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IJRET: International Journal of Research in Engineering and Technology eISSN: 2319-1163 | pISSN: 2321-7308
__________________________________________________________________________________________
Volume: 02 Issue: 09 | Sep-2013, Available @ http://www.ijret.org 339
VERIFICATION OF AREAS OF I.S. ROLLED STEEL SECTIONS
K. V. Pramod1
, Gururaj A. Kulkarni2
1
Professor, Civil Engineering Department, SDMCET, Karnataka, India, pramodkarnecivil@gmail.com
2
Associate Professor, Physics Department, SDMCET, Karnataka, India, gakulkarni1@gmail.com
Abstract
General Steel Structures are designed using standard steel sections. The design is governed by the Code IS 800-2007, and the
standard steel sections are chosen from SP: 6(1)-1964.The standard steel sections regularly used in construction are, I, Channel, Tee
and Angle (Equal & Unequal) sections, i.e., overall 252 sections. SP: 6(1)-1964 gives the sectional properties of all these 252
standard sections, including the cross sectional areas, for the use of designers, to select the most stable and economical section to
satisfy the loading conditions of the structure. An economical section is one which has the least cross sectional area and hence, least
weight. In SP: 6(1)-1964, the cross sectional areas are given in cm2
to an accuracy of two decimal places. In this paper, the accuracy
of the areas of all these sections, except ISHB sections (all IS Heavy Beams) and ISWB 600 @ 145.1 kg/m, i.e., totally 234 sections,
are verified in mm2
to an accuracy of two decimal places. The results show differences in values of areas for eight Tee-sections only,
which have been tabulated. Cross sectional areas of all other 226 sections perfectly match with the values given in SP: 6(1)-1964.
Index Terms: IS 800-2007, SP: 6(1)-1964, Cross Sectional Areas
-----------------------------------------------------------------------***-----------------------------------------------------------------------
1. INTRODUCTION
As per IS 800- 2007 [1], steel structures are to be designed by
Limit State Method, where the designer has to select the most
stable and economical section to satisfy the loading conditions
of the structure. An economical section is the one which has
the least cross sectional area and hence, least weight. Also,
important properties like, Moment of inertia, Radius of
Gyration, Section Modulus, Plastic Modulus, etc. depend upon
the cross sectional area. Indian rolled steel sections consist of
sloping flanges, fillets at junctions and rounded ends. These
geometrical complexities have been incorporated in the
calculation of the cross sectional areas in this paper. To be
more specific, the Indian Standard Rolled Steel I, Channel and
Tee - Sections can be seen as having two main components,
namely flanges and webs. The web is usually a straight
portion, with parallel edges, whose area and other properties
can be easily determined. However, the flanges are in the form
of cantilevering outstands having two straight non parallel
edges with one end attached to the web, and the other free end
rounded off by a circular arc of definite radius, r2 [2]. Also, at
the junction of the flange outstand and web, a circular fillet of
definite radius, r1 [2], is provided. The calculation of the area
and other properties of this flange outstand portion is not
simple due to these geometrical complexities. Similarly, the
Indian Standard Angle Sections, both Equal and Unequal
Sections, are made of two legs, each perpendicular to the other
with a circular fillet of definite radius, r1 [2], at their junction.
The two long edges of each leg are parallel, and the free end is
rounded off by a circular arc of definite radius, r2 [2].
The cross sectional properties given by the SP: 6(1)-1964 [2]
are used by the structural designers across the country (India).
The nation has switched to the SI units, but the units used in
the SP: 6(1) -1964 [2] still exist in cm2
, cm3
and cm4
, for some
important properties like, Moment of inertia, Area, Section
Modulus, etc. In this paper, the areas of the above mentioned
standard sections are calculated in mm2, to an accuracy of two
decimal places, considering the geometry described above,
and are verified with the areas already in use, since 1964, vide
SP : 6(1) -1964 [2]. The results show differences in values of
areas for eight Tee-sections only and these values have been
tabulated.
2. METHOD OF CALCULATION
Fig. 1 represents typical geometry of the flange with non-
parallel sides with respect to I, Channel and Tee sections. For
I, Channel and Tee sections, the web is treated as a rectangular
area, with one side as the thickness of web and the other side
as the full depth of the section. The flange outstand is treated
as made of three components, - (i) Trapezoidal area ABCD (ii)
Circular Spandrel (Fillet) area, ECF, at the junction with web
(iii) Negative Circular Spandrel area ABG, at the free end.
