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Block A has a mass of 5.0 kg and rests on a smooth table and is connected to block B, which has
a mass of 3.0 kg, after passing over an ideal pulley, as shown. Block B is released from rest and
it accelerates down. What is the velocity of the block A at the instant when block B falls through
a distance of 10 m. Use g = 10 m/st I A. 10 m/s B. 25 m/s C. (75) m/s D. 5.0 m/s
Solution
Here,
let the acceleration is a
Using second law of motion
a = net force/total mass
a = (3 * 10)/(3 + 5)
a = 3.75 m/s^2
Now , for the velocity after falling 10 m
vf^2 = 2 * a * d
vf^2 =2 * 3.75 * 10
vf = sqrt(75)
the velocity of the block A at the instant is C) sqrt(75) m/s
Block A has a mass of 5-0 kg and rests on a smooth table and is connec.docx

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Block A has a mass of 5-0 kg and rests on a smooth table and is connec.docx

  • 1. Block A has a mass of 5.0 kg and rests on a smooth table and is connected to block B, which has a mass of 3.0 kg, after passing over an ideal pulley, as shown. Block B is released from rest and it accelerates down. What is the velocity of the block A at the instant when block B falls through a distance of 10 m. Use g = 10 m/st I A. 10 m/s B. 25 m/s C. (75) m/s D. 5.0 m/s Solution Here, let the acceleration is a Using second law of motion a = net force/total mass a = (3 * 10)/(3 + 5) a = 3.75 m/s^2 Now , for the velocity after falling 10 m vf^2 = 2 * a * d vf^2 =2 * 3.75 * 10 vf = sqrt(75) the velocity of the block A at the instant is C) sqrt(75) m/s