O- A disk of mass M and radius R is on the table as shown in Figure ab.docx

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O. A disk of mass M and radius R is on the table as shown in Figure above. N is the normal force. Fa is the gravity force, and F, is the friction force. point of contact of the disk with the table), and Os the point shown in the Figure above. Calculate torques of all forces with respect to points: O, (the center of the disk), O2 (the TN Solution for point o1 fG and N acts aqlong the lone of o1 so TN = TG = 0 Tf = =Ff*R into the page for point o2 Ff acts along the axis so Tf = 0 TN = R*N*sin180 = 0 TG = 0 (ANGLE 0) for point o3 Tf = 0 TG = -Fg*o2o3 o2o3 is the distance of o3 from the bottom of disk TN = No2o3 .

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Neilson Company has monthly salaries of $22,000. Assume Neilson pays all the standard payroll taxes and no employees have reached the payroll tax limits. Journalize the accrual and payment of employer payroll taxes for Neilson Company (Assume all of the monthly salary is subject to FUTA and SUTA). (Click the icon to view payroll tax rate information.) Begin with the entry to accrue employer payr appear on the last line of the journal entry tab Now record the payment of employer payroll taxes for Nelson Company. (Record debits first, then credits. Explanations will appear on the last line of the journal entry table.) Solution Info is hidden for the first journal Please unhide this .

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Neuron cells generate electrical signals by concentration gradients across membranes. Assuming a potassium ion concentration of 0.00350 M inside the cell, and a concentration of 0.135 M outside the cell, what is the electrical potential across the cell membrane? Body temperature is 315 K. The sign identifies the change in the electrical potential across the membrane and which way the ions flow. (answer in mV) Solution Let us consider Nernst equation: E = (RT/zF)ln([X] out /[X] in ) where, R = gas constant , 8.314J/Kmol T = Temperature, 315K z = Charge of the ion , for K+ it is +1 F = Faraday constant, 96485C/mol Therefore, E =((2.303Ã— 8.314(J/K mol) Ã—315K)/(+1Ã—96485C/mol))log(0.135M/0.0035M) = 0.0625VÃ—log(0.135/0.0035) E= 0.099V .

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nest Rutherford was a prominent scientist who contributed significantly to the theory of atomic structure. Which of the following statements are true? Select all that apply. Rutherford devised the solar system model to describe the layout of the atom. Rutherford disproved the plum pudding model of the atom. Rutherford theorized that atoms contain a positively charged region called the nucleus. Rutherford devised the plum pudding model to describe the layout of an atom. Solution Correct one: c) Rutherford theorized that atoms contain a positively charged region called the nucleus. After completing the alpha-particle scattering experiment, he theorized the presence of nucleus. Due to which plum pudding model given by J.J. thomson got disapproved. .

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Need some help!! Explain why all polynomial functions are continuous. Explain how to find an irrational zero. Describe the concept of continuity. Provide one example of a continuous function and one example of a discontinuous function. Why is it important to know synthetic division? What is another way to accomplish the same thing? Solution yes. all polynomials are continuous. reasons for discontinuity: 1. there is a denominator (which becomes 0 for some value of x) 2. there is a split in the definition of the function - this is for a piecewise function 3. there is a radical (even-indexed) for a polynomial, none of these cases occur.. . . thus there is no value of x where you expect a discontinuity. .

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On January 1, 2015, Alice Corporation had 20,000 shares of $6 par value common stock and 10,000 shares of 8%, $100 par value convertible preferred stock outstanding. The preferred shares carried a 3 for 1 conversion privilege. As of December 31, 2015, none of the preferred shares had been converted. What number of shares must Alice use in computing diluted earnings per share at December 31, 2015? Solution b.20,000 .

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On January 1, 2014, Jay Company had 10,000 shares of $1 par common stock outstanding, and 4,000 shares of $100 par value, 7% cumulative, nonconvertible preferred stock. On April 1, 2014, Jay Company had a 2-for-1 stock split. On July 1, 2014, Jay Company issued 5,000 additional shares of common stock. What is the weighted average shares outstanding to be used in basic earnings per share for 2014? A) 20,000 B) 22,500 C) 25,000 D) 27,000 Solution Weighted average shares outstanding to be used in basic earnings per share for 2014 = 10000*2*12/12 + 5000*6/12 Weighted average shares outstanding to be used in basic earnings per share for 2014 = 22500 Answer B) 22,500 .

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