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UNIT: 1
SOLID STATE
Part-III
1.4 Crystal Structure
Marks 4-6
Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad
1.4.1 Crystal, lattice and basis
Lattice +Basis = Crystal
What is lattice?
Regular and periodic three dimensional geometric arrangement of
points in space. It is used to describe structure of crystal.
Two dimensional lattice.
Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad
Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad
What is Basis?
Set of atoms associated with each lattice point.
Crystal = lattice + basis
Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad
1.4.2 Unit Cell
- Unit cell is smallest repeating structural unit of
crystalline solid
Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad
Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad
➢ When unit cells are
stacked together to
generate crystal each
unit cell share its faces
edges and corners with
neighboring unit cell.
➢ a, b, c are the
dimensions of unit cell.
➢ α β γ are the angles
between these axes
Unit cell Unit cell
Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad
Unit
cell
1) Primitive or simple unit cell
Constituent particles are present at its corners
2) Body centered unit cell
One constituent particles is present at the center of its
body
in addition to the corner particles
3) Face centered unit cell
constituent particles are present at the center of each faces
in addition to the corner particlesFace centered unit cell
4)Base centered unit cell
Constituent particles are present at the centers of any two its
opposite faces
in addition to the corner particles
Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad
1.4.3Types of unit cell
1) Primitive or simple unit cell-
✓ constituent particles are present at its corners only.
Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad
2) Body centered unit cell
✓ One constituent particle
is present at the center of
its body in addition to the
corner particles.
3) Face centered unit cell
✓ Consists of particles at
the center of each of the
faces in addition to the
corner particles.
4) Base centered unit cell
✓ Consist of particles at the
center of any two of its
opposite faces in addition
to corner particles.
Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad
1.4.4 Crystal system
✓ 14 different kind of space lattices are possible which describe the
crystal structure ,are called Bravais lattice.
Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad
14 Bravais
lattice
1) Cubic
2) Tetragonal
3) Orthorhombic
4) Rhombohedral
5) Monoclinic
6) Triclinic
7) Hexagonal
Bravais lattice are
divided in to 7 crystal
systems.
Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad
Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad
Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad
Cubic
system
Simple cubic
Particles are at the 8 corners of cube.
Body centered cubic
particles at its 8 corners & an additional particle
in the center of the cube.
Face centered cubic
particles at its 8 corners & at the center of each of six
faces of the cube .
1.5 Cubic system
Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad
1) Simple
Cubic((SC)
. Has 8 corners
1/8 × 8 =1
particle per
unit cell.
2)Body
Centered
Cubic(BCC)H
as 8 corners
1/8 × 8 =1
1 particle at the
center.
1+ 1 = 2
particles per unit
cell
3)Face
Centered
Cubic (FCC)
Has 8 corners
1/8 × 8 =1 .
Has 6 faces.
1/2 × 6 = 3
1+3 = 4
particles per unit
cell
1.5.1 Cubic system :-3 types of cubic cells
Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad
Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad
Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad
Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad
Tetragonal system Monoclinic system
Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad
Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad
Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad
Important points
1) Each corner particle of a cube is shared by 8
cubes.
2) Each face particle is shared by 2 cubes.
3) Each edge particle is shared by 4 cubes.
Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad
1.5.2 Relationship between molar mass, density
of the substance and unit cell edge length, is
deduced in the following steps
1)If edge length of cubic unit cell is a, the
volume of unit cell is a3
2) Suppose that mass of one particle is m
and that there are n particles per unit cell.
•Mass of unit cell = m × n ……..(1.1)
Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad
3) The density of unit cell (ρ), which is same as
density of the sub-substance is given by
ρ = mass of unit cell
Volume of unit cell
= m× n
a3
= density of substance……..(1.2)
Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad
4) Molar mass (M) of the substance is given by
M = mass of one particle × number of particles per mole
= m × NA
Therefore, m= M/NA……………(1.3)
5) Combining Eq. (1.1) and (1.3), gives
ρ = n M/ a3NA…………(1.4)
By knowing any four parameters of Eq. (1.4),
the fifth can be calculated.
(NA is Avogadro number)
THANK YOU!
Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad

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Solid state part 3 | Chemistry Class 12 | By Mrs. Shubhada Walawalkar

  • 1. UNIT: 1 SOLID STATE Part-III 1.4 Crystal Structure Marks 4-6 Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad
  • 2. 1.4.1 Crystal, lattice and basis Lattice +Basis = Crystal What is lattice? Regular and periodic three dimensional geometric arrangement of points in space. It is used to describe structure of crystal. Two dimensional lattice. Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad
  • 3. Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad What is Basis? Set of atoms associated with each lattice point. Crystal = lattice + basis
  • 4. Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad
  • 5. 1.4.2 Unit Cell - Unit cell is smallest repeating structural unit of crystalline solid Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad
  • 6. Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad ➢ When unit cells are stacked together to generate crystal each unit cell share its faces edges and corners with neighboring unit cell. ➢ a, b, c are the dimensions of unit cell. ➢ α β γ are the angles between these axes Unit cell Unit cell
  • 7. Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad Unit cell 1) Primitive or simple unit cell Constituent particles are present at its corners 2) Body centered unit cell One constituent particles is present at the center of its body in addition to the corner particles 3) Face centered unit cell constituent particles are present at the center of each faces in addition to the corner particlesFace centered unit cell 4)Base centered unit cell Constituent particles are present at the centers of any two its opposite faces in addition to the corner particles
  • 8. Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad 1.4.3Types of unit cell 1) Primitive or simple unit cell- ✓ constituent particles are present at its corners only.
  • 9. Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad 2) Body centered unit cell ✓ One constituent particle is present at the center of its body in addition to the corner particles. 3) Face centered unit cell ✓ Consists of particles at the center of each of the faces in addition to the corner particles. 4) Base centered unit cell ✓ Consist of particles at the center of any two of its opposite faces in addition to corner particles.
  • 10. Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad 1.4.4 Crystal system ✓ 14 different kind of space lattices are possible which describe the crystal structure ,are called Bravais lattice.
  • 11. Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad 14 Bravais lattice 1) Cubic 2) Tetragonal 3) Orthorhombic 4) Rhombohedral 5) Monoclinic 6) Triclinic 7) Hexagonal Bravais lattice are divided in to 7 crystal systems.
  • 12. Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad
  • 13. Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad
  • 14. Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad Cubic system Simple cubic Particles are at the 8 corners of cube. Body centered cubic particles at its 8 corners & an additional particle in the center of the cube. Face centered cubic particles at its 8 corners & at the center of each of six faces of the cube . 1.5 Cubic system
  • 15. Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad 1) Simple Cubic((SC) . Has 8 corners 1/8 × 8 =1 particle per unit cell. 2)Body Centered Cubic(BCC)H as 8 corners 1/8 × 8 =1 1 particle at the center. 1+ 1 = 2 particles per unit cell 3)Face Centered Cubic (FCC) Has 8 corners 1/8 × 8 =1 . Has 6 faces. 1/2 × 6 = 3 1+3 = 4 particles per unit cell 1.5.1 Cubic system :-3 types of cubic cells
  • 16. Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad
  • 17. Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad
  • 18. Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad
  • 19. Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad Tetragonal system Monoclinic system
  • 20. Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad
  • 21. Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad
  • 22. Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad Important points 1) Each corner particle of a cube is shared by 8 cubes. 2) Each face particle is shared by 2 cubes. 3) Each edge particle is shared by 4 cubes.
  • 23. Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad 1.5.2 Relationship between molar mass, density of the substance and unit cell edge length, is deduced in the following steps 1)If edge length of cubic unit cell is a, the volume of unit cell is a3 2) Suppose that mass of one particle is m and that there are n particles per unit cell. •Mass of unit cell = m × n ……..(1.1)
  • 24. Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad 3) The density of unit cell (ρ), which is same as density of the sub-substance is given by ρ = mass of unit cell Volume of unit cell = m× n a3 = density of substance……..(1.2)
  • 25. Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad 4) Molar mass (M) of the substance is given by M = mass of one particle × number of particles per mole = m × NA Therefore, m= M/NA……………(1.3) 5) Combining Eq. (1.1) and (1.3), gives ρ = n M/ a3NA…………(1.4) By knowing any four parameters of Eq. (1.4), the fifth can be calculated. (NA is Avogadro number)
  • 26. THANK YOU! Sou S.S.Walawalkar - N.S.P.Jr.college.Devgad