Ecuaciones Logaritmicas (Caso II)
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The document discusses solving a logarithmic equation (log(x+6) = 1 + log(x-3)). It shows the steps of: 1) Isolating the logarithm terms 2) Applying the property that log(a) - log(b) = log(a/b) 3) Solving the resulting equation The solution is found to be x = 4.
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Ecuaciones Logaritmicas (Caso II)
- 2. Ecuaciones Logarítmicas (Caso II) log (x + 6) = 1 + log (x – 3)
- 3. Ecuaciones Logarítmicas (Caso II) log (x + 6) = 1 + log (x – 3) log (x + 6) - log (x – 3) = 1
- 4. Ecuaciones Logarítmicas (Caso II) log (x + 6) = 1 + log (x – 3) log (x + 6) - log (x – 3) = 1 log = 1
- 5. Ecuaciones Logarítmicas (Caso II) log (x + 6) = 1 + log (x – 3) log (x + 6) - log (x – 3) = 1 log = 1 10 1 =
- 6. Ecuaciones Logarítmicas (Caso II) log (x + 6) = 1 + log (x – 3) log (x + 6) - log (x – 3) = 1 log = 1 10 1 = 10 (x – 3) = x + 6
- 7. Ecuaciones Logarítmicas (Caso II) log (x + 6) = 1 + log (x – 3) log (x + 6) - log (x – 3) = 1 log = 1 10 1 = 10 (x – 3) = x + 6 10 x – 30 = x + 6
- 8. Ecuaciones Logarítmicas (Caso II) log (x + 6) = 1 + log (x – 3) log (x + 6) - log (x – 3) = 1 log = 1 10 1 = 10 (x – 3) = x + 6 10 x – 30 = x + 6 10 x – x = 30 + 6
- 9. Ecuaciones Logarítmicas (Caso II) log (x + 6) = 1 + log (x – 3) log (x + 6) - log (x – 3) = 1 log = 1 10 1 = 10 (x – 3) = x + 6 10 x – 30 = x + 6 10 x – x = 30 + 6 9 x = 36
- 10. Ecuaciones Logarítmicas (Caso II) log (x + 6) = 1 + log (x – 3) log (x + 6) - log (x – 3) = 1 log = 1 10 1 = 10 (x – 3) = x + 6 10 x – 30 = x + 6 10 x – x = 30 + 6 9 x = 36
- 11. Ecuaciones Logarítmicas (Caso II) log (x + 6) = 1 + log (x – 3) log (x + 6) - log (x – 3) = 1 log = 1 10 1 = 10 (x – 3) = x + 6 10 x – 30 = x + 6 10 x – x = 30 + 6 9 x = 36
- 12. Fin de la presentación