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SECTION 2-7 
Proving Segment Relationships
ESSENTIAL QUESTIONS 
How do you write proofs involving segment addition? 
How do you write proofs involving segment 
congruence?
POSTULATES & THEOREMS 
Ruler Postulate: 
Segment Addition Postulate:
POSTULATES & THEOREMS 
Rule r P o s t u l a t e : The points on any line or segment can be put 
into one-to-one correspondence with real numbers 
Segment Addition Postulate:
POSTULATES & THEOREMS 
Rule r P o s t u l a t e : The points on any line or segment can be put 
into one-to-one correspondence with real numbers 
You can measure the distance between two points 
Segment Addition Postulate:
POSTULATES & THEOREMS 
Rule r P o s t u l a t e : The points on any line or segment can be put 
into one-to-one correspondence with real numbers 
You can measure the distance between two points 
Segm e n t A d d i t i o n P o s t u l a t e : If A, B, and C are collinear, then B is 
between A and C if and only if (IFF) AB + BC = AC
THEOREM 2.2 - PROPERTIES OF 
SEGMENT CONGRUENCE 
Reflexive Property of Congruence: 
Symmetric Property of Congruence: 
Transitive Property of Congruence:
THEOREM 2.2 - PROPERTIES OF 
SEGMENT CONGRUENCE 
Reflexive Property of Congruence: 
Symmetric Property of Congruence: 
Transitive Property of Congruence:
THEOREM 2.2 - PROPERTIES OF 
SEGMENT CONGRUENCE 
Reflexive Property of Congruence: 
Symmetric Property of Congruence: If AB ≅ CD, then CD ≅ AB 
Transitive Property of Congruence:
THEOREM 2.2 - PROPERTIES OF 
SEGMENT CONGRUENCE 
Reflexive Property of Congruence: 
Symmetric Property of Congruence: If AB ≅ CD, then CD ≅ AB 
Transitive Property of Congruence: If AB ≅ CD and CD ≅ EF, then 
AB ≅ EF
EXAMPLE 1 
Prove that if AB ≅ CD, then AC ≅ BD
EXAMPLE 1 
Prove that if AB ≅ CD, then AC ≅ BD 
1. AB ≅ CD
EXAMPLE 1 
Prove that if AB ≅ CD, then AC ≅ BD 
1. AB ≅ CD Given
EXAMPLE 1 
Prove that if AB ≅ CD, then AC ≅ BD 
1. AB ≅ CD Given 
2. AB = CD
EXAMPLE 1 
Prove that if AB ≅ CD, then AC ≅ BD 
1. AB ≅ CD Given 
2. AB = CD Def. of ≅ segments
EXAMPLE 1 
Prove that if AB ≅ CD, then AC ≅ BD 
1. AB ≅ CD Given 
2. AB = CD Def. of ≅ segments 
3. BC = BC
EXAMPLE 1 
Prove that if AB ≅ CD, then AC ≅ BD 
1. AB ≅ CD Given 
2. AB = CD Def. of ≅ segments 
3. BC = BC Reflexive property of equality
EXAMPLE 1 
Prove that if AB ≅ CD, then AC ≅ BD 
1. AB ≅ CD Given 
2. AB = CD Def. of ≅ segments 
3. BC = BC Reflexive property of equality 
4. AB + BC = AC
EXAMPLE 1 
Prove that if AB ≅ CD, then AC ≅ BD 
1. AB ≅ CD Given 
2. AB = CD Def. of ≅ segments 
3. BC = BC Reflexive property of equality 
4. AB + BC = AC Segment Addition
EXAMPLE 1 
Prove that if AB ≅ CD, then AC ≅ BD 
1. AB ≅ CD Given 
2. AB = CD Def. of ≅ segments 
3. BC = BC Reflexive property of equality 
4. AB + BC = AC Segment Addition 
5. CD + BC = AC
EXAMPLE 1 
Prove that if AB ≅ CD, then AC ≅ BD 
1. AB ≅ CD Given 
2. AB = CD Def. of ≅ segments 
3. BC = BC Reflexive property of equality 
4. AB + BC = AC Segment Addition 
5. CD + BC = AC Substitution prop. of equality
EXAMPLE 1 
Prove that if AB ≅ CD, then AC ≅ BD
EXAMPLE 1 
Prove that if AB ≅ CD, then AC ≅ BD 
6. CD + BC = BD
EXAMPLE 1 
Prove that if AB ≅ CD, then AC ≅ BD 
6. CD + BC = BD Segment Addition
EXAMPLE 1 
Prove that if AB ≅ CD, then AC ≅ BD 
6. CD + BC = BD Segment Addition 
7. AC = BD
EXAMPLE 1 
Prove that if AB ≅ CD, then AC ≅ BD 
