2. This Slideshow was developed to accompany the textbook
OpenStax Physics
Available for free at https://openstaxcollege.org/textbooks/college-physics
By OpenStax College and Rice University
2013 edition
Some examples and diagrams are taken from the textbook.
Slides created by
Richard Wright, Andrews Academy
rwright@andrews.edu
3. 05-01 FLUIDS AND DENSITY
In this lesson you will…
• State the common phases of matter.
• Explain the physical characteristics of solids, liquids, and gases.
• Describe the arrangement of atoms in solids, liquids, and gases.
• Define density.
• Calculate the mass of a reservoir from its density.
• Compare and contrast the densities of various substances.
4. 05-01 FLUIDS AND DENSITY
Phases of Matter
Solid
Atoms in close contact so they can’t
move much
Set volume and shape
Can’t compress
Liquid
Atoms move past each other
Set volume
Takes shape of container
Hard to compress
5. 05-01 FLUIDS AND DENSITY
Gas
Atoms far apart
Neither set volume or shape
Compressible
Fluids
Flow
Both liquids and gases
6. 05-01 FLUIDS AND DENSITY
Density
𝜌 =
𝑚
𝑉
Where
𝜌 = density
m = mass
V = Volume
Things with small density float
on things with more density
Solids most dense
Gases least dense
See Table 11.1
7. 05-01 FLUIDS AND DENSITY
Can use density to determine unknown material
An ornate silver crown is thought to be fake. How could we determine if is silver
without damaging the crown?
Find its mass using a balance. (It is 1.25 kg)
Find its volume by submerging in water and finding volume of displaces water. (It is
1.60 × 10−4
m3)
Find the density
𝜌 = 7.81 × 103
kg/m3
Table 11.1 says it is steel
Silver’s density is 10.5 × 103
kg/m3
8. 05-01 FLUIDS AND DENSITY
Do the Density Lab
Objective
Find the density in a coin and use it to help identify the metal.
Use a Vernier caliper.
Materials
Coins of standard metals
Japan 1 Yen (1955-1989)
Denmark 2 øre (1948-1972)
Italy 50 Lire (1955-1989)
France 1 Franc (1959-2001)
Vernier caliper
10. 05-02 PRESSURE AND DEPTH
In this lesson you will…
• Define pressure.
• Explain the relationship between pressure and force.
• Calculate force given pressure and area.
• Define pressure in terms of weight.
• Explain the variation of pressure with depth in a fluid.
• Calculate density given pressure and altitude.
11. 05-02 PRESSURE AND DEPTH
The molecules in a fluid are free to wander around
In their wanderings they sometimes collide with the sides of their
container (i.e. balloon)
The more the molecules collide with the walls, the more force is felt
12. 05-02 PRESSURE AND DEPTH
𝑃 =
𝐹
𝐴
P = Pressure
F = Force perpendicular to surface
A = Area of surface
Unit: N/m2 = Pa (pascal)
1 Pa is very small so we usually use kPa or atm
13. 05-02 PRESSURE AND DEPTH
In a fluid the pressure is exerted
perpendicularly to all surfaces
A static fluid cannot produce a force parallel to
a surface since it is not moving parallel to
surface
14. 05-02 PRESSURE AND DEPTH
You are drinking a juice box. In the process you suck all the juice and air
out of the box. The top of the box is 7.5 cm by 5 cm. If the air pressure is
1.013 × 105 Pa, how much force is acting on the top of the box?
380 N = 85 lbs
Would the force of the side of the box be more or less than the top?
More because more area
15. 05-02 PRESSURE AND DEPTH
The force that squashes the juice box is from the weight of all the
air above it
Atmospheric Pressure at Sea Level
1.013 × 105 Pa = 1 atmosphere (1 atm)
16. 05-02 PRESSURE AND DEPTH
Do the Pressure vs. Depth Lab
When will the water flow out the
farthest: when the water is nearly full,
half-full, or nearly empty?
Hold the bottle over the bucket so that
the water will flow out the hole into
the bucket and loosen the bottle cap.
Observe the flow of water. PUT THE
CAP BACK ON!
Describe how the distance the water
flowed out changed as the depth of
the water changed.
The pressure of a fluid
_________________________ as depth
increases. So pressure and depth are
____________________________ proportional.
This can be written as
____________________
Next Page
17. 05-02 PRESSURE AND DEPTH
Consider taking an elevator down
from the top floor of a tall building.
Consider diving down under water.
Which one makes your ears hurt
more?
