Suppose that the random variable X has the uniform distribution on the interval (a,b). Show that epsilon(X) = (a + b)/2 Solution since it\'s a uniform distribution f(x)=1/(b-a).E(x)= \\(\\int_{a}^{b}xf(x) dx\\) => x^2/2*(b-a)|a,b =>(b^2-a^2)/2*(b-a) => b+a/2.