6. CD + BC = BD Segment Addition 
7. AC = BD Substitution property of equality
EXAMPLE 1 
Prove that if AB ≅ CD, then AC ≅ BD 
6. CD + BC = BD Segment Addition 
7. AC = BD Substitution property of equality 
8. AC ≅ BD
EXAMPLE 1 
Prove that if AB ≅ CD, then AC ≅ BD 
6. CD + BC = BD Segment Addition 
7. AC = BD Substitution property of equality 
8. AC ≅ BD Def. of ≅ segments
PROOF 
The Transitive Property of Congruence 
If AB ≅ CD and CD ≅ EF, then AB ≅ EF
PROOF 
The Transitive Property of Congruence 
If AB ≅ CD and CD ≅ EF, then AB ≅ EF 
1. AB ≅ CD and CD ≅ EF
PROOF 
The Transitive Property of Congruence 
If AB ≅ CD and CD ≅ EF, then AB ≅ EF 
1. AB ≅ CD and CD ≅ EF Given
PROOF 
The Transitive Property of Congruence 
If AB ≅ CD and CD ≅ EF, then AB ≅ EF 
1. AB ≅ CD and CD ≅ EF Given 
2. AB = CD and CD = EF
PROOF 
The Transitive Property of Congruence 
If AB ≅ CD and CD ≅ EF, then AB ≅ EF 
1. AB ≅ CD and CD ≅ EF Given 
2. AB = CD and CD = EF Def. of ≅ segments
PROOF 
The Transitive Property of Congruence 
If AB ≅ CD and CD ≅ EF, then AB ≅ EF 
1. AB ≅ CD and CD ≅ EF Given 
2. AB = CD and CD = EF Def. of ≅ segments 
3. AB = EF
PROOF 
The Transitive Property of Congruence 
If AB ≅ CD and CD ≅ EF, then AB ≅ EF 
1. AB ≅ CD and CD ≅ EF Given 
2. AB = CD and CD = EF Def. of ≅ segments 
3. AB = EF Transitive property 
of Equality
PROOF 
The Transitive Property of Congruence 
If AB ≅ CD and CD ≅ EF, then AB ≅ EF 
1. AB ≅ CD and CD ≅ EF Given 
2. AB = CD and CD = EF Def. of ≅ segments 
3. AB = EF Transitive property 
of Equality 
4. AB ≅ EF
PROOF 
The Transitive Property of Congruence 
If AB ≅ CD and CD ≅ EF, then AB ≅ EF 
1. AB ≅ CD and CD ≅ EF Given 
2. AB = CD and CD = EF Def. of ≅ segments 
3. AB = EF Transitive property 
of Equality 
4. AB ≅ EF Def. of ≅ segments
EXAMPLE 2 
Matt Mitarnowski is designing a badge for his club. The length of 
the top edge of the badge is equal to the length of the left edge of the 
badge. The top edge of the badge is congruent to the right edge of the 
badge, and the right edge of the badge is congruent to the bottom edge 
of the badge. Prove that the bottom edge of the badge is congruent to 
the left edge of the badge.
EXAMPLE 2 
Matt Mitarnowski is designing a badge for his club. The length of 
the top edge of the badge is equal to the length of the left edge of the 
badge. The top edge of the badge is congruent to the right edge of the 
badge, and the right edge of the badge is congruent to the bottom edge 
of the badge. Prove that the bottom edge of the badge is congruent to 
the left edge of the badge. 
A B 
D C
EXAMPLE 2 
Matt Mitarnowski is designing a badge for his club. The length of 
the top edge of the badge is equal to the length of the left edge of the 
badge. The top edge of the badge is congruent to the right edge of the 
badge, and the right edge of the badge is congruent to the bottom edge 
of the badge. Prove that the bottom edge of the badge is congruent to 
the left edge of the badge. 
A B 
D C 
Given: AB = AD, AB ≅ BC, and BC ≅ CD
EXAMPLE 2 
Matt Mitarnowski is designing a badge for his club. The length of 
the top edge of the badge is equal to the length of the left edge of the 
badge. The top edge of the badge is congruent to the right edge of the 
badge, and the right edge of the badge is congruent to the bottom edge 
of the badge. Prove that the bottom edge of the badge is congruent to 
the left edge of the badge. 