The area of a section is the sum of the areas of the web and
four flanges outstands for I sections or two flanges outstands
for Channel/Tee sections.
IJRET: International Journal of Research in Engineering and Technology eISSN: 2319-1163 | pISSN: 2321-7308
__________________________________________________________________________________________
Volume: 02 Issue: 09 | Sep-2013, Available @ http://www.ijret.org 340
The calculations of area of flange outstand is as follows:
Area of the trapezium ABCD is given by:
AD × ((AB + CD) / 2) .......… (1)
Area of Circular Spandrel (Fillet) ECF is given by:
r1
2
sinα1 (cosα1+ sinα1 tanα1) - α1 r1
2
.......… (2)
Area of Negative Spandrel ABG is given by:
r2
2
sinα2 (cosα2+ sinα2 tanα2) – α2 r2
2
.......… (3)
Area of Cantilevering Flange outstand is given by,
AGFECDA = (1) + (2) – (3)
2.1 Typical calculation for ISWB 600 @ 133.7 kg/m:
As per SP: 6(1) -1964 [2];
Area = 170.38 cm2
; Depth = 600 mm;
Width of flange = 250 mm; Thickness of flange = 21.3 mm
Thickness of web = 11.2 mm; r1 = 17 mm, r2 = 8.5 mm and
θ = 96o
;
Therefore, α1 = (180 – 96) / 2 = 42o
= 0.73308 Rad,
α2 = (180 – 96) / 2 = 42o
= 0.73308 Rad,
Area of web = 600 x 11.2 = 6720.0000 mm2
For trapezium,
AB = 15.02528 mm; CD = 27.57472 mm; AD = 119.4 mm
Therefore, Area of the trapezium = 2543.2200 mm2
Area of Circular Spandrel (Fillet) ECF = 48.3687 mm2
Area of Negative Spandrel ABG = 12.09218 mm2
Area of flange outstand = 2543.2200 + 48.3687 – 12.09218
= 2579.49652 mm2
Therefore, area of I section = 6720.00 + (4 x 2579.49652)
= 17037.98608 mm2
Therefore, area in cm2
= 170.38 cm2
(correct to two decimal
places), the value exactly matches with the value given in SP:
6(1) -1964 [2].
Fig. 2 represents typical geometry of the flange with parallel
sides with respect to Equal and Unequal Angle sections. For
Equal and Unequal Angle sections, the area is treated as made
of (i) Two rectangular legs of given thickness, one leg with
full length of leg and the other leg length reduced by the
thickness value (ii) Circular Spandrel (Fillet) area, at the
junction of the two legs (iii) & (iv) Negative Circular Spandrel
areas, at both the free ends, which are equal. The area of an
angle section is given by (i) + (ii) - (iii) – (iv).
Fig.2 Geometry of Angle
The calculations are as follows:
Area of the two rectangular legs is given by:
( l1 + l2 – t ) × t ....… (1)
Area of Circular Spandrel (Fillet) ECF is given by:
r1
2
sinα1 (cosα1+ sinα1 tanα1) - α1 r1
2
....… (2)
Area of Negative Circular Spandrel, at both free ends:
2 × (r2
2
sinα2 (cosα2+ sinα2 tanα2) – α2 r2
2
) ....… (3) & (4)
2.2 Typical calculation for ISA 200150 @ 46.9 kg/m:
As per SP: 6(1) -1964 [2];
Thickness = 18 mm; Area = 59.76 cm2
;
r1 = 13.5 mm, r2 = 9.5 mm and θ = 90o
;
r1
r2
θ
A
B
C
D
E
F
G
α1
O1
α2
O2
tangentassumed
Fig.1 Flange Geometry of I, C & T Sections
r1
r2
vertical
IJRET: International Journal of Research in Engineering and Technology eISSN: 2319-1163 | pISSN: 2321-7308
__________________________________________________________________________________________
Volume: 02 Issue: 09 | Sep-2013, Available @ http://www.ijret.org 341
Therefore, α1 = (180 – 90) / 2 = 45o
= 0.785398 Rad,
α2 = (180 – 90) / 2 = 45o
= 0.785398 Rad,
Area of legs = (200+ 150 – 18) x 18 = 5976.0000 mm2
Area of Circular Spandrel (Fillet) ECF = 39.11118 mm2
The two negative spandrel areas, one at each free end,
i.e., Twice the Area of Negative Spandrel
ABG = 19.36782 mm2
Therefore, area of Angle section = 5976.0000 + 39.11118
– 19.36782
= 5976.375553
Therefore area in cm2
= 59.76 cm2
(correct to two decimal
places), the value exactly matches with the value given in SP:
6(1) -1964 [2].
