2. Multiplicity of infection (moi)
An experiment with bacteriophage typically begins with an initial period
during which the virus is allowed to adsorb to the host cells.
It is important to know the ratio of the number of bacteriophages to the
number of cells at this stage of the infection process.
Too many bacteriophages attaching to an individual cell can cause cell lysis,
even before the infection process can yield progeny virus particles (‘lysis from
without’).
If too few bacterio phages are used for the infection, it may be difficult to
detect or measure the response being tested.
The bacteriophage to cell ratio is called the multiplicity of infection (moi).
3. A 0.1 mL aliquot of a bacteriophage stock having a concentration
of 4 X 109 phage/mL is added to 0.5 mL of E. coli cells having a
concentration of 2 X 108 cells/mL. What is the moi?
First, calculate the total number of bacteriophage and the total number of bacteria.
Total number of bacteriophage:
0.1mL X 4x109 phage/ml = 4 X108 bacteriophage
Total number of cells:
0.5mL X 2x108 cells/ml =1 x 108 cells
4. The moi is then calculated as bacteriophage per cell:
moi = 4 x 108 phage / 1x 108 cells
= 4 phage/cell
Therefore, the moi is 4 phage/cell.
5. Reference
Calculations for molecular biology and Biotechnology – A Guide to mathematics in
the laboratory, Second Edition – Frank. H. Stephenson
11-09-2021
Dr.SS
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