The pressure of a fluid
__________________________ as density
increases. So pressure and density are
___________________________ proportional.
This can be written as __________________
Pressure is also directly proportional to
the acceleration due to gravity, so P = kg.
Put set 5, 9, and 10 together to write an
equation relating pressure, depth,
density, and gravity. Put all the variables
that were directly related to pressure on
the top of a fraction and all the variables
that were inversely proportional on the
bottom. (Let k = 1)
Why does the water not flow out of the
bottle with the cap on tightly?
18. 05-02 PRESSURE AND DEPTH
The column of static fluid
experiences several vertical
forces
Since the fluid is not moving, it
is in equilibrium and ∑𝐹 = 0
19. 05-02 PRESSURE AND DEPTH
∑𝐹 = 𝑃2𝐴 − 𝑃1𝐴 − 𝑚𝑔 = 0
𝑃2𝐴 = 𝑃1𝐴 + 𝑚𝑔
𝜌 =
𝑚
𝑉
→ 𝑚 = 𝜌𝑉
𝑃2𝐴 = 𝑃1𝐴 + 𝜌𝑉𝑔
𝑉 = 𝐴ℎ
𝑃2𝐴 = 𝑃1𝐴 + 𝜌𝑔𝐴ℎ
𝑃2 = 𝑃1 + 𝜌𝑔ℎ
Or 𝑃 = 𝜌𝑔ℎ where P is the
pressure due to the fluid at a
depth h below the surface
20. 05-02 PRESSURE AND DEPTH
If the pressure is known at a depth, the pressure lower down can
be found by adding ρgh
This assumes ρ is constant with depth
This is a good estimate for liquids, but not for gasses unless h is
small
21. 05-02 PRESSURE AND DEPTH
Would Hoover Dam need to be just as strong if the entire lake
behind the dam was reduced to an inch of water behind the dam,
but the same depth as the lake?
Yes, the pressure
depends only on the depth
22. 05-02 PRESSURE AND DEPTH
What is the total pressure at
points A and B?
1.55 × 105 𝑃𝑎
24. 05-03 PASCAL’S PRINCIPLE AND MEASURING
PRESSURE
In this lesson you will…
• Define pressure.
• State Pascal’s principle.
• Understand applications of Pascal’s principle.
• Derive relationships between forces in a hydraulic system.
• Define gauge pressure and absolute pressure.
25. 05-03 PASCAL’S PRINCIPLE AND MEASURING
PRESSURE
Do the Pascal’s Principle Lab.
Did anything surprising happen?
26. 05-03 PASCAL’S PRINCIPLE AND MEASURING
PRESSURE
Pascal’s Principle
A change in pressure applied to an
enclosed fluid is transmitted
undiminished to all portions of the fluid
and the walls of its container.
Basis of hydraulics
Since 𝑃 =
𝐹
𝐴
, if we change the area, the
force is changed
𝐹1
𝐴1
=
𝐹2
𝐴2
27. 05-03 PASCAL’S PRINCIPLE AND MEASURING
PRESSURE
A
B
How much force must be exerted at A to support the 850-kg car at
B? The piston at A has a diameter of 17 mm and the piston at B a
diameter of 300 mm.
F = 26.7 N
28. 05-03 PASCAL’S PRINCIPLE AND MEASURING
PRESSURE
Gauge Pressure
Used by pressure gauges
Measures pressure relative to atmospheric pressure
Absolute Pressure
Sum of gauge pressure and atmospheric pressure
𝑃𝑎𝑏𝑠 = 𝑃
𝑔𝑎𝑢𝑔𝑒 + 𝑃𝑎𝑡𝑚
29. 05-03 PASCAL’S PRINCIPLE AND MEASURING
PRESSURE
Open-Tube Manometer
U-shaped tube with fluid in it
One end is connected to the
container of which we want to
measure the pressure
The other end is open to the
air
𝑃2 = 𝜌𝑔ℎ + 𝑃𝑎𝑡𝑚
• 𝑃2 = 𝑃𝑎𝑏𝑠
• 𝑃2 − 𝑃𝑎𝑡𝑚 = 𝑃
𝑔𝑎𝑢𝑔𝑒
30. 05-03 PASCAL’S PRINCIPLE AND MEASURING
PRESSURE
Barometer
Used to measure air pressure
A tube with the top sealed and filled with
mercury
The bottom is open and sitting in a pool
of mercury
Pressure at top = 0
Pressure at bottom = 𝑃𝑎𝑡𝑚
𝑃 = 𝜌𝑔ℎ
32. 05-04 ARCHIMEDES’ PRINCIPLE
In this lesson you will…
• Define buoyant force.
• State Archimedes’ principle.