3. RESULTS AND DISCUSSION
The SP: 6(1) -1964 [2] gives details of 65 – I sections, 27
channel sections, 72 equal angle sections, 65 unequal angle
sections and 23 – T sections. i.e., overall 252 sections. Out of
these, areas of 234 sections have been calculated in the present
paper. For the remaining 18 sections, calculations differ
because of manufacturing process and hence the results of
these sections will be taken for separate publication. As per
the methodology used in the calculation of areas of these
sections it is found that for 226 sections the difference in area
is less than 0.5 mm2
. Hence for these 226 sections, when the
area is converted to cm2
with two decimal places, they
perfectly match with the areas given in SP: 6(1) -1964 [2]. The
remaining 8 sections are only T sections. The difference in
area found by this methodology for these 8 T- sections is
greater than 0.5 mm2
and the range of difference is 0.88 to
13.01 mm2
, the range of difference in percentage being 0.15 to
0.78. Excel software has been used for the above calculations
and details are available in reference [3].
The tangent at A in fig. 1 and fig. 2, assumed to be vertical is
true for all sections except few sections which have smaller
flange thickness, such that the centre of curvature lies out of
the flange. Even with such thinner flanges, the error in the
calculation of area is found to affect the overall area in mm2
at
the second or third decimal place, and as such has been
neglected.
Table 1
I.S. Section
Given
Area
(cm2
)
Calculated
Area
(mm2
)
Calculated
Area
(cm2
)
Difference
(cm2
)
Difference
(mm2
)
Percentage
Difference (%)
ISNT 20 @ 0.9 kg/m 1.13 113.88 1.14 0.01 0.88 +0.78
ISNT 30 @ 1.4 kg/m 1.75 176.25 1.76 0.01 1.25 +0.71
ISNT 40 @ 3.5 kg/m 4.48 449.87 4.50 0.02 1.87 +0.42
ISNT 50 @ 4.5 kg/m 5.70 572.24 5.72 0.02 2.24 +0.39
ISNT 60 @ 5.4 kg/m 6.90 693.07 6.93 0.03 3.07 +0.45
ISNT 80 @ 9.6 kg/m 12.25 1229.91 12.30 0.05 4.91 +0.40
ISNT 100 @ 15.0 kg/m 19.10 1918.54 19.19 0.09 8.54 +0.45
ISNT 150 @ 22.8 kg/m 29.08 2921.01 29.21 0.13 13.01 +0.45
IJRET: International Journal of Research in Engineering and Technology eISSN: 2319-1163 | pISSN: 2321-7308
__________________________________________________________________________________________
Volume: 02 Issue: 09 | Sep-2013, Available @ http://www.ijret.org 342
CONCLUSIONS
The areas of 234 out of 252 standard steel sections namely I,
Channel, Tee, and Equal & Unequal Angle Sections have been
calculated and verified to an accuracy of two decimal places in
mm2
. It has been observed that 8 Tee sections only have
slightly different areas than mentioned in the SP: 6(1)-1964,
by the methodology used. This may lead to change in values
of parameters like Moment of Inertia, Radius of Gyration,
Section Modulus etc., which are dependent on areas or
component areas, for these sections. These results may be of
interest for the calculation of the other dependent parameters.
REFERENCES
[1]. IS 800: 2007, Indian Standard General Construction in
Steel- Code of Practice, Bureau of Indian Standards.
[2]. SP: 6(1)-1964, Handbook for Structural Engineers,
Bureau of Indian Standard (Reaffirmed in 1998).
[3] S.S. Bhavikatti and K.V. Pramod, Steel Tables with
Plastic Modulus of I.S. Sections, IK International Publishing
House Pvt. Ltd., New Delhi, India (2013).
BIOGRAPHIES
Prof. K. V. Pramod completed BE Civil and
M.Tech in Industrial Structures both from KREC
Surathkal (present NIT, Karnataka). He is
serving as Professor in Civil Department at
SDMCET, Dharwad. He handles subjects related
to Steel Design at both UG and PG levels.
