)  The equation of the line that goes through the points (−5,−3) and (4,3)( can be written in the form y=mx+b where its slope m is:   20.)   (a) What is the average rate of change of g(x)=−8−7x between the points (−3,13) and (3,−29)?   answer =  The function g is (increasing or decreasing) on the interval -3 ≤x≤3 21.) Let g(x)=7−8x+4x ² then the expression g(x+h)−g(x)/h can be written in the form Ah+Bx+C where A, B, and C are constants. (Note: It's possible for one or more of these constants to be 0.) (A) Find the constants.  A= B= C= 22.)  Let f(x)=5x ²+ 3x+3 and let g(h)= f(3+h)-f(3)/h a) g (1) b) g (0.1) c) g (0.01)  You will notice that the values that you entered are getting closer and closer to a number L. This number is called the limit of g(h)as h approaches 0 and is also called the derivative of f(x) at the p.

1. 1.) Find the slope and the equation for the line passing through
the point (−6,8) with y-intercept at y=−1y=−1.
a) m=
b) The equation for the line in slope-intercept form:
2.) The graphs given above show data representing the
percentage of women and the percentage of men on weight-loss
diets for three selected years after 1987. The lines were drawn
to pass through or be near the three points. Estimate the slope
and the equation for the line for the percentage of men on diets.
a) Slope of the line for the men: m=
b) The equation of the line for the men in slope-intercept form:
3.) Find the slope, mm, and y-intercept of the line y=3x+1.
a) m =
b) The y-intercept is
4.) The equation of the line that goes through the points
(−2,7)and (3,−3)can be written in the form y=mx+b
m=
b=

2. 5.) (a) Put the linear expression 4−9(x+3)+3(4x+4)in the form
mx+b
b) Give the constant term and the coefficient of x in the linear
expression
4−9(x+3)+3(4x+4)
The constant term is
The coefficient of x is
6.) A line’s equation is given in point-slope form:
y−29=5(x−5)
This line’s slope is
A point on this line that is apparent from the given equation is
7.) Write an equation for the line through the point (2,9) with
slope 5 in point-slope form y=y0+m(x−x0).
8.) Write an equation for the line through the points (8,10) and
(5,4) in point-slope form y=y0+m(x−x0).
9.) Find the slope, x-intercept, and y-intercept for the line
2x−10y−16=0
The slope is

3. The x-intercept is
The y-intercept is
Note: Your answers must be decimals.
10.) The equation, in general form, of the line that passes
through the point (0,5) and is perpendicular to the line
6x+7y+9=0 is Ax+By+C=0, where
A=
B=
C=
12) * Fine the equation for the line passing through the point
(−4,−1) and parallel to the line whose equation is y=2x+7.
13) Find the value of k so that the line containing the points
(3,k) and (−8,1) is perpendicular to the line y=−6/5x−4.
k=
16.) Find the slope of the line passing through the points

4. (a,−1a+5)(a,−1a+5) and (a+h,−1(a+2h)+5).
The slope is
18.) The equation of the line that goes through the points
(−5,−3) and (4,3)( can be written in the form y=mx+b where its
slope m is:
20.)
(a)
What is the average rate of change of g(x)=−8−7x between the
points (−3,13) and (3,−29)?
answer =
The function g is (increasing or decreasing) on the interval -3
≤x≤3
21.) Let g(x)=7−8x+4x ² then the expression
g(x+h)−g(x)/h
can be written in the form Ah+Bx+C where A, B, and C are
constants. (Note: It's possible for one or more of these constants
to be 0.)
(A) Find the constants.
A=

5. B=
C=
22.) Let f(x)=5x ²+ 3x+3 and let g(h)= f(3+h)-f(3)/h
a) g (1)
b) g (0.1)
c) g (0.01)
You will notice that the values that you entered are getting
closer and closer to a number L. This number is called the limit
of g(h)as h approaches 0 and is also called the derivative of f(x)
at the point when x=3 We will see more of this when we get to
the calculus textbook.
Enter the value of L:
23.) Let f(x)=7−7x+5x². Calculate the following values:
f(a)=
f(a+h)=
f(a+h)-f(a)/h =
24.) The height s of a ball (in feet) at time t(in seconds) is

6. given by the formula s(t)=64−16(t−1)². Consider the following
expression.
Compute the value of AV[0.5,1]
26.) An open box is to be made from a flat piece of material 16
inches long and 5 inches wide by cutting equal squares of length
x from the corners and folding up the sides.
Write the volume V of the box as a function of x. Leave it as a
product of factors, do not multiply out the factors.
V(x)=
If we write the domain of V(x) as an open interval in the form
(a,b)(a,b), then what is a?
a=
and what is b?
b=
30.) The domain of the function
g(x)=√x(x-17)
is=

7. Note:
Write the answer in interval notation. If the answer includes
more than one interval write the intervals separated by the
"union" symbol, U. If needed enter −∞as -
infinity
and ∞ as
infinity
.
31.) The domain of the function
f(x)=√2x-62
32.) Express the function f(x)=3|x−2|−|x+4| in piece wise form
without using absolute values. [
Suggestion
: It may help to generate the graph of the function.]
f(x)={ f1 x ≤ a
{ f2 a
{ f3 x≥b
a=
b=

8. f1=
f2=
f3=
33.) Find f(0),f(7),f(−7),f(3) and f(7–√) for
f(x)={2/x if x>3
{3x if x≤3
f(0)=
f(7)=
f(-7)=
f(3)=
f( √-7)=