• Understand why objects float or sink.
• Understand the relationship between density and Archimedes’
principle.
33. 05-04 ARCHIMEDES’ PRINCIPLE
Think of trying to push a beach ball under water
The water pushes it up
All fluids push things up because the pressure is higher at greater depths
The upward force is buoyant force
34. 05-04 ARCHIMEDES’ PRINCIPLE
Do the Buoyancy Lab.
When you are finished DRY the washer before putting them away!!
Make a conclusion about the buoyant force and the weight of water
displaced.
36. 05-04 ARCHIMEDES’ PRINCIPLE
Archimedes’ Principle
Buoyant force = weight of the displaced fluid
𝐹𝐵 = 𝑊𝑓𝑙
If buoyant force ≥ gravity, then it floats
If buoyant force < gravity, then it sinks
37. 05-04 ARCHIMEDES’ PRINCIPLE
As you might have guessed
An object will float if its average density < density of the fluid
In other words, it will float if it displaces more fluid than its own
weight
38. 05-04 ARCHIMEDES’ PRINCIPLE
Specific Gravity
𝑠𝑝𝑒𝑐𝑖𝑓𝑖𝑐 𝑔𝑟𝑎𝑣𝑖𝑡𝑦 =
𝜌
𝜌𝑓𝑙
= fraction submerged
If specific gravity < 1 it floats
If specific gravity > 1 it sinks
39. 05-04 ARCHIMEDES’ PRINCIPLE
h
An ice cube is floating in a glass of fresh water. The cube is 3 cm on
each side. If the cube is floating so a flat face is facing up, what is
the distance between the top of the cube and the water?
0.25 cm
40. 05-04 ARCHIMEDES’ PRINCIPLE
A man tied a bunch of helium balloons to a lawn chair
and flew to a great altitude. If a single balloon is
estimated as a sphere with a radius of 20 cm and is filled
with helium, what is the net force on one balloon?
0.3648 N
How many balloons would be required
to lift a 80 kg man and chair?
2150 balloons
41. 05-04 HOMEWORK
Be buoyed up by the thought of
the joy derived from solving
these problems
Read 12.1, 12.2
42. 05-05 FLOW RATE AND BERNOULLI’S
EQUATION
In this lesson you will…
• Calculate flow rate.
• Describe incompressible fluids.
• Explain the consequences of the equation of continuity.
• Explain the terms in Bernoulli’s equation.
• Explain how Bernoulli’s equation is related to conservation of energy.
• Calculate with Bernoulli’s principle.
• List some applications of Bernoulli’s principle.
43. 05-05 FLOW RATE AND BERNOULLI’S EQUATION
Do the Air Streams Lab
All the motion observed in this lab was caused by differences in pressure.
In all the experiments, which way is the object move: towards or away
from the moving air?
An object will move from higher to lower pressure. Where was the
pressure the lowest: moving or still air?
Where was the pressure the highest?
44. 05-05 FLOW RATE AND BERNOULLI’S EQUATION
Flow Rate
𝑄 =
𝑉
𝑡
Q = Flow rate
V = Volume of fluid
t = time
𝑄 =
𝑉
𝑡
=
𝐴𝑑
𝑡
= 𝐴𝑣
A = cross-section area
𝑣 = average velocity of fluid
45. 05-05 FLOW RATE AND BERNOULLI’S EQUATION
Since flow rate is constant for a
given moving fluid
Equation of continuity
𝜌1𝐴1𝑣1 = 𝜌2𝐴2𝑣2
If incompressible
𝐴1𝑣1 = 𝐴2𝑣2
If incompressible and several
branches
𝑛1𝐴1𝑣1 = 𝑛2𝐴2𝑣2
46. 05-05 FLOW RATE AND BERNOULLI’S EQUATION
A B C
Where does the water flow the fastest?
47. 05-05 FLOW RATE AND BERNOULLI’S EQUATION
A garden hose has a diameter of 2 cm and water enters it at 0.5
m/s. You block 90% of the end of the hose with your thumb. How
fast does the water exit the hose?
v = 5 m/s
48. 05-05 FLOW RATE AND BERNOULLI’S EQUATION
When a fluid goes through narrower channel, it speeds up
It increases kinetic energy
𝑊𝑛𝑒𝑡 =
1
2
𝑚𝑣2
−
1
2
𝑚𝑣0
2
Net work comes from pressure pushing the fluid
50. 05-05 FLOW RATE AND BERNOULLI’S EQUATION
𝑊𝑛𝑒𝑡 = 𝑃2 − 𝑃1 𝑉 =
1
2
𝑚𝑣1
2
+ 𝑚𝑔ℎ1 −
1
2
𝑚𝑣2
2
+ 𝑚𝑔ℎ2
Divide by V and rearrange
𝜌 =
𝑚
𝑉
Bernoulli’s Equation
𝑃1 +
1
2
𝜌𝑣1
2
+ 𝜌𝑔ℎ1 = 𝑃2 +
1
2
𝜌𝑣2
2
+ 𝜌𝑔ℎ2
This is a form of conservation of energy 𝐸0 + 𝑊
𝑛𝑐 = 𝐸𝑓 where the net work comes
from the pressure in the fluid.
