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Pertemuan 6-8 Fisika Modern Application Schrodinger Equation In Hydrogen Atom Hadi Nasbey, M.Si ,[object Object],[object Object],07/03/11 ©  2010 Universitas Negeri Jakarta  |  www.unj.ac.id  |
Outline ,[object Object],[object Object],[object Object],07/03/11 ©  2010 Universitas Negeri Jakarta  |  www.unj.ac.id  |
[object Object],[object Object],[object Object],[object Object],Application of the Schrödinger Equation to the Hydrogen Atom 07/03/11 ©  2010 Universitas Negeri Jakarta  |  www.unj.ac.id  |
[object Object],Spherical Coordinates Transform to spherical polar coordinates because of the radial symmetry. 07/03/11 ©  2010 Universitas Negeri Jakarta  |  www.unj.ac.id  |
The Schrödinger Equation in Spherical Coordinates Transformed into spherical coordinates, the Schrödinger equation becomes: 07/03/11 ©  2010 Universitas Negeri Jakarta  |  www.unj.ac.id  |
Separable Solution ,[object Object],[object Object],This would make life much simpler, and it turns out to work. 07/03/11 ©  2010 Universitas Negeri Jakarta  |  www.unj.ac.id  |
[object Object],Solution of the Schrödinger Equation for Hydrogen Multiply both sides by   r 2  sin 2   /  R f g : Substitute: 07/03/11 ©  2010 Universitas Negeri Jakarta  |  www.unj.ac.id  |
r  and    appear only on the left side and    appears only on the right side. The left side of the equation cannot change as    changes. The right side cannot change with either  r  or   . Each side needs to be equal to a  constant  for the equation to be true. Set the constant to be  − m ℓ 2 Solution of the Schrödinger Equation for H azimuthal equation 07/03/11 ©  2010 Universitas Negeri Jakarta  |  www.unj.ac.id  |
satisfies the azimuthal equation for any value of  m ℓ . The solution must be single valued to be a valid solution for any   : Solution of the Schrödinger Equation for H m ℓ  must be an integer (positive or negative) for this to be true. Specifically: So: 07/03/11 ©  2010 Universitas Negeri Jakarta  |  www.unj.ac.id  |
[object Object],Solution of the Schrödinger Equation for H Now, the left side depends only on  r , and the right side depends only on   .  We can use the same trick again! Rearrange it and divide by  sin 2 (  ) : 07/03/11 ©  2010 Universitas Negeri Jakarta  |  www.unj.ac.id  | − m ℓ 2
[object Object],Solution of the Schrödinger Equation for H Radial equation Angular equation We’ve separated the Schrödinger equation into three ordinary second-order differential equations, each containing only one variable. 07/03/11 ©  2010 Universitas Negeri Jakarta  |  www.unj.ac.id  |
TERIMA KASIH 07/03/11 ©  2010 Universitas Negeri Jakarta  |  www.unj.ac.id  |

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Fisika Modern 08 schrodinger eqinhydrogenatom

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  • 5. The Schrödinger Equation in Spherical Coordinates Transformed into spherical coordinates, the Schrödinger equation becomes: 07/03/11 © 2010 Universitas Negeri Jakarta | www.unj.ac.id |
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  • 8. r and  appear only on the left side and  appears only on the right side. The left side of the equation cannot change as  changes. The right side cannot change with either r or  . Each side needs to be equal to a constant for the equation to be true. Set the constant to be − m ℓ 2 Solution of the Schrödinger Equation for H azimuthal equation 07/03/11 © 2010 Universitas Negeri Jakarta | www.unj.ac.id |
  • 9. satisfies the azimuthal equation for any value of m ℓ . The solution must be single valued to be a valid solution for any  : Solution of the Schrödinger Equation for H m ℓ must be an integer (positive or negative) for this to be true. Specifically: So: 07/03/11 © 2010 Universitas Negeri Jakarta | www.unj.ac.id |
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  • 12. TERIMA KASIH 07/03/11 © 2010 Universitas Negeri Jakarta | www.unj.ac.id |