SlideShare une entreprise Scribd logo
1  sur  78
Chapter 6
Graphing Functions
Section 6-1
Distance in the Coordinate Plane
Essential Questions

How do you use the distance formula to find the distance
between two points?

How do you use the midpoint formula?



Where you’ll see this:

  Geography, market research, community service,
  architecture
Vocabulary
1. Coordinate Plane:


2. Quadrants:

3. x-axis:

4. y-axis:

5. Ordered Pairs:

6. Origin:
Vocabulary
1. Coordinate Plane: Two number lines drawn perpendicular to each
    other

2. Quadrants:

3. x-axis:

4. y-axis:

5. Ordered Pairs:

6. Origin:
Vocabulary
1. Coordinate Plane: Two number lines drawn perpendicular to each
    other; used for graphing points

2. Quadrants:

3. x-axis:

4. y-axis:

5. Ordered Pairs:

6. Origin:
Vocabulary
1. Coordinate Plane: Two number lines drawn perpendicular to each
    other; used for graphing points

2. Quadrants: Four areas created by the coordinate plane

3. x-axis:

4. y-axis:

5. Ordered Pairs:

6. Origin:
Vocabulary
1. Coordinate Plane: Two number lines drawn perpendicular to each
    other; used for graphing points

2. Quadrants: Four areas created by the coordinate plane

3. x-axis: The horizontal axis on the coordinate plane

4. y-axis:

5. Ordered Pairs:

6. Origin:
Vocabulary
1. Coordinate Plane: Two number lines drawn perpendicular to each
    other; used for graphing points

2. Quadrants: Four areas created by the coordinate plane

3. x-axis: The horizontal axis on the coordinate plane

4. y-axis: The vertical axis on the coordinate plane

5. Ordered Pairs:

6. Origin:
Vocabulary
1. Coordinate Plane: Two number lines drawn perpendicular to each
    other; used for graphing points

2. Quadrants: Four areas created by the coordinate plane

3. x-axis: The horizontal axis on the coordinate plane

4. y-axis: The vertical axis on the coordinate plane

5. Ordered Pairs: Give us points in the form (x, y)

6. Origin:
Vocabulary
1. Coordinate Plane: Two number lines drawn perpendicular to each
    other; used for graphing points

2. Quadrants: Four areas created by the coordinate plane

3. x-axis: The horizontal axis on the coordinate plane

4. y-axis: The vertical axis on the coordinate plane

5. Ordered Pairs: Give us points in the form (x, y)

6. Origin: The point (0, 0), which is where the x-axis and y-axis meet
Example 1

 The vertices of rectangle ABCD are as follows: A = (-2, -2),
B = (4, -2), C = (4, 5), and D = (-2, 5). Find the area of ABCD.
Example 1

 The vertices of rectangle ABCD are as follows: A = (-2, -2),
B = (4, -2), C = (4, 5), and D = (-2, 5). Find the area of ABCD.




        A
Example 1

 The vertices of rectangle ABCD are as follows: A = (-2, -2),
B = (4, -2), C = (4, 5), and D = (-2, 5). Find the area of ABCD.




        A             B
Example 1

 The vertices of rectangle ABCD are as follows: A = (-2, -2),
B = (4, -2), C = (4, 5), and D = (-2, 5). Find the area of ABCD.

                      C




        A             B
Example 1

 The vertices of rectangle ABCD are as follows: A = (-2, -2),
B = (4, -2), C = (4, 5), and D = (-2, 5). Find the area of ABCD.

         D            C




        A             B
Example 1

 The vertices of rectangle ABCD are as follows: A = (-2, -2),
B = (4, -2), C = (4, 5), and D = (-2, 5). Find the area of ABCD.

         D            C




        A             B
Example 1

 The vertices of rectangle ABCD are as follows: A = (-2, -2),
B = (4, -2), C = (4, 5), and D = (-2, 5). Find the area of ABCD.

         D            C
                                AB = 4 −(−2)



        A             B
Example 1

 The vertices of rectangle ABCD are as follows: A = (-2, -2),
B = (4, -2), C = (4, 5), and D = (-2, 5). Find the area of ABCD.

         D            C
                                AB = 4 −(−2) = 4 + 2



        A             B
Example 1

 The vertices of rectangle ABCD are as follows: A = (-2, -2),
B = (4, -2), C = (4, 5), and D = (-2, 5). Find the area of ABCD.

         D            C
                                AB = 4 −(−2) = 4 + 2 = 6



        A             B
Example 1

 The vertices of rectangle ABCD are as follows: A = (-2, -2),
B = (4, -2), C = (4, 5), and D = (-2, 5). Find the area of ABCD.

                      C
         D                      AB = 4 −(−2) = 4 + 2 = 6 = 6



        A             B
Example 1

 The vertices of rectangle ABCD are as follows: A = (-2, -2),
B = (4, -2), C = (4, 5), and D = (-2, 5). Find the area of ABCD.

                      C
         D                      AB = 4 −(−2) = 4 + 2 = 6 = 6

                                AD = 5−(−2)

        A             B
Example 1

 The vertices of rectangle ABCD are as follows: A = (-2, -2),
B = (4, -2), C = (4, 5), and D = (-2, 5). Find the area of ABCD.

                      C
         D                      AB = 4 −(−2) = 4 + 2 = 6 = 6

                                AD = 5−(−2) = 5+ 2

        A             B
Example 1

 The vertices of rectangle ABCD are as follows: A = (-2, -2),
B = (4, -2), C = (4, 5), and D = (-2, 5). Find the area of ABCD.

                      C
         D                      AB = 4 −(−2) = 4 + 2 = 6 = 6

                                AD = 5−(−2) = 5+ 2 = 7

        A             B
Example 1

 The vertices of rectangle ABCD are as follows: A = (-2, -2),
B = (4, -2), C = (4, 5), and D = (-2, 5). Find the area of ABCD.

                      C
         D                      AB = 4 −(−2) = 4 + 2 = 6 = 6

                                AD = 5−(−2) = 5+ 2 = 7 = 7

        A             B
Example 1

 The vertices of rectangle ABCD are as follows: A = (-2, -2),
B = (4, -2), C = (4, 5), and D = (-2, 5). Find the area of ABCD.

                      C
         D                      AB = 4 −(−2) = 4 + 2 = 6 = 6

                                AD = 5−(−2) = 5+ 2 = 7 = 7

        A             B        Area = lw
Example 1

 The vertices of rectangle ABCD are as follows: A = (-2, -2),
B = (4, -2), C = (4, 5), and D = (-2, 5). Find the area of ABCD.

                      C
         D                      AB = 4 −(−2) = 4 + 2 = 6 = 6

                                AD = 5−(−2) = 5+ 2 = 7 = 7

        A             B        Area = lw = 6(7)
Example 1

 The vertices of rectangle ABCD are as follows: A = (-2, -2),
B = (4, -2), C = (4, 5), and D = (-2, 5). Find the area of ABCD.