51. 05-05 FLOW RATE AND BERNOULLI’S EQUATION
Think about driving down a road with something in your car’s
trunk. The object is too large to completely shut the trunk lid.
While the car is stopped, the lid quietly rests as far down as it can
go. As you drive down the road, why does the trunk open?
The air in the trunk is still. The air above the trunk is moving.
The air in the trunk is at a higher pressure than above the trunk. So
the trunk is pushed open.
52. 05-05 FLOW RATE AND BERNOULLI’S EQUATION
The blood speed in a normal segment of a horizontal artery is 0.15 m/s. An
abnormal segment of the artery is narrowed down by an arteriosclerotic plaque
to one-half the normal cross-sectional area. What is the difference in blood
pressures between the normal and constricted segments of the artery?
35.8 Pa
53. 05-05 FLOW RATE AND BERNOULLI’S EQUATION
Why do all houses need a plumbing vent?
Waste water flows through a sewer line.
Something like a sink is connected to the line, but there is a water trap to
keep the sewer gasses from entering the house.
The flowing water in the sewer means the air directly above the flowing
water has a lower pressure than the air above the sink.
This pushes the water in the trap down the pipe and sewer gasses enter
the house
55. 05-05 FLOW RATE AND BERNOULLI’S EQUATION
How do airplane wings work (even paper airplanes)?
The top of the wing is curved and the bottom is not. The air flows
faster over the top of the wing, than the bottom. This pushes the
wing up.
56. 05-05 FLOW RATE AND BERNOULLI’S EQUATION
How does a curve ball in baseball work?
58. 05-06 THE MOST GENERAL APPLICATIONS
OF BERNOULLI’S EQUATION
In this lesson you will…
• Calculate with Bernoulli’s principle.
• Calculate power in fluid flow.
59. 05-06 THE MOST GENERAL APPLICATIONS OF
BERNOULLI’S EQUATION
Previous examples of Bernoulli’s Equation had simplified
conditions
Bernoulli’s Equation work in real world
60. 05-06 THE MOST GENERAL APPLICATIONS OF
BERNOULLI’S EQUATION
Water circulates throughout a house in a hot-water heating system. If the
water is pumped at a speed of 0.50 m/s through a 4.0-cm-diameter pipe
in the basement under a pressure of 3.0 atm, what will be the flow speed
and pressure in a 2.6-cm-diameter pipe on the second floor 5.0 m above?
Assume the pipes do not divide into branches.
𝑣2 = 1.2
𝑚
𝑠
𝑃2 = 2.5 𝑎𝑡𝑚
61. 05-06 THE MOST GENERAL APPLICATIONS OF
BERNOULLI’S EQUATION
The tank is open to the
atmosphere at the top. Find an
expression for the speed of the
liquid leaving the pipe at the
bottom.
𝑣1 = 2𝑔ℎ
62. 05-06 THE MOST GENERAL APPLICATIONS OF
BERNOULLI’S EQUATION
Since Bernoulli’s Equation is
conservation of energy, the
water would rise up to the
same height as the water in the
tank.
63. 05-06 THE MOST GENERAL APPLICATIONS OF
BERNOULLI’S EQUATION
AirDancer used to draw attention at used car lots.
The behavior is explained by Bernoulli’s principle.
Initially, the moving air, which behaves as an incompressible flow in
the open-ended AirDancer, creates enough pressure to inflate the
tube.
As the tube stands more upright, the turbulent air inside flows more
freely and its speed increases until the decreasing pressure can no
longer support the mass of the nylon fabric.
The collapsing material creates a kink in the tube, a constriction that
causes the air speed to temporarily slow and the pressure to rise
again.
The elevated pressure drives the bend upward, sending a shimmy
through the AirDancer and restarting the cycle.