A B 
D C 
Given: AB = AD, AB ≅ BC, and BC ≅ CD 
Prove: AD ≅ CD
EXAMPLE 2 A B 
D C
EXAMPLE 2 
1. AB = AD, 
AB ≅ BC, and 
BC ≅ CD 
A B 
D C
EXAMPLE 2 
1. AB = AD, 
AB ≅ BC, and 
BC ≅ CD 
A B 
D C 
Given
EXAMPLE 2 
1. AB = AD, 
AB ≅ BC, and 
BC ≅ CD 
Given 
2. AB ≅ AD 
A B 
D C
EXAMPLE 2 
1. AB = AD, 
AB ≅ BC, and 
BC ≅ CD 
A B 
D C 
Given 
2. AB ≅ AD Def. of ≅ segments
EXAMPLE 2 
1. AB = AD, 
AB ≅ BC, and 
BC ≅ CD 
Given 
2. AB ≅ AD Def. of ≅ segments 
3. AB ≅ CD 
A B 
D C
EXAMPLE 2 
1. AB = AD, 
AB ≅ BC, and 
BC ≅ CD 
A B 
D C 
Given 
2. AB ≅ AD Def. of ≅ segments 
3. AB ≅ CD Transitive property
EXAMPLE 2 
1. AB = AD, 
AB ≅ BC, and 
BC ≅ CD 
A B 
D C 
Given 
2. AB ≅ AD Def. of ≅ segments 
3. AB ≅ CD Transitive property 
4. AD ≅ AB
EXAMPLE 2 
1. AB = AD, 
AB ≅ BC, and 
BC ≅ CD 
A B 
D C 
Given 
2. AB ≅ AD Def. of ≅ segments 
3. AB ≅ CD Transitive property 
4. AD ≅ AB Symmetric property
EXAMPLE 2 
1. AB = AD, 
AB ≅ BC, and 
BC ≅ CD 
A B 
D C 
Given 
2. AB ≅ AD Def. of ≅ segments 
3. AB ≅ CD Transitive property 
4. AD ≅ AB Symmetric property 
5. AD ≅ CD
EXAMPLE 2 
1. AB = AD, 
AB ≅ BC, and 
BC ≅ CD 
A B 
D C 
Given 
2. AB ≅ AD Def. of ≅ segments 
3. AB ≅ CD Transitive property 
4. AD ≅ AB Symmetric property 
5. AD ≅ CD Transitive property
PROBLEM SET
PROBLEM SET 
p. 145 #1-13, 15, 17, 18 
“Trust yourself. Think for yourself. Act for yourself. Speak for 
yourself. Be yourself. Imitation is suicide.” - Marva Collins

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Geometry Section 2-7 1112

  • 1. SECTION 2-7 Proving Segment Relationships
  • 2. ESSENTIAL QUESTIONS How do you write proofs involving segment addition? How do you write proofs involving segment congruence?
  • 3. POSTULATES & THEOREMS Ruler Postulate: Segment Addition Postulate:
  • 4. POSTULATES & THEOREMS Rule r P o s t u l a t e : The points on any line or segment can be put into one-to-one correspondence with real numbers Segment Addition Postulate:
  • 5. POSTULATES & THEOREMS Rule r P o s t u l a t e : The points on any line or segment can be put into one-to-one correspondence with real numbers You can measure the distance between two points Segment Addition Postulate:
  • 6. POSTULATES & THEOREMS Rule r P o s t u l a t e : The points on any line or segment can be put into one-to-one correspondence with real numbers You can measure the distance between two points Segm e n t A d d i t i o n P o s t u l a t e : If A, B, and C are collinear, then B is between A and C if and only if (IFF) AB + BC = AC
  • 7. THEOREM 2.2 - PROPERTIES OF SEGMENT CONGRUENCE Reflexive Property of Congruence: Symmetric Property of Congruence: Transitive Property of Congruence:
  • 8. THEOREM 2.2 - PROPERTIES OF SEGMENT CONGRUENCE Reflexive Property of Congruence: Symmetric Property of Congruence: Transitive Property of Congruence:
  • 9. THEOREM 2.2 - PROPERTIES OF SEGMENT CONGRUENCE Reflexive Property of Congruence: Symmetric Property of Congruence: If AB ≅ CD, then CD ≅ AB Transitive Property of Congruence:
  • 10. THEOREM 2.2 - PROPERTIES OF SEGMENT CONGRUENCE Reflexive Property of Congruence: Symmetric Property of Congruence: If AB ≅ CD, then CD ≅ AB Transitive Property of Congruence: If AB ≅ CD and CD ≅ EF, then AB ≅ EF
  • 11. EXAMPLE 1 Prove that if AB ≅ CD, then AC ≅ BD
  • 12. EXAMPLE 1 Prove that if AB ≅ CD, then AC ≅ BD 1. AB ≅ CD
  • 13. EXAMPLE 1 Prove that if AB ≅ CD, then AC ≅ BD 1. AB ≅ CD Given
  • 14. EXAMPLE 1 Prove that if AB ≅ CD, then AC ≅ BD 1. AB ≅ CD Given 2. AB = CD
  • 15. EXAMPLE 1 Prove that if AB ≅ CD, then AC ≅ BD 1. AB ≅ CD Given 2. AB = CD Def. of ≅ segments