                      C
         D                      AB = 4 −(−2) = 4 + 2 = 6 = 6

                                AD = 5−(−2) = 5+ 2 = 7 = 7

        A             B        Area = lw = 6(7) = 42 square units
Example 2

Find the distance between the points (0, 4) and (4, 0).
Example 2

Find the distance between the points (0, 4) and (4, 0).
Example 2

Find the distance between the points (0, 4) and (4, 0).
Example 2

Find the distance between the points (0, 4) and (4, 0).
Example 2

Find the distance between the points (0, 4) and (4, 0).
Example 2

Find the distance between the points (0, 4) and (4, 0).

                                         2   2    2
                                       a +b =c
Example 2

Find the distance between the points (0, 4) and (4, 0).

                                         2   2    2
                                       a +b =c
                                         2        2
                                                      2
                                   0−4 + 4−0 = c
Example 2

Find the distance between the points (0, 4) and (4, 0).

                                         2   2    2
                                       a +b =c
                                         2        2
                                                      2
                                   0−4 + 4−0 = c
                                        2    2    2
                                       4 +4 = c
Example 2

Find the distance between the points (0, 4) and (4, 0).

                                         2   2    2
                                       a +b =c
                                         2        2
                                                      2
                                   0−4 + 4−0 = c
                                        2    2    2
                                       4 +4 = c
                                                  2
                                      16+16 = c
Example 2

Find the distance between the points (0, 4) and (4, 0).

                                         2   2        2
                                       a +b =c
                                         2            2
                                                          2
                                   0−4 + 4−0 = c
                                        2    2        2
                                       4 +4 = c
                                                      2
                                      16+16 = c
                                                  2
                                         32 = c
Example 2

Find the distance between the points (0, 4) and (4, 0).

                                         2   2        2
                                       a +b =c
                                         2            2
                                                          2
                                   0−4 + 4−0 = c
                                        2    2        2
                                       4 +4 = c
                                                      2
                                      16+16 = c
                                                  2
                                         32 = c
                                         2
                                        c = ± 32
Example 2

Find the distance between the points (0, 4) and (4, 0).

                                         2   2        2
                                       a +b =c
                                         2            2
                                                          2
                                   0−4 + 4−0 = c
                                        2    2        2
                                       4 +4 = c
                                                      2
                                      16+16 = c
                                                  2
                                         32 = c
                                         2
                                        c = ± 32
                                        c = 32
Example 2

Find the distance between the points (0, 4) and (4, 0).

                                         2   2        2
                                       a +b =c
                                         2            2
                                                          2
                                   0−4 + 4−0 = c
                                        2    2        2
                                       4 +4 = c
                                                      2
                                      16+16 = c
                                                  2
                                         32 = c
                                         2
                                        c = ± 32
                                        c = 32 units
Distance Formula:




Midpoint Formula:
Distance Formula: d = (x1 − x2 )2 +( y1 − y2 )2 , for points (x1 , y1 ),(x2 , y2 )




Midpoint Formula:
Distance Formula: d = (x1 − x2 )2 +( y1 − y2 )2 , for points (x1 , y1 ),(x2 , y2 )

   This is nothing more than the Pythagorean Formula solved for c.




Midpoint Formula:
Distance Formula: d = (x1 − x2 )2 +( y1 − y2 )2 , for points (x1 , y1 ),(x2 , y2 )

   This is nothing more than the Pythagorean Formula solved for c.




                       x1 + x2 y1 + y2 
Midpoint Formula: M =         ,         , for points (x1 , y1 ),(x2 , y2 )
                       2          2 
Distance Formula: d = (x1 − x2 )2 +( y1 − y2 )2 , for points (x1 , y1 ),(x2 , y2 )

   This is nothing more than the Pythagorean Formula solved for c.




                       x1 + x2 y1 + y2 
Midpoint Formula: M =         ,         , for points (x1 , y1 ),(x2 , y2 )
                       2          2 

     This is nothing more than averaging the x and y coordinates.
Example 3
The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2),
                 C = (-2, -1), and D = (5, 1).
   a. What kind of quadrilateral does ABCD appear to be?
Example 3
The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2),
                 C = (-2, -1), and D = (5, 1).
   a. What kind of quadrilateral does ABCD appear to be?


            A
Example 3
    The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2),
                     C = (-2, -1), and D = (5, 1).
       a. What kind of quadrilateral does ABCD appear to be?


                A
B
Example 3
    The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2),
                     C = (-2, -1), and D = (5, 1).
       a. What kind of quadrilateral does ABCD appear to be?


                A
B



      C
Example 3
    The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2),
                     C = (-2, -1), and D = (5, 1).
       a. What kind of quadrilateral does ABCD appear to be?


                A
B
                      D


      C
Example 3
    The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2),
                     C = (-2, -1), and D = (5, 1).
       a. What kind of quadrilateral does ABCD appear to be?


                A
B
                      D


      C
Example 3
    The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2),
                     C = (-2, -1), and D = (5, 1).
       a. What kind of quadrilateral does ABCD appear to be?


                A                    This quadrilateral appears
B                                      to be a parallelogram
                      D


      C
Example 3
    The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2),
                     C = (-2, -1), and D = (5, 1).
                b. Use distances to justify your guess.


                A
B
                      D


      C
Example 3
    The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2),
                     C = (-2, -1), and D = (5, 1).
                b. Use distances to justify your guess.
                                               2          2
                               AB = (2 −(−5)) +(4 − 2)
                A
B
                      D


      C
Example 3
    The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2),
                     C = (-2, -1), and D = (5, 1).
                b. Use distances to justify your guess.
                                               2          2     2     2
                               AB = (2 −(−5)) +(4 − 2) = (7) +(2)
                A
B
                      D


      C
Example 3
    The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2),
                     C = (-2, -1), and D = (5, 1).
                b. Use distances to justify your guess.
                                               2          2     2     2
                               AB = (2 −(−5)) +(4 − 2) = (7) +(2)
                A
B                                 = 49+ 4
                      D


      C
Example 3
    The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2),
                     C = (-2, -1), and D = (5, 1).
                b. Use distances to justify your guess.
                                               2          2     2     2
                               AB = (2 −(−5)) +(4 − 2) = (7) +(2)
                A
B                                 = 49+ 4 = 53
                      D


      C
Example 3
    The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2),
                     C = (-2, -1), and D = (5, 1).
                b. Use distances to justify your guess.
                                               2          2     2     2
                               AB = (2 −(−5)) +(4 − 2) = (7) +(2)
                A
B                                 = 49+ 4 = 53 units
                      D


