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Alcohols
• General formula is CnH2n+1OH.
• Alcohols have an –OH functional group.
• The –OH group is polar and so decreases the
volatility and increases the solubility, in water,
of alcohols, relative to alkanes of comparable
molecular mass.
• The most common alcohol, ethanol C2H5OH,
is readily soluble in water, as we know from its
presence in alcoholic drinks.
Combustion of alcohols
• Alcohols are important source of fuel and are
used in alcohol burners and similar heaters.
• The amount of energy released per mole of
alcohol increases as we go up the homologous
series, chiefly due to the increasing number of
carbon dioxide molecules produced.
Ex : burning of methanol
• 1:1 ratio of CO2 : alcohol
• ∆H𝑐 𝜃
= -726.1 kJ mol-1
Ex : burning of pentanol
• 5:1 ratio of CO2 : alcohol
• ∆H𝑐 𝜃
= -3330.9 kJ mol-1
In the presence of a
limited supply of
oxygen, alcohol will
produce carbon
monoxide instead of
carbon dioxide.
Oxidation of
alcohols• Alcohols can be classified as primary,
secondary and tertiary according to the
number of carbon atoms joined to the carbon
attached to the OH group.
• Primary and secondary alcohols can be
oxidised using an oxidising agent such as
acidified potassium dichromate (IV)
(K2Cr2O7/H+) or acidified potassium
manganate (VII) (KMnO4/H+).
EXAM TIP :
Don’t forget the
word ‘acidified’
when describing
the oxidising agent.
Primary alcohols
• Primary alcohols are oxidised, first to an
aldehyde (partial oxidation).
• Then the aldehyde is oxidised further to a
carboxylic acid (complete oxidation).
Primary alcohol ---------- aldehyde ---------- carboxylic acid
Cr2O7
2-/H+ Cr2O7
2-/H+
Heat Heat
Cr2O7
2-/H+ Cr2O7
2-/H+
Heat Heat
Each reaction can be shown in a balanced equation
using [O] to represent oxygen from the oxidising agent:
CH3CH2OH + [O]  CH3CHO + H2O
CH3CHO + [O]  CH3COOH
• However, if a fully balanced equation for the
oxidation of an alcohol using acidified
dichromate (IV), is required we must consider
the half-equations involves.
• Cr2O7
2- (orange) is the oxidising agent and is
reduced during the reaction to the Cr3+
(aq) ion
(green).
The half-equation of the reduction :
• Oxidation half-equation(in the first reaction) :
Orange Green
CH3CH2OH  CH3CHO + 2H+ + 2e-
• The two half equation can be combined by
multiplying the oxidation half-equation by
three to generate 6e- and then adding them
together.
• When H+ ions are cancelled from both sides,
the overall equation obtained is :
Cr2O7
2- + 8H+ +3CH3CH2OH  3CH3CHO + 2Cr3+ + 7H2O
The half-equation for the reduction of the
manganate (VII) ions (purple) to colourless
Mn2+
(aq) ions is:
• The half-equation for the oxidation of ethanal
to ethanoic acid is :
MnO4
- + 8H+ + 5e-  Mn2+ + 4H2O
CH3CHO + H2O  CH3COOH + 2H+ + 2e-
To get overall redox equation,
• Balance the electrons.
• So the oxidation half-equation is multiplied by
five and the reduction half-equation by two :
2MnO4
- + 5CH3CHO + 6H+  5CH3COOH + 2Mn2+ + 3H2O
• If a reaction mixture containing ethanol and
acidified potassium dichromate (VI) is heated
under reflux, ethanoic acid is obtained as the
main product and the aldehyde is not usually
isolated.
• However, it is possible to set up the apparatus
so that the aldehyde is distilled of as soon as it
is formed and before it can be oxidised
further.
• This technique works because aldehydes have
lower boiling points than the equivalent
alcohols (and all other components of the
reaction mixture) because they do not have
the hydrogen atom attached directly to an
oxygen atom, and therefore there is no
hydrogen bonding between molecules.
Secondary
alcohols• Secondary alcohols are also oxidised by
heating with acidified potassium dichromate
(VI) (or acidified manganate (VII)).
• They are oxidised to ketones, which cannot be
oxidised any further.
• For example :
Secondary alcohol ketone .
Cr2O7
2-/H+
Heat Heat
Cr2O7
2-/H+
Cr2O7
2-/H+
Heat
• The balanced equation for the reaction is :
CH3CH(OH)CH3 + [O]  (CH3)2CO + H2O
Or
Cr2O7
2- + 8H+ + 3CH3CH(OH)CH3  3(CH3)2CO + 2Cr3+ + 7H2O
• In terms of changes to the functional group,
the reaction can be represented as :
Cr2O7
2-/H+
Heat
• Looking at the reaction of another secondary
alcohol : The only change is to
the group highlighted in
red – the rest of the
molecule is unchanged.
Tertiary alcohol
• Tertiary alcohols are resistant to oxidation.