  • 16. EXAMPLE 1 Prove that if AB ≅ CD, then AC ≅ BD 1. AB ≅ CD Given 2. AB = CD Def. of ≅ segments 3. BC = BC
  • 17. EXAMPLE 1 Prove that if AB ≅ CD, then AC ≅ BD 1. AB ≅ CD Given 2. AB = CD Def. of ≅ segments 3. BC = BC Reflexive property of equality
  • 18. EXAMPLE 1 Prove that if AB ≅ CD, then AC ≅ BD 1. AB ≅ CD Given 2. AB = CD Def. of ≅ segments 3. BC = BC Reflexive property of equality 4. AB + BC = AC
  • 19. EXAMPLE 1 Prove that if AB ≅ CD, then AC ≅ BD 1. AB ≅ CD Given 2. AB = CD Def. of ≅ segments 3. BC = BC Reflexive property of equality 4. AB + BC = AC Segment Addition
  • 20. EXAMPLE 1 Prove that if AB ≅ CD, then AC ≅ BD 1. AB ≅ CD Given 2. AB = CD Def. of ≅ segments 3. BC = BC Reflexive property of equality 4. AB + BC = AC Segment Addition 5. CD + BC = AC
  • 21. EXAMPLE 1 Prove that if AB ≅ CD, then AC ≅ BD 1. AB ≅ CD Given 2. AB = CD Def. of ≅ segments 3. BC = BC Reflexive property of equality 4. AB + BC = AC Segment Addition 5. CD + BC = AC Substitution prop. of equality
  • 22. EXAMPLE 1 Prove that if AB ≅ CD, then AC ≅ BD
  • 23. EXAMPLE 1 Prove that if AB ≅ CD, then AC ≅ BD 6. CD + BC = BD
  • 24. EXAMPLE 1 Prove that if AB ≅ CD, then AC ≅ BD 6. CD + BC = BD Segment Addition
  • 25. EXAMPLE 1 Prove that if AB ≅ CD, then AC ≅ BD 6. CD + BC = BD Segment Addition 7. AC = BD
  • 26. EXAMPLE 1 Prove that if AB ≅ CD, then AC ≅ BD 6. CD + BC = BD Segment Addition 7. AC = BD Substitution property of equality
  • 27. EXAMPLE 1 Prove that if AB ≅ CD, then AC ≅ BD 6. CD + BC = BD Segment Addition 7. AC = BD Substitution property of equality 8. AC ≅ BD
  • 28. EXAMPLE 1 Prove that if AB ≅ CD, then AC ≅ BD 6. CD + BC = BD Segment Addition 7. AC = BD Substitution property of equality 8. AC ≅ BD Def. of ≅ segments
  • 29. PROOF The Transitive Property of Congruence If AB ≅ CD and CD ≅ EF, then AB ≅ EF
  • 30. PROOF The Transitive Property of Congruence If AB ≅ CD and CD ≅ EF, then AB ≅ EF 1. AB ≅ CD and CD ≅ EF
  • 31. PROOF The Transitive Property of Congruence If AB ≅ CD and CD ≅ EF, then AB ≅ EF 1. AB ≅ CD and CD ≅ EF Given
  • 32. PROOF The Transitive Property of Congruence If AB ≅ CD and CD ≅ EF, then AB ≅ EF 1. AB ≅ CD and CD ≅ EF Given 2. AB = CD and CD = EF
  • 33. PROOF The Transitive Property of Congruence If AB ≅ CD and CD ≅ EF, then AB ≅ EF 1. AB ≅ CD and CD ≅ EF Given 2. AB = CD and CD = EF Def. of ≅ segments
  • 34. PROOF The Transitive Property of Congruence If AB ≅ CD and CD ≅ EF, then AB ≅ EF 1. AB ≅ CD and CD ≅ EF Given 2. AB = CD and CD = EF Def. of ≅ segments 3. AB = EF
  • 35. PROOF The Transitive Property of Congruence If AB ≅ CD and CD ≅ EF, then AB ≅ EF 1. AB ≅ CD and CD ≅ EF Given 2. AB = CD and CD = EF Def. of ≅ segments 3. AB = EF Transitive property of Equality
  • 36. PROOF The Transitive Property of Congruence If AB ≅ CD and CD ≅ EF, then AB ≅ EF 1. AB ≅ CD and CD ≅ EF Given 2. AB = CD and CD = EF Def. of ≅ segments 3. AB = EF Transitive property of Equality 4. AB ≅ EF
  • 37. PROOF The Transitive Property of Congruence If AB ≅ CD and CD ≅ EF, then AB ≅ EF 1. AB ≅ CD and CD ≅ EF Given 2. AB = CD and CD = EF Def. of ≅ segments 3. AB = EF Transitive property of Equality 4. AB ≅ EF Def. of ≅ segments
  • 38. EXAMPLE 2 Matt Mitarnowski is designing a badge for his club. The length of the top edge of the badge is equal to the length of the left edge of the badge. The top edge of the badge is congruent to the right edge of the badge, and the right edge of the badge is congruent to the bottom edge of the badge. Prove that the bottom edge of the badge is congruent to the left edge of the badge.