      C
Example 3
    The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2),
                     C = (-2, -1), and D = (5, 1).
                b. Use distances to justify your guess.
                                               2          2     2     2
                               AB = (2 −(−5)) +(4 − 2) = (7) +(2)
                A
B                                 = 49+ 4 = 53 units
                      D
                              CD = (−2 −5)2 +(−1−1)2
      C
Example 3
    The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2),
                     C = (-2, -1), and D = (5, 1).
                b. Use distances to justify your guess.
                                                 2            2   2   2
                               AB = (2 −(−5)) +(4 − 2) = (7) +(2)
                A
B                                 = 49+ 4 = 53 units
                      D
                                             2            2       2   2
                              CD = (−2 −5) +(−1−1) = (−7) +(−2)
      C
Example 3
    The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2),
                     C = (-2, -1), and D = (5, 1).
                b. Use distances to justify your guess.
                                                 2            2   2   2
                               AB = (2 −(−5)) +(4 − 2) = (7) +(2)
                A
B                                 = 49+ 4 = 53 units
                      D
                                             2            2       2   2
                              CD = (−2 −5) +(−1−1) = (−7) +(−2)
      C
                                  = 49+ 4
Example 3
    The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2),
                     C = (-2, -1), and D = (5, 1).
                b. Use distances to justify your guess.
                                                 2            2   2   2
                               AB = (2 −(−5)) +(4 − 2) = (7) +(2)
                A
B                                 = 49+ 4 = 53 units
                      D
                                             2            2       2   2
                              CD = (−2 −5) +(−1−1) = (−7) +(−2)
      C
                                  = 49+ 4 = 53
Example 3
    The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2),
                     C = (-2, -1), and D = (5, 1).
                b. Use distances to justify your guess.
                                                 2            2   2   2
                               AB = (2 −(−5)) +(4 − 2) = (7) +(2)
                A
B                                 = 49+ 4 = 53 units
                      D
                                             2            2       2   2
                              CD = (−2 −5) +(−1−1) = (−7) +(−2)
      C
                                  = 49+ 4 = 53 units
Example 3
    The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2),
                     C = (-2, -1), and D = (5, 1).
                b. Use distances to justify your guess.


                A
B
                      D


      C
Example 3
    The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2),
                     C = (-2, -1), and D = (5, 1).
                b. Use distances to justify your guess.
                                              2           2
                            BC = (−5−(−2)) +(2 −(−1))
                A
B
                      D


      C
Example 3
    The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2),
                     C = (-2, -1), and D = (5, 1).
                b. Use distances to justify your guess.
                                              2           2           2   2
                            BC = (−5−(−2)) +(2 −(−1)) = (−3) +(3)
                A
B
                      D


      C
Example 3
    The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2),
                     C = (-2, -1), and D = (5, 1).
                b. Use distances to justify your guess.
                                              2           2           2   2
                            BC = (−5−(−2)) +(2 −(−1)) = (−3) +(3)
                A
B                               = 9+ 9
                      D


      C
Example 3
    The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2),
                     C = (-2, -1), and D = (5, 1).
                b. Use distances to justify your guess.
                                              2           2           2   2
                            BC = (−5−(−2)) +(2 −(−1)) = (−3) +(3)
                A
B                               = 9+ 9 = 18
                      D


      C
Example 3
    The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2),
                     C = (-2, -1), and D = (5, 1).
                b. Use distances to justify your guess.
                                              2           2           2   2
                            BC = (−5−(−2)) +(2 −(−1)) = (−3) +(3)
                A
B                               = 9+ 9 = 18 units
                      D


      C
Example 3
    The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2),
                     C = (-2, -1), and D = (5, 1).
                b. Use distances to justify your guess.
                                              2           2           2   2
                            BC = (−5−(−2)) +(2 −(−1)) = (−3) +(3)
                A
B                               = 9+ 9 = 18 units
                      D
                                          2        2
                            AD = (2 −5) +(4 −1)
      C
Example 3
    The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2),
                     C = (-2, -1), and D = (5, 1).
                b. Use distances to justify your guess.
                                              2           2           2   2
                            BC = (−5−(−2)) +(2 −(−1)) = (−3) +(3)
                A
B                               = 9+ 9 = 18 units
                      D
                                          2        2          2   2
                            AD = (2 −5) +(4 −1) = (−3) +(3)
      C
Example 3
    The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2),
                     C = (-2, -1), and D = (5, 1).
                b. Use distances to justify your guess.
                                              2           2           2   2
                            BC = (−5−(−2)) +(2 −(−1)) = (−3) +(3)
                A
B                               = 9+ 9 = 18 units
                      D
                                          2        2          2   2
                            AD = (2 −5) +(4 −1) = (−3) +(3)
      C
                                = 9+ 9
Example 3
    The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2),
                     C = (-2, -1), and D = (5, 1).
                b. Use distances to justify your guess.
                                              2           2           2   2
                            BC = (−5−(−2)) +(2 −(−1)) = (−3) +(3)
                A
B                               = 9+ 9 = 18 units
                      D
                                          2        2          2   2
                            AD = (2 −5) +(4 −1) = (−3) +(3)
      C
                                = 9+ 9 = 18
Example 3
    The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2),
                     C = (-2, -1), and D = (5, 1).
                b. Use distances to justify your guess.
                                              2           2           2   2
                            BC = (−5−(−2)) +(2 −(−1)) = (−3) +(3)
                A
B                               = 9+ 9 = 18 units
                      D
                                          2        2          2   2
                            AD = (2 −5) +(4 −1) = (−3) +(3)
      C
                                = 9+ 9 = 18 units
Example 3
    The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2),
                     C = (-2, -1), and D = (5, 1).
                b. Use distances to justify your guess.
                                              2           2           2   2
                            BC = (−5−(−2)) +(2 −(−1)) = (−3) +(3)
                A
B                               = 9+ 9 = 18 units
                      D
                                          2        2          2   2
                            AD = (2 −5) +(4 −1) = (−3) +(3)
      C
                                = 9+ 9 = 18 units
                                     It is a parallelogram, as
                                    opposite sides are equal.
Homework
Homework



                  p. 246 #1-33 odd, 18, 34, 36




“If I have seen further it is by standing on the shoulders of giants.”
                             - Isaac Newton

Contenu connexe

Tendances

Chapter 10 practice test
Chapter 10 practice testChapter 10 practice test
Chapter 10 practice test
mlabuski
 
F4 10 Angles Of Elevation Dep
F4 10 Angles Of Elevation   DepF4 10 Angles Of Elevation   Dep
F4 10 Angles Of Elevation Dep
guestcc333c
 
Chapter 10 practice test
Chapter 10 practice testChapter 10 practice test
Chapter 10 practice test
mlabuski
 
maths sample paper 2012 class 09
maths sample paper 2012 class 09maths sample paper 2012 class 09
maths sample paper 2012 class 09
aditya36
 
