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Ch30 12

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Exercice 12 • Variante 1 : Combinatoire C38 56 P(FFF) = 18 = 0, 0686 C3 816 • Variante 2 : Arbre de probabilités 6/16 f 7/17 f 8/18 f h h h 8 7 6 P(FFF) = × × 0, 0686 18 17 16

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Ch39 15
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Ch38 31
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Ch38 19
Ch38 19Ch38 19
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Ch38 17
Ch38 17Ch38 17
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Ch38 15
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Ch39 17
Ch39 17Ch39 17
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Ch39 15
Ch39 15Ch39 15
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Ch39 11
Ch39 11Ch39 11
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Ch38 35
Ch38 35Ch38 35
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Ch38 31
Ch38 31Ch38 31
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Ch38 26
Ch38 26Ch38 26
Ch38 26
 
Ch38 24
Ch38 24Ch38 24
Ch38 24
 
Ch38 22
Ch38 22Ch38 22
Ch38 22
 
Ch38 19
Ch38 19Ch38 19
Ch38 19
 
Ch38 17
Ch38 17Ch38 17
Ch38 17
 
Ch38 15
Ch38 15Ch38 15
Ch38 15
 
Ch37 34
Ch37 34Ch37 34
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Ch37 29
Ch37 29Ch37 29
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Ch37 28
Ch37 28Ch37 28
Ch37 28
 
Ch37 25
Ch37 25Ch37 25
Ch37 25
 
Ch37 23
Ch37 23Ch37 23
Ch37 23
 
Ch37 19
Ch37 19Ch37 19
Ch37 19
 
Ch37 16
Ch37 16Ch37 16
Ch37 16
 

Ch30 12

  • 1. Exercice 12 • Variante 1 : Combinatoire C38 56 P(FFF) = 18 = 0, 0686 C3 816 • Variante 2 : Arbre de probabilités 6/16 f 7/17 f 8/18 f h h h 8 7 6 P(FFF) = × × 0, 0686 18 17 16