64. 05-06 THE MOST GENERAL APPLICATIONS OF
BERNOULLI’S EQUATION
Power in Fluid Flow
Power is rate of work or energy
Bernoulli’s Equation terms are
in energy per volume
Multiply Bernoulli’s Equation
by volume and divide by time
Or multiply by flow rate Q
𝑃𝑜𝑤𝑒𝑟 = 𝑃 +
1
2
𝜌𝑣2 + 𝜌𝑔ℎ 𝑄
66. 05-07 VISCOSITY, POISEUILLE’S LAW, AND
TURBULENCE
In this lesson you will…
• Define laminar flow and turbulent flow.
• Explain what viscosity is.
• Calculate flow and resistance with Poiseuille’s law.
• Explain how pressure drops due to resistance.
• Calculate Reynolds number.
• Use the Reynolds number for a system to determine whether it is laminar or
turbulent.
67. 05-07 VISCOSITY, POISEUILLE’S LAW, AND
TURBULENCE
Laminar
Turbulent
Viscosity
Fluid friction
Laminar Flow
Smooth flow in layers that don’t mix
Turbulent Flow
Has eddies and swirls that mix
layers of fluid
Turbulent flow is slower than
laminar flow
68. 05-07 VISCOSITY, POISEUILLE’S LAW, AND
TURBULENCE
𝜂 =
𝐹𝐿
𝑣𝐴
How viscosity is measured
Two plates with fluid
between
Top plate moved
Friction causes the fluid to
move
69. 05-07 VISCOSITY, POISEUILLE’S LAW, AND
TURBULENCE
Laminar flow in tubes
Difference in pressure causes
fluids to flow
𝑄 =
𝑃2 − 𝑃1
𝑅
Where
Q is flow rate
𝑃1 and 𝑃2 are pressures
R is resistance
Poiseuille’s law for resistance
𝑅 =
8𝜂𝑙
𝜋𝑟4
Where
𝜂 is viscosity
l is length of tube
r is radius of tube
70. 05-07 VISCOSITY, POISEUILLE’S LAW, AND
TURBULENCE
Since flow rate depends on
pressure
Higher pressure difference,
higher Q
Higher resistance, higher
pressure difference to
maintain constant Q
In blood vessels this is a
problem with plaque on
artery walls
71. 05-07 VISCOSITY, POISEUILLE’S LAW, AND
TURBULENCE
How to tell if laminar or
turbulent flow
Low speed with smooth,
streamlined object
laminar
High speed or rough object
turbulent
Reynolds number
Below 2000 laminar
Above 3000 turbulent
Between 2000 and 3000
depends on conditions
𝑁𝑅 =
2𝜌𝑣𝑟
𝜂
72. 05-07 VISCOSITY, POISEUILLE’S LAW, AND
TURBULENCE
A hypodermic syringe is filled with a
solution whose viscosity is 1.5 ×
10−3
Pa ⋅ s. The plunger area of the
syringe is 8.0 × 10−5
m2
, and the
length of the needle is 0.025 m. The
internal radius of the needle is 4.0 ×
10−4
m. The gauge pressure in a vein
is 1900 Pa (14 mmHg). What force
must be applied to the plunger, so that
1.0 × 10−6 m3 of solution can be
injected in 3.0 s?
𝐹 = 0.25 N
Is the flow laminar if the density is
1000 kg/m3?
𝑁𝑅 = 353; Yes
Increases; directly; 𝑃 = 𝑘𝜌
𝑃=𝜌𝑔ℎ
There is no pressure in the bottle to push the water out.
There are horizontal forces also, but they will cancel each other.
Add a picture of Hoover Dam
𝑃 1 =1.013× 10 5 𝑃𝑎
ℎ=5.50 𝑚
𝜌=1000 𝑘𝑔/ 𝑚 3
𝑃 𝐴 = 𝑃 1 +𝜌𝑔ℎ 1.013× 10 5 𝑃𝑎+ 1000 𝑘𝑔 𝑚 3 9.80 𝑚 𝑠 2 5.50 𝑚 =1.55× 10 5 𝑃𝑎
The pressures are the same because the depth is the same. It doesn’t matter that B has rock above it.
The fluid has no where to go. It flows in the container, but cannot go anywhere so the whole pressure increases.
P2 = ρgh
P2 = 13600 kg/m3 (9.80m/s2)h
P2 = 1.33x105 Pa/m h
1 atm is 760 mm if we make P2 = 1.013x105 Pa
Changes in weather are often due to change in air pressure. Low pressure = bad weather; high pressure = sunny weather
B, then C, then A
My old woodstove had 8in round pipe, then entered 10in square chimney. Since the area got bigger, the smoke slowed down. That let the creosote in the smoke build up on the chimney walls more and cause chimney fires.