Matematik soalan kertas 1
Matematik soalan kertas 1Matematik soalan kertas 1
Matematik soalan kertas 1
coxxiee
 
Assignment # 5
Assignment # 5Assignment # 5
Assignment # 5
Aya Chavez
 
F4 Add Maths - Coordinate Geometry
F4 Add Maths - Coordinate GeometryF4 Add Maths - Coordinate Geometry
F4 Add Maths - Coordinate Geometry
Pamela Mardiyah
 
Final examination 2011 class vi
Final examination 2011 class viFinal examination 2011 class vi
Final examination 2011 class vi
Asad Shafat
 

Tendances (19)

Ch 6 quadrilaterals
Ch 6 quadrilateralsCh 6 quadrilaterals
Ch 6 quadrilaterals
 
Chapter 10 practice test
Chapter 10 practice testChapter 10 practice test
Chapter 10 practice test
 
F4 10 Angles Of Elevation Dep
F4 10 Angles Of Elevation   DepF4 10 Angles Of Elevation   Dep
F4 10 Angles Of Elevation Dep
 
Chapter 10 practice test
Chapter 10 practice testChapter 10 practice test
Chapter 10 practice test
 
C14 ee-102-engg maths-1
C14 ee-102-engg maths-1C14 ee-102-engg maths-1
C14 ee-102-engg maths-1
 
maths sample paper 2012 class 09
maths sample paper 2012 class 09maths sample paper 2012 class 09
maths sample paper 2012 class 09
 
Matematik soalan kertas 1
Matematik soalan kertas 1Matematik soalan kertas 1
Matematik soalan kertas 1
 
Assignment # 5
Assignment # 5Assignment # 5
Assignment # 5
 
F4 Add Maths - Coordinate Geometry
F4 Add Maths - Coordinate GeometryF4 Add Maths - Coordinate Geometry
F4 Add Maths - Coordinate Geometry
 
Final examination 2011 class vi
Final examination 2011 class viFinal examination 2011 class vi
Final examination 2011 class vi
 
Geometry Section 1-2
Geometry Section 1-2Geometry Section 1-2
Geometry Section 1-2
 
Mathematics keynotes 1
Mathematics keynotes 1Mathematics keynotes 1
Mathematics keynotes 1
 
Đề Thi HK2 Toán 9 - TH THCS THPT  Vạn Hạnh
Đề Thi HK2 Toán 9 - TH THCS THPT  Vạn HạnhĐề Thi HK2 Toán 9 - TH THCS THPT  Vạn Hạnh
Đề Thi HK2 Toán 9 - TH THCS THPT  Vạn Hạnh
 
Đề Thi HK2 Toán 9 - Trung Tâm Gia Sư Việt Trí
Đề Thi HK2 Toán 9 - Trung Tâm Gia Sư Việt TríĐề Thi HK2 Toán 9 - Trung Tâm Gia Sư Việt Trí
Đề Thi HK2 Toán 9 - Trung Tâm Gia Sư Việt Trí
 
Final examination 2011 class viii
Final examination 2011 class viiiFinal examination 2011 class viii
Final examination 2011 class viii
 
2.6 ellipses t
2.6 ellipses t2.6 ellipses t
2.6 ellipses t
 
RELATION
RELATIONRELATION
RELATION
 
Equation of a circle
Equation of a circleEquation of a circle
Equation of a circle
 
Mathketball
MathketballMathketball
Mathketball
 

Similaire à Integrated Math 2 Section 6-1

Similaire à Integrated Math 2 Section 6-1 (20)

1.1.5 Midpoint and Partition Formulas
1.1.5 Midpoint and Partition Formulas1.1.5 Midpoint and Partition Formulas
1.1.5 Midpoint and Partition Formulas
 
ISMATDR : Coordinate Graphing Project
ISMATDR : Coordinate Graphing ProjectISMATDR : Coordinate Graphing Project
ISMATDR : Coordinate Graphing Project
 
The distance formula
The distance formulaThe distance formula
The distance formula
 
Geometry unit 6.7
Geometry unit 6.7Geometry unit 6.7
Geometry unit 6.7
 
10 Mathematics Standard.pdf
10 Mathematics Standard.pdf10 Mathematics Standard.pdf
10 Mathematics Standard.pdf
 
Obj. 20 Coordinate Proof
Obj. 20 Coordinate ProofObj. 20 Coordinate Proof
Obj. 20 Coordinate Proof
 
1.1.3 Midpoint and Partitions
1.1.3 Midpoint and Partitions1.1.3 Midpoint and Partitions
1.1.3 Midpoint and Partitions
 
Class 9 Cbse Maths Sample Paper Term 2
Class 9 Cbse Maths Sample Paper Term 2Class 9 Cbse Maths Sample Paper Term 2
Class 9 Cbse Maths Sample Paper Term 2
 
Coordinate
CoordinateCoordinate
Coordinate
 
GROUP 1 PPT QUIZ -ETECH_063817.pptx
GROUP 1 PPT QUIZ -ETECH_063817.pptxGROUP 1 PPT QUIZ -ETECH_063817.pptx
GROUP 1 PPT QUIZ -ETECH_063817.pptx
 
GROUP 1 PPT QUIZ -ETECH_063817.pptx
GROUP 1 PPT QUIZ -ETECH_063817.pptxGROUP 1 PPT QUIZ -ETECH_063817.pptx
GROUP 1 PPT QUIZ -ETECH_063817.pptx
 
Lista 4-ga-equação-da-circunferência
Lista 4-ga-equação-da-circunferênciaLista 4-ga-equação-da-circunferência
Lista 4-ga-equação-da-circunferência
 
Assignment 1.polar equation revision exercise
Assignment 1.polar equation revision exerciseAssignment 1.polar equation revision exercise
Assignment 1.polar equation revision exercise
 
Premier semestre g8
Premier semestre g8Premier semestre g8
Premier semestre g8
 
Obj. 19 Coordinate Proof
Obj. 19 Coordinate ProofObj. 19 Coordinate Proof
Obj. 19 Coordinate Proof
 
Coordinate geometry i revision card
Coordinate geometry i   revision cardCoordinate geometry i   revision card
Coordinate geometry i revision card
 
Math p1
Math p1Math p1
Math p1
 
Cbse sample-papers-class-10-maths-sa-ii-solved-2
Cbse sample-papers-class-10-maths-sa-ii-solved-2Cbse sample-papers-class-10-maths-sa-ii-solved-2
Cbse sample-papers-class-10-maths-sa-ii-solved-2
 
Cbse sample-papers-class-10-maths-sa-ii-solved-4
Cbse sample-papers-class-10-maths-sa-ii-solved-4Cbse sample-papers-class-10-maths-sa-ii-solved-4
Cbse sample-papers-class-10-maths-sa-ii-solved-4
 
