A rifle round is fired at a bulls eye target. Let Z represent the horzontal miss distance measured from the center of the bulls eye. Thus Z<0 if the round hits to the right of the center. Assume that Z is standing normal and evaluate the probabilities of the events. Z>1.25 Z<-.67 absvalue Z<.5 absvalue Z>1.55 absvalue Z<1 or absvalue Z>.4 absvalue Z<1 or absvalue Z>.2 Solution No- standard normal distribution P(Z>1.25)=1-P(Z<1.25)=1-No(1.25) = No(-1.25) P(Z<-0.67)=No(-0.67) P(|Z|<0.5)=P(-0.51.55)=1-P(|Z|<1.55) =1- (P(-1.55.