Dr. Gururaj A. Kulkarni obtained his PhD from
Indian Institute of Science in the faculty of
Science in 2011. Presently he is serving the
Dept. of Physics @ SDMCET, Dharwad as an
Associate Professor. He is interested in solving
research problems related to Physics and its applications.

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Verification of areas of i.s. rolled steel sections

  • 1. IJRET: International Journal of Research in Engineering and Technology eISSN: 2319-1163 | pISSN: 2321-7308 __________________________________________________________________________________________ Volume: 02 Issue: 09 | Sep-2013, Available @ http://www.ijret.org 339 VERIFICATION OF AREAS OF I.S. ROLLED STEEL SECTIONS K. V. Pramod1 , Gururaj A. Kulkarni2 1 Professor, Civil Engineering Department, SDMCET, Karnataka, India, pramodkarnecivil@gmail.com 2 Associate Professor, Physics Department, SDMCET, Karnataka, India, gakulkarni1@gmail.com Abstract General Steel Structures are designed using standard steel sections. The design is governed by the Code IS 800-2007, and the standard steel sections are chosen from SP: 6(1)-1964.The standard steel sections regularly used in construction are, I, Channel, Tee and Angle (Equal & Unequal) sections, i.e., overall 252 sections. SP: 6(1)-1964 gives the sectional properties of all these 252 standard sections, including the cross sectional areas, for the use of designers, to select the most stable and economical section to satisfy the loading conditions of the structure. An economical section is one which has the least cross sectional area and hence, least weight. In SP: 6(1)-1964, the cross sectional areas are given in cm2 to an accuracy of two decimal places. In this paper, the accuracy of the areas of all these sections, except ISHB sections (all IS Heavy Beams) and ISWB 600 @ 145.1 kg/m, i.e., totally 234 sections, are verified in mm2 to an accuracy of two decimal places. The results show differences in values of areas for eight Tee-sections only, which have been tabulated. Cross sectional areas of all other 226 sections perfectly match with the values given in SP: 6(1)-1964. Index Terms: IS 800-2007, SP: 6(1)-1964, Cross Sectional Areas -----------------------------------------------------------------------***----------------------------------------------------------------------- 1. INTRODUCTION As per IS 800- 2007 [1], steel structures are to be designed by Limit State Method, where the designer has to select the most stable and economical section to satisfy the loading conditions of the structure. An economical section is the one which has the least cross sectional area and hence, least weight. Also, important properties like, Moment of inertia, Radius of Gyration, Section Modulus, Plastic Modulus, etc. depend upon the cross sectional area. Indian rolled steel sections consist of sloping flanges, fillets at junctions and rounded ends. These geometrical complexities have been incorporated in the calculation of the cross sectional areas in this paper. To be more specific, the Indian Standard Rolled Steel I, Channel and Tee - Sections can be seen as having two main components, namely flanges and webs. The web is usually a straight portion, with parallel edges, whose area and other properties can be easily determined. However, the flanges are in the form of cantilevering outstands having two straight non parallel edges with one end attached to the web, and the other free end rounded off by a circular arc of definite radius, r2 [2]. Also, at the junction of the flange outstand and web, a circular fillet of definite radius, r1 [2], is provided. The calculation of the area and other properties of this flange outstand portion is not simple due to these geometrical complexities. Similarly, the Indian Standard Angle Sections, both Equal and Unequal Sections, are made of two legs, each perpendicular to the other with a circular fillet of definite radius, r1 [2], at their junction. The two long edges of each leg are parallel, and the free end is rounded off by a circular arc of definite radius, r2 [2]. The cross sectional properties given by the SP: 6(1)-1964 [2] are used by the structural designers across the country (India). The nation has switched to the SI units, but the units used in the SP: 6(1) -1964 [2] still exist in cm2 , cm3 and cm4 , for some important properties like, Moment of inertia, Area, Section Modulus, etc. In this paper, the areas of the above mentioned standard sections are calculated in mm2, to an accuracy of two decimal places, considering the geometry described above, and are verified with the areas already in use, since 1964, vide SP : 6(1) -1964 [2]. The results show differences in values of areas for eight Tee-sections only and these values have been tabulated. 2. METHOD OF CALCULATION Fig. 1 represents typical geometry of the flange with non- parallel sides with respect to I, Channel and Tee sections. For I, Channel and Tee sections, the web is treated as a rectangular area, with one side as the thickness of web and the other side as the full depth of the section. The flange outstand is treated as made of three components, - (i) Trapezoidal area ABCD (ii) Circular Spandrel (Fillet) area, ECF, at the junction with web (iii) Negative Circular Spandrel area ABG, at the free end. The area of a section is the sum of the areas of the web and four flanges outstands for I sections or two flanges outstands for Channel/Tee sections.