1.1.1C Midpoint and Distance Formulas
1.1.1C Midpoint and Distance Formulas1.1.1C Midpoint and Distance Formulas
1.1.1C Midpoint and Distance Formulas
 

Plus de Jimbo Lamb

Plus de Jimbo Lamb (20)

Geometry Section 1-5
Geometry Section 1-5Geometry Section 1-5
Geometry Section 1-5
 
Geometry Section 1-4
Geometry Section 1-4Geometry Section 1-4
Geometry Section 1-4
 
Geometry Section 1-3
Geometry Section 1-3Geometry Section 1-3
Geometry Section 1-3
 
Geometry Section 1-2
Geometry Section 1-2Geometry Section 1-2
Geometry Section 1-2
 
Geometry Section 1-1
Geometry Section 1-1Geometry Section 1-1
Geometry Section 1-1
 
Algebra 2 Section 5-3
Algebra 2 Section 5-3Algebra 2 Section 5-3
Algebra 2 Section 5-3
 
Algebra 2 Section 5-2
Algebra 2 Section 5-2Algebra 2 Section 5-2
Algebra 2 Section 5-2
 
Algebra 2 Section 5-1
Algebra 2 Section 5-1Algebra 2 Section 5-1
Algebra 2 Section 5-1
 
Algebra 2 Section 4-9
Algebra 2 Section 4-9Algebra 2 Section 4-9
Algebra 2 Section 4-9
 
Algebra 2 Section 4-8
Algebra 2 Section 4-8Algebra 2 Section 4-8
Algebra 2 Section 4-8
 
Algebra 2 Section 4-6
Algebra 2 Section 4-6Algebra 2 Section 4-6
Algebra 2 Section 4-6
 
Geometry Section 6-6
Geometry Section 6-6Geometry Section 6-6
Geometry Section 6-6
 
Geometry Section 6-5
Geometry Section 6-5Geometry Section 6-5
Geometry Section 6-5
 
Geometry Section 6-4
Geometry Section 6-4Geometry Section 6-4
Geometry Section 6-4
 
Geometry Section 6-3
Geometry Section 6-3Geometry Section 6-3
Geometry Section 6-3
 
Geometry Section 6-2
Geometry Section 6-2Geometry Section 6-2
Geometry Section 6-2
 
Geometry Section 6-1
Geometry Section 6-1Geometry Section 6-1
Geometry Section 6-1
 
Algebra 2 Section 4-5
Algebra 2 Section 4-5Algebra 2 Section 4-5
Algebra 2 Section 4-5
 
Algebra 2 Section 4-4
Algebra 2 Section 4-4Algebra 2 Section 4-4
Algebra 2 Section 4-4
 
Algebra 2 Section 4-2
Algebra 2 Section 4-2Algebra 2 Section 4-2
Algebra 2 Section 4-2
 

Dernier

Beyond the EU: DORA and NIS 2 Directive's Global Impact
Beyond the EU: DORA and NIS 2 Directive's Global ImpactBeyond the EU: DORA and NIS 2 Directive's Global Impact
Beyond the EU: DORA and NIS 2 Directive's Global Impact
PECB
 
1029 - Danh muc Sach Giao Khoa 10 . pdf
1029 -  Danh muc Sach Giao Khoa 10 . pdf1029 -  Danh muc Sach Giao Khoa 10 . pdf
1029 - Danh muc Sach Giao Khoa 10 . pdf
QucHHunhnh
 

Dernier (20)

psychiatric nursing HISTORY COLLECTION .docx
psychiatric  nursing HISTORY  COLLECTION  .docxpsychiatric  nursing HISTORY  COLLECTION  .docx
psychiatric nursing HISTORY COLLECTION .docx
 
Ecological Succession. ( ECOSYSTEM, B. Pharmacy, 1st Year, Sem-II, Environmen...
Ecological Succession. ( ECOSYSTEM, B. Pharmacy, 1st Year, Sem-II, Environmen...Ecological Succession. ( ECOSYSTEM, B. Pharmacy, 1st Year, Sem-II, Environmen...
Ecological Succession. ( ECOSYSTEM, B. Pharmacy, 1st Year, Sem-II, Environmen...
 
ICT Role in 21st Century Education & its Challenges.pptx
ICT Role in 21st Century Education & its Challenges.pptxICT Role in 21st Century Education & its Challenges.pptx
ICT Role in 21st Century Education & its Challenges.pptx
 
Key note speaker Neum_Admir Softic_ENG.pdf
Key note speaker Neum_Admir Softic_ENG.pdfKey note speaker Neum_Admir Softic_ENG.pdf
Key note speaker Neum_Admir Softic_ENG.pdf
 
Unit-V; Pricing (Pharma Marketing Management).pptx
Unit-V; Pricing (Pharma Marketing Management).pptxUnit-V; Pricing (Pharma Marketing Management).pptx
Unit-V; Pricing (Pharma Marketing Management).pptx
 
This PowerPoint helps students to consider the concept of infinity.
This PowerPoint helps students to consider the concept of infinity.This PowerPoint helps students to consider the concept of infinity.
This PowerPoint helps students to consider the concept of infinity.
 
APM Welcome, APM North West Network Conference, Synergies Across Sectors
APM Welcome, APM North West Network Conference, Synergies Across SectorsAPM Welcome, APM North West Network Conference, Synergies Across Sectors
APM Welcome, APM North West Network Conference, Synergies Across Sectors
 
Mehran University Newsletter Vol-X, Issue-I, 2024
Mehran University Newsletter Vol-X, Issue-I, 2024Mehran University Newsletter Vol-X, Issue-I, 2024
Mehran University Newsletter Vol-X, Issue-I, 2024
 
SECOND SEMESTER TOPIC COVERAGE SY 2023-2024 Trends, Networks, and Critical Th...
SECOND SEMESTER TOPIC COVERAGE SY 2023-2024 Trends, Networks, and Critical Th...SECOND SEMESTER TOPIC COVERAGE SY 2023-2024 Trends, Networks, and Critical Th...
SECOND SEMESTER TOPIC COVERAGE SY 2023-2024 Trends, Networks, and Critical Th...
 