Cr2O7
2-/H+
Heat
TOPIC 10 : ORGANIC CHEMISTRY

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TOPIC 10 : ORGANIC CHEMISTRY

  • 2. • General formula is CnH2n+1OH. • Alcohols have an –OH functional group. • The –OH group is polar and so decreases the volatility and increases the solubility, in water, of alcohols, relative to alkanes of comparable molecular mass. • The most common alcohol, ethanol C2H5OH, is readily soluble in water, as we know from its presence in alcoholic drinks.
  • 3. Combustion of alcohols • Alcohols are important source of fuel and are used in alcohol burners and similar heaters. • The amount of energy released per mole of alcohol increases as we go up the homologous series, chiefly due to the increasing number of carbon dioxide molecules produced.
  • 4. Ex : burning of methanol • 1:1 ratio of CO2 : alcohol • ∆H𝑐 𝜃 = -726.1 kJ mol-1
  • 5. Ex : burning of pentanol • 5:1 ratio of CO2 : alcohol • ∆H𝑐 𝜃 = -3330.9 kJ mol-1 In the presence of a limited supply of oxygen, alcohol will produce carbon monoxide instead of carbon dioxide.
  • 6. Oxidation of alcohols• Alcohols can be classified as primary, secondary and tertiary according to the number of carbon atoms joined to the carbon attached to the OH group.
  • 7. • Primary and secondary alcohols can be oxidised using an oxidising agent such as acidified potassium dichromate (IV) (K2Cr2O7/H+) or acidified potassium manganate (VII) (KMnO4/H+). EXAM TIP : Don’t forget the word ‘acidified’ when describing the oxidising agent.
  • 8. Primary alcohols • Primary alcohols are oxidised, first to an aldehyde (partial oxidation). • Then the aldehyde is oxidised further to a carboxylic acid (complete oxidation). Primary alcohol ---------- aldehyde ---------- carboxylic acid Cr2O7 2-/H+ Cr2O7 2-/H+ Heat Heat
  • 9. Cr2O7 2-/H+ Cr2O7 2-/H+ Heat Heat Each reaction can be shown in a balanced equation using [O] to represent oxygen from the oxidising agent: CH3CH2OH + [O]  CH3CHO + H2O CH3CHO + [O]  CH3COOH
  • 10. • However, if a fully balanced equation for the oxidation of an alcohol using acidified dichromate (IV), is required we must consider the half-equations involves. • Cr2O7 2- (orange) is the oxidising agent and is reduced during the reaction to the Cr3+ (aq) ion (green).
  • 11. The half-equation of the reduction : • Oxidation half-equation(in the first reaction) : Orange Green CH3CH2OH  CH3CHO + 2H+ + 2e-
  • 12. • The two half equation can be combined by multiplying the oxidation half-equation by three to generate 6e- and then adding them together. • When H+ ions are cancelled from both sides, the overall equation obtained is : Cr2O7 2- + 8H+ +3CH3CH2OH  3CH3CHO + 2Cr3+ + 7H2O
  • 13. The half-equation for the reduction of the manganate (VII) ions (purple) to colourless Mn2+ (aq) ions is: • The half-equation for the oxidation of ethanal to ethanoic acid is : MnO4 - + 8H+ + 5e-  Mn2+ + 4H2O CH3CHO + H2O  CH3COOH + 2H+ + 2e-
  • 14. To get overall redox equation, • Balance the electrons. • So the oxidation half-equation is multiplied by five and the reduction half-equation by two : 2MnO4 - + 5CH3CHO + 6H+  5CH3COOH + 2Mn2+ + 3H2O
  • 15. • If a reaction mixture containing ethanol and acidified potassium dichromate (VI) is heated under reflux, ethanoic acid is obtained as the main product and the aldehyde is not usually isolated.
  • 16. • However, it is possible to set up the apparatus so that the aldehyde is distilled of as soon as it is formed and before it can be oxidised further.
  • 17. • This technique works because aldehydes have lower boiling points than the equivalent alcohols (and all other components of the reaction mixture) because they do not have the hydrogen atom attached directly to an oxygen atom, and therefore there is no hydrogen bonding between molecules.
  • 18. Secondary alcohols• Secondary alcohols are also oxidised by heating with acidified potassium dichromate (VI) (or acidified manganate (VII)). • They are oxidised to ketones, which cannot be oxidised any further.
  • 19. • For example : Secondary alcohol ketone . Cr2O7 2-/H+ Heat Heat Cr2O7 2-/H+ Cr2O7 2-/H+ Heat
  • 20. • The balanced equation for the reaction is : CH3CH(OH)CH3 + [O]  (CH3)2CO + H2O Or Cr2O7 2- + 8H+ + 3CH3CH(OH)CH3  3(CH3)2CO + 2Cr3+ + 7H2O
  • 21. • In terms of changes to the functional group, the reaction can be represented as : Cr2O7 2-/H+ Heat
  • 22. • Looking at the reaction of another secondary alcohol : The only change is to the group highlighted in red – the rest of the molecule is unchanged.
  • 23. Tertiary alcohol • Tertiary alcohols are resistant to oxidation. Cr2O7 2-/H+ Heat