  • 2. IJRET: International Journal of Research in Engineering and Technology eISSN: 2319-1163 | pISSN: 2321-7308 __________________________________________________________________________________________ Volume: 02 Issue: 09 | Sep-2013, Available @ http://www.ijret.org 340 The calculations of area of flange outstand is as follows: Area of the trapezium ABCD is given by: AD × ((AB + CD) / 2) .......… (1) Area of Circular Spandrel (Fillet) ECF is given by: r1 2 sinα1 (cosα1+ sinα1 tanα1) - α1 r1 2 .......… (2) Area of Negative Spandrel ABG is given by: r2 2 sinα2 (cosα2+ sinα2 tanα2) – α2 r2 2 .......… (3) Area of Cantilevering Flange outstand is given by, AGFECDA = (1) + (2) – (3) 2.1 Typical calculation for ISWB 600 @ 133.7 kg/m: As per SP: 6(1) -1964 [2]; Area = 170.38 cm2 ; Depth = 600 mm; Width of flange = 250 mm; Thickness of flange = 21.3 mm Thickness of web = 11.2 mm; r1 = 17 mm, r2 = 8.5 mm and θ = 96o ; Therefore, α1 = (180 – 96) / 2 = 42o = 0.73308 Rad, α2 = (180 – 96) / 2 = 42o = 0.73308 Rad, Area of web = 600 x 11.2 = 6720.0000 mm2 For trapezium, AB = 15.02528 mm; CD = 27.57472 mm; AD = 119.4 mm Therefore, Area of the trapezium = 2543.2200 mm2 Area of Circular Spandrel (Fillet) ECF = 48.3687 mm2 Area of Negative Spandrel ABG = 12.09218 mm2 Area of flange outstand = 2543.2200 + 48.3687 – 12.09218 = 2579.49652 mm2 Therefore, area of I section = 6720.00 + (4 x 2579.49652) = 17037.98608 mm2 Therefore, area in cm2 = 170.38 cm2 (correct to two decimal places), the value exactly matches with the value given in SP: 6(1) -1964 [2]. Fig. 2 represents typical geometry of the flange with parallel sides with respect to Equal and Unequal Angle sections. For Equal and Unequal Angle sections, the area is treated as made of (i) Two rectangular legs of given thickness, one leg with full length of leg and the other leg length reduced by the thickness value (ii) Circular Spandrel (Fillet) area, at the junction of the two legs (iii) & (iv) Negative Circular Spandrel areas, at both the free ends, which are equal. The area of an angle section is given by (i) + (ii) - (iii) – (iv). Fig.2 Geometry of Angle The calculations are as follows: Area of the two rectangular legs is given by: ( l1 + l2 – t ) × t ....… (1) Area of Circular Spandrel (Fillet) ECF is given by: r1 2 sinα1 (cosα1+ sinα1 tanα1) - α1 r1 2 ....… (2) Area of Negative Circular Spandrel, at both free ends: 2 × (r2 2 sinα2 (cosα2+ sinα2 tanα2) – α2 r2 2 ) ....… (3) & (4) 2.2 Typical calculation for ISA 200150 @ 46.9 kg/m: As per SP: 6(1) -1964 [2]; Thickness = 18 mm; Area = 59.76 cm2 ; r1 = 13.5 mm, r2 = 9.5 mm and θ = 90o ; r1 r2 θ A B C D E F G α1 O1 α2 O2 tangentassumed Fig.1 Flange Geometry of I, C & T Sections r1 r2 vertical
  • 3. IJRET: International Journal of Research in Engineering and Technology eISSN: 2319-1163 | pISSN: 2321-7308 __________________________________________________________________________________________ Volume: 02 Issue: 09 | Sep-2013, Available @ http://www.ijret.org 341 Therefore, α1 = (180 – 90) / 2 = 45o = 0.785398 Rad, α2 = (180 – 90) / 2 = 45o = 0.785398 Rad, Area of legs = (200+ 150 – 18) x 18 = 5976.0000 mm2 Area of Circular Spandrel (Fillet) ECF = 39.11118 mm2 The two negative spandrel areas, one at each free end, i.e., Twice the Area of Negative Spandrel ABG = 19.36782 mm2 Therefore, area of Angle section = 5976.0000 + 39.11118 – 19.36782 = 5976.375553 Therefore area in cm2 = 59.76 cm2 (correct to two decimal places), the value exactly matches with the value given in SP: 6(1) -1964 [2]. 