This document defines key terms and concepts related to Newton's Second Law of Motion, including force, mass, weight, and acceleration. It states Newton's Second Law - that the acceleration of an object is directly proportional to the net force acting on it, and inversely proportional to its mass. Several example problems are worked through to demonstrate how to use the law to calculate force, mass, or acceleration given values for the other two quantities.

1. Law of Acceleration
Prepared by: Jeve F. Gonzales
Isaac Newton

2. Objectives:
define and identify the units for
acceleration, mass, and force
State the Law of Acceleration
Solve problems on law of
acceleration

3. Getting started
 First, you need to define and know the units
of mass, force and acceleration:
 Force is a push or a pull
 The unit that used to measure Force is
Newton (N)
 Gravity is the force of attraction that exists
between two objects that have mass
 The force of gravity depends on the mass of
the object and the distance between them.

4. The force of the gravity causes all objects
near Earth’s surface to fall with an
acceleration of 9.8 m/s².
Your weight on Earth is the gravitational
force between you and Earth.

5. How are weight and mass different?
Weight is a force and is measured in
newtons
Mass is the amount of matter in an object
and does not depend on location
- it is measured in kg
Weight will vary in location but mass will
remain constant.
F = W = mg

6. Acceleration
Is a change in velocity
 Speeding up
- positive acceleration
 Slowing down
- negative acceleration
- deceleration
 Changing direction
 Unbalanced forces cause objects to accelerate

10. But there is a twist
Acceleration is inversely related
to the mass of the object

12. a ∝ F a ∝ 1/𝑚 a = F/m

13. 1.

14. Given:
m = 1 000 kg
a = 0.05 m/s²
F = ?
Solution:
F= ma
F = 1 000 kg x 0.05 m/s²
F= 50 kg.m/s² or 50 N

15. Problem Number 2
A golf ball has a mass of
approximately 0.046 kg.
How much force must be
applied by the tee so
that the ball will move
from rest to 8.25 m/s in
10.0 seconds?

16. Given:
m = 0.046 kg F = ?
t = 10 sec.
Vi = 0
Vf = 8.25 m/s
Solving for acceleration,
a = vf-vi
t
a = 8.25 m/s – 0
10 sec
F = ma
F = 0.046 kg x 0.825 m/s²
a = 0.825 m/s²
F = 0.038 N

17. Problem no. 3
Suppose a bus
weighs 1,200N and
slows down in a
distance of 55m from
50m/s. How much
force is exerted to
the brakes?

18. Given:
w = 1,200 N F =?
d = 55 m
Vf = 0
Vi = 50 m/s
Solution:
a = vf²-Vi²
2d
a =(0)² – (50 m/s)²
2 (55 m )
a = - 2 500 m²/s²
110 m
m = w/g
m = 1, 200 kg.m/s²
-9.8 m/s²
F = ma
F = (- 122.45 kg) ( - 22.73
m/s²)
a = - 22.73 m/s²
m = - 122.45 kg
F = 2, 783.29 N

19. Supply the following with the
correct answer:
Net Force
(N)
Mass
(kg)
Acceleration
( m/s²)
10 2 5
20 2 10
20 5
10 5
1 10

20. Net Force N) Mass
(kg)
Acceleration
( m/s²)
10 2 5
20 2 10
20 4 5
10 5 2
10 1 10
If mass remains constant, doubling the acceleration,
doubles the force. If force remains constant, doubling
the mass, halves the acceleration.

21. Thank you!