Advanced Views - Calendar View in Odoo 17
Advanced Views - Calendar View in Odoo 17Advanced Views - Calendar View in Odoo 17
Advanced Views - Calendar View in Odoo 17
 
Unit-IV; Professional Sales Representative (PSR).pptx
Unit-IV; Professional Sales Representative (PSR).pptxUnit-IV; Professional Sales Representative (PSR).pptx
Unit-IV; Professional Sales Representative (PSR).pptx
 
Application orientated numerical on hev.ppt
Application orientated numerical on hev.pptApplication orientated numerical on hev.ppt
Application orientated numerical on hev.ppt
 
Paris 2024 Olympic Geographies - an activity
Paris 2024 Olympic Geographies - an activityParis 2024 Olympic Geographies - an activity
Paris 2024 Olympic Geographies - an activity
 
Explore beautiful and ugly buildings. Mathematics helps us create beautiful d...
Explore beautiful and ugly buildings. Mathematics helps us create beautiful d...Explore beautiful and ugly buildings. Mathematics helps us create beautiful d...
Explore beautiful and ugly buildings. Mathematics helps us create beautiful d...
 
Presentation by Andreas Schleicher Tackling the School Absenteeism Crisis 30 ...
Presentation by Andreas Schleicher Tackling the School Absenteeism Crisis 30 ...Presentation by Andreas Schleicher Tackling the School Absenteeism Crisis 30 ...
Presentation by Andreas Schleicher Tackling the School Absenteeism Crisis 30 ...
 
Código Creativo y Arte de Software | Unidad 1
Código Creativo y Arte de Software | Unidad 1Código Creativo y Arte de Software | Unidad 1
Código Creativo y Arte de Software | Unidad 1
 
INDIA QUIZ 2024 RLAC DELHI UNIVERSITY.pptx
INDIA QUIZ 2024 RLAC DELHI UNIVERSITY.pptxINDIA QUIZ 2024 RLAC DELHI UNIVERSITY.pptx
INDIA QUIZ 2024 RLAC DELHI UNIVERSITY.pptx
 
Measures of Dispersion and Variability: Range, QD, AD and SD
Measures of Dispersion and Variability: Range, QD, AD and SDMeasures of Dispersion and Variability: Range, QD, AD and SD
Measures of Dispersion and Variability: Range, QD, AD and SD
 
Beyond the EU: DORA and NIS 2 Directive's Global Impact
Beyond the EU: DORA and NIS 2 Directive's Global ImpactBeyond the EU: DORA and NIS 2 Directive's Global Impact
Beyond the EU: DORA and NIS 2 Directive's Global Impact
 
1029 - Danh muc Sach Giao Khoa 10 . pdf
1029 -  Danh muc Sach Giao Khoa 10 . pdf1029 -  Danh muc Sach Giao Khoa 10 . pdf
1029 - Danh muc Sach Giao Khoa 10 . pdf
 