  • 39. EXAMPLE 2 Matt Mitarnowski is designing a badge for his club. The length of the top edge of the badge is equal to the length of the left edge of the badge. The top edge of the badge is congruent to the right edge of the badge, and the right edge of the badge is congruent to the bottom edge of the badge. Prove that the bottom edge of the badge is congruent to the left edge of the badge. A B D C
  • 40. EXAMPLE 2 Matt Mitarnowski is designing a badge for his club. The length of the top edge of the badge is equal to the length of the left edge of the badge. The top edge of the badge is congruent to the right edge of the badge, and the right edge of the badge is congruent to the bottom edge of the badge. Prove that the bottom edge of the badge is congruent to the left edge of the badge. A B D C Given: AB = AD, AB ≅ BC, and BC ≅ CD
  • 41. EXAMPLE 2 Matt Mitarnowski is designing a badge for his club. The length of the top edge of the badge is equal to the length of the left edge of the badge. The top edge of the badge is congruent to the right edge of the badge, and the right edge of the badge is congruent to the bottom edge of the badge. Prove that the bottom edge of the badge is congruent to the left edge of the badge. A B D C Given: AB = AD, AB ≅ BC, and BC ≅ CD Prove: AD ≅ CD
  • 42. EXAMPLE 2 A B D C
  • 43. EXAMPLE 2 1. AB = AD, AB ≅ BC, and BC ≅ CD A B D C
  • 44. EXAMPLE 2 1. AB = AD, AB ≅ BC, and BC ≅ CD A B D C Given
  • 45. EXAMPLE 2 1. AB = AD, AB ≅ BC, and BC ≅ CD Given 2. AB ≅ AD A B D C
  • 46. EXAMPLE 2 1. AB = AD, AB ≅ BC, and BC ≅ CD A B D C Given 2. AB ≅ AD Def. of ≅ segments
  • 47. EXAMPLE 2 1. AB = AD, AB ≅ BC, and BC ≅ CD Given 2. AB ≅ AD Def. of ≅ segments 3. AB ≅ CD A B D C
  • 48. EXAMPLE 2 1. AB = AD, AB ≅ BC, and BC ≅ CD A B D C Given 2. AB ≅ AD Def. of ≅ segments 3. AB ≅ CD Transitive property
  • 49. EXAMPLE 2 1. AB = AD, AB ≅ BC, and BC ≅ CD A B D C Given 2. AB ≅ AD Def. of ≅ segments 3. AB ≅ CD Transitive property 4. AD ≅ AB
  • 50. EXAMPLE 2 1. AB = AD, AB ≅ BC, and BC ≅ CD A B D C Given 2. AB ≅ AD Def. of ≅ segments 3. AB ≅ CD Transitive property 4. AD ≅ AB Symmetric property
  • 51. EXAMPLE 2 1. AB = AD, AB ≅ BC, and BC ≅ CD A B D C Given 2. AB ≅ AD Def. of ≅ segments 3. AB ≅ CD Transitive property 4. AD ≅ AB Symmetric property 5. AD ≅ CD
  • 52. EXAMPLE 2 1. AB = AD, AB ≅ BC, and BC ≅ CD A B D C Given 2. AB ≅ AD Def. of ≅ segments 3. AB ≅ CD Transitive property 4. AD ≅ AB Symmetric property 5. AD ≅ CD Transitive property
  • 54. PROBLEM SET p. 145 #1-13, 15, 17, 18 “Trust yourself. Think for yourself. Act for yourself. Speak for yourself. Be yourself. Imitation is suicide.” - Marva Collins