3. RESULTS AND DISCUSSION The SP: 6(1) -1964 [2] gives details of 65 – I sections, 27 channel sections, 72 equal angle sections, 65 unequal angle sections and 23 – T sections. i.e., overall 252 sections. Out of these, areas of 234 sections have been calculated in the present paper. For the remaining 18 sections, calculations differ because of manufacturing process and hence the results of these sections will be taken for separate publication. As per the methodology used in the calculation of areas of these sections it is found that for 226 sections the difference in area is less than 0.5 mm2 . Hence for these 226 sections, when the area is converted to cm2 with two decimal places, they perfectly match with the areas given in SP: 6(1) -1964 [2]. The remaining 8 sections are only T sections. The difference in area found by this methodology for these 8 T- sections is greater than 0.5 mm2 and the range of difference is 0.88 to 13.01 mm2 , the range of difference in percentage being 0.15 to 0.78. Excel software has been used for the above calculations and details are available in reference [3]. The tangent at A in fig. 1 and fig. 2, assumed to be vertical is true for all sections except few sections which have smaller flange thickness, such that the centre of curvature lies out of the flange. Even with such thinner flanges, the error in the calculation of area is found to affect the overall area in mm2 at the second or third decimal place, and as such has been neglected. Table 1 I.S. Section Given Area (cm2 ) Calculated Area (mm2 ) Calculated Area (cm2 ) Difference (cm2 ) Difference (mm2 ) Percentage Difference (%) ISNT 20 @ 0.9 kg/m 1.13 113.88 1.14 0.01 0.88 +0.78 ISNT 30 @ 1.4 kg/m 1.75 176.25 1.76 0.01 1.25 +0.71 ISNT 40 @ 3.5 kg/m 4.48 449.87 4.50 0.02 1.87 +0.42 ISNT 50 @ 4.5 kg/m 5.70 572.24 5.72 0.02 2.24 +0.39 ISNT 60 @ 5.4 kg/m 6.90 693.07 6.93 0.03 3.07 +0.45 ISNT 80 @ 9.6 kg/m 12.25 1229.91 12.30 0.05 4.91 +0.40 ISNT 100 @ 15.0 kg/m 19.10 1918.54 19.19 0.09 8.54 +0.45 ISNT 150 @ 22.8 kg/m 29.08 2921.01 29.21 0.13 13.01 +0.45
  • 4. IJRET: International Journal of Research in Engineering and Technology eISSN: 2319-1163 | pISSN: 2321-7308 __________________________________________________________________________________________ Volume: 02 Issue: 09 | Sep-2013, Available @ http://www.ijret.org 342 CONCLUSIONS The areas of 234 out of 252 standard steel sections namely I, Channel, Tee, and Equal & Unequal Angle Sections have been calculated and verified to an accuracy of two decimal places in mm2 . It has been observed that 8 Tee sections only have slightly different areas than mentioned in the SP: 6(1)-1964, by the methodology used. This may lead to change in values of parameters like Moment of Inertia, Radius of Gyration, Section Modulus etc., which are dependent on areas or component areas, for these sections. These results may be of interest for the calculation of the other dependent parameters. REFERENCES [1]. IS 800: 2007, Indian Standard General Construction in Steel- Code of Practice, Bureau of Indian Standards. [2]. SP: 6(1)-1964, Handbook for Structural Engineers, Bureau of Indian Standard (Reaffirmed in 1998). [3] S.S. Bhavikatti and K.V. Pramod, Steel Tables with Plastic Modulus of I.S. Sections, IK International Publishing House Pvt. Ltd., New Delhi, India (2013). BIOGRAPHIES Prof. K. V. Pramod completed BE Civil and M.Tech in Industrial Structures both from KREC Surathkal (present NIT, Karnataka). He is serving as Professor in Civil Department at SDMCET, Dharwad. He handles subjects related to Steel Design at both UG and PG levels. Dr. Gururaj A. Kulkarni obtained his PhD from Indian Institute of Science in the faculty of Science in 2011. Presently he is serving the Dept. of Physics @ SDMCET, Dharwad as an Associate Professor. He is interested in solving research problems related to Physics and its applications.