Integrated Math 2 Section 6-1

  • 2. Section 6-1 Distance in the Coordinate Plane
  • 3. Essential Questions How do you use the distance formula to find the distance between two points? How do you use the midpoint formula? Where you’ll see this: Geography, market research, community service, architecture
  • 4. Vocabulary 1. Coordinate Plane: 2. Quadrants: 3. x-axis: 4. y-axis: 5. Ordered Pairs: 6. Origin:
  • 5. Vocabulary 1. Coordinate Plane: Two number lines drawn perpendicular to each other 2. Quadrants: 3. x-axis: 4. y-axis: 5. Ordered Pairs: 6. Origin:
  • 6. Vocabulary 1. Coordinate Plane: Two number lines drawn perpendicular to each other; used for graphing points 2. Quadrants: 3. x-axis: 4. y-axis: 5. Ordered Pairs: 6. Origin:
  • 7. Vocabulary 1. Coordinate Plane: Two number lines drawn perpendicular to each other; used for graphing points 2. Quadrants: Four areas created by the coordinate plane 3. x-axis: 4. y-axis: 5. Ordered Pairs: 6. Origin:
  • 8. Vocabulary 1. Coordinate Plane: Two number lines drawn perpendicular to each other; used for graphing points 2. Quadrants: Four areas created by the coordinate plane 3. x-axis: The horizontal axis on the coordinate plane 4. y-axis: 5. Ordered Pairs: 6. Origin:
  • 9. Vocabulary 1. Coordinate Plane: Two number lines drawn perpendicular to each other; used for graphing points 2. Quadrants: Four areas created by the coordinate plane 3. x-axis: The horizontal axis on the coordinate plane 4. y-axis: The vertical axis on the coordinate plane 5. Ordered Pairs: 6. Origin:
  • 10. Vocabulary 1. Coordinate Plane: Two number lines drawn perpendicular to each other; used for graphing points 2. Quadrants: Four areas created by the coordinate plane 3. x-axis: The horizontal axis on the coordinate plane 4. y-axis: The vertical axis on the coordinate plane 5. Ordered Pairs: Give us points in the form (x, y) 6. Origin:
  • 11. Vocabulary 1. Coordinate Plane: Two number lines drawn perpendicular to each other; used for graphing points 2. Quadrants: Four areas created by the coordinate plane 3. x-axis: The horizontal axis on the coordinate plane 4. y-axis: The vertical axis on the coordinate plane 5. Ordered Pairs: Give us points in the form (x, y) 6. Origin: The point (0, 0), which is where the x-axis and y-axis meet
  • 12. Example 1 The vertices of rectangle ABCD are as follows: A = (-2, -2), B = (4, -2), C = (4, 5), and D = (-2, 5). Find the area of ABCD.
  • 13. Example 1 The vertices of rectangle ABCD are as follows: A = (-2, -2), B = (4, -2), C = (4, 5), and D = (-2, 5). Find the area of ABCD. A
  • 14. Example 1 The vertices of rectangle ABCD are as follows: A = (-2, -2), B = (4, -2), C = (4, 5), and D = (-2, 5). Find the area of ABCD. A B
  • 15. Example 1 The vertices of rectangle ABCD are as follows: A = (-2, -2), B = (4, -2), C = (4, 5), and D = (-2, 5). Find the area of ABCD. C A B
  • 16. Example 1 The vertices of rectangle ABCD are as follows: A = (-2, -2), B = (4, -2), C = (4, 5), and D = (-2, 5). Find the area of ABCD. D C A B
  • 17. Example 1 The vertices of rectangle ABCD are as follows: A = (-2, -2), B = (4, -2), C = (4, 5), and D = (-2, 5). Find the area of ABCD. D C A B
  • 18. Example 1 The vertices of rectangle ABCD are as follows: A = (-2, -2), B = (4, -2), C = (4, 5), and D = (-2, 5). Find the area of ABCD. D C AB = 4 −(−2) A B
  • 19. Example 1 The vertices of rectangle ABCD are as follows: A = (-2, -2), B = (4, -2), C = (4, 5), and D = (-2, 5). Find the area of ABCD. D C AB = 4 −(−2) = 4 + 2 A B
  • 20. Example 1 The vertices of rectangle ABCD are as follows: A = (-2, -2), B = (4, -2), C = (4, 5), and D = (-2, 5). Find the area of ABCD. D C AB = 4 −(−2) = 4 + 2 = 6 A B
  • 21. Example 1 The vertices of rectangle ABCD are as follows: A = (-2, -2), B = (4, -2), C = (4, 5), and D = (-2, 5). Find the area of ABCD. C D AB = 4 −(−2) = 4 + 2 = 6 = 6 A B
  • 22. Example 1 The vertices of rectangle ABCD are as follows: A = (-2, -2), B = (4, -2), C = (4, 5), and D = (-2, 5). Find the area of ABCD. C D AB = 4 −(−2) = 4 + 2 = 6 = 6 AD = 5−(−2) A B
  • 23. Example 1 The vertices of rectangle ABCD are as follows: A = (-2, -2), B = (4, -2), C = (4, 5), and D = (-2, 5). Find the area of ABCD. C D AB = 4 −(−2) = 4 + 2 = 6 = 6 AD = 5−(−2) = 5+ 2 A B
  • 24. Example 1 The vertices of rectangle ABCD are as follows: A = (-2, -2), B = (4, -2), C = (4, 5), and D = (-2, 5). Find the area of ABCD. C D AB = 4 −(−2) = 4 + 2 = 6 = 6 AD = 5−(−2) = 5+ 2 = 7 A B
  • 25. Example 1 The vertices of rectangle ABCD are as follows: A = (-2, -2), B = (4, -2), C = (4, 5), and D = (-2, 5). Find the area of ABCD. C D AB = 4 −(−2) = 4 + 2 = 6 = 6 AD = 5−(−2) = 5+ 2 = 7 = 7 A B
  • 26. Example 1 The vertices of rectangle ABCD are as follows: A = (-2, -2), B = (4, -2), C = (4, 5), and D = (-2, 5). Find the area of ABCD. C D AB = 4 −(−2) = 4 + 2 = 6 = 6 AD = 5−(−2) = 5+ 2 = 7 = 7 A B Area = lw
  • 27. Example 1 The vertices of rectangle ABCD are as follows: A = (-2, -2), B = (4, -2), C = (4, 5), and D = (-2, 5). Find the area of ABCD. C D AB = 4 −(−2) = 4 + 2 = 6 = 6 AD = 5−(−2) = 5+ 2 = 7 = 7 A B Area = lw = 6(7)
  • 28. Example 1 The vertices of rectangle ABCD are as follows: A = (-2, -2), B = (4, -2), C = (4, 5), and D = (-2, 5). Find the area of ABCD. C D AB = 4 −(−2) = 4 + 2 = 6 = 6 AD = 5−(−2) = 5+ 2 = 7 = 7 A B Area = lw = 6(7) = 42 square units
  • 29. Example 2 Find the distance between the points (0, 4) and (4, 0).
  • 30. Example 2 Find the distance between the points (0, 4) and (4, 0).
  • 31. Example 2 Find the distance between the points (0, 4) and (4, 0).
  • 32. Example 2 Find the distance between the points (0, 4) and (4, 0).
  • 33. Example 2 Find the distance between the points (0, 4) and (4, 0).
  • 34. Example 2 Find the distance between the points (0, 4) and (4, 0). 2 2 2 a +b =c
  • 35. Example 2 Find the distance between the points (0, 4) and (4, 0). 2 2 2 a +b =c 2 2 2 0−4 + 4−0 = c
  • 36. Example 2 Find the distance between the points (0, 4) and (4, 0). 2 2 2 a +b =c 2 2 2 0−4 + 4−0 = c 2 2 2 4 +4 = c
  • 37. Example 2 Find the distance between the points (0, 4) and (4, 0). 2 2 2 a +b =c 2 2 2 0−4 + 4−0 = c 2 2 2 4 +4 = c 2 16+16 = c
  • 38. Example 2 Find the distance between the points (0, 4) and (4, 0). 2 2 2 a +b =c 2 2 2 0−4 + 4−0 = c 2 2 2 4 +4 = c 2 16+16 = c 2 32 = c
  • 39. Example 2 Find the distance between the points (0, 4) and (4, 0). 2 2 2 a +b =c 2 2 2 0−4 + 4−0 = c 2 2 2 4 +4 = c 2 16+16 = c 2 32 = c 2 c = ± 32
  • 40. Example 2 Find the distance between the points (0, 4) and (4, 0). 2 2 2 a +b =c 2 2 2 0−4 + 4−0 = c 2 2 2 4 +4 = c 2 16+16 = c 2 32 = c 2 c = ± 32 c = 32
  • 41. Example 2 Find the distance between the points (0, 4) and (4, 0). 2 2 2 a +b =c 2 2 2 0−4 + 4−0 = c 2 2 2 4 +4 = c 2 16+16 = c 2 32 = c 2 c = ± 32 c = 32 units
  • 43. Distance Formula: d = (x1 − x2 )2 +( y1 − y2 )2 , for points (x1 , y1 ),(x2 , y2 ) Midpoint Formula:
  • 44. Distance Formula: d = (x1 − x2 )2 +( y1 − y2 )2 , for points (x1 , y1 ),(x2 , y2 ) This is nothing more than the Pythagorean Formula solved for c. Midpoint Formula:
  • 45. Distance Formula: d = (x1 − x2 )2 +( y1 − y2 )2 , for points (x1 , y1 ),(x2 , y2 ) This is nothing more than the Pythagorean Formula solved for c.  x1 + x2 y1 + y2  Midpoint Formula: M =  ,  , for points (x1 , y1 ),(x2 , y2 )  2 2 
  • 46. Distance Formula: d = (x1 − x2 )2 +( y1 − y2 )2 , for points (x1 , y1 ),(x2 , y2 ) This is nothing more than the Pythagorean Formula solved for c.  x1 + x2 y1 + y2  Midpoint Formula: M =  ,  , for points (x1 , y1 ),(x2 , y2 )  2 2  This is nothing more than averaging the x and y coordinates.
  • 47. Example 3 The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2), C = (-2, -1), and D = (5, 1). a. What kind of quadrilateral does ABCD appear to be?
  • 48. Example 3 The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2), C = (-2, -1), and D = (5, 1). a. What kind of quadrilateral does ABCD appear to be? A
  • 49. Example 3 The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2), C = (-2, -1), and D = (5, 1). a. What kind of quadrilateral does ABCD appear to be? A B
  • 50. Example 3 The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2), C = (-2, -1), and D = (5, 1). a. What kind of quadrilateral does ABCD appear to be? A B C
  • 51. Example 3 The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2), C = (-2, -1), and D = (5, 1). a. What kind of quadrilateral does ABCD appear to be? A B D C
  • 52. Example 3 The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2), C = (-2, -1), and D = (5, 1). a. What kind of quadrilateral does ABCD appear to be? A B D C
  • 53. Example 3 The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2), C = (-2, -1), and D = (5, 1). a. What kind of quadrilateral does ABCD appear to be? A This quadrilateral appears B to be a parallelogram D C
  • 54. Example 3 The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2), C = (-2, -1), and D = (5, 1). b. Use distances to justify your guess. A B D C
  • 55. Example 3 The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2), C = (-2, -1), and D = (5, 1). b. Use distances to justify your guess. 2 2 AB = (2 −(−5)) +(4 − 2) A B D C
  • 56. Example 3 The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2), C = (-2, -1), and D = (5, 1). b. Use distances to justify your guess. 2 2 2 2 AB = (2 −(−5)) +(4 − 2) = (7) +(2) A B D C
  • 57. Example 3 The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2), C = (-2, -1), and D = (5, 1). b. Use distances to justify your guess. 2 2 2 2 AB = (2 −(−5)) +(4 − 2) = (7) +(2) A B = 49+ 4 D C
  • 58. Example 3 The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2), C = (-2, -1), and D = (5, 1). b. Use distances to justify your guess. 2 2 2 2 AB = (2 −(−5)) +(4 − 2) = (7) +(2) A B = 49+ 4 = 53 D C
  • 59. Example 3 The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2), C = (-2, -1), and D = (5, 1). b. Use distances to justify your guess. 2 2 2 2 AB = (2 −(−5)) +(4 − 2) = (7) +(2) A B = 49+ 4 = 53 units D C
  • 60. Example 3 The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2), C = (-2, -1), and D = (5, 1). b. Use distances to justify your guess. 2 2 2 2 AB = (2 −(−5)) +(4 − 2) = (7) +(2) A B = 49+ 4 = 53 units D CD = (−2 −5)2 +(−1−1)2 C
  • 61. Example 3 The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2), C = (-2, -1), and D = (5, 1). b. Use distances to justify your guess. 2 2 2 2 AB = (2 −(−5)) +(4 − 2) = (7) +(2) A B = 49+ 4 = 53 units D 2 2 2 2 CD = (−2 −5) +(−1−1) = (−7) +(−2) C
  • 62. Example 3 The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2), C = (-2, -1), and D = (5, 1). b. Use distances to justify your guess. 2 2 2 2 AB = (2 −(−5)) +(4 − 2) = (7) +(2) A B = 49+ 4 = 53 units D 2 2 2 2 CD = (−2 −5) +(−1−1) = (−7) +(−2) C = 49+ 4
  • 63. Example 3 The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2), C = (-2, -1), and D = (5, 1). b. Use distances to justify your guess. 2 2 2 2 AB = (2 −(−5)) +(4 − 2) = (7) +(2) A B = 49+ 4 = 53 units D 2 2 2 2 CD = (−2 −5) +(−1−1) = (−7) +(−2) C = 49+ 4 = 53
  • 64. Example 3 The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2), C = (-2, -1), and D = (5, 1). b. Use distances to justify your guess. 2 2 2 2 AB = (2 −(−5)) +(4 − 2) = (7) +(2) A B = 49+ 4 = 53 units D 2 2 2 2 CD = (−2 −5) +(−1−1) = (−7) +(−2) C = 49+ 4 = 53 units
  • 65. Example 3 The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2), C = (-2, -1), and D = (5, 1). b. Use distances to justify your guess. A B D C
  • 66. Example 3 The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2), C = (-2, -1), and D = (5, 1). b. Use distances to justify your guess. 2 2 BC = (−5−(−2)) +(2 −(−1)) A B D C
  • 67. Example 3 The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2), C = (-2, -1), and D = (5, 1). b. Use distances to justify your guess. 2 2 2 2 BC = (−5−(−2)) +(2 −(−1)) = (−3) +(3) A B D C
  • 68. Example 3 The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2), C = (-2, -1), and D = (5, 1). b. Use distances to justify your guess. 2 2 2 2 BC = (−5−(−2)) +(2 −(−1)) = (−3) +(3) A B = 9+ 9 D C
  • 69. Example 3 The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2), C = (-2, -1), and D = (5, 1). b. Use distances to justify your guess. 2 2 2 2 BC = (−5−(−2)) +(2 −(−1)) = (−3) +(3) A B = 9+ 9 = 18 D C
  • 70. Example 3 The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2), C = (-2, -1), and D = (5, 1). b. Use distances to justify your guess. 2 2 2 2 BC = (−5−(−2)) +(2 −(−1)) = (−3) +(3) A B = 9+ 9 = 18 units D C
  • 71. Example 3 The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2), C = (-2, -1), and D = (5, 1). b. Use distances to justify your guess. 2 2 2 2 BC = (−5−(−2)) +(2 −(−1)) = (−3) +(3) A B = 9+ 9 = 18 units D 2 2 AD = (2 −5) +(4 −1) C
  • 72. Example 3 The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2), C = (-2, -1), and D = (5, 1). b. Use distances to justify your guess. 2 2 2 2 BC = (−5−(−2)) +(2 −(−1)) = (−3) +(3) A B = 9+ 9 = 18 units D 2 2 2 2 AD = (2 −5) +(4 −1) = (−3) +(3) C
  • 73. Example 3 The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2), C = (-2, -1), and D = (5, 1). b. Use distances to justify your guess. 2 2 2 2 BC = (−5−(−2)) +(2 −(−1)) = (−3) +(3) A B = 9+ 9 = 18 units D 2 2 2 2 AD = (2 −5) +(4 −1) = (−3) +(3) C = 9+ 9
  • 74. Example 3 The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2), C = (-2, -1), and D = (5, 1). b. Use distances to justify your guess. 2 2 2 2 BC = (−5−(−2)) +(2 −(−1)) = (−3) +(3) A B = 9+ 9 = 18 units D 2 2 2 2 AD = (2 −5) +(4 −1) = (−3) +(3) C = 9+ 9 = 18
  • 75. Example 3 The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2), C = (-2, -1), and D = (5, 1). b. Use distances to justify your guess. 2 2 2 2 BC = (−5−(−2)) +(2 −(−1)) = (−3) +(3) A B = 9+ 9 = 18 units D 2 2 2 2 AD = (2 −5) +(4 −1) = (−3) +(3) C = 9+ 9 = 18 units
  • 76. Example 3 The vertices of quadrilateral ABCD are A = (2, 4), B = (-5, 2), C = (-2, -1), and D = (5, 1). b. Use distances to justify your guess. 2 2 2 2 BC = (−5−(−2)) +(2 −(−1)) = (−3) +(3) A B = 9+ 9 = 18 units D 2 2 2 2 AD = (2 −5) +(4 −1) = (−3) +(3) C = 9+ 9 = 18 units It is a parallelogram, as opposite sides are equal.
  • 78. Homework p. 246 #1-33 odd, 18, 34, 36 “If I have seen further it is by standing on the shoulders of giants.” - Isaac Newton