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Chi square test
Sucheta Tripathy, Biostatistics course
work IICB,Nov, 2013
Definitions
•Model or Hypothesis
•Null Hypothesis
•There is no significant difference between the 2.
TRUE

FALSE

•Goodness of fit
What you need
• A probability value
• Degree of freedom
• A contingent table
Determine if the deviation is due to chance

Accept

10%
Reject
Chi Square Test
Example 1
• Mendellian law of dominance
A -> Tall (Dominant)
a -> Dwarf (recessive)
Aa is …….

Aa X Aa

A

a X A

a
639 Tall and
281 dwarf

AA Aa Aa aa

Chi square requires that you have numeric
values
Chi square should not be calculated if the
expected value is less than 5
Example
9:3:3:1
Example
Number of sixes
0
1
2
3

Number of Rolls
48
35
15
03

p1 = P(roll 0 sixes) = P(X=0) = 0.58
p2 = P(roll 1 six) = P(X=1) = 0.345
p3 = P(roll 2 sixes) = P(X=2) = 0.07
p4 = P(roll 3 sixes) = P(X=3) = 0.005

P(k out of n) =

n!
k!(n-k)!

http://www.mathsisfun.com/data/binomial-distribution.html

pk(1-p)(n-k)

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Stat2013

  • 1. Chi square test Sucheta Tripathy, Biostatistics course work IICB,Nov, 2013
  • 2. Definitions •Model or Hypothesis •Null Hypothesis •There is no significant difference between the 2. TRUE FALSE •Goodness of fit
  • 3. What you need • A probability value • Degree of freedom • A contingent table Determine if the deviation is due to chance Accept 10% Reject
  • 5. Example 1 • Mendellian law of dominance A -> Tall (Dominant) a -> Dwarf (recessive) Aa is ……. Aa X Aa A a X A a 639 Tall and 281 dwarf AA Aa Aa aa Chi square requires that you have numeric values Chi square should not be calculated if the expected value is less than 5
  • 7. Example Number of sixes 0 1 2 3 Number of Rolls 48 35 15 03 p1 = P(roll 0 sixes) = P(X=0) = 0.58 p2 = P(roll 1 six) = P(X=1) = 0.345 p3 = P(roll 2 sixes) = P(X=2) = 0.07 p4 = P(roll 3 sixes) = P(X=3) = 0.005 P(k out of n) = n! k!(n-k)! http://www.mathsisfun.com/data/binomial-distribution.html pk(1-p)(n-k)