17. Repulsion between 5 pairs of valence electrons on the phosphorous atom in PF5 can be minimized by distributing these electrons towards the corners.
There are only two places in the valence shell of the central atom of BeF2 where electrons can be found.Repulsion between these pairs of electrons can be minimized by arranging them so that they point in opposite directions.Therefore the VSEPR theory predicts that BeF2 should be a linear molecule, with a 180° angle between the two Be-F bonds.
There are three places on the central atom in BF3 where valence electrons can be found.Repulsion between these electrons can be minimized by arranging them toward the corner of an equilateral triangle.Therefore this theory predicts the F-B-F bond angle to be 120°
Have four regions of electron densityThree bonding regions and one lone pair regionIn the NH3 structure, the angle is less than 109° because the lone pair likes to spread out as much as possible
There are 6 places on the central atom in these molecule where valence electrons can be foundThe repulsion between these electrons can be minimized by distributing them toward the corners of the octahedron.The term octahedron means 8 sides, but it is the 6 corners, or vertices, that interest us